I'm trying to check to see if a string from standard input is alphanumeric or not. I feel as though there may be a function for this but...
Code:
for(test_pass = i; test_pass < i; i++){
if(test_pass[i] == ('1', '2', '3', '4', '5', '6', '7', '8', '9', '0'))
printf("Your password is alphanumeric!
");
}
The compiler wasn't too happy with this.
my program only checks the first character of the string.. D:
View 8 Replies View RelatedI made this function to check in string is alpha only or alphanumeric but always give me alfa way ?
Code:
int checkIfStringisAlfa(const char str[]){
int lenStr = getStringLength(str);
int i = 0;
int ret;
for(i = 0; i < lenStr; i++){
if(str[i] >= 'a' && str[i] <= 'z' || str[i] >= 'A' && str[i] <= 'Z'){
//printf(" alfa
[Code] .....
I'm trying to write a short program that takes the input from a user and trims any leading/trailing white space, and then checks how many words are in the string. Problem is, I'm only allowed to use stdio.h and stdlib.h. How can I accomplish this? Also, how would I check if any of the characters which were entered aren't either a number, letter, or '-'?
View 3 Replies View RelatedHere's my code, it's for a poker hand evaluator
input:
'ad 2d 3d 4d 5d...
...4s 5s 6s 7s 8s'
I think it should go through all the 10 crads and disply the name of each card, but it seems to only do it for the second hand
Code:
include <stdio.h>
#include <ctype.h>
int main( void ) {
char inputtedhand[64];
int z=0, counter=0;
int index;
int i=0,m=0,n=0;
[Code].....
so i'm using scanf() this way
Code:
int i;
while (scanf("%i", &i))
printf("%i ", i);
printf("
done
");
i tried several combination of Ctrl+D and "Enter", it's not terminating, Ctrl+C just "cancels" the whole thing without printing "done", i'm running this on linux installed on a PC
So I'm working on an assignment that is roughly about implementing the grep utility, only it has to be programmed in C. The weird nuance of the assignment is that while we are implementing the utility, we can use grep only we cannot pass grep a filename to search through(we are supposed to pipe a line from the file to standard input so that grep can examine it there.) Anyways, when I reach execlp, it will print out what is in stdin from the terminal, but it hangs at that point and I have to press Ctrl+Z to exit. I probably have the most difficulty with using this function, so I came up with a smaller scale model to get the basics down. Anyways, here's my code:
#include <unistd.h>
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
int main(int argc, char* argv[]){
[Code] ....
I have an HTTP/1.0 webserver that I'm building in C that needs to exhibit CGI script functionality. Specifically, what I'm having trouble with is that I have two processes: process 1 is the webserver, process 2 is the CGI script. I fork in the webserver, and then call exec to run the CGI script (specifically, I used execv()). I've read from the CGI specifications in the RFC that in the case of a webserver receiving a POST request, the CGI script should read the arguments for the POST request from stdin. However, when I write to stdin, it simply echoes what was written to the terminal window and when the CGI script tries to read from stdin, it blocks.
So, with all that said, I'm pretty sure there is some simple conceptual explanation to my problem, but I can't figure it out. Do I need to use pipes or some form of interprocess communication to send the data from the webserver to the CGI script, or can it just be done with stdin (and possible stdout)?
So running the following code
Code:
#include <stdio.h>
int main(void) {
char c;
int i=1;
while (scanf("%c", &c)==1)
printf("loop sequence %i: %c(%i)
[Code] ......
Done it seems a "carriage return" serves two purposes here, one is to signal the program to read in the character typed in before the "carriage return", another serves as a second character typed, how can i do this cleanly, that is without having to use a "carriage return" as the second character to signal "I've typed in the first character already".
I've been experimenting a bit and can't find a decent way to make a brute forcing script that accepts a password from standard input, and goes through all possible combinations until it is matched. How to structure the code?
View 1 Replies View RelatedWrite code to do the following:
1) declare a variable ptr as a pointer to int and initialize it to NULL
2) dynamically allocate memory for an array of 100 elements
3) read 100 elements from the standard input device and store them in the array.
This is what I have so far, I'd like to know if its ok or if something is wrong.
int *ptr = NULL;
ptr = new int[100];
cin >> dataPtr [arr];
A Bookseller makes special discount for multiple orders of a book as follows:
AMOUNT and DISCOUNT as follows.
5-9 5% 10-14 10% 15-19 15% 20+ 20%
Write a C main function to read the amount of order from the standard input and compute and print the total price of the given order after the discount. Assume that unit price of a book is 10.00$
My problem is that.When i start with this
Code:
#include<stdio.h>
#include <stdlib.h>
int main(void)
{
int number;
float TotalPrice;
printf("enter a number:");
[Code] ....
I get 0 if i enter a number between 0 and 4(0 and 4 included). I don't know where I am doing a mistake. I also want to know if i can handle this buy just if statements. or how can i do it by while and for loops ?
Code:
char value;
printf_s("enter:");
if (scanf_s("%c", &value) != 1)
{
printf_s("oppppssss
");
}
else
{
printf_s("ok");
}
I wanted to check whether the input is a character or not, if a character is given then the output suppose to be "ok", but the output is always "oppppssss", where is the problem here?
