If input value was shifted to the right on bit level. How can I determine whether a logical or arithmetic shift is performed.
Code:
#include <stdio.h>
#include <stdlib.h>
void main ()
[Code]......
Question: State the values of each of these int variables after the calculation is performed. Assumed that, when each statement begins executing, all variables have the integer value 5.
a) product *= x++;
b) quotient /= ++x;
What is the answer for a and b?
Write a user-friendly C++ program that allows a user to select repeatedly an operation to be performed from a displayed menu of actions. The menu includes the following items:
1. Simple Statistics
2. Vector Addition
3. Dot Product
4. Exit
The menu actions are described by the following points:
Simple Statistics: This action includes finding the average, and standard deviation of a list of data items. The option should allow the user to specify the name of a file from which the data are read into an array. All the results of this option are displayed on the screen.
Vector Addition: This action allows the user to enter the name of a file from which two vectors, V1 and V2, of equal size N are read. Accordingly, the two vectors are added, and displayed along with the resultant vector on the screen. Your program should check that the two added vectors are of the same size. Otherwise, the program should display a message and allow the user to make another choice from the menu.
Dot Product: This action is similar to the Vector Addition in terms of input, output, and checking validity of the vector operands.
Exit: This action terminates the program.
Your program should include at least the following functions:
1. A function, called ReadVector(), which reads a vector of any size from a given file name, and returns the vector and its size to the caller. The function prototype is defined as follows:
void ReadVector(double V[], int &size, ifstream infile);
2. A function, called DisplayMenu(), which displays the menu and returns the user’s choice as an integer value between 1 and 4. The function prototype is defined as follows:
int DisplayMenu (void);
3. A function, called VectorAdd(), which performs the addition of two vectors, A and B, and returns the resultant vector, C. The function prototype is defined as follows:
void VectorAdd(const double A[], const double B[], double C[], int size);
The sum of two vectors, A = (a1, a2, …, an) and B = (b1, b2, …, bn) of size n, is defined as: C = A + B.
Where, C = (c1, c2, …, cn), and ci = ai + bi, for1 i n .
4. A function, called DotProduct(), which performs the dot product of two vectors, A and B, and returns the result. The function prototype is defined as follows:
void DotProduct(const double A[], const double B[], int size, double &result);
The dot-product of two vectors A = (a1, a2, …, an) and B = (b1, b2, …, bn) of size n is defined as
n n
n
i
i i b a ....... b a b a b a B . A
1 1 2 2
1
5. A function, called Simple_Stat(), which finds the maximum, minimum, average, and standard deviation of a list of data items passed to it by a one-dimensional array. The function returns the average and standard deviation values. The function prototype is defined as follows:
void Simple_Stat(const double list[], int size, double &average, double
&std_dev);
I am having this problem were the user types in a substring to search in the main string and replace it with another string
for example:
string: hello
sub string: el
replace: i
should print this: hillo
I tried using some string functions but I am having problems with that.
I need to circular right shift a cstring in C++
Let's say I have unsigned char test[10] = "HELLO!!!"; How would I go about circularly shifting this to the right? Inline assembly instructions would be ok too
I have this BCD string: 890123...78FFF and need to right shift by say 3 nibbles, resulting in: FFF890123...78
length is fixed, number of 'f' nibbles are varying.
when we are trying to shift one tab to other one event should occur, can any one tell what is the event,how and where we have to write the event? give example. if he successfully login in first tab only then second tab will open,if he doesnt login in first and tries to open the second tab message should appear...
View 1 Replies View RelatedI wrote this program using an online compiler i am getting a lot of errors.
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
int main() {
string birthmonth;
string birthday;
[Code] ....
I have a doubt in Left Shift Operator
int i = 1;
i <<= (sizeof (int) *8);
cout << i;
It prints 1.
Doubt:
i has been initialized to 1.
