C Sharp :: Adding 3 Decimals Places?
Apr 24, 2012i wanted to add 3 decimals places to either string or int.
let say
scenario 1:
a = 8
to
a = 8.000
b = 11.6
to
b= 11.600
c= 34.55
to
c= 34.550
i wanted to add 3 decimals places to either string or int.
let say
scenario 1:
a = 8
to
a = 8.000
b = 11.6
to
b= 11.600
c= 34.55
to
c= 34.550
I have the following code which allows me to add the pdf files if I give the exact name and path of the file. But I have multiple pdf files in a folder which I want to add to each cell in the first column. I am having trouble thinking of the logic to have a for loop for a folder which contains the pdf files.
private void button1_Click(object sender, EventArgs e) {
Excel.Application xlApp;
Excel.Workbook xlWorkBook;
Excel.Worksheet xlWorkSheet;
xlApp = new Excel.ApplicationClass();
xlWorkBook = xlApp.Workbooks.Add(true);
[Code] ...
But this is very very rough draft. I have say 20 files in the folder pdf with different names(Title). How can I add all the 20 pdf files in the excel sheet?
I am getting an error "Unreachable code detected" when I add a switch statement.
My code looks like:
private void calbtn_click(object sender, EventArgs e) {
double regFee;
double lodging;
double days;
string Total {
string course;
[Code] ....
(Everything works functionally until I try to add the switch statement.)
float put;
put = 6/120;
cout << put;
This outputs 0. Why is it so and how can I make it output 6/120 in a more precise way?
I am trying to make the code below display the result with decimals. I tried using setprecision, but I am not too sure where to put it. I placed it in cout section where the answer is but it still doesn't come out correctly.
#include <iostream>
using namespace std;
//*Delcare function prototype*
int ConvertToCentimeters (double, double );
//declare exception class*
class NegativeNumber
[Code] ....
I have written a code but i tried to alter it a little in this manner. But it seemed to not recognise what hexStack.getsize() > 0) is..??
while(hexStack.getSize() > 0)
{
//buffer being a previously declared int
buffer = hexStack.pop();
[Code]....
I have a task to hold a number like 4.0000000000000000199e+30 and, in a variable like long double (the largest of the data type) doesn't hold the whole number, holds only 4.099e+30, like that.
Any way to hold the whole number?
I'm working on a Fraction Class assignment where I'm supposed to provide conversion operators to allow Fraction objects to be used in expressions containing float data values. The way I have it now, I'm getting an error that says operator float(const Fraction &) must contain 'void', which makes no sense to me. Lines 155 - 173.
// Fractions CLASS
// Source: Fraction2012.cpp
// Author: Warren H. Knox, Jr.
// Date: 11/8/2012
#include <iostream>
#include <cstdlib>
using namespace std;
class Fraction {
[Code] ....
input: array[] = {0,1,2,3,4};
output should be {3,4,0,1,2};
I am trying to find out when using float in a calculation how to set the number of decimal places. For example my code below
Code:
#include stdio.h>
int main()
{
float x=123.0;
[Code]....
This returns an answer 8487.0000 I would like it not to show all the decimal places. However if the sum has decimal places I would like to select the number of decimal places shown.
I assume floating point numbers in C++ have a default maximum of 5 decimal places. You can use setprecision() but is this limitless?
So how would find say write a program to calculate Pi to N number of places?
I need the user to be able to input the number of decimal places they wish to have displayed in the output. Everything works fine as is, I just don't know how to allow for the user to input the number of decimal places they want the output to have.
Code:
#include<stdio.h>
#include<math.h>
#define PI 3.141592654
int main(void) {
//Local Declarations
int x; //desired number of decimal places
float radius; //radius of circle
float circumference; //circumference of circle
[Code] .....
I have to create a converter but the results must be in 4 decimal places just like, if i Entered 5000mm the result would be 500.0000cm . what should I do ? I used Float function
View 1 Replies View Relatedhow I can make my output only have 2 decimal places because I want it to be a monetary value. In my code I used this:
cout.setf(ios::fixed);
cout.setf(ios::showpoint);
cout.precision(2);
which worked well at first because on my command prompt screen the numbers had two decimal places and looked liked this:
Premium for Pol1 is $14101.62
Premium for Pol2 is $14221.16
Premium for Pol3 is $582390.50
Premium for Pol4 is $220384.49
However, I also have the program outputting to a textfile called "output.txt" and when I opened this text file the numbers only had one or no decimal places.
Premium for Pol1 is $14101.6
Premium for Pol2 is $14221.2
Premium for Pol3 is $582391
Premium for Pol4 is $220384
How come the code for two decimal places is working for my output to command prompt but not my output to the text file?
Here is my code.
double ratesmn[86] = {
#include "MaleNonSmoker.txt"
- 1
};
[Code].....
So my inventory program runs fine as far as I can tell. Except when entering "Amounts" with more that 1-precision . ie
Amount Entered : 25.99 // Problem
Amount Entered : 25.9 // No Problem
When entering say 25.99, the rest of the file is jibberish. but 25.9, the rest of the file is fine
Code:
#include <stdio.h>
typedef struct toolRecord{
int record_num;
char tool_name[16];
int quantity;
double price;
[Code] .....
