I am trying to write a simple application that resembles the game "Computer Co", but I am stuck with this problem: If the board is represented by a dimensional array, with what algorithm could I tell if one player's pieces are captivated by the other's? In other words, how can I recognise whether the pieces of one colour form a circle?
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I've made an effort for three days to write this code. But, my brain has stopped now. I wrote code to find the status of the game (win, loss or tie). However, I can't determine the tie status of the game. Tie status is the problem
View 5 Replies View RelatedI'm working with arrays that might have NULL bytes in them and I'm wondering how to determine the length of the array or store it somewhere with the array (strlen() won't work because of the NULL, right?).
I've found advice like store the length of the array in the first byte of the array, but since sizeof(size_t) is 8 should I leave the first 8 bytes for the length?
Would it be better do define my own structure which would store the array and its length? What's the usual way these things are handled in practice?
I would like to make a handler for input events, but not be required to define all the functions.For example, if I had
void mouseDown(int button,vec2 pos);
void mouseUp(int button,vec2 pos);
static void mouseStateHandle(int button,int state,int x,int y) {
switch(state){
case DOWN:
[code]....
in the 'mouseStateHandle' function? I don't know enough about C++ to be able to come up with a solution.
I am making an eVoting program which takes input from .txt file and outputs in the same .txt file. I need to ask the user to enter the candidate they wish to vote and then read the previous tally from the .txt file and add one to it. The problem is determining the numbers in a .txt file and adding one to it.
For example voting_Tally.txt contains:
Bloomberg 1234
Bill De Blasio 6789
How would it be possible to first determine the name and then add one to their tally. For Example:
Bloomberg 1235
Bill De Blasio 6790
How can I determine whether there is a collision between 2 meshes? I'd just like to see if one mesh is inside another.
View 10 Replies View RelatedI have a service A, and an application B. Service A needs to launch application B only if it's not running currently. This can be easily done in Windows by calling GetExitCodeProcess function. I cannot find an equivalent method for doing so in Linux/Mac.
So my current code says:
system("open /Users/adsmaster/client/client &"); // to launch the application from the service in a new shell
I read that on a Linux-line machine you can use $ cal to get the exit value of the recently run process but I am not sure how can get the exit value of a particular process?
I need to count how many times letter appears in a text. I know that for default letters from 'a' to 'z' and from 'A' to 'Z' there is an interval. But I need also Lithuanian letters, such as ž,č,ę. I wrote this method: (it accepts char code and checks whether that char is a letter)
bool eilutė::YraRaidė(int kodas)
{
if(kodas >= 'a' && kodas <= 'z') {
return true;
[Code]....
As you can see, a lot of checking in switch statement. I use 256 for this reason to have the same effect as unsigned char. But maybe there is a way to shrink down this method, or use some library?
Is there any code I can use to determine my compiler version and which Standard It uses? I know the following code determine that my compiler followed ANSI But how about a version of that? ****My OS is now Ubuntu
Code:
#include <stdio.h>
int main(void){
printf("File :%s
", __FILE__ );
printf("ANSI :%d
", __STDC__ ); //return 1 if it follow ANSI but version?
return 0;
}
You are given an integer, perhaps a very long long integer, composed of only the digits 1 and/or 2. You have the ability to change a 1 digit into a 2 and a 2 digit into a 1 and must determine the min. number of changes that you can make resulting in no 2 digits remaining in the number that are in a position(in terms of powers of ten) higher than any 1 digit.
example:
2222212 number of changes:1
1111121 1
2211221 3
1122112 2
no negative numbers.
how to get started. Also I'm not allowed to use anything related to arrays or sorting.
I have a current assignment for C++ involving us to make a program to determine coin change for example if you input the number 127 you would need 2 half dollars 1quarter and 2 pennies I have no way how to program this.
This is my code that doesn't do what i want it to
#include <iostream>
using namespace std;
int main ( ) {
float change;
int half_dollars, quarters, dimes, nickels, pennies; // declare variables
[Code] ....
Write a C++ program that can be used to determine grades at the end of the semester. For each student, who is identified by an integer number between 1 and 60, four examination grades must be kept. Additionally, two final grade averages must be computed. The first grade average is simply the average of all four grades. The second grade average is computed by weighting the four grades as follows: the first grade gets a weight of 0.2, the second grade gets a weight of 0.3, the third grade a weight of 0.3, an the fourth grade a weight of 0.2; that is computed as:
0.3*grade1 + 0.2*grade2 + 0.2*grade3 + 0.3*grade4
Using this info, you are to construct a 60X7 two dimensional array, in which the first column used for the student number, the next four columns for the grades, and the last two columns for the computed final grades. The output of the program should be a display of the data in the completed array.
I have to write a program that use a while loop and that each time around the loop reads two double, prints out the largest, the smallest and if they are equal.
I have no problem with this program but I can't understand how to modify it following the author : Change the program so that it writes out "the numbers are almost equal" after writing out which is the larger and the smaller if the two numbers differ by less than 1.0/100.
for now this is my code :
int main() {
double a = 0;
double b = 0;
while (cin >> a >> b) {
cout << "first number is : " << a << "
second number is : " << b << "
[Code] ....
The problem is that I don't know how to test if the numbers differ by less than 0.01 because my if statement doesn't work in any case. If I enter 2 and 1.99 It doesn't work, why ?
