changing a 9 digit integer into a new 9 digit integer through simple mathematical operations. For example, I need to change 123456789 into the new digit 456123789. Sometimes I need to change a 9 digit integer into an 8 digit integer. An example is 789062456 into 62789456. I can ONLY use simple mathematical operations (addition, subtraction, multiplication, division and modulo).
View 4 RepliesI intend to reference this thread from another thread so I do not clutter that thread with code
/* This code is relied on by some of the functions I will post */
typedef unsigned long long zxumax;
typedef signed long long zxsmax;
[Code]....
Why this class doesn't work for Subtraction, Division and Square Root. When I try to get results for Subtraction, it output right answer, but with any trash. And When I try to get answer for Division and Square Root, it just brakes and don't output anything. For Addition and Multiplication class work correctly.
Its the link to this class [URL]
I'm working on a class project, and I'm having a difficulty. Suppose I have: string a = "21" and string b = "30"; normally, a+b=2130 (i.e concatenation of the characters in the string) but suppose I want a+b=51 (i.e. numerical addition) how do I go about this?
View 1 Replies View RelatedI've been assigned to build a program which completes mathematical operations using matrices. I have to use dynamically allocated 2d arrays, and can only use * to dereference and not []. I have this code so far, but the multiply_matrix function does not work with most values. I've looked at other similar posts, which have a similar algorithm to mine, but mine does not work for some reason.
/*
*(*matrix(matrix+i)+j)
*/
#include <iostream>
//for sleep() which allows user to see messages before screen is cleared
#include <unistd.h>
using namespace std;
[Code] .....
In code, I need to transform these values:
256 becomes 0
128 becomes 1
64 becomes 2
32 becomes 3
16 becomes 4
8 becomes 5
4 becomes6
Is there some way to express this mathematically so that I do nto have to use a table lookup? I know this sounds like I am an idiot, but I can not figure out an obvious algorithm.
I am trying to assign the integer value to unsigned char array. But it is not storing the integer values. It prints the ascii values. Here the code snippet
Code: uchar uc[100];
for(i=0;i<100;i++)
{
uc[i] = i;
}
The values which are stored in uc[] is ascii values.I need the integer values to be stored in uc[]. I tried to do it with sprintf. but the output is not as expected. if I print the uc[i] it should diplay the value as 0,1,2....99.
Complete the function myitohex so that its converts 8-byte integer to string based hexadecimals.
Ex: printf("0x%s",myitohex(64,hex)); should printout "0x40" on the screen
char *myitohex(uint8_t i, char *result){
???
return result;
}
I wrote:
#include <stdio.h>
#include <stdint.h>
char *myitohex(uint8_t i, char *result){
*result = i + '0';
[Code] ....
0xp gets printed out which is wrong. I think *result = i + '0'; is wrong. What changes should i do on this row ?
The code meant to generate a simple tree. As you can see from the output, somewhere the parent pointers get messed up. And yet, I can't seem to find where, and if I output them in the constructor (only time they get modified) they all look OK. When I run output_path_to_root() on any grandchildren of the root I get a segmentation fault. How the parents are getting messed up? I was wondering if my vectors changing size is causing pointers to shift around but I'm not sure.
//tree.cpp
#include <iostream>
#include <vector>
using namespace std;
struct A {
int n;
vector<A> get_children() {
[Code] .....
12 ( )
6 ( parent->node.n: 12)
3 ( parent->node.n: -1487162336)
1 ( parent->node.n: -1429198496)
2 ( parent->node.n: -1487162336)
1 ( parent->node.n: -1429198496)
4 ( parent->node.n: 12)
2 ( parent->node.n: -1487162336)
1 ( parent->node.n: -1429198496)
I have an assignment that calls for a C program using a for loop AND a while loop that will receive an integer (called daNumba) and double it -- Using the integer the program will call the sumFor function and then the sumWhile function. These functions will both sum the values from daNumba to (daNumba * 2) ifdaNumba is positive. If daNumba is not positive it will add the values from (daNumba*2) to daNumba. Both functions will receive the value of daNumba and return a summed value. The only difference between the 2 functions is that sumFor will only use for loops and sumWhile will only use while loops. We are not to use arrays.
