Description: This program asks the user to enter a Fahrenheit temperature and then converts it into Celsius and Kelvin temperature.
Code :
#include <stdio.h>
void Temperatures(double temp_F);
int main(void) {
double temp;
[Code]...
Code:
char value;
printf_s("enter:");
if (scanf_s("%c", &value) != 1)
{
printf_s("oppppssss
");
}
else
{
printf_s("ok");
}
I wanted to check whether the input is a character or not, if a character is given then the output suppose to be "ok", but the output is always "oppppssss", where is the problem here?
I have an assignment to do..i have done it..but i need to do one more thing. Things sound like this: user inputs 6 integers program needs to check them if there are integer if not it has to output a message for the user if the input is integer it has to go further and work with the input. I have used this structure :
if ( ! ( cin >> temp ) ) {
cout<<"Input is not integer.This program will end ! "<<endl<<endl<<endl;
system("pause");
return 0;
}
Where I declared temp as being int since i started, the problem is after it gets the last input still waits for an input i will attach the source code if needed.
I have a homework that needs to verify if the input of the user is an integer using only loops no if statements Here's the problem:
A program is required that prompts the user for a number. The program will then print a series of asterisks to represent the number. If the user enters a number less than 1, the program stops. For example:
Enter a number: 5
*****
Enter a number: 3
***
Enter a number: 9
*********
Enter a number: 0
All user input must be validated:
- Check for non-numeric input when reading numeric input
- Check that values entered are within the expected range for their purpose, or in range based on the requirements statement
i'm making a for loop for a mini game which required the user to enter the input number.Let say if the user accidently entered a character instead of integer the whole program will go haywire so is there anyway to check for the error and prompt the user to input the data again?Here is the simple program...
for(row=0;row<4;row++)
{
printf("Enter Row%d:",row);
for(col=0;col<4;col++)
{
scanf("%d",&num[row][col]);
}
I need a function to check if the inputted string contains a colon. It has to be in an if loop as the condition.
View 1 Replies View RelatedThis program works but i need to build an additional loop that will re-prompt a user if his initial entry (int y_n) is other than 'Y', 'y', 'N', 'n'. For instance if a user tries to enter 'Yup', he will be prompted "That isn't a valid entry" and then re-asked to enter int y_n.
Note: If user answers Y he is asked to enter a value that is entered into an array. If the user at any point answers N, the program ends and final stats are cout.
#include <iostream>
using namespace std;
int main(){
char y_n;
int i = 0;
float input_value;
float myarray[100];
[Code] .....
If I have a char array that that looks like
char array[] = {'a', 'b', 'c'};
How can I check user input against all of these values at once?
In my WinForm, Our client insists to use Textbox instead of DateTimePicker field, and they want to input in ddmmyy format.
Using Visual Studio 2010 C# 4.0.
PC date time setting: GMT +08:00 dd-MMM-yy.
Assumed today date is 291014 (29-Oct-14).
CodeBehind:
DateTime inputDate;
// the WinForm allows user to input date not earlier than 2 years before today date and not more than 1 months from today date too.
//Assumed I input date as 261014 (26-Oct-14)
if(DateTime.TryParseExact(input, "ddMMyy", new System.Globalization.CultureInfo("en-US"), System.Globalization.DateTimeStyles.None, out inputDate)) {
DateTime minDate = DateTime.Now.AddMonths(-24);//Assumed it is 29-Nov-14
DateTime maxDate = DateTime.Now.AddMonths(1);//Assumed it is 29-Oct-12
I tried many methods but none works (I have checked many threads/forums also).
//Method 1
if(inputDate >= minDate && inputDate <= maxDate)
return true
//Method 2: B return true but A ***always*** return false, Why??
if (inputDate >= minDate)
A = true;
[code]....
I have been trying to make a very simply programme that checks if the inputted information is an integer or not (i.e: that it contains no other characters).
I have tried using the isdigit function (but this only works for single characters). I have tried cin.clear, cin.ignore (1000) but this doesn't work either..
Any effective way to check if x in the following programme has been entered correctly
#include <iostream>
using namespace std;
int main() {
cout << "Please enter an integer (positive or negative)" << endl;
int x;
cin >> x;
HERE I WOULD LIKE CODE TO CHECK IF THE USERS INPUT IS VALID
}
I'm trying to check to see if a string from standard input is alphanumeric or not. I feel as though there may be a function for this but...
Code:
for(test_pass = i; test_pass < i; i++){
if(test_pass[i] == ('1', '2', '3', '4', '5', '6', '7', '8', '9', '0'))
printf("Your password is alphanumeric!
");
}
The compiler wasn't too happy with this.
I wonder how can I improve my validity check for user input? I only want them to key in certain range of digit.
Also for my validity check, when I key in character such as ABC, it lead to infinity loop
Here is my code : Code: /*Write a program that can calculate user's age by getting user input their birth date.*/
#include "stdafx.h"
#include <iostream>
#include <time.h>
using namespace std;
int main()
{
int yyyy, mm, dd; //year, month, day
int i = 0; //for the sake of validity check
[Code]...