I have to make an email validation program and i am halfway done. I only have one more problem, consider the ff. example:
Enter email:
myemail.@something.com //this is the input
Invalid //this should be the output
How can i determine if there is a special character near the '@' sign? and vice versa?
Originally I had to create a simple integer palindrome program that looped while the user entered 5 digit inputs (entering -1 stopped the loop). I did this using a conversion to string, reading the length to determine if the length was valid, and then reading the string forward and backwards inside of a while loop. (snippet below)
while( digitsEntered != -1)//Allow user to quit by entering -1 to end the loop
{
ostringstream convert;//conversion stream
convert << digitsEntered;//converted text from number goes in the stream
convertedString = convert.str();//store the resulting conversion to convertedString
[Code] ....
The next stage of this program was to do the same thing with strings instead of integers. However, the option to end the loop by entering -1 is still a requirement.
I think the way to do this is to first determining whether the input is a string or an integer, and if it is a string then read it and if it's an integer determine if it's -1. However, whenever I write code to do this, it converts strings to 0 so the string is not stored and cannot be read to determine if it is a palindrome. Is there a way to determine the type of input without converting it into a different type i.e. read string and then keep string or read number and keep number?
Write a program that will prompt a user to enter a single character, the prompting will continue till a sentinel value is entered. For each character entered perform the following tests and print out a relevant message if the character passes the test. Print out a default message if the character does not pass any of the tests.
Tests that should be in program: Punctuation, Upper Case, Digit, White Space.
Sample Run: “A”, “a”, “7”, <tab>, “?”, “$”
So far I have the following code done. The problem is that when I run the program, the first character is correctly identified. However, every character afterwards is defined as a whitespace character.
#include <iostream>
#include <cctype>
#include <cstring>
using namespace std;
int main() {
char input;
char response;
[Code] .....
In a fashion similar to that in Fig. 3.11(shown below), write a short program to determine the smallest number, xmin, used on the computer you will be employing along with this book. Note that your computer will be unable to reliably distinguish between zero and a quantity that is smaller than this number.
fig311.png
I have given following exercise in my cpp book: Determine the roots of quadratic equations
ax^2 + bx + c = 0
using formula
x = -b +(plus-minus) (root)b^2 - 4ac/2a
i don't now how to write such code...
Can I determine if a templated class has a particular constructor, in my case using a string within function to which T is used?
Code:
template<class T>
void MakeObject(std::vector<T>& dataVector)
{
std::string str "con string,Joe,24";
// catch if T has string constructor
T someObject(str); // T someObject should have constructor from string
dataVector.push_back(someObject);
}
I use new to allocate a buffer, as follows:
BYTE *p;
p = new BYTE[20];
...
delete p;
After p is deleted, if I do NOT assign NULL to p, is there a way to determine whether it has already been freed?
When I use my perceptron, it classifies everything appropriately, except it always says points that are exactly on the line are above it.
View 9 Replies View RelatedWrite a program to determine the number of binary palindromes in a given range [a;b]. A binary palindrome is a number whose binary representation is reading the same in either forward or reverse direction (leading zeros not accounted for). Example: the decimal number 5 (binary 101) is palindromic.
View 2 Replies View RelatedWrite a program that determines the day number (1 to 366) in a year for a date that is provided as input data. As an example, January 1st, 1994, is day 1. December 31, 1993, is day 365. December 31, 1996 is day 366, since 1996 is a leap year. A year is a leap year if it is divisible by four, except that any year divisible by 100 is a leap year only if it is divisible by 40. Your program should accept the month, day, and year as integers. Include a function leap that returns 1 if called with a leap year, 0 otherwise. Extend the requested solution so that your program continues to prompt the user for new dates until a negative year is entered. This is what I have so far.
Code:
#include <stdio.h>
#include <stdbool.h>
int main(void) {
int d,m,y;
int days=0;
int k;
[Code] .....
I am unsure how to make this a loop so that it keeps asking for dates?
For part of my program in class I have to take a pointer address and determine if it is equal to 0 modulus 16. But I can't figure it out.
View 1 Replies View RelatedIf input value was shifted to the right on bit level. How can I determine whether a logical or arithmetic shift is performed.
Code:
#include <stdio.h>
#include <stdlib.h>
void main ()
[Code]......
I've pretty much finished the entire program, except for the actual calculation part.
"Given a range of values determine how many integers within that range, including the end points, are multiples of a third value entered by the user. The user should be permitted to enter as many of these third values as desired and your output will be the sum of total multiples found."
I've defined functions to take user input for the low range, high range and a do-while loop to take as many third inputs as the user wants (terminated by entering -1, as requested by the question)
To actually calculate if they're divisible, I found out that if A%B = 0, then they are divisible, so I thought I would create a loop where each value in the range between A and B is checked against the third value to see if they output a zero.
What I need to end up with is a program that tells the user how many integers are divisible by the numbers in the range, i.e: "Enter the low range value: 335 Enter the high range value: 475 Enter a value to check within the range: 17 Enter a value to check within the range: -1 There are 8 total values that are divisible by the numbers in the range." Going back to my original question, how would I create a loop or something to "check" how many values are equal to zero, and consequently increment a variable for each instance? (This is how I think it should be done)
Code:
#include <stdio.h>
//GLOBAL DECLARATIONS
int getlowR();
int gethighR(int);
[Code].....
