C++ :: Program To Determine Slope Of A Line - Stuck On Commas When Entering Numbers
Jan 1, 2013
The program I have is from a tutorial where the user enters two points on a line, and then the program calculates the mid-point and slope.
I want to modify it from it's initial form so that co-ordinates can be input in (x,y) fashion. Right now the user has to enter the x-coordinate, enter a space, and then enter the y-coordinate (lame...)
I saw people using SStream and using that to either write functions to ignore the comma or similar things for converting one file into an array, but not quite what I am trying here.
// program to determine slope of a line
#include <ios>
#include <iostream>
#include <istream>
#include <limits>
using namespace std;
void myflush ( istream& in ) {
[Code] .....
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Jan 11, 2015
I am not sure how to enter command line arguments when I run the executable of the file below. I want check an make sure that only two arguments get into the main() before running the rest of the code. I'm using bash on linux.
An example that I have tried to test for 2 arguments in command line -arg1 arg2 > ./a.out This of course does not work
#include <stdio.h>
#include <stdlib.h>
#include <errno.h>
[Code].....
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Aug 13, 2014
Write a program that prompts the user to enter three integer values, and then outputs the values in numerical sequence separated by commas.
So, if the user enters the values 10 4 6, the output should be 4, 6, 10.
If two values are the same, they should just be ordered together.
So, the input 4 5 4 should give 4, 4, 5.
Code:
#include "std_lib_facilities.h"
int main()
{
cout << "Enter three integers, separated by space: ";
int a, b, c, temp1 = 0, temp2 = 0;
cin >> a >> b >> c;
[Code] ....
My first solution has a bug, so here's the corrected solution, written using only features I have learned in the first three chapters:
Code:
#include "std_lib_facilities.h"
int main()
{
cout << "Enter three words, separated by space: ";
string a, b, c, temp;
cin >> a >> b >> c;
[Code] ....
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Feb 21, 2014
I'm currently trying to code a sorting algorithm program.
let's asume I have a string given: aa, aaa, bbb, bas, zya!
I first of all want to split the given string on commas and '!' tells the program the string ends here and is no part of the last word. lower and upper case is not important at the moment. trying to implement everything with standard libary
output should be like that ofc:
aa
aaa
bas
bbb
zya
I already looked into the bubble sort algorithm and I think it benefits my needs. Just wanted to know how I should start out with the string split.
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Jul 19, 2013
How do I prevent user from entering characters or symbols instead of numbers?
int num;
cout<<"Enter a number."<<endl;
cin>>num;
Also, how do I prevent user from entering a number instead of a character?
char c;
cout<<"Enter a character."<<endl;
cin>>c;
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Jan 26, 2014
When I use my perceptron, it classifies everything appropriately, except it always says points that are exactly on the line are above it.
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Feb 18, 2013
The problem is with the first "Type and Run," where the code looks like this:
Code:
/* print_it.c--This program prints a listing with line numbers! */
#include <stdlib.h>
#include <stdio.h>
void do_heading(char *filename);
int line = 0, page = 0;
[Code] ....
I am using the gcc compiler in Ubuntu 12.04 LTS and I get the following error:
Code:
print_it.c: In function "main":
print_it.c:36:15: error: "stdprn" undeclared (first use in this function)
print_it.c:36:15: note: each undeclared identifier is reported only once for each function it appears in
print_it.c: In function "do_heading":
print_it.c:49:16: error: "stdprn" undeclared (first use in this function)
I was told that "stdprn" can be recognised by a DOS based compiler and the book says I can try using "stdout" instead. It looks like this now:
Code:
/* print_it.c--This program prints a listing with line numbers! */
#include <stdlib.h>
#include <stdio.h>
void do_heading(char *filename);
int line = 0, page = 0;
[Code] .....
It compiled OK with the gcc compiler but I only get this when I run the program:
Code:
Proper Usage is:
print_it filename.ext
I am not sure whether I should continue looking into this but even when I tried compiling and running it on Windows, the .exe file won't even launch. The other ones do but this first one doesn't.
Questions:
1. What should be done to make this program run?
2. Even though the book says "don't care" if the reader does not understand the items (It's Day 1/Lesson 1), I would still like it to run as I don't want to experience compiling and running problems in the future. Should I even bother doing this section of the book or is it obsolete and should be skipped?
