C/C++ :: Multiply 2 Variables That Go From 0 To 7 - Logical Operators?
Apr 9, 2015
#include <iostream>
using namespace std;
int main(){
int polje[8][8];{
for(int i=0;i<8;i++)
for(int j=0;j<8;j++) {
[Code] .....
I don't get any errors,the program works. The problem is that it doesnt work how it should. This is a simple program that multiplies 2 variables(i and j)that go from 0 to 7. The problem I have is with the logical operators,i want the program to skip multiplication with 0 and when the 2 variables are the same value. When i try using only 1 logical operator it work.
I am new to C programming and I am just wondering how to multiply / divide two different variables which the user type in as the promt is asking like this:
Code: void inmatning3 (double *a, double *b) { printf("Mata in tv217 stycken flyttal: "); /* asks you to type in 2 numbers */ scanf("%lf %lf", a, b); }
When you've enterd the two numbers I need to eather multiply or divide the two variables "a" & "b" .....
There are, or course, better ways to do this, but I need to stick to some rules:
(1) Use only pointer variables and not arrays or structs. (2) Use the three functions shown--regardless of easier methods.
The program should ask for some input, operate on those numbers, and then display the results. I know I am confused over these things:
(1) All that syntax using '*' and '&' or neither. (2) How to use the char type correctly. (3) How to use a char type input as an operator (a + b). (4) How to use the pointer of the operator variable (+,-,*,/) in an actual equation.
Code: If str[i] is not equal to NULL character nor ' '; then, keep printing the chars within the word to variable result.
To understand what the function does, here's the whole code:
static char result[999]; /* char *split_word(const char *str, long n); * Splits a string word-by-word. Where N is the word number. */ char *split_word(const char *str, long n) {
[Code]....
I'm trying to accomplish an easier way round to split string by word than using "strtok_r()". It might sound like "re-inventing the wheel", but... i will try to make it neat later.
Let's say I have a product that needs service after 500 hours at 100 RPM. I can dsiplay the remaining hours only as an integer and we only have integer math. Management wants it to display 500 for the first hour, not 499 after the first minute is ticked off. But after a few minutes fullHours will be 499 and partialHours will have some value. I have 3 ways to determine displayHours to suit management and I want to know if the first is ligit.
short fullHours = 500; short partialHours = 0; short displayedHours = 0;
// Method 1 - Is is Kosher to cast a boolean as an int? Is TRUE always a 1 or is that a bad assumption?
I wrote this code to solve a problem in which the user inputs a permutation of size 'N' and the next permutation of the same elements has to be generated.
I went about this in this way: given 3 2 5 4 1, starting from the right, the first no. has to be searched which has a no. greater to it on its right. Here it is 2. Now an array is generated containing all no.s on its right and greater than it. For 2, it is: 5,4. Out of these the smallest member is searched for and switched with 2. So, 4 is switched with 2 to get the Next Permutation: 3 4 5 2 1.
The code I wrote does not show any error but does not return the correct value when run and gives the same value instead. If I enter '3 2 5 4 1' it returns the same value as the answer.
#include<iostream.h> #include<conio.h> void main() { clrscr(); int N,M,i,n,c,swap,flag,count,small,m; int Array[100],Key[100];
when I input the character which is the underscore, and the row # it should display the table and sort that specific row. Why is the if statement skipped? This is not the complete program but has everything needed.
My project is on an online shop in which you can manage a shop(adding ,deleting ,clearing and modifying items) also you can switch to different shops(all shops are same)
The logical problem is serious because i am not able to find the error!!! There is some problem with display lines in void shop()-->if(mode=='s') and if(mode=='d'). I add only one item but in output screen i see two items(sometimes >2) *note* to run the above display lines in the output screen....first register--->add atleast one item--->see your shop
I have to write a program that does the following: Monkey Business A local zoo wants to keep track of how many pounds of food each of its three monkeys eats each day during a typical week. Write a program that stores this information in a two-dimensional 3 - 7 array , where each row represents a different monkey and each column represents a different day of the week. The monkeys are represented by integers 1, 2, and 3; the weekdays are "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday". The program should first prompt the user to input the data for each monkey, starting with "Sunday" for monkey #1, then monkeys #2 and #3, followed by "Monday" for monkey #1, then monkeys #2 and #3 and so on, through "Saturday". The program then creates a report that includes the following information, each properly labeled (see below):
-Average amount of food eaten per day by the whole family of monkeys. -The least amount of food eaten during the week by any one monkey. -The greatest amount of food eaten during the week by any one monkey.
