In my WinForm, Our client insists to use Textbox instead of DateTimePicker field, and they want to input in ddmmyy format.
Using Visual Studio 2010 C# 4.0.
PC date time setting: GMT +08:00 dd-MMM-yy.
Assumed today date is 291014 (29-Oct-14).
CodeBehind:
DateTime inputDate;
// the WinForm allows user to input date not earlier than 2 years before today date and not more than 1 months from today date too.
//Assumed I input date as 261014 (26-Oct-14)
if(DateTime.TryParseExact(input, "ddMMyy", new System.Globalization.CultureInfo("en-US"), System.Globalization.DateTimeStyles.None, out inputDate)) {
DateTime minDate = DateTime.Now.AddMonths(-24);//Assumed it is 29-Nov-14
DateTime maxDate = DateTime.Now.AddMonths(1);//Assumed it is 29-Oct-12
I tried many methods but none works (I have checked many threads/forums also).
I'm supposed to make a program that can tell which date, out of any number of dates entered by the user, is the earliest date. However, this is based off another program that I did not do in the last chapter. Since it's a pretty simple program to use as the base for the more "generalized" one, I decided to make the more basic one that can only take two dates, first. If it was just one integer, I could just use date1 for the first date and date2 for the second date, but each date uses 6-8 separate numbers.
how do I tell it something like, "if(date1 < date2)", with date1 and date2 including their month, day, and year. I could do a separate integer name/tag (I forgot what they're called) for each number, but that sounds like doing a lot more adding and subtracting, and like it could easily get messy.Should I, or can I, add all the numbers under the "date" together to see which date has the "lowest number" or "earliest date", or should I somehow handle each number, that is month, day, and year, separately?Here's the code so far:
Code:
include <stdio.h>int main(void) { int date1, date2; printf("Enter first date (mm/dd/yy): "); scanf("%d/%d/%d", &date1); printf("Enter second date (mm/dd/yy): }
I am not getting all the records.... when i select the same date in both datetimepicker no record is displayed... i also want the record of the selected dates from both datetime picker..
How can I check for an invalid date when I run the program? I am trying to enter a conditional statement that checks for a valid or invalid date.
Programing Question: Write a program that inputs a date (e.g., July 4, 2008) and outputs the day of the week that corresponds to that date. Here is what I Have. The program runs. I need it to loop around.
#include <iostream> using namespace std; const int JANUARY = 1; const int FEBRUARY = 2; const int MARCH = 3; const int APRIL = 4;
So I have a programming assignment which is for getting a user input in the format of m/d/yyyy. This is stored as d/m/yyyy. I have been able to code all the rest of the requirements of the program but the thing that is giving me trouble is this. The year is allowed to go from 1-3000. The format of the displayed date is:
a zero-filled, two-digit day number, a dash, full name of month, a dash, zero-filled, four-digit year.
I am able to use a switch statement in order to get my name of the month. What I am struggling to figure out is the whole zero filled two digit day and zero filled four digit year. From the way the input is store it appears to me that it will be stored as yyyy which means if you were to enter 0001 for year 1 then it should output it as that (this is an assumption based on format). What I don't get is that the day is entered and stored as d which means if you put in 12 how would it be stored. However if you put in 6 to print the output I would need to add a zero and I dont know how to do that either.
Here is the code for getting the input. The function must stay formated this way as per the instructor. The / is stored but ignored hence the char for second and fourth since / is a char
Code: void getDate (int& day, int& month, int& year){ char second; char fourth; cout << "Please enter a date in the format of m/d/yyyy" << endl; cin >> month >> second >> day >>fourth >> year; }
I am building a template for CodeBlocks, which pre-write some includes, the main skull and a header.
This header looks like that : /** * @Author Me * @Description Brief description * @Date ?? */
I would like to put the current Date, just after the line @Date, is-it possible ? And if yes, it-is possible to put a field @FileName which copy the filename into the comment ?
I'm just starting coding and I just want it to input a date, then output a day of the week.
Code: #include <iostream> #include <cmath> using namespace std; int main() { int startday = 0, sm = 1, sd = 1, sy = 2000, cm = 0, cd = 0, cy = 0; cout << "Please enter the current month, day, and year: ";
I am writing a C++ program which takes date & time input from the user. This is then parsed into a struct such as:
struct time { short year; short month; short day; short hour; short min; };
My question is: how can I convert such a struct into a time_t object, which is an unsigned long giving the time as the number of seconds elapsed since the epoch Jan 1st 1970, 00:00, as set out in time.h.
