void armazenaFA( std::vector <int> &vFA) // this function only knows about vFA { vsFA[n] [m]= simTime().dbl(); OR vsFA[n].push_back(simTime().dbl()); }
we conform to the ISO C standard and this snippet of code : Code: vector<tree*> *leaves = new vector<tree*>[num_threads]; where num_threads is specified from command line arguments so not dynamically allocating it violates the standard.
Let's also assume num_threads is greater than one.
What I want to do is scan each vector in leaves for duplicates. If any two vectors in the set have matching addresses, they both immediately go onto the "unsafe" pile and will no longer be subject for testing.
If a vector clears one vector, we test it against the others in the set.
So if we have 3 vectors, A, B and C we test A against B then A against C. For efficiency, we then then just test B against C.
Like I said, I want a "safe" and "unsafe" pile. Every vector in "safe" is fully unique while every vector in "unsafe" is not unique.
I thought about just using a for-loop to loop through leaves and then iterate through each element but I'm not sure if that'll work just right out of the box.
I can't compile this code as I am at work and the computers are security protected, So i''l have to wait until i get home to test this, but I am pretty sure I am wrong. The problem is I have to create two vectors with 10 elements and input random numbers into it, then pick one of the elements of the second vector at random and append it to an element from the first vector at random. This has to be done 10 times and the I am assuming i have to print the 10 results. This is what I have:
#include <cstdlib> #include <ctime> #include <iostream> using namespace std; int main() { vector<int> random (10);
I'm doing a project where I have to store information gathered (temperature and the time it was taken in seconds) in two separate vectors. After an unknown amount of data has been entered, and the end-of-file has been reached, I have to display the highest temperature and the time(s) it occured (bear in mind that the highest temperature may be recorded more than once). The output of that part should be as follows:
Highest temperature: 51 Recorded at time(s): 22:45 2:27
Something like that. The time should also be converted to hours and minutes. To the point: I've done some research on bubble sorting, but they only use it for arrays.
I am trying to print the prime numbers, so i put the numbers into the vector and then erase the non prime numbers. if i comment the break statement i get runtime error saying out of bound, but if i don't comment it out it prints the primes but it also prints the multiples of 3.
void Eratos( int length, vector< int > &v ) { int i; for (i=0; i<length; ++i) { v.push_back(i); cout <<v[i];
Say I have 5 vectors of unsigned char each of size 5. I want to take the max of each index and store it in a new vector. What is the most optimal way to accomplish this?
Suppose I want to represent an apartment building in terms of floors and rooms with a single data object. Each floor has the same number of rooms at any given time. During the course of the program, I will need to change the number of floors occasionally and will need to change the number of rooms on each floor occasionally. (Don't worry about the building permits needed to do this.) Now, I also want to be able to iterate over either each floor (think "row") or each room (think "column"). For example, I might want to program the equivalent of "Johnson, go fix all the front doors on the 8th floor" or the equivalent of "Johnson, go fix all the front doors to room B on each floor". (Yeah, I know, for the latter I could iterate over each floor and then access room B but that doesn't feel as "clean" as being able to iterate over a separate room/column.)
Suppose I want to represent an apartment building in terms of floors and rooms with a single data object. Each floor has the same number of rooms at any given time. During the course of the program, I will need to change the number of floors occasionally and will need to change the number of rooms on each floor occasionally. (Don't worry about the building permits needed to do this.)
Now, I also want to be able to iterate over either each floor (think "row") or each room (think "column"). For example, I might want to program the equivalent of "Johnson, go fix all the front doors on the 8th floor" or the equivalent of "Johnson, go fix all the front doors to room B on each floor". (Yeah, I know, for the latter I could iterate over each floor and then access room B but that doesn't feel as "clean" as being able to iterate over a separate room/column.)
If I have a Vector of pointers, how can I iterate through that vector, to access the name function of each object in the vector? There seems to be a problem with my implementation, the output returns only random symbols.
Implementation of the name() function in Drug.cpp:
//name() is a function returning the name in the parent class string Drug::name() { string out = "Drug: "; out += mName + " [ "; //The problem is with this loop for (int k = 0; k < mComponents.size(); k++)
there is a way to iterate through the controls on a webpage. For instance, I tried EnumChildWindows using the parent window of the browser, but I haven't had any luck - it returns nothing. s where I can start researching how to find the child controls?
This is probably a very basic question, but I need to create two vectors and then loop through the vectors and output each pair that is found.
The user will input min1 and max1 with step1 for the first vector and min2 and max2 and step2 for the second vector. Then the loops will go through and return the combinations will return each pair of the two vectors.
So if I input min1=1 and max1=10 and step1=1 and same for vector two the return would be:
[1,1] [1,2] . . . [10,10]
This is for part of a homework assignment, but I can't continue on the assignment without first getting this simple part to work.
This is a round robin execution. with gantt chart. arrival time and burst time. I think there is an error in my formula to get the right answer,i cant resolve it but my program is running. What is the code or the right formula??
#include<stdio.h> int main(){ int i,j=0,n,time,remain,flag=0,ts; int sum_wait=0,sum_turnaround=0,at[10],bt[10],rt[10]; int ganttP[50],ganttStartTime[50]; printf("Enter no of Processes : "); scanf("%d",&n); remain=n;
I am making a program where the user enters numbers into an array and then a number,x. The array is sorted, then x is inserted into the appropriate place. I wrote my selection sort
Code:
void Sort(int ary[], int size) { int temp; int smallest; int current; int move; }
[code]....
put it wont print the numbers sorted when I use my print function, just the unsorted numbers.
I want to add 2 vectors to print out so that there on the same line. What I am trying to make is an inventory system that will use 2 vectors to keep the pounds of the item and list the 2 vectors on one line.
(I am using Microsoft Visual C++ 2010 Express)
Like this:
0. empty 0 1. empty 0 2. empty 0
etc...
Right now it looks like this:
0. empty 0. 0
The code:
#include "stdafx.h" #include <iostream> #include <vector> #include <string> #include <fstream> #include <cmath> using namespace std; int main() { vector<string> inv;
I have a vector I want to add book titles to, then i want to print my updated vector. This is best I have come up with but the program fails at the getline line. why?
string book; cout << "Enter book to add: "<< endl; getline(cin, book); books.push_back(book); for(int i = 0; i < books.size(); ++i) { cout << i+1 << ". " << books[i] << endl; }