So my assignment requires us to write a C program to generate a list of powers of 3 where each output line lists three numbers: k 3k 3‐k
It should look like this (just pretend all the numbers are lined up in their respective columns)
1 0 1.0
3 1 0.333333343
9 2 0.111111112
27 3 0.037037037
81 4 0.012345679
243 5 0.004115226
729 6 0.001371742
2187 7 0.000457247
6561 8 0.000152416
19683 9 0.000050805
This is what I keep getting:
1 0 1.000000000
3 1 0.333333343
9 2 0.111111112
27 3 0.037037037
81 4 0.012345679
243 5 0.004115226
729 6 0.001371742
2187 7 0.000457247
6561 8 0.000152416
19683 9 0.000050805
My input:
Code:
#include <stdio.h>
#include <stdlib.h>
void powers(void) {
int i=0;
int n=9;
int x=1;
float h=1;
[Code] .....
Notice how I'm getting 1.000000000 for my first h value in my output whereas I should be getting 1.0. What am I doing wrong?
event................. red house.............. blue house........... yellow house
Chess ......................12.................... 5....................................8
TableTennis .................. 4.......................... 11.....................17
Basket Ball .................... 6......................... 5......................14
karathe ..........................5........................... 8.........................10
Write a program to input the house name, and the score (as shown in the table) of the sport event obtained by the corresponding house. Then find the total score . You should use nested selection statements.
i) If the user inputs a wrong house name, display the error message "In valid House Name".
ii) Modify the program to handle many data. After calculate and disp ay the total score of the house, the program should display a prompt "Do you need to enter nother house name?".
If the user inputs "y" or "Y", program should ask for the next house name and the scores.
If the user inputs "n" or "N" after entering all three houses, program should terminate by printing the score of the winner.
If the user inputs "n" or "N" and without entering all three houses, program should display an error message "Error in finding the winner" and terminate without printing the ranks.
Note: format the output into two decimal places.
Sample output:
Enter the house name: red house
Enter the score of Chess: 12
Enter the score of Table Tennis:4
Enter the score of Basket Ball:6
Enter the score of karathe 5
Score is: 27 Points
Do you enter another house name? y
Enter the house name: blue house
Enter the score of Chess:5
Enter the score of Table Tennis:ll
Enter the score of Basket Ball:5
Enter the score of karathe 8
Score is: 29 Points
Do you enter another house name? y
Enter the house name: yellow house
Enter the score of Chess:8
Enter the score of Table Tennis: 17
Enter the score of Basket Ball: 14
Enter the score of karathe 10
Score is: 49 Points
Do you enter another house name? n
The winner scored: 49 Points
suppose I want to find the value of e ,e^x or sin(x) or any such function in general ,through their infinite series (maclaurin or taylor) how many iteration should I have to make to get the result correct uptu 'n' decimal places?
View 6 Replies View RelatedI tried to add 2 or more strings together but failed.
eg I would like to add "KK" & "LL" together by adding but it couldn't work.
string string_B = "KK";
string string_C = "LL";
string_A = string_B + string_C;
Every time I run if(color=="1") it's supposed to add 1 to redTotal. However, every time I run if(color=="1") if get 1 for redTotal every time.
(Write a program that provides the option of tallying up the results of a poll with 3 possible values. The first input to the program is the poll question; the next three inputs are the possible answers. The first answer is indicated by 1, the second by 2, the third by 3. The answers are tallied until a 0 is entered. The program should then show the results of the poll—try making a bar graph that shows the results properly scaled to fit on your screen no matter how many results were entered.)
Code:
#include <iostream>
#include <string>
using namespace std;
int main()
[Code]....
I am new to c and I have come across a problem when adding other functions to a programme and printing the values. The question I am attempting to solve is :
The following function computes ex by summing the Taylor series expansion to n terms. Write a program to print a table of ex using both this function and the exp() function from the math.h library, for x = 0 to 1 in steps of 0.1. The program should ask the user what value of n to use.
double taylor(double x, int n) {
int i;
double sum = 1.0;
double term = 1.0;
for (i=1; i<=n; i++) {
/*Or we could have written: */
term = term * x / i; /* term *= x / i; */
sum = sum + term; /* sum += term; */
}
return sum;
}
My code is
Code:
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
/*Taylor series for e*/
[code]....
code prints out the values for exp, but it gets stuck in the Taylor function and I'm not sure how to solve it.
So here is what i need i need a way i can add 3 variables one after the other example:
int a = 1;
int b = 2;
int c = 3;
//Here comes my problem
int d = a + b + c;
When I write it like thet d = 6 ,
but I need it to be 123,
int sum=82;
for(int i; i < sum.length; i++)
{
final=sum[i]+final;
}
I need getting the sum and adding the numbers together. for example 82 would be 8+2. I keep getting an error on this piece of code....
How would one add each value from an array? I'm working from a string but I was wondering if there was a way to loop through the string and add each value. This is what I have so far:
#include <iostream>
#include <cmath>
#include <string>
int main() {
std::string numbers;
int sum;
[Code] ....
I have the following code in sourceFile.cpp. functionA() is first called and inserted entires for key1, key2 and key3. Then functionB() gets called to use the vectors for the 3 keys. I want to free all memory after exiting functionC(). Among the three ways to put an entry into the map for the 3 keys, which is correct / better?
Class ClassA { ... }
ClassA *key1 = new ClassA();
ClassA *key2 = new ClassA();
ClassA *key3 = new ClassA();
[Code]....
Currently in development of a cookie clicker clone (for fun)
I am stuck at the idea of the "Cookies Per Second" thing.
Is there a way to implement a per second adder thing that doesnt actually effect the game play (eg even though the player may not be pressing C every second a cookie (or more) will be added, or if they can press C more than once a second, every second a cookie will be added... If you get what I mean).
Code is below if you would like to look />
MAIN.cpp
#include <iostream>
#include <conio.h>
#include <Windows.h>
#include "Shop.h"
#include "Varis mate.h"
[Code] .....