I have to create a converter but the results must be in 4 decimal places just like, if i Entered 5000mm the result would be 500.0000cm . what should I do ? I used Float function
View 1 RepliesI am trying to find out when using float in a calculation how to set the number of decimal places. For example my code below
Code:
#include stdio.h>
int main()
{
float x=123.0;
[Code]....
This returns an answer 8487.0000 I would like it not to show all the decimal places. However if the sum has decimal places I would like to select the number of decimal places shown.
I need the user to be able to input the number of decimal places they wish to have displayed in the output. Everything works fine as is, I just don't know how to allow for the user to input the number of decimal places they want the output to have.
Code:
#include<stdio.h>
#include<math.h>
#define PI 3.141592654
int main(void) {
//Local Declarations
int x; //desired number of decimal places
float radius; //radius of circle
float circumference; //circumference of circle
[Code] .....
how I can make my output only have 2 decimal places because I want it to be a monetary value. In my code I used this:
cout.setf(ios::fixed);
cout.setf(ios::showpoint);
cout.precision(2);
which worked well at first because on my command prompt screen the numbers had two decimal places and looked liked this:
Premium for Pol1 is $14101.62
Premium for Pol2 is $14221.16
Premium for Pol3 is $582390.50
Premium for Pol4 is $220384.49
However, I also have the program outputting to a textfile called "output.txt" and when I opened this text file the numbers only had one or no decimal places.
Premium for Pol1 is $14101.6
Premium for Pol2 is $14221.2
Premium for Pol3 is $582391
Premium for Pol4 is $220384
How come the code for two decimal places is working for my output to command prompt but not my output to the text file?
Here is my code.
double ratesmn[86] = {
#include "MaleNonSmoker.txt"
- 1
};
[Code].....
So my inventory program runs fine as far as I can tell. Except when entering "Amounts" with more that 1-precision . ie
Amount Entered : 25.99 // Problem
Amount Entered : 25.9 // No Problem
When entering say 25.99, the rest of the file is jibberish. but 25.9, the rest of the file is fine
Code:
#include <stdio.h>
typedef struct toolRecord{
int record_num;
char tool_name[16];
int quantity;
double price;
[Code] .....
So my assignment requires us to write a C program to generate a list of powers of 3 where each output line lists three numbers: k 3k 3‐k
It should look like this (just pretend all the numbers are lined up in their respective columns)
1 0 1.0
3 1 0.333333343
9 2 0.111111112
27 3 0.037037037
81 4 0.012345679
243 5 0.004115226
729 6 0.001371742
2187 7 0.000457247
6561 8 0.000152416
19683 9 0.000050805
This is what I keep getting:
1 0 1.000000000
3 1 0.333333343
9 2 0.111111112
27 3 0.037037037
81 4 0.012345679
243 5 0.004115226
729 6 0.001371742
2187 7 0.000457247
6561 8 0.000152416
19683 9 0.000050805
My input:
Code:
#include <stdio.h>
#include <stdlib.h>
void powers(void) {
int i=0;
int n=9;
int x=1;
float h=1;
[Code] .....
Notice how I'm getting 1.000000000 for my first h value in my output whereas I should be getting 1.0. What am I doing wrong?
I'm trying to make a program that takes up to a seven digit binary number and converts it to its decimal equivalent. I'm still a beginner, so this might be a simple question but how do I stop the user from entering anything but 1s and 0s? This means no decimals or numbers other than 1 or 0.I already made it so it won't accept anything below 0 or above 1111111.
View 1 Replies View Related#include <iostream>
#include <math.h>
using namespace std;
int main() {
int N=0, counter=0, counter1=0,counter2=0, temp=0, temp1=0,dec=0,result=0, moder=0;
[Code] .....
This is Binary to Decimal Converter. It's not working. Although Dry Run of this program works fine.
event................. red house.............. blue house........... yellow house
Chess ......................12.................... 5....................................8
TableTennis .................. 4.......................... 11.....................17
Basket Ball .................... 6......................... 5......................14
karathe ..........................5........................... 8.........................10
Write a program to input the house name, and the score (as shown in the table) of the sport event obtained by the corresponding house. Then find the total score . You should use nested selection statements.
i) If the user inputs a wrong house name, display the error message "In valid House Name".
ii) Modify the program to handle many data. After calculate and disp ay the total score of the house, the program should display a prompt "Do you need to enter nother house name?".
If the user inputs "y" or "Y", program should ask for the next house name and the scores.
If the user inputs "n" or "N" after entering all three houses, program should terminate by printing the score of the winner.
If the user inputs "n" or "N" and without entering all three houses, program should display an error message "Error in finding the winner" and terminate without printing the ranks.
Note: format the output into two decimal places.
