if there is a program which i can use to change the name of a variable in a c program for example if i declare a variable like
Code:
int ch;
printf("%d", ch);
Can i later change the name of the ch variable to lets say "number" the code now becomes
Code:
int number;
printf("%d", number);
How to change an enum type variable to a string type variable?
View 2 Replies View RelatedI'm currently writing a poker game and am trying my best to avoid using global variables. I have a few variables in int main() which i was hoping to use to store the value of each players hand. I then created a function which calculates the value of the hand but cannot get this value back into the main function.
For example:
Code:
#include <iostream>
using namespace std;
void getValue(int value) {
value = 4;
[Code] ....
Is there any way i can get the value of value using this function? If not what can I do?
what compiler that change all variable in one occurrence?
View 5 Replies View RelatedI am stuck at a problem where I have two pointers pointing to the same object, and I need to change an int on one of the pointers but point to the same object.
To be more specific, there is an array of Item objects. A long list of items a player can buy. Then, there is the player's inventory, a vector pointer. Whenever a player buys an item, it sets the pointer to the bought object.
The problem arises when he buys two of the same object. I tried to identify the objects with an ID, but it does nothing, because they are just pointing to the same object, and so I have no way of telling them apart.
This is further complicated by the fact that it is a polymorphic object. So, I can't simply make a new every time I buy an object, without making a hassle. Well, at least I am not familiar with that kind of code just yet.
I'm using const_cast to change the data of the constant variable. but on next while i'm trying to print the value its showing old data stored.
#include <iostream>
using namespace std;
int main() {
const int a = 5;
const_cast<int &>(a) = 6;
cout << "Hello World " << a << endl;
return 0;
}
Output : Hello World 5
why the value is getting changed again.?
is there any variable type(or with another keyword) that we can change it's value in global scope?
View 5 Replies View RelatedI started to learn programming through this site two weeks or so ago. I've got a book with exercices and so on, and one of them involves calculating e within a tolerance given by the user.
The formula for calculating e is the summation of 1+(1/i!), where i -> n.
So, here's the code and I'll explain the problem below:
Code:
#include <stdio.h>
int main()
{
float error;
float terme;
float sumatori = 0;
int cicle_euler = 1;
int factorial;
[Code]...
For some reason, when I set factorial to cicle_factorial, factorial remains 0, which I find puzzling; the program always halts when 1 + sumatori is 2.0 no matter what error is.
This must be a common problem and I suspect it has to do with some distinction between variables inside a loop and variables outside it, but as I lack technical vocabulary I can't seem to find anything on Google.
1. I want to do 2 while at the same moment. Exactly I want one while which is checking the time and it should di something every X second and the other should check something parallel.
2. How i can write the program what i write automaticly into the autorun on every windows pc.
3. Can i change the process-name when the programm started?
4. Can i save my .exe under another name in the autorun
I have a current assignment for C++ involving us to make a program to determine coin change for example if you input the number 127 you would need 2 half dollars 1quarter and 2 pennies I have no way how to program this.
This is my code that doesn't do what i want it to
#include <iostream>
using namespace std;
int main ( ) {
float change;
int half_dollars, quarters, dimes, nickels, pennies; // declare variables
[Code] ....
How do i change color of text in the program more than once . rite now i use the code
system ("color 0c");//makes the color of the text red
cout <<"hey";
system ("color 02") //change color to green;
cout<<"only in green ";
it displays both the lines in green not the first in red and second in green.
the problem and my code is at the bottom, the thing is when i checked out what my change was, it was it was like -14.23 which is werid.
Write a program that determines the change that the user should receive after having paid for their purchase. Your program
prompts the user for the number of items purchased
accepts the number of items purchased
prompts the user for the unit price of each item
accepts the unit price of each item
calculates the total purchase price, including HST
outputs the total purchase price
prompts the user for the cash tendered
accepts the amount of cash tendered
calculates the change owed to the user
outputs the number of loonies in the change
outputs the number of cents in the change
You may assume that the user enters valid amounts and tenders enough cash to cover the total purchase price.
The output from your program looks something like:
Enter the number of items : 4
Enter the unit price : 3.15
Purchase price 12.60
HST (13%) 1.64
Total price 14.24
Cash tendered 20.00
Change loonies 5
Change cents 76
[code]....
Alright so I'm in a computer programming class and I was given the following problem..Write a problem that takes an integer value and multiplies each of the digits together. 4 digit numbers only.
IE; What number do you want to process? 2684
Starting number 2684
End result 384
I know how to start the begging of the program, but i dont understand how to have it to where you can type in all four digits and then it will multiply each number by the other. Also, what are some ways to change the color scheme of the program? I know how it works using CMD, but in Visual C++ its totally different aha.
And for some reason my program pauses (nothing displays, and my cursor changes to the little "loading" cursor thingy) when it hits line 139. That is where I added an additional piece of code that should change the shape of the triangle while the program is running.
