C++ :: Program To Predict Size Of Population Of Organisms
Feb 22, 2015
Write a program that will predict the size of a population of organisms. The program should ask the user for the starting number of organisms, their average daily population increase (as a percentage), and the number of days they will multiply. A loop should display the size of the population for each day.
Input Validation: Do not accept a number less than 2 for the starting size of the population. Do not accept a negative number for average daily population increase. Do not accept a number less than 1 for the number of days they will multiply.
My code works fine just up until the end.
#include <iostream>
using namespace std;
int main() {
int organisms = 0, growthRate, rate, days, amount = 0;
//int x; //for loop
[Code] .....
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May 20, 2012
I'm new to C++ and am trying to create a program to solve the problem as described in this image: [URL] .....
Here's my code. It fails to execute the main part of the problem (years, population of A & B) but works well in recognizing errors (if PopA >PopB or if growth rate of PopA<PopB)
Code:
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
int main() {
string city1, city2;
[Code] .....
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Apr 16, 2012
In a cartesian coordinate system, I want to be able to predict a compass angle of an object. So I have a base position of (0,0) and then a distance and compass angle to an object. This object also has a heading and a speed. How can I predict the new compass angle of the object with that information?
my coordinate system is like this:
Code:
0 y
|
|
270-------------- 90 x
|
|
180
I think the first step would be to compute the cartesian coordinates of the object:
float degs_to_rads = 3.141592653589793 / 180.0;
x = distance * sin(angle*degs_to_rads);
y = distance * cos(angle*degs_to_rads);
then the next step would be to compute the predicted x and y from the speed and heading of the object:
predictedx = ??
predictedy = ??
then finally convert back to an angle, and distance:
newDistance = sqrt(predictedx^2 + predictedy^2);
newAngle = atan2(predictedy, predictedx);
fill in the blanks?? Are my other things correct?
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Mar 12, 2014
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Anyway here's the code:
Code:
#include <iostream>
long swe_pop = 9644864;
int main ()
[Code] .....
The result I'm getting is 0%.
I was under the impression that long (or long long) integers could hold high values. And that I could then divide these and answer with a float type value. Giving space for the decimals.
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#include <stdio.h>
#include <stdlib.h>
#define MaxPopulation 10000
#define MaxChildren 10
#define maxAge 70
#define ranf() ((double) random()/(double)RAND_MAX)
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struct d{
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int c;
[code].....
When I run this program, the output is 80(for my compiler). That would mean that each element in the array is 16 bytes but I don't understand how struct d is 16 bytes.
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May 10, 2013
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Code:
void foo1(double *x, double *y, int *nsamp){
int i, j, k, oper=2, l;
double* v1v2=malloc(sizeof(double)*((*nsamp)*(*nsamp-1)/2 + 1));
outer_pos(x, y, nsamp, &v1v2[0]);
double v1v2b[1999000]; //<-------HERE
for(i=1; i<= 1999000]; i++){
v1v2b[i-1]=1;
} }
However, in foo2, I first create an integer variable called index, and store the value 1999000 in it. I then use it to initialize the same array. When I tried calling this function in R, it either led to a stack overflow error, or completely crashed R.
Code:
void foo2(double *x, double *y, int *nsamp){
int i, j, k, oper=2, l;
double* v1v2=malloc(sizeof(double)*((*nsamp)*(*nsamp-1)/2 + 1));
[Code] .....
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The second issue is after reading this number I have to print each number in the .txt file under a different column. (Note that it skips a line after reading the row count.) The .txt file is set up as follows:
9 1 3 6 4 7 8 8 6 1
The output should look sort of like:
Number 1 3 6 4 7 8 8 6 1
Here's my attempt:
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <math.h>
typedef struct{
int number;
[Code] .......
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Code:
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And this text
Code:
s=_T("Let's try to calculate the size of this text");
and with MM_LOMETRIC map mode
GetTextExtent() returns me:
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Ink printer + print preview: (1589,100)
PDFCreator + print preview: (1580,100)
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Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <errno.h>
#include <stdint.h>
[Code]....
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short int capacity(int* a) {
int capacity;
[Code] ....
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[URL]
Also, I know that I just enter the size of the list manually, in this case make i < 6 but I still want to know if there is a built in function or something.
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Code:
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";
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C++ masters,
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Code:
#include <stdio.h>
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[Code] .....
All is right except the size. Why does it give 80x1 as size instead of the digit 5?
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Here is my code:
Code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
char *strreplace(char * string, char * sub, char * replace);
}
[code]....
Here is the same code, but with execution + some syntax highlighting: Ideone.com | Online C Compiler & Debugging Tool..It works great, until it gets to grabbing whatever remains in the search string after the last found sub. The realloc throws a runtime error:
Code:
*** glibc detected *** ./a.out: realloc(): invalid next size: 0x00011008 ***
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Code:
int evensToRead(int* const List, const int Size){
//body
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