Input Validation: Do not accept negative numbers for pounds of food eaten. When a negative value is entered, the program outputs "invalid (negative) food quantity -- re-enter" and attempts to reread the value . Prompts And Output Labels: Decimal values should be displayed using default precision, i.e. do not specify precision. Each item read should be prompted for by a string of the form "Enter the food eaten by monkey #N on DAY:" when N is 1 or 2 or 3 and DAY is "Sunday" or "Monday" or ... or "Saturday".
The output should be of the form:
Average food consumed daily: 6.23 The least daily food consumed was by Monkey #0 on Friday The most daily food consumed was by Monkey #2 on Sunday where the specific amount of food or specific monkeys or specific days identified depend on the actual input.
However after the process of resolving the errors unable to convert to standard string and unresolved externals I now have a logical error that causes the output of the DAYNAME variable to output as what appears to be hex in the following picture:
How I can fix this and why it's casting them as this in the output.
My full code is as follows because I don't know exactly, which line of code is causing this to happen:
Code: // #include <iostream> #include <iomanip> #include <string> using namespace std; // constants const int MONKEYS = 3; const int DAYS = 7;
This is an example of how sub string and math can be used to make logical decisions without using if/elses or switches. It works because of this equation
(x + |x|)/x = 2 if x > 0 and = 2 if x < 0.
#include <iostream> #include <string> #include <cmath> using namespace std; int main() { //declaration of variables
Using the old fashioned (unsigned) multiplication instruction in x64 assembly multiplies RAX (64 bit register) by a 64 bit register. The answer is stored in RDX:RAX (i.e. the answer is 128 bits). Is there any way, using native c++ to get the value in RDX (higher 64 bits)? One I can think of is: right/(limit/left) e.g. if we are limited to a byte then 97*123 would overflow:
97/(255/123) = 46 times, which is RDX's (if it was one byte) value. But this is too inefficient. Is there a fast way?
I haven't found anything that small for Matrix multiplication i was just going to ask about how i would multiply to matrices together in c++ as easy as possible, so for example say a i have the following
[2 0 1 0 * [3 0 6 -1 0 2] 0 3 1 2 3 1]
How would i multiply these together. Here is the example
When things at work get overwhelming, it's not unusual for me to briefly "escape" by writing small programs simply for fun. A few days ago, I had an idea for a "binary game". I completed the first draft of it yesterday.
The idea is simple. The game uses 8-bit values. At the start of the game, a random "target" value is generated. The player is dealt a "hand" of seven values. The object is to use the values in your hand, along with some basic logical operations, to create the "target" value. While the idea is simple, the game itself can be quite difficult.
: Looking at the first column: - 'T' is the "target" value - '0' can be thought of as the "game board" - this is the value that needs to match the target value for a win - '1' - '7' are the values in your "hand"
You can apply logic AND ('A'), OR ('O'), or XOR ('X') to a value in your hand with the value on the "game board". You are also allowed to apply logic to two values in your hand to create a new value for your hand. When a value from your hand is used, it is removed.
Some examples of the commands:
A30 --- apply logic AND to value #3 in your hand, and the "game board" value O23 --- apply logic OR to value #2 in your hand and value #3 in your hand X70 --- apply logic XOR to value #7 in your hand, and the "game board" value
You can also be dealt new values (as long as there's room in your hand) with the '+' command. 'H' or 'h' prints the help, and 'Q' or 'q' exits the game.
I haven't thoroughly tested it yet, since I just finished it a yesterday, but so far it looks good. The program itself uses only standard C.
I was dickering with the idea of supporting more logical operators (NOT, NAND, NOR, XNOR, shift), but I like the simplicity and resulting difficulty of the current implementation.
