I know my current program will not compile. How can I store the the start temperature so it can be used again in the final printf statement "start degrees Fahrenheit is converted Celsius."?
Note - I want to use the float data type for precision.
Code:
//THIS PROGRAM WILL CONVERT TEMPERATURES BETWEEN DEGREES FAHRENHEIT AND DEGREES CELSIUS
#include <stdio.h>
int main(void)
[Code].....
One of the questions requires writing up a code, that converts Fahrenheit scale to Celsius scale.
The relation between temperature in ◦ C and ◦F is given by the formula:
◦C = 5/9 . ( ◦F - 32 )
Write a program that prints a table (just two columns without any borders) with temperature in ◦F and ◦C for temperatures between 0 and 300 ◦F in steps of 20◦. Compile and run your program. I wanted to approach this problem via arrays and for loops, and I wrote up this
Code:
#include<stdlib.h>
#include<stdio.h>
int main() {
// begin main()
// units
double[] celsius = new double[ 16 ];
double[] fahrenheit = new double[ 16 ];
[Code] ....
Now when I'm trying to compile that, the compailer throws an error which makes absolutely no sense to me.
Code:
fahrenheitCelsius.c: In function ‘main’:
fahrenheitCelsius.c:18:9: error: expected identifier or ‘(’ before ‘[’ token
double[] celsius = new double[ 16 ];
[Code] ....
Im trying to write a code that converts Fahrenheit to Celsius and Celsius to Fahrenheit. Im having trouble prompting the user to enter in "f" for Fahrenheit and "c" for Celsius. I am not getting any errors when running the program but the output includes all the cout statements even after I have used :
if (g=='f'|| g=='F') and if (g=='c'|| g=='C')
#include<iostream>
using namespace std;
int main() {
int f_temp;
int c_temp;
int f,c,g; {
cout << "Choose between Fahrenheit and Celsius: " << endl;
[code]....
The program should create two integer variables for the temperature in Celsius and Fahrenheit. Initialize the temperature to 100 degrees Celsius. In a loop, decrement the Celsius value and compute the corresponding temperature in Fahrenheit until the values are the same. But for some reason i either get no output or an out put of -43.
#include <iostream>
using namespace std;
int main() {
int celsius;
int fahrenheit;
fahrenheit = 0;
celsius = 100;
[Code] ....
So here is the program:
//Program to convert from Fahrenheit to Celcius
#include <iostream>
double fahrenToCelsius (double t);
//precondition:
//t is a valid tempreture in Fahrenheit
//postcondition:
//returns equivalent temp. in Celcius
[Code] .....
And here is the problem:
[Linker error] C:UsersOwnerAppDataLocalTempcckex8SZ.o:fahrenToCelsius.cpp: (.text+0x3d): undefined reference to `fahrenToCelsius(double)'
collect2: ld returned 1 exit status
I'm suspecting the program maybe that I saved it wrong? I saved it as fahrentoCelsius.cpp inside the folder "Work" ( I created this folder) which is inside the folder "Dev-cpp".
This C++ question is related to Temperatures and Our task is to : Write a well-documented C program that prints out a table of temperatures in Celsius, from 0 to 100, in steps of 5 degrees, with the equivalent Fahrenheit.
To convert temperatures from Celsius to Fahrenheit use the equation : Temp(F) = Temp(C)*9/5 + 32
Include headings on the columns of figures.
Use the following formatting in your printf to produce a tabulated output:
Printf(“%4.1f %4.1f
”, Cent, Fahr);
This format will print each variable in a fieldwidth of 4 digits, with one place of decimal. The ‘ ’ inserts a tab to space the columns. This is our code, but for some reason its not working.
#include<stdio.h>
void main() {
int Cent=1, Fahr=1;
int Temp;
int F;
int C;
[Code] ....
I am trying to write a unit convertor for converting temperatures Celsius, Kelvin and Fahrenheit.
Code:
if (select_one == 't' || select_one == 'T'){// this one works perfectly...
//This section does not tell you the use of variables.
//The use of variables can be seen as comments in the main program
[Code].....
This part of code will be part of a larger Unit Converter program. Do you think this method of conversion is wise? The error codes are for debugging use only.
I convert all temperatures of all units, whether Celsius, Kelvin or Farhenheit into Celsius and then convert it into the units the user wants.
For example:
Kelvin -----> Celsius ------------------> Farhenheit
(Input) (base of conversion) (desired output unit)
Do you think this type of conversion is okay?
I need to write a program to input 6 temperatures in degrees Fahrenheit and output it in degrees Celsius. I used a for loop but it keeps giving me 0 as the output whenever I enter a temperature...
