I want to multiply and divide 2 string that contains number. For example
s1=4 and s2=8 s1*s2=32 ,s2/s1=2
I don't want convert string to integer and do it.because i deal with big numbers.and these should be in string form.
I am new to C programming and I am just wondering how to multiply / divide two different variables which the user type in as the promt is asking like this:
Code:
void inmatning3 (double *a, double *b) {
printf("Mata in tv217 stycken flyttal: "); /* asks you to type in 2 numbers */
scanf("%lf %lf", a, b);
}
When you've enterd the two numbers I need to eather multiply or divide the two variables "a" & "b" .....
Create a program that adds, subtracts, multiplies, or divides two integers. The program will need to get a letter (A for addition, S for subtractions, M for multiplication, or D for division) and two integers from the user. If the user enters an invalid letter, the program should display an appropriate error message before the program ends. If the letter is A (or a), the program should calculate and display the sum of both integers. If the letter is S (or s), the program should display the difference between both integers. When calculating the difference, always subtract the smaller number from the larger one. If the letter is M (or m), the program should display the product of both integers. If the letter is D (or d), the program should divide both integers, always dividing the larger number by the smaller one."
And here is the test data. I am posting the results from my desk-check table.
operation first integer second integer answer
A 10 20 30
a 45 15 60
S 65 50 15
s 7 13 6
G -1
M 10 20 200
d 45 15 3
d 50 100 2
Then, I transferred my program into a source file. Here it is:
//Exercise16.cpp - display answer of two integers
#include <iostream>
using namespace std;
int main() {
//declare variables
int firstInteger = 0;
[Code] ....
After putting in the data, everything worked fine, except the last two operations, which are M (multiplication) and D (division). All the answers for the last two operations essentially give me a 0.
How to convert int into string ? I had done conversion string to int.
My code :
/*Convert string into int using stringstream */
#include <iostream>
#include <string>
#include "console.h"
#include <sstream>
using namespace std;
[Code] .....
Code:
#include <stdio.h> Code: #include <string.h>
int main() {
int i;
[Code]....
need to make triplet for the output
Whats wrong with my program ? It always says that coundn't find match operator ? What can i do ? I want to multiply string pay to int HOURS.
#include<iostream>
#include<fstream>
#include<string>
using namespace std;
int main () {
system("color 8e");
string ID,name, address,No, pos ,pay, hanap;
string hours;
[Code] .....
working on this code I have encountered a few issues. My program lists the occurrence of each letter but i'm unsure of how to enable numeric variables. how to improve the overall quality of the code.
Code:
#include <stdio.h>
#include <string.h>
int main()
{
char string[100], ch;
int c = 0, count[26] = {0};
printf("Enter a string
[Code]...
Description: This program asks the user to enter a Fahrenheit temperature and then converts it into Celsius and Kelvin temperature.
Code :
#include <stdio.h>
void Temperatures(double temp_F);
int main(void) {
double temp;
[Code]...
when I was looking for a way how to convert char into numeric value for std::cout I found some old discussion with this statement: Operations on unsigned int are typically faster than on unsigned char, because your processor cannot fetch single bytes but has to get at least a multiple of 4 and mask out the other 3 bytes. Is this true? By using smaller (in bytes) variable I actually slow down my program? I always thought that it is a good practice if I use the smallest variable which will do the work. Is it also dependent on a compiler and OS?
View 2 Replies View RelatedI want to avoid converting the char[] into a string as an intermediate step, since I'm trying to write some "string" parser helpers which don't allocate a bunch of different strings onto the heap. (whole point of this little project is to reduce GC pressure in applications that do alot of string parsing).
basically if I have a char[] that contains {'1','2','3'}, I'd want to to be converted into 123.
I tried messing around with the stackalloc operator in C#, but its illegal to stackalloc a string unfortunately. I also googled around for converting a char[] into a numeric value, but all the solutions convert each individual char into their ASCII code, or convert the char[] into a string as an intermediate step.
i was suppose to write a program that gives a divide error but output is not showing anything like it.I am using orwell devc++ 5.4.2 and all the default built tools(gcc compiler etc.) with default settings.so, what should i do to see this error?
Code:
#include<stdio.h>
#include<conio.h>
int main()
{
int a,b,c;
float x;
}
[code]....
I am trying to multiply one array by another, for example:
enter 5 letters
enter 5 numbers,2 3 4 2
output= qq, www, tttt, ee
but im stuck with the last calculation.
Code:
#include <stdio.h>
#include <stdlib.h>
int main() {
char array1 [5];
int i, j;
int array2[5];
[code]....