During initial testing, I realized it's possible to have doubles in your hand. Also, it's quite possible to be dealt the target value directly, which means that you could potentially win with one move, chance permitting. At first I thought about defending against these conditions, but came to the conclusion that it is fine as is - chances of an instant win are small, and if it does occur, would still be an enjoyable experience. Besides, if you're dealt the target value after the "game board" value has been modified.
Also, I did not allow a value of "zero" in the players hand. This was originally because I thought it would be of little use (though I've been reconsidering this). This also means that if two values in the hand are combined and result in zero, both values are removed and no new value is added. This was originally a bug, but I think I'll just reclassify it as a feature
So far, I found that the best strategy is to avoid modifying the "game board" value, and just play with the values in your hand. If you can get the target value in your hand, you just OR it with the "game board" and you're done.
I've encountered a slight logical error in my code
/* Lab06_pensionplans.cpp Purpose : - Create a simple financial application to calculate retirement plans */ #include <iostream> #include <cstdlib> using namespace std; void displayMenu() { system("cls");
[Code] ....
Look at case 2, which the user supposed to key in a new input, the problem is the value will never got into main function, I don't know what should I modify with the function.
I've been working on this program to create a simple desk calculator for a school assignment, and I managed to finish. All we had to do was add, subtract, multiply, and divide positive integers - and I was able to do that just fine. This program got me thinking though, because I do not know how to write commands to multiply/divide negative numbers.
In fact, when I divide a number like 21 by 4, it comes out to 5 because I don't know how to allow it to compute remainders (which wasn't a requirement for my program). This intrigued me so I've been trying to figure it out for the last few days but to no avail. Here's my code:
Code: void flush_buffer(){ int ch; while ((ch = getchar()) != ' ' && ch != EOF);
[Code]....
And just know that my code works perfectly fine, I'm not here for troubleshooting it. I just want to know what I can change to allow negative values to be correctly computed.
I'm building two DLLs - let's call them DLL_A and DLL_B. DLL_A builds as a standalone entity but DLL_B needs to link to the lib file for DLL_A (i.e. it imports some functionality from DLL_A). While linking DLL_B I see lots of errors taking the following form (bear in mind that port.cpp and port.h are source files in DLL_B:-
I'm not sure if I'm reading that correctly but to me, it seems to be saying that some STL components are somehow getting exported from DLL_A (std::vector maybe?? Or std::string??) and that they conflict with similar objects already in port.obj. Sure enough, when I used dumpbin /EXPORTS on DLL_A there did seem to be some evidence that that was true. So my next step was to examine the source code for port.obj. Of course, strictly speaking I should be examining some code from DLL_A but it has hundreds of source modules so I figured that I should start by identifying whatever it is in DLL_B that's throwing up the conflict (since I at least know which module the conflict is in!).
When I examined the source files for port.obj, std::string seems to get used quite often - but fortunately I could only find one occurrence of std::vector.
In port.h it occurs here:-
Code: class DLL_B_API Port : public boost::noncopyable { public: // c'tors + d'tors int get_connections (std::vector<std::string> &) const; // rest of class
In port.cpp it occurs here:-
Code: int Port::get_connections (std::vector<std::string> & c) const { if (!port_engine.available()) { c.insert (c.end(), _connections.begin(), _connections.end()); return c.size(); } return port_engine.get_connections (_port_handle, c); }
Is there anything in there that would be causing the above linker error? It's entirely possible that I'm looking in the wrong place but I suppose I've got to start somewhere....
I just found a possible clue in one of the header files for DLL_A, where I found this class declaration:-
Code: namespace PBD { class DLL_A_API Searchpath : public std::vector<std::string> { // Whatever... }; }
Might that be causing std::vector<std::string> to get exported?
I'm trying to get my C program to compile but it's not working at all. I've programmed a little in C++ before but I'm not used to C. Here's my program so far:
Code: int main(void){ // Establishes variables int num1, num2, product; float quotient;
[Code] .....
It keeps giving me an error message as follows:
"/usr/bin/ldrelabwk2: file format not recognized; treating as linker script /usr/bin/ldrelabwk2:1: syntax error collect2: ld returned 1 exit status"