Sample output:
Enter the house name: red house
Enter the score of Chess: 12
Enter the score of Table Tennis:4
Enter the score of Basket Ball:6
Enter the score of karathe 5
Score is: 27 Points
Do you enter another house name? y
Enter the house name: blue house
Enter the score of Chess:5
Enter the score of Table Tennis:ll
Enter the score of Basket Ball:5
Enter the score of karathe 8
Score is: 29 Points
Do you enter another house name? y
Enter the house name: yellow house
Enter the score of Chess:8
Enter the score of Table Tennis: 17
Enter the score of Basket Ball: 14
Enter the score of karathe 10
Score is: 49 Points
Do you enter another house name? n
The winner scored: 49 Points
I was trying to program an decimal to binary converter (8-bits) in C. I am a complete beginner so I tried to put the 1's and 0's of the binary number as they come without reversing the order for beginning. I have seen example on the internet but didn't understand them so I decided to write it as I understood it. So, I typed the code as shown below:
Code:
#include <stdio.h>
#include <stdlib.h>
int main() {
int number;
int BitNum[8], x;
[Code] ....
The problem with the code is that if binary form has 0s in it then program displays a random number instead of a 0. For example if decimal is 7, it should print out 11100000 but it displays only 111(and some stupid numbers instead of 0). I have tried to solve it but failed.
Basically I have 2 questions.
1. Because of how limited integers are in terms of storage, the largest binary number i can give seems to be 1 111 111 111. Anything larger breaks the program. Is there any way to increase the largest input I can give without completely rewriting the program? I tried changing the num/numCounter (and the typecasting) to long doubles, but it just messed stuff up (or I did).
2. I'd also like to make it so that if someone inputs a non-binary number my program tells them so and stops. I figured a switch statement within the while loop would work (for when numCounter/divisor is negative or greater than 1), but I was wondering if instead it was possible to use an if statement that could break the while loop?
Anyway, here's the code:
Code:
#include <QtCore/QCoreApplication>
#include <iostream>
#include <cstdlib>
#include <iomanip>
#include <cmath>
using namespace std;
int main(int argc, char *argv[]) {
QCoreApplication a(argc, argv);
[code]....
I'm trying to figure out why the binary to decimal part is not working correctly when the binary value finishes with a 1. In those cases, the decimal value shown in one unit smaller than it should be.
Code:
#include <iostream>
#include <cstdio>
#include <cstdlib>
using namespace std;
void Binary_to_Decimal(), Decimal_to_Binary(); //prototype for the 2 functions that contain the converters
int main() //the menu {
int a_Choice;
cout << "Enter 1 - for binary to decimal" << endl;
cout << "Enter 2 - for decimal to binary" << endl;
[code]....
suppose I want to find the value of e ,e^x or sin(x) or any such function in general ,through their infinite series (maclaurin or taylor) how many iteration should I have to make to get the result correct uptu 'n' decimal places?
View 6 Replies View RelatedThis program compiles, but has a bunch of logical errors. I know my problem is somewhere in the while loop that I have, but I can't figure out where. Here are some of the issues I am experiencing:
1. At the beginning of the program it asks you to enter a number, and when you do it does nothing while proceeding to the while loop where I have it asking the same question
Code:
"Please enter a number between 1 and 20 (Enter 0 to stop)
";
cin >> num;
cout << endl;
I want to be able to eliminate that first statement but if I only run this in the loop without the above statement the program will display nothing on the screen and proceeds to stop.
2. This code runs fine, except that if you make a mistake, it will prompt you to enter a valid number, however; it ignores your first response if the number you enter is valid and asks you to enter a valid number anyway. Once you enter it a second time, it will accept it and the program will continue on.
Code:
while(num != SENTINEL) {
cout << "Please enter a number between 1 and 20 (Enter 0 to stop) ";
cin >> num;
cout << endl;
Also if you type in 0 on your first response, it will prompt you that it is not a valid number and ask you to try again, instead of stopping the program like it is supposed to do. On your second response the program will accept your 0 and stop the program correctly.
//Write a program that displays the roman numeral equivalent of any decimal number between 1 and 20 that the user enters. The roman numerals should be stored in an array of strings and the decimal number that the user enters should be used to locate the array element holding the roman numeral equivalent. The program should have a loop that allows the user to continue entering numbers until an end sentinel of 0 is entered.
Input validation: Do not accept scores less than 0 or greater than 20
#include <iostream>
#include <string>
using namespace std;
int main() {
// Declare constants and variables
const int romanNum = 21; // Size of the elements in the array
[Code] ....
input: array[] = {0,1,2,3,4};
output should be {3,4,0,1,2};
i wanted to add 3 decimals places to either string or int.
let say
scenario 1:
a = 8
to
a = 8.000
b = 11.6
to
b= 11.600
c= 34.55
to
c= 34.550
I assume floating point numbers in C++ have a default maximum of 5 decimal places. You can use setprecision() but is this limitless?
