C :: Function To Check Whether Input Is Composed ONLY Of Alphabet / Space
Feb 15, 2013
This code is supposed to ask the user to input characters at most 20 and they should only be composed of alphabets/spaces..
Code:
#include <string.h>
#include <stdio.h>
#include <ctype.h>
int main(){
char addressbook[6][30][0];
int current_record = 0, length, i=0;
[Code] ....
I have removed the error from the main code but there's still this lingering error in the return part.
syntax error before 'return'.
It won't compile.
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Oct 3, 2013
How i could go about extracting and checking if the very first character in my string array is an alphabet
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Jun 10, 2013
I need a function to check if the inputted string contains a colon. It has to be in an if loop as the condition.
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Sep 20, 2014
how to input with space what i mean is like this, for example:
Product Code: 0000001
Product Name: Mobile Phone
if the users input is like that in the (Product Name)it will skip the next input that is the
Price: Quantity: 100
Manufacturer: Alcatel
something like that...
Heres the code
Code:
if(b<=10)
{/*Start for IF Statement*/
for(a=1;a<=b;a++)
{/*Start of FOR loop*/
printf("
");
printf("Product Code : ");
scanf("%s", &prod_code);
}
[code]....
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Apr 20, 2014
I trying to get input from the user and split into words that separated by a space.
string s = "1 2 3";
istringstream iss(s);
int n;
while (iss >> n) {
cout << "* " << n << endl;
}
The code above works fine but i want to get the string from user. the code below only prints the first word and trashes rest of the words in the sentence.
string s ;
cin>>s;
istringstream iss(s);
string n;
while (iss >> n) {
cout << "* " << n << endl;
}
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Nov 3, 2014
I have a class Square that is composed of two Points, I pass the former to the Square as references (second ctor) and two Points are created.
The problem is, at the end of the program, 4 Points are now being deleted which suggests that somewhere copies were made (regardless of the references) and the m_p1, m_p2 have different addresses than p1 and p2.
#include <iostream>
using namespace std;
class Point {
public:
Point();
Point(double x,double y);
double printCor() const;
[Code] .....
Even though, the objects were passed to the ctor by references, the copy constructor (compiler generated) for Point was called and now we have two points and an object square with distinct Point objects.
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Jan 18, 2013
I have a question regarding composition and accessing members "deep" inside the composed structure. For example;
class A {
private:
int m_myInt;
public:
int myInt() const {return this->m_myInt;};
void myInt(int newInt) {this->m_myInt = newInt;};
[Code] ....
Now, from somwhere I have access to an object of type B where I want to update the A::m_myInt. How would you do this without "breaking" the whole purpose of private/public members?
B myB;
myB.m_a.myInt(3); // Not allowed, and not desireable
I thought about implementing access through functons kind of like;
A & B::a() {return this->m_a;};
myB.a().myInt(3);
but I'm worried that this exposes my B::m_a-object too much. This would allow
myB.a() = A();
, right?
The following is a more desireable way of acces, but doesn't work for updating;
A const & B::a() {return this->m_a;};
myB.a().myInt(3); //Disallowed? myInt(int) is non-const.
What about this? Is this a good way of doing it?
class A {
private:
int m_myInt;
public:
int myInt() const {return this->m_myInt;};
[Code] ....
I guess it works? It would lead to a lot of data shuffling in case of larger sub-components.I would really like to do the following without exposing my components so much:
B myB;
myB.a().myInt(3);
Can it be done?
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Jan 23, 2013
this function has to check if an array is not descending it has to be recursive and it's space complexity has to be O(log(n))
Code:
int is_sorted(int a[ ], int n) {
int check=n-1;
if(n==1 || n==0) return 1;
if(a[check]<a[check-1])return 0;
else return(is_sorted(a,n-1));
}
this is what i came up with. i know it's space complexity is O(n) how do i make it O(log(n))?
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Apr 27, 2013
Code:
char value;
printf_s("enter:");
if (scanf_s("%c", &value) != 1)
{
printf_s("oppppssss
");
}
else
{
printf_s("ok");
}
I wanted to check whether the input is a character or not, if a character is given then the output suppose to be "ok", but the output is always "oppppssss", where is the problem here?