And while moving the bits till the size of the integer, it fills the LSB with 0's and as 1 crosses the limit of integer, i was expecting the output to be 0.
How and Why it is 1?
I've received a segmentation fault in this part of code:
Code:
for (; str[i] != ' ' || str[i] != ' '; i++) {
result[result_pos] = str[i];
result_pos++;
}
which, should mean:
Code: If str[i] is not equal to NULL character nor ' '; then, keep printing the chars within the word to variable result.
To understand what the function does, here's the whole code:
static char result[999];
/* char *split_word(const char *str, long n);
* Splits a string word-by-word. Where N is the word number. */
char *split_word(const char *str, long n) {
[Code]....
I'm trying to accomplish an easier way round to split string by word than using "strtok_r()". It might sound like "re-inventing the wheel", but... i will try to make it neat later.
The code looks okay, why would it segfault?
Let's say I have a product that needs service after 500 hours at 100 RPM. I can dsiplay the remaining hours only as an integer and we only have integer math. Management wants it to display 500 for the first hour, not 499 after the first minute is ticked off. But after a few minutes fullHours will be 499 and partialHours will have some value. I have 3 ways to determine displayHours to suit management and I want to know if the first is ligit.
short fullHours = 500;
short partialHours = 0;
short displayedHours = 0;
// Method 1 - Is is Kosher to cast a boolean as an int? Is TRUE always a 1 or is that a bad assumption?
displayedHours = fullHours + (short) (partialHours != 0);
//Method 2 - Works but some have disdain for the ternary conditional
displayHours = fullHours + (partialHours ? 1 : 0);
//Method 3 - seems a bit pedantic
displayHours = fullHours;
if (partialHours != 0) {
displayHours++;
}
I wrote this code to solve a problem in which the user inputs a permutation of size 'N' and the next permutation of the same elements has to be generated.
I went about this in this way: given 3 2 5 4 1, starting from the right, the first no. has to be searched which has a no. greater to it on its right. Here it is 2. Now an array is generated containing all no.s on its right and greater than it. For 2, it is: 5,4. Out of these the smallest member is searched for and switched with 2. So, 4 is switched with 2 to get the Next Permutation: 3 4 5 2 1.
The code I wrote does not show any error but does not return the correct value when run and gives the same value instead. If I enter '3 2 5 4 1' it returns the same value as the answer.
#include<iostream.h>
#include<conio.h>
void main() {
clrscr();
int N,M,i,n,c,swap,flag,count,small,m;
int Array[100],Key[100];
[Code] .....
int main()
{
char rORc, choice;
int sizerc;
[Code]....
when I input the character which is the underscore, and the row # it should display the table and sort that specific row. Why is the if statement skipped? This is not the complete program but has everything needed.
how to show all the bits of a number using bitwise shift operator....and hence represent the number in 2's complement representation
View 1 Replies View RelatedI am struggling to write a code about caesar cipher shift and using ascii code with it. For example letter b should be replaced with the letter c and using the ascii code it should be from 98 to 99 and so on..
View 1 Replies View RelatedMy project is on an online shop in which you can manage a shop(adding ,deleting ,clearing and modifying items) also you can switch to different shops(all shops are same)
Code:
#include<iostream>
#include<fstream>
#include<conio.h>
#include<stdlib.h>
#include<string.h>
[Code] ....
The logical problem is serious because i am not able to find the error!!! There is some problem with display lines in void shop()-->if(mode=='s') and if(mode=='d'). I add only one item but in output screen i see two items(sometimes >2)
*note* to run the above display lines in the output screen....first register--->add atleast one item--->see your shop
#include <iostream>
using namespace std;
int main(){
int polje[8][8];{
for(int i=0;i<8;i++)
for(int j=0;j<8;j++) {
[Code] .....
I don't get any errors,the program works. The problem is that it doesnt work how it should. This is a simple program that multiplies 2 variables(i and j)that go from 0 to 7. The problem I have is with the logical operators,i want the program to skip multiplication with 0 and when the 2 variables are the same value. When i try using only 1 logical operator it work.