So how would find say write a program to calculate Pi to N number of places?
I know my current program will not compile. How can I store the the start temperature so it can be used again in the final printf statement "start degrees Fahrenheit is converted Celsius."?
Note - I want to use the float data type for precision.
Code:
//THIS PROGRAM WILL CONVERT TEMPERATURES BETWEEN DEGREES FAHRENHEIT AND DEGREES CELSIUS
#include <stdio.h>
int main(void)
[Code].....
I am writing a program that converts arabic numbers into roman numerals.
Quote Write a program that asks the user to enter a number within the range of 1 through 10. Use a switch statement to display the Roman numeral version of that number.
Input Validation: Do not accept a number less than 1 or greater than 10.
Prompts And Output Labels. Use the following prompt for input: "Enter a number (1 - 10): ". The output of the program should be of the form "The Roman numeral version of A is R" where A is the Arabic numeral entered (1,2,3,...) and R is the all-capitals form of a Roman numeral, such as VII.
I wrote this code purely for educational purposes. It also learn more about how exactly things look in memory. code I have right now ( I will likely add more and change it in the future) .....
Code:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <ctype.h>
[Code].....
One of the questions requires writing up a code, that converts Fahrenheit scale to Celsius scale.
The relation between temperature in ◦ C and ◦F is given by the formula:
◦C = 5/9 . ( ◦F - 32 )
Write a program that prints a table (just two columns without any borders) with temperature in ◦F and ◦C for temperatures between 0 and 300 ◦F in steps of 20◦. Compile and run your program. I wanted to approach this problem via arrays and for loops, and I wrote up this
Code:
#include<stdlib.h>
#include<stdio.h>
int main() {
// begin main()
// units
double[] celsius = new double[ 16 ];
double[] fahrenheit = new double[ 16 ];
[Code] ....
Now when I'm trying to compile that, the compailer throws an error which makes absolutely no sense to me.
Code:
fahrenheitCelsius.c: In function ‘main’:
fahrenheitCelsius.c:18:9: error: expected identifier or ‘(’ before ‘[’ token
double[] celsius = new double[ 16 ];
[Code] ....
I wrote a program that converts Binary code to Grey code. It works, but I feel like it's highly inefficient. I've also been trying out Project Euler, but I seem to always turn to using vectors whenever solving a problem.
/* Binary to Grey Code Converter */
#include <iostream>
#include <vector>
using namespace std;
// Global Variables (I'd like to not use them because I've been told it's bad practice)
static int numDigits;
int digit;
vector<int> bin;
[Code] .....
I need to convert a string into a Font object. I'm trying to use the Font Converter but I don't see support for the font Style. I need to save a font to a string and back again using the font name, size and style.
Font font1 = (Font) converter.ConvertFromString("Arial, 12pt");
I am attempting to reconfigure a working code that before used while loops and if statements to convert a numeric score to a letter grade. I now wish to take this same code however I want to change the char convertGrade(int numScore) to simply use a parallel array as a replacement to the if statements.
The array needs to consist of 3 arrays of fixed size 5:
int minScores[SIZE]
int maxScores[SIZE]
char letterGrade[SIZE]
I know the declarations need to go in the function convertGrade but this is the first time I have worked with arrays and I am having trouble trying to figure out how this array will replace my previous if statement.
In order to access the array elements I need to write specifications such as
minScores[i]
maxScores[i]
letterGrade[i]
(where i = 0, 1, 2, 3, or 4)
#include <stdio.h>
#include <stdlib.h>
#define SIZE 5
int getScore(void);
char convertGrade(int numScore);
[Code] .....
I recently wrote a program to convert numbers to binary in c++, Well here it is:
#include <iostream>
void recur(int convert) {
if(convert == 0) //if input is 0 , return nothing. {
return;
}
recur(convert/2); // divide convert by 2, get only a 1 or 0
[Code] ....
I've been doing some practice programming challenges and I am currently making a temperature converter from Imperial to Metric.
My approach was to make it as simple as possible but it must display correctly and use decent I/O manipulations corresponding with how high the counter is.
This is what I have come up with, and everything seems to work fine for a base where I could possibly add more code to include user input, but before I go to that one step further I'd just like to know if the approaches I have taken to using iomanip is OK practice and I haven't done any serious no-nos, as I haven't seen any code from example videos that people make that includes this!
Here's the code:
#include <iostream>
#include <iomanip>
using namespace std;
int main()
[Code] ....
The reason I added the IO manipulators is because I couldn't stand seeing everything not lining up, it looked very sloppy and unprofessional..