I need to write a program that accepts a number from the user, divides that number by two until it reaches one or cannot be divided evenly anymore, then adds all of the quotients from each division and displays them.
So something like this should be displayed:
Please enter a number: 8
8/2=4
4/2=2
2/2=1
4+2+1= 7
I thought about using an array to possibly store the quotients but I just can't see how that would work.
Whats the symbol for divide In C++
View 10 Replies View RelatedUsing the old fashioned (unsigned) multiplication instruction in x64 assembly multiplies RAX (64 bit register) by a 64 bit register. The answer is stored in RDX:RAX (i.e. the answer is 128 bits). Is there any way, using native c++ to get the value in RDX (higher 64 bits)? One I can think of is: right/(limit/left) e.g. if we are limited to a byte then 97*123 would overflow:
97/(255/123) = 46 times, which is RDX's (if it was one byte) value. But this is too inefficient. Is there a fast way?
I haven't found anything that small for Matrix multiplication i was just going to ask about how i would multiply to matrices together in c++ as easy as possible, so for example say a i have the following
[2 0 1 0 * [3 0
6 -1 0 2] 0 3
1 2
3 1]
How would i multiply these together. Here is the example
Attached image(s)
I want to create an object that uses visual C#'s Numeric Up/Down and a Track bar.
The reason is that I have a GUI that uses lots of these linked together with events and I want a common event handler for all of them.
Maybe just adding a property that is a Numeric Up/Down in the Track bar and vice-versa will allow me to create a common event for all of these pairs.
I'm trying to perform a simple input operation, and check to make sure that whatever the user input is a valid input (is within data type bounds, is correct data type...). But when I get to ignoring the input, I keep getting an error.
unsigned short num;
while (true) {
std::cin >> num;
if (std::cin.fail()) {
num = 1;
[Code] ....
I don't fully understand why this error is here.
The code runs but asks me for my score twice then just comes to an abrupt end with out giving me a letter grade.
#include <stdio.h>
int getScore(void);
char convertGrade(int numscore, char letterGrade);
void showGrade(int numscore, char letterGrade);
// Function to prompt for and read a numeric score
// Returns an integer score as read in using scanf
[Code] ....
I have a button which selects a particular tab and tab page on a form. This tab page has an embedded tab control with several more pages.
When I click on this button, the desired tab page is selected, but the NumericUpDown value (which is on the tab page) is not visible. The value is the current year.
Could it be that somehow, the click event for the button is hiding the value?
this is my code in c++ and its very simpile but wont compile
#include <iostream>
using namespace std;
int main() {
cout << "Here is some text
";
cout << "Here is a number: ";
[Code] ...
Code where the user wants to divide a number until it reaches to zero?
View 5 Replies View RelatedI need to make a program that takes in a user’s number and keep dividing it by 2 until it is 1.I need to display the division steps ...
I do not know how to keep making it divide by 2 until 1. I tired this but it obviously did not work..
Code:
#include <iostream>
using namespace std;
int main() {
//User Input
int input,total;
cout <<"Enter A Number To Be Divided By 2 Until 1" << endl << endl;
[Code] ....
If we have array like
int numbers [] = {3,4,8,9,6,3,2,58,6,3,2,5};
how can we fast do smth like 3*4*8*9*6*3*2*58*6*3*2*5
also numbers[0]*numbers[1]*numbers[2] etc
all must be in one loop....
By using operator overloads i need to be able to * two dynamic arrays;
this is what i have so far
MyInt operator* (const MyInt& x, const MyInt& y) {
MyInt Temp;
int carry = 0;
if(x.currentSize > y.currentSize){
for( int i =0; i < y.currentSize; i++)
for(int j = 0; j < x.currentSize; j++)
[Code] ....
I've been stuck on a divide a conquer algorithm problem for about an hour now, and I'm not sure how to solve it. I need to use divide-and-conquer to implement an algorithm that finds the dominant element of an array of positive integers and returns -1 if the array does not have a dominant element (a dominant element is one that occurs in more than half the elements of a given array).
No sorting may be used, and the only comparison that may be used is a test for equality.
I understand the general process I need to follow to solve this problem, but I'm not sure exactly how to convert my thoughts to code. I know that if a number x is the dominant element of an array A, the x must be the dominant element in either the first half of A, the second half of A, or both.
Here is what I have so far.
#include <iostream>
#include <string>
#include <vector>
using namespace std;
int find_dominant(int *A, int p, int r) {
[Code] ....
The program must run in O(n log n) time.