I am looking for a library to aid me in evaluating Boolean expressions. For example, i have an expression like this:
(1*(5+3)+9*65/5-(354*4565*5643+98) >= 12345) && ( 654*987+123 || (2345 > 23423 && 1 != 2)))
(It can also be much longer!) and would like to evaluate them to a true/false boolean.
There are tons of libraries to calculate the (numerical) result of a mathematical expression, but this is not what i want to do.
I have to write a program that does the following: Monkey Business A local zoo wants to keep track of how many pounds of food each of its three monkeys eats each day during a typical week. Write a program that stores this information in a two-dimensional 3 - 7 array , where each row represents a different monkey and each column represents a different day of the week. The monkeys are represented by integers 1, 2, and 3; the weekdays are "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday". The program should first prompt the user to input the data for each monkey, starting with "Sunday" for monkey #1, then monkeys #2 and #3, followed by "Monday" for monkey #1, then monkeys #2 and #3 and so on, through "Saturday". The program then creates a report that includes the following information, each properly labeled (see below):
-Average amount of food eaten per day by the whole family of monkeys.
-The least amount of food eaten during the week by any one monkey.
-The greatest amount of food eaten during the week by any one monkey.
Input Validation: Do not accept negative numbers for pounds of food eaten. When a negative value is entered, the program outputs "invalid (negative) food quantity -- re-enter" and attempts to reread the value . Prompts And Output Labels: Decimal values should be displayed using default precision, i.e. do not specify precision. Each item read should be prompted for by a string of the form "Enter the food eaten by monkey #N on DAY:" when N is 1 or 2 or 3 and DAY is "Sunday" or "Monday" or ... or "Saturday".
The output should be of the form:
Average food consumed daily: 6.23
The least daily food consumed was by Monkey #0 on Friday
The most daily food consumed was by Monkey #2 on Sunday where the specific amount of food or specific monkeys or specific days identified depend on the actual input.
However after the process of resolving the errors unable to convert to standard string and unresolved externals I now have a logical error that causes the output of the DAYNAME variable to output as what appears to be hex in the following picture:
How I can fix this and why it's casting them as this in the output.
My full code is as follows because I don't know exactly, which line of code is causing this to happen:
Code:
//
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
// constants
const int MONKEYS = 3;
const int DAYS = 7;
[Code] .....
This is an example of how sub string and math can be used to make logical decisions without using if/elses or switches. It works because of this equation
(x + |x|)/x = 2 if x > 0 and = 2 if x < 0.
#include <iostream>
#include <string>
#include <cmath>
using namespace std;
int main() {
//declaration of variables
[Code] ....
In a SDI app, I constraint the mouse to move only an horizontal direction, if "Shift" key is pressed ... here is the code:
Code:
void CTestMouseView::OnKeyDown(UINT nChar, UINT nRepCnt, UINT nFlags) {
// TODO: Add your message handler code here and/or call default
if(GetKeyState(VK_SHIFT) < 0) {
CRect rect;
GetWindowRect(&rect);
GetCursorPos(&m_point);
[Code] ....
Nothing complicated, and it works well ... except one thing: when I press the shift key and the mouse is moving by SetCursorPos, is moving pretty slow ... why ? I can not figure out why ! For testing, I attached the test project ...
When things at work get overwhelming, it's not unusual for me to briefly "escape" by writing small programs simply for fun. A few days ago, I had an idea for a "binary game". I completed the first draft of it yesterday.
The idea is simple. The game uses 8-bit values. At the start of the game, a random "target" value is generated. The player is dealt a "hand" of seven values. The object is to use the values in your hand, along with some basic logical operations, to create the "target" value. While the idea is simple, the game itself can be quite difficult.