The program compiles without error. So far my while loop works for positive integers, but not with a negative integer (I have it commented out) I cannot get the for loop to work properly This is what I have so far -- I am stuck....
Code:
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
int main () {
[Code] ....
i have the following problem to solve.... im unable even to start with an idea....can anybody help me giving an idea how to do this problem?
the problem is:
___*****____
Write a C++ program that factorize an integer n into p and q.
Step1. reads an integer n from the keyboard.
Step2. Write a for loop as below to check if there is any factor j > 1.
for (int j = 2; j <= square root of n; j ++)
{
If (n % j == 0)
{
factorizable = true;
break;
}
}
Step3. If there is no such factor, print the message n is not factorizable. If there is such a factor j,
check programmatically if j is a prime and n / j is a prime Also check if j and n / j are the same.
___****___
How can I add integer value to a stringstream or read an integer value from it?
View 1 Replies View RelatedThe programming problem is supposed to take a decimal number from a user and turn it into a binary number. Here is my code:
for (int i=0; i< count; i++) {
binary[i] = decimal % 2;
decimal = decimal/2;
} cout << binary[2] << endl;
decimal is the number entered by the user.
binary [] is the char array and count is... you know how many times the for loop will turn. So my question is, how do i know the length of the number ? Any function that shows the integer length ? because its impossible to know what count is equal to. like 100 is 3.
Is it really needed to specify 0 as an unsigned integer? I mean 0 is always 0 regardless it's signed or not, no? In the below example is the 0U really needed?
#include <stdio.h>
unsigned invert(unsigned x, int p, int n) {
return x ^ (~(~0U << n) << p);
}
int main(void) {
[Code]...
I was trying to implement Big Integer Implementation. I wanted to start with the basic operation of addition. I am having some problems with operator overloading part
/**
BigInteger implementation
*/
#include "conio.h"
#include "iostream"
[Code]....
DisplayImages.aspx.cs file
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Net;
using System.IO;
using mshtml;
using HtmlAgilityPack;
[Code]...
Now I'm getting the value of id i.e "DisplayImages.aspx?id=3" from DailyDarshan.aspx and want to display the images of each respective link according id.. when I click on "DisplayImages.aspx?id=4" link so it has to show the if(id == 4) images...but The problem is int id its not taking value itself.on DisplayImages.aspx.cs page I must have to define the id. for e.g. I wrote int id =3; on DisplayImages.aspx.cs file so it shows the images of id = 3 on each and every link.. Tell me what should I do to take value from another page or else how int id takes value by itself...
this is my code
#include<stdio.h>
main()
{
[Code]....
N=1st number M=2nd number(accrding to my prof we will name it N and M
ctr= increment of factorial of N, ctr2= increment of factorial of (N-M)
the problem is when i got the factorial of N / factorial of (N-M) i need to get the last non zero digit. so i use mod if it has zero in it. but mod can be only used with an int value. and when i change it to int value, the value of fact1 which is a float change
what is the size of integer in dos?
View 2 Replies View Relatedi wanna put an integer into a string for example:
Code:
string name;
int num=8;
name= "George"
//
I want in the end of George to pas the num variable i ve seen some examples but ive not yet come up with a solution like str.insert();
I am aiming to read an integer from stdin(pointed to the uart) and echo it with the uart interrupt service routine. there is a simple retarget file along with the main code shown below. So far i can read chars (char x[32] but i am struggling with int.
I have gathered that i need to use the scanf function to read an int from the pointer defined in fgets.
My output is giving me weird values, i enter 8 and ill get a random 3 digits back. I have a feeling its a problem with the input buffer.