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Mar 20, 2013
Description: This program asks the user to enter a Fahrenheit temperature and then converts it into Celsius and Kelvin temperature.
Code :
#include <stdio.h>
void Temperatures(double temp_F);
int main(void) {
double temp;
[Code]...
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Jan 15, 2013
I have an assignment to do..i have done it..but i need to do one more thing. Things sound like this: user inputs 6 integers program needs to check them if there are integer if not it has to output a message for the user if the input is integer it has to go further and work with the input. I have used this structure :
if ( ! ( cin >> temp ) ) {
cout<<"Input is not integer.This program will end ! "<<endl<<endl<<endl;
system("pause");
return 0;
}
Where I declared temp as being int since i started, the problem is after it gets the last input still waits for an input i will attach the source code if needed.
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Nov 3, 2013
I have a homework that needs to verify if the input of the user is an integer using only loops no if statements Here's the problem:
A program is required that prompts the user for a number. The program will then print a series of asterisks to represent the number. If the user enters a number less than 1, the program stops. For example:
Enter a number: 5
*****
Enter a number: 3
***
Enter a number: 9
*********
Enter a number: 0
All user input must be validated:
- Check for non-numeric input when reading numeric input
- Check that values entered are within the expected range for their purpose, or in range based on the requirements statement
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Jan 20, 2013
i'm making a for loop for a mini game which required the user to enter the input number.Let say if the user accidently entered a character instead of integer the whole program will go haywire so is there anyway to check for the error and prompt the user to input the data again?Here is the simple program...
for(row=0;row<4;row++)
{
printf("Enter Row%d:",row);
for(col=0;col<4;col++)
{
scanf("%d",&num[row][col]);
}
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Nov 8, 2013
This program works but i need to build an additional loop that will re-prompt a user if his initial entry (int y_n) is other than 'Y', 'y', 'N', 'n'. For instance if a user tries to enter 'Yup', he will be prompted "That isn't a valid entry" and then re-asked to enter int y_n.
Note: If user answers Y he is asked to enter a value that is entered into an array. If the user at any point answers N, the program ends and final stats are cout.
#include <iostream>
using namespace std;
int main(){
char y_n;
int i = 0;
float input_value;
float myarray[100];
[Code] .....
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Oct 16, 2013
If I have a char array that that looks like
char array[] = {'a', 'b', 'c'};
How can I check user input against all of these values at once?
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Oct 8, 2014
In my WinForm, Our client insists to use Textbox instead of DateTimePicker field, and they want to input in ddmmyy format.
Using Visual Studio 2010 C# 4.0.
PC date time setting: GMT +08:00 dd-MMM-yy.
Assumed today date is 291014 (29-Oct-14).
CodeBehind:
DateTime inputDate;
// the WinForm allows user to input date not earlier than 2 years before today date and not more than 1 months from today date too.
//Assumed I input date as 261014 (26-Oct-14)
if(DateTime.TryParseExact(input, "ddMMyy", new System.Globalization.CultureInfo("en-US"), System.Globalization.DateTimeStyles.None, out inputDate)) {
DateTime minDate = DateTime.Now.AddMonths(-24);//Assumed it is 29-Nov-14
DateTime maxDate = DateTime.Now.AddMonths(1);//Assumed it is 29-Oct-12
I tried many methods but none works (I have checked many threads/forums also).
//Method 1
if(inputDate >= minDate && inputDate <= maxDate)
return true
//Method 2: B return true but A ***always*** return false, Why??
if (inputDate >= minDate)
A = true;
[code]....
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Jun 20, 2014
I have been trying to make a very simply programme that checks if the inputted information is an integer or not (i.e: that it contains no other characters).
I have tried using the isdigit function (but this only works for single characters). I have tried cin.clear, cin.ignore (1000) but this doesn't work either..