How would I check for proper data type when someone is to input a value into the program? Ex:
int i;
string a;
cout << "Enter a number: ";
cin >> i;
cout >> "Enter a string: ";
cin >> a;
How would you check to make sure that int i would be an actual number and not a letter like "a"?
This code is supposed to ask the user to input characters at most 20 and they should only be composed of alphabets/spaces..
Code:
#include <string.h>
#include <stdio.h>
#include <ctype.h>
int main(){
char addressbook[6][30][0];
int current_record = 0, length, i=0;
[Code] ....
I have removed the error from the main code but there's still this lingering error in the return part.
syntax error before 'return'.
It won't compile.
I'm trying to write a short program that takes the input from a user and trims any leading/trailing white space, and then checks how many words are in the string. Problem is, I'm only allowed to use stdio.h and stdlib.h. How can I accomplish this? Also, how would I check if any of the characters which were entered aren't either a number, letter, or '-'?
View 3 Replies View RelatedHow do I error check if the user is inputting letters and not numbers? For example, if the user inputs "Lab.txt" I need to display an error message. If they input "Lab2part2.txt" then this is correct and what I want.
I've found a lot of information online on how to error check for numbers or a single letter (EX: 1,2,3, etc. or 'A' 'B' 'C') but nothing for actual WORDS or maybe I should refer to it as a string of characters?
Is there any way to do this? Because my program requires I ask the user to input the name of the file. But the way my code is currently set up is even when the user inputs the wrong file name it still opens the file. I want to prevent this from happening so my thought was to error check user input.
/*Program to determine company's weekly payroll*/
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
void OpenTheFile() {
ifstream inputFile;
string filename;
char letter;
int number;
[Code] .....
working on this code I have encountered a few issues. My program lists the occurrence of each letter but i'm unsure of how to enable numeric variables. how to improve the overall quality of the code.
Code:
#include <stdio.h>
#include <string.h>
int main()
{
char string[100], ch;
int c = 0, count[26] = {0};
printf("Enter a string
[Code]...
when I was looking for a way how to convert char into numeric value for std::cout I found some old discussion with this statement: Operations on unsigned int are typically faster than on unsigned char, because your processor cannot fetch single bytes but has to get at least a multiple of 4 and mask out the other 3 bytes. Is this true? By using smaller (in bytes) variable I actually slow down my program? I always thought that it is a good practice if I use the smallest variable which will do the work. Is it also dependent on a compiler and OS?
View 2 Replies View RelatedI want to avoid converting the char[] into a string as an intermediate step, since I'm trying to write some "string" parser helpers which don't allocate a bunch of different strings onto the heap. (whole point of this little project is to reduce GC pressure in applications that do alot of string parsing).
basically if I have a char[] that contains {'1','2','3'}, I'd want to to be converted into 123.
I tried messing around with the stackalloc operator in C#, but its illegal to stackalloc a string unfortunately. I also googled around for converting a char[] into a numeric value, but all the solutions convert each individual char into their ASCII code, or convert the char[] into a string as an intermediate step.
I want to create an object that uses visual C#'s Numeric Up/Down and a Track bar.
The reason is that I have a GUI that uses lots of these linked together with events and I want a common event handler for all of them.
Maybe just adding a property that is a Numeric Up/Down in the Track bar and vice-versa will allow me to create a common event for all of these pairs.
How to convert int into string ? I had done conversion string to int.
My code :
/*Convert string into int using stringstream */
#include <iostream>
#include <string>
#include "console.h"
#include <sstream>
using namespace std;
[Code] .....
I'm trying to perform a simple input operation, and check to make sure that whatever the user input is a valid input (is within data type bounds, is correct data type...). But when I get to ignoring the input, I keep getting an error.
unsigned short num;
while (true) {
std::cin >> num;
if (std::cin.fail()) {
num = 1;
[Code] ....
I don't fully understand why this error is here.
The code runs but asks me for my score twice then just comes to an abrupt end with out giving me a letter grade.
#include <stdio.h>
int getScore(void);
char convertGrade(int numscore, char letterGrade);
void showGrade(int numscore, char letterGrade);
// Function to prompt for and read a numeric score
// Returns an integer score as read in using scanf
[Code] ....
I want to multiply and divide 2 string that contains number. For example
s1=4 and s2=8 s1*s2=32 ,s2/s1=2
I don't want convert string to integer and do it.because i deal with big numbers.and these should be in string form.
I have a button which selects a particular tab and tab page on a form. This tab page has an embedded tab control with several more pages.
When I click on this button, the desired tab page is selected, but the NumericUpDown value (which is on the tab page) is not visible. The value is the current year.
Could it be that somehow, the click event for the button is hiding the value?
this is my code in c++ and its very simpile but wont compile
#include <iostream>
using namespace std;
int main() {
cout << "Here is some text
";
cout << "Here is a number: ";
[Code] ...