C :: Define Array Type With 4 Elements?

How can I define type MARKS which will be able to hold 4 elements just like array? I want to access it just like normal array elements using brackets []. In the following struct I want to use such type.

Code:

typedef struct {
MARKS ** pointers;
} ARGUMENTS
void main(){
ARGUMENTS arguments;

[Code] ......

Purpose of the struct ARGUMENTS is to hold 4 pointers to string. I want to mark few positions in string so I can simple access them. E.g. name=John

Code:
arguments[0][0]=0; // begin of the param name
arguments[0][1]=3; // end of the param name
arguments[0][2]=5; // begin of the value
arguments[0][3]=8; // end of the value I mean not to save int but the pointer to the corresponding position.