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Aug 24, 2013
I'm trying to get my C program to compile but it's not working at all. I've programmed a little in C++ before but I'm not used to C. Here's my program so far:
Code:
int main(void){
// Establishes variables
int num1, num2, product;
float quotient;
[Code] .....
It keeps giving me an error message as follows:
"/usr/bin/ldrelabwk2: file format not recognized; treating as linker script
/usr/bin/ldrelabwk2:1: syntax error
collect2: ld returned 1 exit status"
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Jun 7, 2013
So my inventory program runs fine as far as I can tell. Except when entering "Amounts" with more that 1-precision . ie
Amount Entered : 25.99 // Problem
Amount Entered : 25.9 // No Problem
When entering say 25.99, the rest of the file is jibberish. but 25.9, the rest of the file is fine
Code:
#include <stdio.h>
typedef struct toolRecord{
int record_num;
char tool_name[16];
int quantity;
double price;
[Code] .....
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Mar 1, 2013
I'm trying to write a program where the user will keep entering data until pressing control + D. Then the it will display the mean, smallest number, and largest number.
Here are three samples of my program running.
Sample 1
Enter the price for stock 1: $ 10
Enter the price for stock 2: $ 1.555
Enter the price for stock 3: $ 3.648
[Code].....
As you can see in Sample 1, the program runs correctly. The largest number was 20 and the lowest number was 1.555. But in Sample 2, the program shows min as 15.500, where it should be showing 15.000 and Sample 3, the program shows min as 110.000 when it should be showing 55.564.
Here's the code.
#include <iostream>
#include <iomanip>
using namespace std;
[Code].....
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Dec 2, 2014
I have to write a program that use a while loop and that each time around the loop reads two double, prints out the largest, the smallest and if they are equal.
I have no problem with this program but I can't understand how to modify it following the author : Change the program so that it writes out "the numbers are almost equal" after writing out which is the larger and the smaller if the two numbers differ by less than 1.0/100.
for now this is my code :
int main() {
double a = 0;
double b = 0;
while (cin >> a >> b) {
cout << "first number is : " << a << "
second number is : " << b << "
[Code] ....
The problem is that I don't know how to test if the numbers differ by less than 0.01 because my if statement doesn't work in any case. If I enter 2 and 1.99 It doesn't work, why ?
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Mar 18, 2014
I'm having trouble getting my loop to work correctly. If I iterate the for loop once it works as expected and displays proper output. When I try to iterate two times or more the program gets stuck in an infinite loop.
testData8.dat:
Code:
12 9
13 756
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Oct 21, 2013
I am making a math game program that simple and need to have a user input a name and then that name.txt is brought up and use variables from the text to add to their score. heres my code kinda long.
#include <iostream>
#include <cmath>
#include <cctype>
#include <string>
#include <ctime>
#include <cstdlib>
[Code] ....
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Jan 27, 2015
I have a bw(grayscale) image and want to calculate the slope for each pixel which returns a value 0 to 255 value.
Pixels are always between 0 and 255. The highest possible difference is 255. The end result would be 0 for no slope and 256 for the highest slope.
Would this formula work?
slopex = pixel[x+1,y] - pixel[x - 1,y];
slopey = pixel[x,y+1] - pixel[x,y - 1];
totalslope = sqrt(slopex * slopex + slopey * slopey)*256;
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Mar 1, 2013
I've pretty much finished the entire program, except for the actual calculation part.
"Given a range of values determine how many integers within that range, including the end points, are multiples of a third value entered by the user. The user should be permitted to enter as many of these third values as desired and your output will be the sum of total multiples found."
I've defined functions to take user input for the low range, high range and a do-while loop to take as many third inputs as the user wants (terminated by entering -1, as requested by the question)
To actually calculate if they're divisible, I found out that if A%B = 0, then they are divisible, so I thought I would create a loop where each value in the range between A and B is checked against the third value to see if they output a zero.
What I need to end up with is a program that tells the user how many integers are divisible by the numbers in the range, i.e: "Enter the low range value: 335 Enter the high range value: 475 Enter a value to check within the range: 17 Enter a value to check within the range: -1 There are 8 total values that are divisible by the numbers in the range." Going back to my original question, how would I create a loop or something to "check" how many values are equal to zero, and consequently increment a variable for each instance? (This is how I think it should be done)
Code:
#include <stdio.h>
//GLOBAL DECLARATIONS
int getlowR();
int gethighR(int);
[Code].....