I am wondering if this can be achieved using the standard library, or whether I just need to write a function to perform the appropriate arithmetic.
I'm trying to write a program that uses the Boost library to input a string date in the format mm/dd/year and outputs to the string its corresponding day of the week. I wrote the program that I thought would accomplish this, but it doesn't seem to work. Below is the code I wrote:
When I compile this using codeblocks it gives me the error "In function `ZN5boost9date_time19month_str_to_ushortINS_9gregorian10greg_monthEEEtRKSs':| C:Users osaDesktop est3........Liboost_1_55_0oostdate_timedate_parsing.hpp|67|undefined reference to `boost::gregorian::greg_month::get_month_map_ptr()'". And it takes me to the file date_parsing.hpp and highlights line 67. I don't understand why this isn't working.
I have an assignment in which i must create a program which prompts for user input of current and birth date, which will compare said dates and output if its your birthday or not. I've completed a large portion of it, but cannot figure out how to get the user input of month as an integer such a 2 into February.
#include <iostream> using namespace std; class DayOfYear { public: void input();
I wanted to check whether the input is a character or not, if a character is given then the output suppose to be "ok", but the output is always "oppppssss", where is the problem here?
I have an assignment to do..i have done it..but i need to do one more thing. Things sound like this: user inputs 6 integers program needs to check them if there are integer if not it has to output a message for the user if the input is integer it has to go further and work with the input. I have used this structure :
if ( ! ( cin >> temp ) ) { cout<<"Input is not integer.This program will end ! "<<endl<<endl<<endl; system("pause"); return 0; }
Where I declared temp as being int since i started, the problem is after it gets the last input still waits for an input i will attach the source code if needed.
i'm making a program that, given a person's birthdate or any other date, will display the day of the week of the person was born.
There is this part where it says "use a switch statement to make this calculation, If desired month is 12, add the number of days for November, if desired month is 11 add the number of days for october....
So it's suppose to start with "case 12 :...
I can't figure out what to write for the statement....
I have a homework that needs to verify if the input of the user is an integer using only loops no if statements Here's the problem:
A program is required that prompts the user for a number. The program will then print a series of asterisks to represent the number. If the user enters a number less than 1, the program stops. For example:
Enter a number: 5 ***** Enter a number: 3 *** Enter a number: 9 ********* Enter a number: 0
All user input must be validated: - Check for non-numeric input when reading numeric input - Check that values entered are within the expected range for their purpose, or in range based on the requirements statement
i'm making a for loop for a mini game which required the user to enter the input number.Let say if the user accidently entered a character instead of integer the whole program will go haywire so is there anyway to check for the error and prompt the user to input the data again?Here is the simple program...
This program works but i need to build an additional loop that will re-prompt a user if his initial entry (int y_n) is other than 'Y', 'y', 'N', 'n'. For instance if a user tries to enter 'Yup', he will be prompted "That isn't a valid entry" and then re-asked to enter int y_n.
Note: If user answers Y he is asked to enter a value that is entered into an array. If the user at any point answers N, the program ends and final stats are cout.
#include <iostream> using namespace std; int main(){ char y_n; int i = 0; float input_value; float myarray[100];
I have been trying to make a very simply programme that checks if the inputted information is an integer or not (i.e: that it contains no other characters).
I have tried using the isdigit function (but this only works for single characters). I have tried cin.clear, cin.ignore (1000) but this doesn't work either..
Any effective way to check if x in the following programme has been entered correctly
#include <iostream> using namespace std; int main() { cout << "Please enter an integer (positive or negative)" << endl; int x; cin >> x; HERE I WOULD LIKE CODE TO CHECK IF THE USERS INPUT IS VALID }
I wonder how can I improve my validity check for user input? I only want them to key in certain range of digit.
Also for my validity check, when I key in character such as ABC, it lead to infinity loop
Here is my code : Code: /*Write a program that can calculate user's age by getting user input their birth date.*/
#include "stdafx.h" #include <iostream> #include <time.h> using namespace std; int main() { int yyyy, mm, dd; //year, month, day int i = 0; //for the sake of validity check