Description: This program asks the user to enter a Fahrenheit temperature and then converts it into Celsius and Kelvin temperature.
Code :
#include <stdio.h>
void Temperatures(double temp_F);
int main(void) {
double temp;
[Code]...
I have an assignment to do..i have done it..but i need to do one more thing. Things sound like this: user inputs 6 integers program needs to check them if there are integer if not it has to output a message for the user if the input is integer it has to go further and work with the input. I have used this structure :
if ( ! ( cin >> temp ) ) {
cout<<"Input is not integer.This program will end ! "<<endl<<endl<<endl;
system("pause");
return 0;
}
Where I declared temp as being int since i started, the problem is after it gets the last input still waits for an input i will attach the source code if needed.
I have a homework that needs to verify if the input of the user is an integer using only loops no if statements Here's the problem:
A program is required that prompts the user for a number. The program will then print a series of asterisks to represent the number. If the user enters a number less than 1, the program stops. For example:
Enter a number: 5
*****
Enter a number: 3
***
Enter a number: 9
*********
Enter a number: 0
All user input must be validated:
- Check for non-numeric input when reading numeric input
- Check that values entered are within the expected range for their purpose, or in range based on the requirements statement
i'm making a for loop for a mini game which required the user to enter the input number.Let say if the user accidently entered a character instead of integer the whole program will go haywire so is there anyway to check for the error and prompt the user to input the data again?Here is the simple program...
for(row=0;row<4;row++)
{
printf("Enter Row%d:",row);
for(col=0;col<4;col++)
{
scanf("%d",&num[row][col]);
}
I need a function to check if the inputted string contains a colon. It has to be in an if loop as the condition.
View 1 Replies View RelatedThis program works but i need to build an additional loop that will re-prompt a user if his initial entry (int y_n) is other than 'Y', 'y', 'N', 'n'. For instance if a user tries to enter 'Yup', he will be prompted "That isn't a valid entry" and then re-asked to enter int y_n.
Note: If user answers Y he is asked to enter a value that is entered into an array. If the user at any point answers N, the program ends and final stats are cout.
#include <iostream>
using namespace std;
int main(){
char y_n;
int i = 0;
float input_value;
float myarray[100];
[Code] .....
If I have a char array that that looks like
char array[] = {'a', 'b', 'c'};
How can I check user input against all of these values at once?
In my WinForm, Our client insists to use Textbox instead of DateTimePicker field, and they want to input in ddmmyy format.
Using Visual Studio 2010 C# 4.0.
PC date time setting: GMT +08:00 dd-MMM-yy.
Assumed today date is 291014 (29-Oct-14).
CodeBehind:
DateTime inputDate;
// the WinForm allows user to input date not earlier than 2 years before today date and not more than 1 months from today date too.
//Assumed I input date as 261014 (26-Oct-14)
if(DateTime.TryParseExact(input, "ddMMyy", new System.Globalization.CultureInfo("en-US"), System.Globalization.DateTimeStyles.None, out inputDate)) {
DateTime minDate = DateTime.Now.AddMonths(-24);//Assumed it is 29-Nov-14
DateTime maxDate = DateTime.Now.AddMonths(1);//Assumed it is 29-Oct-12
I tried many methods but none works (I have checked many threads/forums also).
//Method 1
if(inputDate >= minDate && inputDate <= maxDate)
return true
//Method 2: B return true but A ***always*** return false, Why??
if (inputDate >= minDate)
A = true;
[code]....
I have been trying to make a very simply programme that checks if the inputted information is an integer or not (i.e: that it contains no other characters).
I have tried using the isdigit function (but this only works for single characters). I have tried cin.clear, cin.ignore (1000) but this doesn't work either..
Any effective way to check if x in the following programme has been entered correctly
#include <iostream>
using namespace std;
int main() {
cout << "Please enter an integer (positive or negative)" << endl;
int x;
cin >> x;
HERE I WOULD LIKE CODE TO CHECK IF THE USERS INPUT IS VALID
}
The output should also give a file which doesnt consits alphanumeric. I tried this
while( ( ch = fgetc(fp) ) != EOF ){
if(isalpha(ch)||ch==' ')
Is this correct.than how to complete it.
I wonder how can I improve my validity check for user input? I only want them to key in certain range of digit.
Also for my validity check, when I key in character such as ABC, it lead to infinity loop
Here is my code : Code: /*Write a program that can calculate user's age by getting user input their birth date.*/
#include "stdafx.h"
#include <iostream>
#include <time.h>
using namespace std;
int main()
{
int yyyy, mm, dd; //year, month, day
int i = 0; //for the sake of validity check
[Code]...
How would I check for proper data type when someone is to input a value into the program? Ex:
int i;
string a;
cout << "Enter a number: ";
cin >> i;
cout >> "Enter a string: ";
cin >> a;
How would you check to make sure that int i would be an actual number and not a letter like "a"?
This code is supposed to ask the user to input characters at most 20 and they should only be composed of alphabets/spaces..
Code:
#include <string.h>
#include <stdio.h>
#include <ctype.h>
int main(){
char addressbook[6][30][0];
int current_record = 0, length, i=0;
[Code] ....
I have removed the error from the main code but there's still this lingering error in the return part.
syntax error before 'return'.
It won't compile.