Code:
#include <stdio.h>
#include <math.h>
int main() {
double farenheit,celsius;
for(int i=0; i<6; i++) {
printf("Enter temperature in degrees farenheit: ");
scanf("%lf",&farenheit);
celsius = (5/9)*(farenheit-32);
printf("Temperature in degrees celsius: %lf ",celsius);
} }
I am using Microsoft Visual C++ 2010 Express.
This is my Algorithm. [URL] ....
#include <iostream>
#include <iomanip>
using namespace std;
//function prototypes
int getFahrenheit();
double calcCelsius(int tempF)
[Code] ....
for some reason it keeps giving me a
Error C2144: syntax error: 'int' should be preceded by ';' on line 16 column 1
Error C2143: syntax error: missing ';' before 'return' on line 34 column 1
IntelliSence: expected a ';' on Line 34 Column 2
I have tried to fix both of these problems and no matter what I do I either get more errors or they wont go away...
I am trying to write a program where i take temperature in Fahrenheit and convert it into centigrade. I keep getting this error "The program '[5980] lab3.exe: Native' has exited with code 0 (0x0)."
My Code is :
#include <iostream>
using namespace std;
int main() {
double fahrenheit, centigrade;
cout << "Enter the temperature in Fahrenheit: ";
cin >> fahrenheit;
centigrade = (5/9)(fahrenheit-32);
cout << "The Temperature in Centigrade is " << centigrade << endl;
return 0;
}
I'm trying to make a program that takes up to a seven digit binary number and converts it to its decimal equivalent. I'm still a beginner, so this might be a simple question but how do I stop the user from entering anything but 1s and 0s? This means no decimals or numbers other than 1 or 0.I already made it so it won't accept anything below 0 or above 1111111.
View 1 Replies View Related#include <iostream>
#include <math.h>
using namespace std;
int main() {
int N=0, counter=0, counter1=0,counter2=0, temp=0, temp1=0,dec=0,result=0, moder=0;
[Code] .....
This is Binary to Decimal Converter. It's not working. Although Dry Run of this program works fine.
I am writing a program that converts arabic numbers into roman numerals.
Quote Write a program that asks the user to enter a number within the range of 1 through 10. Use a switch statement to display the Roman numeral version of that number.
Input Validation: Do not accept a number less than 1 or greater than 10.
Prompts And Output Labels. Use the following prompt for input: "Enter a number (1 - 10): ". The output of the program should be of the form "The Roman numeral version of A is R" where A is the Arabic numeral entered (1,2,3,...) and R is the all-capitals form of a Roman numeral, such as VII.
I wrote this code purely for educational purposes. It also learn more about how exactly things look in memory. code I have right now ( I will likely add more and change it in the future) .....
Code:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <ctype.h>
[Code].....
I was trying to program an decimal to binary converter (8-bits) in C. I am a complete beginner so I tried to put the 1's and 0's of the binary number as they come without reversing the order for beginning. I have seen example on the internet but didn't understand them so I decided to write it as I understood it. So, I typed the code as shown below:
Code:
#include <stdio.h>
#include <stdlib.h>
int main() {
int number;
int BitNum[8], x;
[Code] ....
The problem with the code is that if binary form has 0s in it then program displays a random number instead of a 0. For example if decimal is 7, it should print out 11100000 but it displays only 111(and some stupid numbers instead of 0). I have tried to solve it but failed.
I wrote a program that converts Binary code to Grey code. It works, but I feel like it's highly inefficient. I've also been trying out Project Euler, but I seem to always turn to using vectors whenever solving a problem.
/* Binary to Grey Code Converter */
#include <iostream>
#include <vector>
using namespace std;
// Global Variables (I'd like to not use them because I've been told it's bad practice)
static int numDigits;
int digit;
vector<int> bin;
[Code] .....
I need to convert a string into a Font object. I'm trying to use the Font Converter but I don't see support for the font Style. I need to save a font to a string and back again using the font name, size and style.
Font font1 = (Font) converter.ConvertFromString("Arial, 12pt");
I am attempting to reconfigure a working code that before used while loops and if statements to convert a numeric score to a letter grade. I now wish to take this same code however I want to change the char convertGrade(int numScore) to simply use a parallel array as a replacement to the if statements.
The array needs to consist of 3 arrays of fixed size 5:
int minScores[SIZE]
int maxScores[SIZE]
char letterGrade[SIZE]
I know the declarations need to go in the function convertGrade but this is the first time I have worked with arrays and I am having trouble trying to figure out how this array will replace my previous if statement.
In order to access the array elements I need to write specifications such as
minScores[i]
maxScores[i]
letterGrade[i]
(where i = 0, 1, 2, 3, or 4)
#include <stdio.h>
#include <stdlib.h>
#define SIZE 5
int getScore(void);
char convertGrade(int numScore);
[Code] .....
