I want to concatenate string+int so i make like that
Code:
for(int i=0;i<n;i++)
{
name="obstacle"+i;
cout<<name;
}
I get in the window
obstacle
obstacl
obstac
obsta
obst
...
..
o
but i want instruction that allow me to get
obstacle0
obstacle1
obstacle2
...
This seamed as a simple thing but i am getting something i did not expect: Example:
Code:
vector<char> StrJoin(SubjSeq.size()+ QuerySeq.size());
cout << StrJoin.size()<<"
"; // size x
StrJoin.insert( StrJoin.begin(), QuerySeq.begin(), QuerySeq.end() );
StrJoin.insert( StrJoin.begin(), SubjSeq.begin(), SubjSeq.end() );
cout << StrJoin.size()<<"
"; // x*2
All structures are vector<char>. when i do the above my characters form Query and Subject are copied in my new vector called StrJoin but the size of that vector is twice the size then it should be.
Trying to concatenate the 1st and 2nd element from an array of chars. Then this to be used as a hex value.
so for example
specs[0]='f'
specs[1]='4'
concatenate_value=0xf4
How i can concatenate two integers into one integer. I have code that concatenate two integers but if the 2nd integer is zero it won't work. How can i modify it so that it can cater the case of y=0 too.
Code:
int concatenate(int x, int y) {
int pow = 10;
while(y >= pow)
pow *= 10;
return x * pow + y;
}
when i was finding a way to concatenate three integers in C, I came across a snippet like this
Code:
#include<stdio.h>
#define cat(a,b,c) a##b##c
int main()
{
int d;
d=cat(1,2,3);
return 0;
}
How the macro works here? I am unable to understand the function '#' plays in the macro.
I m concatenating specific range of digits that are same from an array "element" . I have problem with range. As in my case the range is col_elem[ii]=4, but it will continue reading the next element if it is the same. My code is:
Code:
int element[8]={0,1,3,3,3,0,1,2};
col_elem[ii]=4;
for (rr=0; rr<col_elem[ii];rr++){
join_tmp[qq]=rr;
while ((element[ii]== element[ii+1]) ) {
[code]....
The objective of the project is to become familiar with linked lists by writing a series of basic functions that allow us to manipulate a set of linked lists. I've completed all of the functions except for one.
The function I am stuck on is supposed to do the following:
concatenates list1 and list2 to form a new list,
and returns a pointer to this new list;
Note: new list contains copies of all nodes in list1 and list2 */
I have a function that concatenate the strings in an array(2D)
Ex 1: Sean Connery Micheal King James Wood
Result: SeanConnery MichealKing JamesWood ...
The concatenation function working correctly and displays correctly in the function. But if I make another function to display it, it shows this
Ex 2: SeanConnery Sean MichealKing Micheal JamesWood James..
It adds to first name. Why?
Code:
void Concatenation( char dest[200][13] ) {
// loop through and concatenation the strings
for(int i=0;i<200;i+=2) {
myStrCat(dest[i],dest[i+1]); // mystrcat is equalto strcat()
[Code] .....
Actually i found some mistakes in my post. So here is the modified version. I want to concatenate the indexes of elements of array that has the same value for specific range.In my case the range is 4
Code:
int element[8]={2,2,0,3,3,0,1,2};
col=4;
int rr;
int qq=0;
for (rr=0; rr<col;rr++){
join_tmp[qq]=rr;
while ((element[rr]== element[rr+1]) ) {
join_tmp[qq]= concatenate(rr+1, join_tmp[qq]);
printf("%d
",join_tmp[qq]);
rr++;
}
qq++;
}
Code:
//FUNCTION TO CONCATENATE INTEGER VALUES OF SAME GROUP IN A COLUMN
unsigned concatenate(unsigned x, unsigned y) {
unsigned pow = 10;
while(y >= pow)
pow *= 10;
return x * pow + y;
}
Code: I want input like
10
2
3
Instead i get
10
2
34
how can i fix it so it will only iterate to the specific range?
I have two std::string data items that contain binary data (so it may have the null character!). What is the proper way to concatenate them to preserve all of the data? I am guess a simple:
string string3 = string1 + string2;
Will not work, as it will terminate string3 on the first NULL character it encounters.
I am trying to concatenate two words from a file together. ex: "joe" "bob" into "joe bob". I have provided my function(s) below. I am somehow obtaining the terminal readout below. I have initialized my memory (I have to use dynamic, dont suggest fixing that). I have set up my char arrays (I HAVE TO USE CHAR ARRAYS (c-style string) DONT SUGGEST STRINGS) I know this is a weird way to do this, but it is academic. I am currently stuck. My file will read in to my tempfName and templName and will concatenate correctly into my tempName, but I am unable to correctly get into my (*playerPtr).name.
/* this is my terminal readout
joe bob
<- nothing is put into (*playerPtr).name, why not?
joe bob joe bob
seg fault*/
/****************************************************************/
//This is here to show my struct/playerInit
[Code]....
How can I concatenate two 2-dimensional int arrays into one larger 3-dimensional array. This question is also valid for the 3-dimensional vectors. I know the command for the one dimensional vector as:
std::vector<int> results;
results.reserve(arr1.size() + arr2.size());
results.insert(results.end(), arr1.begin(), arr1.end());
results.insert(results.end(), arr2.begin(), arr2.end());
and for the one dimensional array as:
int * result = new int[size1 + size2];
copy(arr1, arr1 + size1, result);
copy(arr2, arr2 + size2, result + size1);
But I do not know how to make a 3-dimensional array or vector.