Code:
//------------------------------------------------------------------------------// Cortex-M0//------------------------------------------------------------------------------
#include <stdio.h>#include <time.h>#include <rt_misc.h>
#include <stdlib.h>#define AHB_LED_BASE
0x50000000#define AHB_UART_BASE
0x51000000void UART_ISR(){
[Code] .....
I am trying to create the lparam for the WM_KEYDOWN message. I know this is the C programming forum, but my code is standard enough to apply here. According to Microsoft, the lparam must be formatted like this : lParam The repeat count, scan code, extended-key flag, context code, previous key-state flag, and transition-state flag, as shown following. Bits Meaning 0-15 The repeat count for the current message. The value is the number of times the keystroke is autorepeated as a result of the user holding down the key. If the keystroke is held long enough, multiple messages are sent.
However, the repeat count is not cumulative. 16-23 The scan code. The value depends on the OEM. 24 Indicates whether the key is an extended key, such as the right-hand ALT and CTRL keys that appear on an enhanced 101- or 102-key keyboard. The value is 1 if it is an extended key; otherwise, it is 0. 25-28 Reserved; do not use. 29 The context code. The value is always 0 for a WM_KEYDOWN message. 30 The previous key state.
The value is 1 if the key is down before the message is sent, or it is zero if the key is up. 31 The transition state. The value is always 0 for a WM_KEYDOWN message. ( WM_KEYDOWN message (Windows) )^ I'm troubled by setting it into the 32-bit value, and I get confused about what exactly happens when the logical or and the bitshift operators are used. I tried to use them below in my code by looking at Stack Overflow for setting a bit. I also don't know how to test for the endianess of my system, and how to handle it if it's big endian or little endian. Here is my code so far :
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
[Code].....
I have to make a program for school to evalute poker hand.I am not asking about the logic of the program,I am asking because I have to take the input from the console,five lines which can be the cards 2,3,4..10 and the problem is with J,Q,K,A ,because I dont know how to tell scanf to expect integer or char ? If I type J,Q,K,A the program crash ,
View 1 Replies View RelatedVerify my Method . I am not getting expected output ..
Code:
int Amount=500;
send(newSocket,Amount,4,0);
close(welcomeSocket);
recv(clientSocket,Amount,4,0);
// Amount= ntohl(Amount);
printf("Data received: %d",atoi(Amount[0]));
Code:
/*
* Instruction_t - stores a specific instruction
*/
typedef struct
{
[code]....
I have a problem. When I run my program (which contains this), through gdb, I can see that burstTime does have a value ( such as 1, 3, 15, etc).But when I dequeue from my list, instruction->burstTime suddenly equals zero!
Consider this piece of code from the following website: [URL] .....
Code:
unsigned intx = 50;
x += (x << 2) + 1;
The website above says the following about the code:
Although this is a valid manipulation, the result of the shift depends on the underlying representation of the integer type and is consequently implementation-defined.
How exactly would a legal left shift operation on an unsigned integer result in implementation-defined behaviour?
I got the following to compile and execute, but I don't understand how this works. Here is the code verbatim:
Code:
// Basic conversions in C
#include <stdio.h>
int main () {
float f1 = 123.125, f2;
int i1, i2 = -150;
char c = 'a';
[Code] .....
Okay, so first we have some variables declared as integers, floats, (and that char what it's doing). On the same lines we have values assigned to some of those variables. At first the "f2" and the "i1" confused me, but I think they're just variables whose type has been declared but have not received a value. So far I think I'm good. Then we get into the routines
I think I understand the first one. i1 didn't originally receive a value assigned to it, so when it says f1 = i1, then f1 (123.125) just becomes an integer, simple enough.
Then we get to the next routine and I'm like what dafuq??? So first we have f1 (123.125) being set to i2 (-150). wtf? So does that mean f1 is now going to have the value of -150? Vice versa? How are they becoming equal? Or does it have nothing to do with the values of the variables at all and just the type??? I'm just totally lost.
The output of that line is "-150 assigned to a float produces -150.000000." Which makes perfect sense to me written in plain English, but I don't understand how the C code works ....