I recently wrote a program to convert numbers to binary in c++, Well here it is:
#include <iostream>
void recur(int convert) {
if(convert == 0) //if input is 0 , return nothing. {
return;
}
recur(convert/2); // divide convert by 2, get only a 1 or 0
[Code] ....
Basically I have 2 questions.
1. Because of how limited integers are in terms of storage, the largest binary number i can give seems to be 1 111 111 111. Anything larger breaks the program. Is there any way to increase the largest input I can give without completely rewriting the program? I tried changing the num/numCounter (and the typecasting) to long doubles, but it just messed stuff up (or I did).
2. I'd also like to make it so that if someone inputs a non-binary number my program tells them so and stops. I figured a switch statement within the while loop would work (for when numCounter/divisor is negative or greater than 1), but I was wondering if instead it was possible to use an if statement that could break the while loop?
Anyway, here's the code:
Code:
#include <QtCore/QCoreApplication>
#include <iostream>
#include <cstdlib>
#include <iomanip>
#include <cmath>
using namespace std;
int main(int argc, char *argv[]) {
QCoreApplication a(argc, argv);
[code]....
I'm trying to figure out why the binary to decimal part is not working correctly when the binary value finishes with a 1. In those cases, the decimal value shown in one unit smaller than it should be.
Code:
#include <iostream>
#include <cstdio>
#include <cstdlib>
using namespace std;
void Binary_to_Decimal(), Decimal_to_Binary(); //prototype for the 2 functions that contain the converters
int main() //the menu {
int a_Choice;
cout << "Enter 1 - for binary to decimal" << endl;
cout << "Enter 2 - for decimal to binary" << endl;
[code]....
I've been doing some practice programming challenges and I am currently making a temperature converter from Imperial to Metric.
My approach was to make it as simple as possible but it must display correctly and use decent I/O manipulations corresponding with how high the counter is.
This is what I have come up with, and everything seems to work fine for a base where I could possibly add more code to include user input, but before I go to that one step further I'd just like to know if the approaches I have taken to using iomanip is OK practice and I haven't done any serious no-nos, as I haven't seen any code from example videos that people make that includes this!
Here's the code:
#include <iostream>
#include <iomanip>
using namespace std;
int main()
[Code] ....
The reason I added the IO manipulators is because I couldn't stand seeing everything not lining up, it looked very sloppy and unprofessional..
I have to create a converter but the results must be in 4 decimal places just like, if i Entered 5000mm the result would be 500.0000cm . what should I do ? I used Float function
View 1 Replies View RelatedI'm trying to make a simple temperature converter with a menu that lets users pick which conversion to perform. But, it won't seem to print the right conversion. It just prints the same temperature that I inputted.
for example:
#include <iostream>
using namespace std;
//prints the menu
void userMenu(){
cout << "Temperature Calculator" << endl << endl;
[Code] .....
I've been working on making a class that makes turning any variable or object into a byte array and vice-versa, quick with minimal pointer interface.
As well as a function for turning any variable or object into a binary text string.
Code:
#include <iostream>
#include <bitset>
#include <sstream>
// Convert a Variable to a Byte Array
template <class var>
unsigned char* VarToBytes(var &data) {
[code].....
This program compiles, but has a bunch of logical errors. I know my problem is somewhere in the while loop that I have, but I can't figure out where. Here are some of the issues I am experiencing:
1. At the beginning of the program it asks you to enter a number, and when you do it does nothing while proceeding to the while loop where I have it asking the same question
Code:
"Please enter a number between 1 and 20 (Enter 0 to stop)
";
cin >> num;
cout << endl;
I want to be able to eliminate that first statement but if I only run this in the loop without the above statement the program will display nothing on the screen and proceeds to stop.
2. This code runs fine, except that if you make a mistake, it will prompt you to enter a valid number, however; it ignores your first response if the number you enter is valid and asks you to enter a valid number anyway. Once you enter it a second time, it will accept it and the program will continue on.
Code:
while(num != SENTINEL) {
cout << "Please enter a number between 1 and 20 (Enter 0 to stop) ";
cin >> num;
cout << endl;
Also if you type in 0 on your first response, it will prompt you that it is not a valid number and ask you to try again, instead of stopping the program like it is supposed to do. On your second response the program will accept your 0 and stop the program correctly.
//Write a program that displays the roman numeral equivalent of any decimal number between 1 and 20 that the user enters. The roman numerals should be stored in an array of strings and the decimal number that the user enters should be used to locate the array element holding the roman numeral equivalent. The program should have a loop that allows the user to continue entering numbers until an end sentinel of 0 is entered.
Input validation: Do not accept scores less than 0 or greater than 20
#include <iostream>
#include <string>
using namespace std;
int main() {
// Declare constants and variables
const int romanNum = 21; // Size of the elements in the array
[Code] ....