What is the efficiency of the two assignments (line 1 and 2), i.e. (function calls, number of copies made, etc), also the Big O notation. I know there are function calls for retrieving the size of each string in order to produce a new buffer for the concatenated string...any difference between line 1 and 2 in terms of efficiency?
String s("Hello");
String t("There");
1. s = s + t;
2. s += t;
Ok, so I'm writing this code and when I build it keeps saying cannot implicitely convert type int to string even though I declared my variables as string. Why is it giving me this error?
private static string Repair()
{
string result="";
string beep;
string spin;
Console.WriteLine("Does your computer beep on startup?:(y,n)");
[Code]...
I would like to understand a function on strings. Below is a code that I took from my teacher where the user inputs a string and prints out the length of the string.
Code:
#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int i = 0;
[Code] ....
Now I understand that it returns the count in "int" so my question is:
Let's say i declared
Code: int count = 0;
at the beginning of the code and then made
Code: count = strlen(str);
why wouldn't i have the same result? Is there a way to do it also?
I have this string d ="3 J JD, K" and i want to split the string to individual string. I have this code which eliminates the comma but doesn't split the string into individual string.
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
int main() {
string str = "3 J JD,K";
stringstream ss(str);
[Code] ....
Output of the code is
3 J JD
k
but I want
3
J
JD
K
Also after I split the string is there any way to put the split string into individual string variables.
Very new to programming, and I know that there must be another way on inputting a string into each array cells not by just inputting it one by one, but as a whole. My code at the meantime is: [URL]
View 1 Replies View RelatedI have problem with string compare. I want to compare the string user input with a string in binary. And I don't know how to do it. Problem in function login();Here is the code: And you also can download file in attachment too..
Code:
#include<conio.h>#include<dos.h>
#include<stdio.h>
#include<process.h>
#include<string.h>
char nsb=1;
char ch, password[20], passlogin[20], inputpass[20], checked[20];
FILE *fp;
}
[code]....
In this code, i declared a string constant and trying to print the length of string. I know that if i write char a1[7] or char a1[] than it runs and give aggregate output, but in this case it is giving double length of string.
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
}
[code]....
I wrote a program that reads a list from a file and stores it in a string type vector. Now, I want the user to input a word so that the program can search the vector to see if that word already exists. I have used every possible way of reading input from the console and storing it in order to compare with the vector but it never results in a match. When I print the input string and the vector string they are exactly the same thing (or at least print to the console as if they were). I've tried using getline; using cin direct to a string var; using cin to a char array and then casting to string using string str(arr); I even added a newline at the end just in case and STILL I cannot get a match.
vector <string> currentSet; //read a list in from a file and has 9 items in it
cin.ignore();
string line;
getline(cin, line);
if(line == vector[0]){//if printed to console line is HEAT and vector[0] is HEAT
cout<<"match"<<endl;
}
write a program that prompts the user to input a string and outputs the string in uppercase letters. (Use a character array to store the string.) Does this follow the criteria? This program is very similar to one I found on these forums but I have one problem, it outputs everything backwards! EX: dogs will output to SGOD. What I need to do to make it output correctly, I think it may have to do with getline?
#include <iostream>
#include <cctype>
#include <cstring>
using namespace std;
int main() {
char let[100];
cout << "Enter what you would like to be UPPERCASE: ";
[Code] ....
I just i would like to know how to record a string from a label to an array string ?
string[] stringArray = labelone.Text
I made a simple little program that takes text from the clipboard, and spits out all the lines I've copied one at a time (so my program can analyze it).
everything works perfectly, except, it spits it own in the wrong order, I want it to spit out from bottom to top. but currently it spits out the data from top to bottom. here is my code :
Code:
#include <iostream>
#include <Windows.h>
#include <string>
#include <sstream>
using namespace std;
int main() {
HANDLE clip; // assigns the var. clip to hold a handle ID.
[Code] .....
I want this loop to run backwards! Like it say's what I want to work backwards. Where as I know how to flip a while loop like this: while(x < 5), how to flip a loop like the one I'm using. how I can do this?
I have the codes for such a problem where, to create a program that counts how many times the second string appears on the first string. Yes it counts if you put 1 letter only, but if you put 2, it is an error. As an example. If the first string is Harry Partear, and the second string is ar, it must count as 3. Here's the code:
Code:
#include <iostream>
#include <conio.h>
using namespace std;
int main ()
[Code] ....
I am stuck in this program, Be given a string of chars, where each single char belongs to the following alphabet: a..zA..Z0..9 (So, in the string there are only lowercases, uppercases and digits. No blank, no comma, ...). For every char of the given alphabet, count how many times in the string
1-- the char belong to a sequence of identical chars whose length is at least three (i.e.: in the string cc74uyrpfccc348fhsjcccc3848djccccc484jd for three times the character 'c' satisfies this condition)
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
[Code]...
2-what is the longest substring of characters strictly rising interm of ASCII code(the following is greater (>) of the previous)
3- what is the longest substring of successive characters interm of given string rannge (i.e.: fhkjshdfruytyzABCDEfglsj => 7)
/*assume array is already initialized and declared and is of array type string.*/
int i = 2;
int j = 1;
string newvalue;
cout<<"Current value at array[i][j] is "<<array[i][j]<<endl;
cout<<"Enter new value "<<endl;
cin>>newvalue;
array[i][j]= newvalue; //PROBLEM IS IN THIS LINE.
cout<<endl;
cout<<array[i][j]<<endl;
I'm having lots of trouble with storing a cin string text into a string array. It just seem that after I cin newvalue, the program crashes. Is this way of storing it considered illegal? I'm just a beginner with 5 months of coding experience in C++.