Here is an example of the output:
Code: --------------------
T: 1111 1100 (0xFC)
--------------------
0: 0000 0000 (0x00)
--------------------
1: 1100 1110 (0xCE)
2: 1010 0011 (0xA3)
3: 1100 0101 (0xC5)
4: 1011 1111 (0xBF)
5: 1010 1011 (0xAB)
6: 0001 1011 (0x1B)
7: 0001 1011 (0x1B)
--------------------
: Looking at the first column:
- 'T' is the "target" value
- '0' can be thought of as the "game board" - this is the value that needs to match the target value for a win
- '1' - '7' are the values in your "hand"
You can apply logic AND ('A'), OR ('O'), or XOR ('X') to a value in your hand with the value on the "game board". You are also allowed to apply logic to two values in your hand to create a new value for your hand. When a value from your hand is used, it is removed.
Some examples of the commands:
A30 --- apply logic AND to value #3 in your hand, and the "game board" value
O23 --- apply logic OR to value #2 in your hand and value #3 in your hand
X70 --- apply logic XOR to value #7 in your hand, and the "game board" value
You can also be dealt new values (as long as there's room in your hand) with the '+' command. 'H' or 'h' prints the help, and 'Q' or 'q' exits the game.
I haven't thoroughly tested it yet, since I just finished it a yesterday, but so far it looks good. The program itself uses only standard C.
I was dickering with the idea of supporting more logical operators (NOT, NAND, NOR, XNOR, shift), but I like the simplicity and resulting difficulty of the current implementation.
During initial testing, I realized it's possible to have doubles in your hand. Also, it's quite possible to be dealt the target value directly, which means that you could potentially win with one move, chance permitting. At first I thought about defending against these conditions, but came to the conclusion that it is fine as is - chances of an instant win are small, and if it does occur, would still be an enjoyable experience. Besides, if you're dealt the target value after the "game board" value has been modified.
Also, I did not allow a value of "zero" in the players hand. This was originally because I thought it would be of little use (though I've been reconsidering this). This also means that if two values in the hand are combined and result in zero, both values are removed and no new value is added. This was originally a bug, but I think I'll just reclassify it as a feature
So far, I found that the best strategy is to avoid modifying the "game board" value, and just play with the values in your hand. If you can get the target value in your hand, you just OR it with the "game board" and you're done.
I've encountered a slight logical error in my code
/*
Lab06_pensionplans.cpp
Purpose :
- Create a simple financial application to calculate retirement plans
*/
#include <iostream>
#include <cstdlib>
using namespace std;
void displayMenu() {
system("cls");
[Code] ....
Look at case 2, which the user supposed to key in a new input, the problem is the value will never got into main function, I don't know what should I modify with the function.
Figured out I need to change the
void changeData(int startingAge, int numOfYears,
double lumpSumAmount, double yearlyAmount, double interestRate )
into
void changeData(int &startingAge, int &numOfYears,
double &lumpSumAmount, double &yearlyAmount, double &interestRate )
One thing that I was not able to fully understand even though I read through the section on it a few times, is the for loop. I mean, I understand the premise of (statement, condition, update statement). However, I do not quite understand how a math problem is affected by this.
How this works using multiplication and division? And lastly, why would you use a do.. while loop?
I've got this string: Code: char * string = "2+2"; I want to get an integer value = 4 from this. How would I go about doing this.
View 1 Replies View RelatedI am a c++ leaner, I am trying to create a BST tree for this expression: 2346*+/8+, and do inorder and postorder to get the in-fix version, and postfix version of the expression. I am having difficulty to create the binary tree for the expression. Here is my peso code:
Tree:
Stack:
inorder fn{}
postorder fn{}
main{
input the file;
while(expression){
[Code] ....
The tree I want to create is like this
+
/
(/) 8
/
+ 2
/
* 3
/
4 6
My problem for this code is that after create (4*6) tree, I cant link (+3) with (4*6).