#include <iostream> #include "sushi.h" using namespace std; int main() { do { ......sushi go; ......string x; <----------------------------Declared x here ......cout << "wanna use a banana?" << endl;
[Code ....
Error reads: 'x' was not declared in this scope.
How do I fix this?
P.S The sushi class does not matter, that is all perfect. Also, the dots are to represent my tabbing to make it easier to understand.
For some reason my compiler says "rename not declared in this scope" .... Isn't it declared in iostream? Or is rename only for C not C++? And if it is only for C how do I rename a file in C++ then?
#include <iostream> #include <cstdlib> using namespace std; int main(int argc, char* argv[]){ char oldname[] = "RomeTW.exe";
I'm working through this neural network tutorial, unfortunately I get stuck trying to compile on line 28, saying "error: 'neuronNum' not declared in this scope." I seem to always get stuck on these kinds of errors, yet I don't understand because I though that the variable was declared and initialized within the for loop.
#include <iostream> #include <vector> using namespace std;
I'm trying to make a dynamic 2d array of a Tile Object I created, the Dynamic 2d array was working when I tested it as an int array but not that I gave it a type of Tile it is giving me the above error. I'm reading values from a .txt .
tile Tile; Tile **grid; grid = new Tile*[a]; for (int i = 0; i < a; ++i) { grid[i] = new Tile[b]; }
#include <iostream> #include <vector> #include <cmath> #include "ANN.h" using namespace std; const int NUM_HIDDEN_NEURONS = 3;
[Code] ....
So I am getting 2 errors. Here is both of them.
ANN.cpp: In member function "void ANN::JustDoIt()": ANN.cpp:36: error: "class std::vector<HiddenNeuron, std::allocator<HiddenNeuron> >" has no member named "SetWeights" ANN.cpp: In member function "void ANN::SetData(double, double)": ANN.cpp:85: error: "SetNeuronData" was not declared in this scope
I've got this sorting program that uses variables from another class but I'm not sure why its not recognizing it. I'm getting an error length and list not declared in this scope.
#include <iostream> #include "arrayListType.h" using namespace std; template<class elemType> class orderedArrayListType: public arrayListType<elemType> {
I am trying to make a linked list. When I compile my code, I get an error saying 'current' is not declared in this scope. I don't understand because I have declared in the first line of my functions body. The variable is local to the function so I don't understand what the problem is.
#include <iostream> #include <cstdlib> using namespace std; class LinkedList { public: LinkedList() // default constructor makes an empty list
1) Generate a series of numbers 2) Write those numbers onto a txt file and 3) Read only the odd numbers out of the txt file.
I have 3 functions besides main that do each of the objectives individually and when separate they work just fine. But when I put them together for some reason the third function is never started. Also when I rearrange the 3rd function infront of the 2nd (since i have the txt file already saved) it works but I get an error when trying to close the txt file. It is the same close function that I'm using when first creating the txt file as well.
Here is the code
Code:
#include <stdio.h> #include <stdlib.h> int main() }
Are there any situations to explicitly use the scope resolution operator with global scope? I can imagine a situation like:
#include <cmath> class IntWrapper{ public: IntWrapper& pow(char); IntWrapper(char); private: int m_int;
[Code] ....
But then I would think that the writer should have used a different name, and that using the scope resolution operator in the constructor body is still pointless...
struct x { y *GetY(); //error: what is "y"? struct y { }; };
Why does GetY have to be declared after struct y is declared? I thought order of class members in C++ did not matter? Does it have to do with the way parsing is done?
EDIT: It also doesn't work if I typename x::y *GetY();, which makes even less sense to me.
EDIT: It works if I forward declare, but this goes against everything I know about C++ classes...
i have two variables which are arrays and want them to be written below the other once all the values of one variable is written . how can i do that using fprintf function in c++ ?
I am trying to take text from a file and have it displayed using fprintf at line 46. When I run the below code nothing prints out. My text file has 4 lines with 5 different strings separated by whitespace.
#include <cstdlib> #include <vector> #include <cstring> #include <stdlib.h> #include <errno.h> #include <stdio.h> using namespace std; //declare my own struct
I'm new to C and was wondering if it was possible to print multiple characters to the same file using the fprintf function provided in one of the C standard libraries?
I have done alot of googling for the scope resolution operator and Ive gained a bit of an understanding as to what it does i know it can distinguish between global and local variables, but I see it used to access methods/members of classes such as this example, why not just use a dot instead to access it?:
sql:: Driver *driver;
Why is the scope resolution operator being used here?
Code: vector<int>& function(int a , int b){ vector<int> s(3000000); vector<int> xxx(4); return xxx }
Not to board people with details but if i am returning the the reference to a vector xxx what happens to vector s. is it destroyed ?? it should be, but i don't see it on my memory map (memory is not released) . can this be or should i go and search for error on some other place.....
From some other code i am calling some function in c# through windows service. That function is going to delete some unwanted data from sql server database. if i wanted i initiate the request it will take 30 min to delete the data.
in this 30 min time i am unable to access other pages in my website. is there any better way to design this?
Ran into something today that does not make sense:
This compiles: Code: int x = 5;
switch(x) { case 0: { int value = 5; } break;
[Code] ....
Ok so it doesn't like int value = 6 b/c of int value = 5 for case 0. However since the value in case 0 is declared within the brackets one would think it has case scope.
So I tried this:
Code: int x = 5; switch(x) { case 0: { int value = 5; } break;
[Code] ....
Now it doesn't like it b/c value has not been declared in case 1:. These two conditions cannot possibly be both true at the same time. You cannot disallow the declaration of value in case 1 b/c it interferes with value in case 0 and at the same time disallow me to use value from case 0 b/c it is not in scope. If it was not in scope then theoretically I should be able to declare value in case 1.
Both MSVS 2012 and 2013 exhibit the same behavior. I checked the standard and it is unclear on the matter.