C++ :: Not Declared In Scope And No Member Name With Vectors

Mar 31, 2015

Code:

#include <iostream>
#include <vector>
#include <cmath>
#include "ANN.h"
using namespace std;
const int NUM_HIDDEN_NEURONS = 3;

[Code] ....

So I am getting 2 errors. Here is both of them.

ANN.cpp: In member function "void ANN::JustDoIt()":
ANN.cpp:36: error: "class std::vector<HiddenNeuron, std::allocator<HiddenNeuron> >" has no member named "SetWeights"
ANN.cpp: In member function "void ANN::SetData(double, double)":
ANN.cpp:85: error: "SetNeuronData" was not declared in this scope

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C++ :: (X) Not Declared In This Scope Error

Oct 29, 2014

main.cpp

#include <iostream>
#include "sushi.h"
using namespace std;
int main()
{
do {
......sushi go;
......string x; <----------------------------Declared x here
......cout << "wanna use a banana?" << endl;

[Code ....

Error reads: 'x' was not declared in this scope.

How do I fix this?

P.S The sushi class does not matter, that is all perfect. Also, the dots are to represent my tabbing to make it easier to understand.

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For some reason my compiler says "rename not declared in this scope" .... Isn't it declared in iostream? Or is rename only for C not C++? And if it is only for C how do I rename a file in C++ then?

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#include <cstdlib>
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[Code] .....

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I have this error - [Error] 'fprintf' was not declared in this scope (line 32)

and this - [Error] 'fclose' was not declared in this scope (line 33)

here's my code.........

1 #include <iostream>
2 using namespace std;
3 #include <windows.h>
4 #include <winuser.h>
5
6 int save (int key_stroke, char *file);

[Code] ......

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[Code]....

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tile Tile;
Tile **grid;
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4#include <iostream>
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8// Function prototype

[code]....

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I've got this sorting program that uses variables from another class but I'm not sure why its not recognizing it. I'm getting an error length and list not declared in this scope.

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template<class elemType>
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[Code] ....

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Feb 10, 2015

I am trying to make a linked list. When I compile my code, I get an error saying 'current' is not declared in this scope. I don't understand because I have declared in the first line of my functions body. The variable is local to the function so I don't understand what the problem is.

#include <iostream>
#include <cstdlib>
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[code].....

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Code:

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std::vector<AStarNode *>solution;

[code]....

CCB is derived from CrowdEntity and in turn is derived from CObjects Inside CObjects, I declared AStarList *OPEN; Why would howmany become garbage (cdcdcdcd) when I reference it in GetBestNode()

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Aug 22, 2013

I have a method:

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I want to use it, in a thread.

std says, use thread, as:

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How can I do this, for my method, that uses more than one, i.e., two, parameters?

My code is:

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compiler says:

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The whole struct is

struct Player {
bool key[256];
char nameString[64];
bool lMouseButton;
bool rMouseButton;
double mouseX;
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[Code] ....

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Apr 1, 2014

I am currently doing the assignment about linked list. Here are some details information about what I am doing.. This program is C++ and should run on Visual Studio 2010. And it contains three file, two datastructure header and one main cpp file.

This program is trying to arrange and show some sports records. The main program which contain the functions such as reading the result text file(each result text file contain several records of athletes), removing a file, arranging the totalresult and printing it out. And the main program is already given and I cannot overwrite it.

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error C2248: 'Datastructure1::Datastructure1' : cannot access private member declared in class 'Datastructure1'
see declaration of 'Datastructure1::Datastructure1'
see declaration of 'Datastructure1'
This diagnostic occurred in the compiler generated function 'Result::Result(const Result &)'

And I have tried to comment each function part of the header file and see if can run or not. But I still fail to do so. Here are my codes...

#ifndef DATASTRUCTURE1_H
#define DATASTRUCTURE1_H
class Datastructure1 {
Public:
Datastructure1( );

[Code] ....

There are two header files and look quite long. They are all some linked list functions . I have read and learn linked list data structure before I complete this programs. However, when I complete the functions required, the function cannot be compile....

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Are there any situations to explicitly use the scope resolution operator with global scope? I can imagine a situation like:

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public:
IntWrapper& pow(char);
IntWrapper(char);
private:
int m_int;

[Code] ....

But then I would think that the writer should have used a different name, and that using the scope resolution operator in the constructor body is still pointless...

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};
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EDIT: It also doesn't work if I typename x::y *GetY();, which makes even less sense to me.

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OR
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[1,1]
[1,2]
.
.
.
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This is the code I enter when trying to access the method from randomiser.h in main.cpp. It is also an overloaded function with doubles and integers:

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This is the code inside randomiser.h:

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[Code] ....

This is the error inside xcode: [URL] ....

I have tried seperating the code for the functions in another class (main.cpp) and then running and it seems to works, so I'm not sure why I can't put everything in the .h file and then access it?

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Then at some pointer later in execution, another function uses the pointer passed to store_for_later.

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sql:: Driver *driver;

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Code:

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struct bank_account {

[Code].....

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I have c# code something like below.
 
void ExecuteSomething() { 
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[Code] ....

I am retrieving the data by using above code

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case 0:
{
int value = 5;
}
break;

[Code] ....

Ok so it doesn't like int value = 6 b/c of int value = 5 for case 0. However since the value in case 0 is declared within the brackets one would think it has case scope.

So I tried this:

Code: int x = 5;
switch(x) {
case 0:
{
int value = 5;
}
break;

[Code] ....

Now it doesn't like it b/c value has not been declared in case 1:. These two conditions cannot possibly be both true at the same time. You cannot disallow the declaration of value in case 1 b/c it interferes with value in case 0 and at the same time disallow me to use value from case 0 b/c it is not in scope. If it was not in scope then theoretically I should be able to declare value in case 1.

Both MSVS 2012 and 2013 exhibit the same behavior. I checked the standard and it is unclear on the matter.

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