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Mar 30, 2013
/* Task: create a function that determines prime number and use it to print out prime numbers from 0-50: */
Function prototype: Should return a `bool` (because it answers a yes/no question) and should take in a single int (to ask whether it's prime).
- An int greater than 2 is prime if it is not divisible by any number between 2 and itself, not including itself.
- Use this function to print out the primes less than 50. Check it against my list:
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47
#include <iostream>
using namespace std;
int prime(int&x) {
if(x%2==1)
[Code] ....
It is printing out the correct prime numbers but also printing this between each number: 1629974960
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Oct 24, 2013
I am just starting out programming and have an assignment due in the near future. the problem is I cant seem to figure it out. I started it already but got stuck cant seem to figure it out. Here is the assignment.
Create a program that will generate a list of 200 random numbers (ranging from 1-1000) and determine the medium, mode, and average of the list of numbers. Have the program display the original list ant then display the list in ascending and descending order on the screen.
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Mar 5, 2013
I need to write a ANSI program to print out each command line argument on a separate line using a for-loop. also it need to print the name of the executable .so far I have
Code:
#include <stdio.h>
int main(int argc, char **argv) {
int i;
printf("")
[code]....
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May 7, 2013
l need to write a program which writes out its command line arguments in reverse order one per line. The output from the program should look like this:
% a.out Two roads diverged in a yellow wood
wood
yellow
a
in
diverged
roads
Two
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Oct 20, 2013
I have a current assignment for C++ involving us to make a program to determine coin change for example if you input the number 127 you would need 2 half dollars 1quarter and 2 pennies I have no way how to program this.
This is my code that doesn't do what i want it to
#include <iostream>
using namespace std;
int main ( ) {
float change;
int half_dollars, quarters, dimes, nickels, pennies; // declare variables
[Code] ....
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Oct 21, 2013
Write a program that determines the day number (1 to 366) in a year for a date that is provided as input data. As an example, January 1st, 1994, is day 1. December 31, 1993, is day 365. December 31, 1996 is day 366, since 1996 is a leap year. A year is a leap year if it is divisible by four, except that any year divisible by 100 is a leap year only if it is divisible by 40. Your program should accept the month, day, and year as integers. Include a function leap that returns 1 if called with a leap year, 0 otherwise. Extend the requested solution so that your program continues to prompt the user for new dates until a negative year is entered. This is what I have so far.
Code:
#include <stdio.h>
#include <stdbool.h>
int main(void) {
int d,m,y;
int days=0;
int k;
[Code] .....
I am unsure how to make this a loop so that it keeps asking for dates?
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Apr 18, 2014
Working on an assignment and I've hit TWO stumbling blocks. I now have to take the first line from a .txt file and use that number to determine the size of rows to create in my program. I am using fscanf but the program hangs. How can I read in this number, store it and use it in a for loop?
The second issue is after reading this number I have to print each number in the .txt file under a different column. (Note that it skips a line after reading the row count.) The .txt file is set up as follows:
9 1 3 6 4 7 8 8 6 1
The output should look sort of like:
Number 1 3 6 4 7 8 8 6 1
Here's my attempt:
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <math.h>
typedef struct{
int number;
[Code] .......
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Jan 16, 2015
I seem to be having a logical error but can not find the sources.
#include <iostream>
using namespace std;
int main() {
int student = 0;
int adult = 0;
[Code] ....
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Oct 6, 2013
If the number 4 is entered, the output should be the following:
1: 1
2: 1, 2
3: 1, 3
4: 1, 2, 4,
My output, however, is different but I know its an error with the comma.f
1: 1, , ,
2: 1, 2, ,
3: 1, , 3,
4: 1, 2, , 4
Here is my code:
#include <iostream>
using namespace std;
int main()
{
[Code].....
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Aug 12, 2013
C program I am making.
For example: if nNum is 12345, the program should display 12,345
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Jun 23, 2014
it will not run and im not sure why. I have a couple of errors, but I'm not sure why.
Here is my code.
//Reads input from user to determine different discounts by number of units sold
#include <iostream>
#include <string>
using namespace std;
int main() {
//Declaration and Initialization of variables
int quantity;
double discount,price = 99.00,totalCost;
[Code] ....
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