Any effective way to check if x in the following programme has been entered correctly
#include <iostream>
using namespace std;
int main() {
cout << "Please enter an integer (positive or negative)" << endl;
int x;
cin >> x;
HERE I WOULD LIKE CODE TO CHECK IF THE USERS INPUT IS VALID
}
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Dec 25, 2014
I'm trying to check to see if a string from standard input is alphanumeric or not. I feel as though there may be a function for this but...
Code:
for(test_pass = i; test_pass < i; i++){
if(test_pass[i] == ('1', '2', '3', '4', '5', '6', '7', '8', '9', '0'))
printf("Your password is alphanumeric!
");
}
The compiler wasn't too happy with this.
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Apr 24, 2013
I wonder how can I improve my validity check for user input? I only want them to key in certain range of digit.
Also for my validity check, when I key in character such as ABC, it lead to infinity loop
Here is my code : Code: /*Write a program that can calculate user's age by getting user input their birth date.*/
#include "stdafx.h"
#include <iostream>
#include <time.h>
using namespace std;
int main()
{
int yyyy, mm, dd; //year, month, day
int i = 0; //for the sake of validity check
[Code]...
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Apr 11, 2013
How would I check for proper data type when someone is to input a value into the program? Ex:
int i;
string a;
cout << "Enter a number: ";
cin >> i;
cout >> "Enter a string: ";
cin >> a;
How would you check to make sure that int i would be an actual number and not a letter like "a"?
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Feb 5, 2013
I'm trying to write a short program that takes the input from a user and trims any leading/trailing white space, and then checks how many words are in the string. Problem is, I'm only allowed to use stdio.h and stdlib.h. How can I accomplish this? Also, how would I check if any of the characters which were entered aren't either a number, letter, or '-'?
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Jun 9, 2014
How do I error check if the user is inputting letters and not numbers? For example, if the user inputs "Lab.txt" I need to display an error message. If they input "Lab2part2.txt" then this is correct and what I want.
I've found a lot of information online on how to error check for numbers or a single letter (EX: 1,2,3, etc. or 'A' 'B' 'C') but nothing for actual WORDS or maybe I should refer to it as a string of characters?
Is there any way to do this? Because my program requires I ask the user to input the name of the file. But the way my code is currently set up is even when the user inputs the wrong file name it still opens the file. I want to prevent this from happening so my thought was to error check user input.
/*Program to determine company's weekly payroll*/
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
void OpenTheFile() {
ifstream inputFile;
string filename;
char letter;
int number;
[Code] .....
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Jan 26, 2011
I'm currently working on a project that utilitzes a Caesar Cipher. Basically, it reads input from a file and then, depending upon the input file, requires encrypting or decrypting. The cipher used to encrypt/decrypt simply adds/subtracts an integer from each character in the input file. All input is lowercase alphabetic characters (ASCII 97-122). My problem is trying to figure out how to wrap the ciphered characters, e.g., if the cipher require a shift of +5 and the character read was 'x', a shift of +5 to the right would produce 'c' (beginning with 'x' and counting up 5 letters: 'y', 'z', 'a', 'b', 'c').
I've written some crude and cumbersome loops that will work, but there has to be a better way. It is my understanding that it can be done using the modulus operation, %, but I cannot figure out how. I spent several hours trying to figure out the modulus approach, but no luck.
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Dec 4, 2014
im working on our project and this part of the project which says to add a new a room.
Details:
Open the file (ROOMS) that maintains all the ROOMS records.
Ask the user to enter the required data Room_Type and Room_Rate, then save it.
Keep asking the user (Do you want to continue?) until the user enters (N OR n), this should stop the data entry and get the user back to the main menu.
Myproblem :: i keep getting error at the bottom says my while statement is wrong " IntelliSense: no operator "!=" matches these operands"
My other problem:: how do i get back to the main menu?
so what ive done till now is.
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main() {
int choice,i=1,Room_rate;
string alphabet;
string Room_type;
[code].....
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Mar 19, 2014
I'm trying to make an alphabet soup on C programming, and I'm stuck with a problem.I need to make a function able to automatically find all the words that exist in alphabet soup.
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May 5, 2014
I am creating a program where I count all the letters of the alphabet from a user submitted string.
How would I go about this?
I am completely new, so simplicity is best. I am suppose to use arrays.
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