#include <Windows.h>
#include <WindowsX.h>
#include <d3d9.h>
#define CUSTOMFVF (D3DFVF_XYZRHW | D3DFVF_DIFFUSE)
[Code].....
My coin/money change code works when there can be an exact change each time, i.e. when the 1 cent option is available. However, when the change options are only $10, $5, $1, 25 cents and 10 cents, it does not give me what I want for instance, I wanted to get change for $237.80, I was expecting to get:
23 10's, one 5, two 1's and 8 dimes. However, the code below is giving me 23 10's, one 5, two 1's and 3 quarters (there is no option left for the 5 remaining cents).how to fix it?
Code:
#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;
void change(double cents, int a[]);
int main() {
double Dollars;
double cents;
[code]...
I have a program that makes change from an amount. It works fine, but the output is the correct output looped over and over. I have tried everything, but it still doesn't work. For example, a amount of 98 should print
3 quarters
2 dimes
0 nickles
3 pennies
but instead it prints
3 quarters
2 dimes
0 nickels
3 pennies
0 quarters
2 dimes
0 nickels
3 pennies
0 quarters
2 dimes
0 nickels
3 pennies
Why it's doing this?
Code:
#include <iostream>
using namespace std;
int coinscount(int& amount, int value) {
int tracker = 0;
int amountdimes = amount;
[Code].....
My motive is to get random variable at every start of program. So it does not show same sequence when it run again and again
Code:
int main(){
srand( time ( NULL ) );
cout<<rand();
}
When i run this program in code::block the following program is opening with error in new tab called TIME.H
Code: /* * time.h
* This file has no copyright assigned and is placed in the Public Domain.
* This file is a part of the mingw-runtime package.
* No warranty is given; refer to the file DISCLAIMER within the package.
*
* Date and time functions and types.
*
*/
[Code] ....
for ex: say i'm declaring two variables under int type and some 3 under char,my output should be lyk this: 2 variables in int and 3 var of type char...(input to the main program is actually another program where these 2 int and 3 char are defined).
View 1 Replies View RelatedThe instructions: A nutritionist who works for a fitness club facilitate members by evaluating their diets.As part of her evaluation, she asks members for the number of fat grams and carbohydrate grams that they consume in a day. Then, she calculates the number of calories that results from the fat using the following formula:
Calories from fat = fat grams x 9
Next, she calculates the number of calories that result from the carbohydrates using the following formula:
Calories from Carbs = Carbs grams x 4
Create an application that will make these calculations
-DO NOT use global variables
-Create two variables in main that will hold the two results
-Pass fat and carbs by value, and the result variables by reference
-Output in main
The key with what you need to pass is this: Pass fat and carbs by value, and the result variables by reference. This is what I have to far but I don't understand how to "pass by value, and results by variable" ....
#include <iostream>
using namespace std;
void grams (int);
void calories ();
int main () {
//Get fat and carb grams
[Code] ....
Program that has the user enter 5 digits then asks the user what they want to know about the 5 digits. My issue is when the program goes to print the value, its a totally ill related number
10 34 8 17 50
program prints out:
2 for smallest
79 for largest
119 for sum
23.80 for average
Code:
#include <stdio.h>#include <stdlib.h>
int main(void)
{
int smallNum, largNum, count=0, sum=0, value, choice;
double avgNum;
printf("Enter 5 integers
");
printf("
");
[Code]...
I have an exam in C programming I'm a little stuck on loops..I have to make a program that multiplies the loop variable by 2 then takes away 1... easy, that was a for loop no problem
for (x=3; x<=65; x=x*2-1)
that should print out 3 5 9 17 33 65 however, my lecturer has given the task for it to reverse, but not to display the number 17 on the way back down using an if statement...however, this time it must be a do while loop... This is what I have so far.
Code:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int x = 129;
}
[code]....
ok to start, windows based program, using pelles c ide
winsock2, using "sample" codes, able to connect, BUT no clue what 1/2 of the codes do, and most of the coding is for nix based systems!
trying to understand, and implement a minimal amount of code to add to a current menu based program!
being able to open connection, wait for input from server, receive input, acknowledge the input, then "act" then return to waiting for new input.
or vice versa, server waiting on client (but then server would have to send all the current status`s to client, so that client could be in real time, prob by sending an array from server to client).
How do you store a variable in memory so that it isn't changed when the program closes? I don't have any experience with this and am just wondering how it is possible. I am creating a program and want it to store your preferences and scores. In a simple program, everything is just reset and I don't want this for my program. How do I store a variable so that it stays the same, but can be changed even when the program is turned off?
View 2 Replies View RelatedWhy is my program outputting zero for the variable pop?
Code:
#include <iostream>
int main(void){
using namespace std;
//capture data
cout << "Enter the world's population: ";
[Code] ....
It's obviously not std::cout, but I'm thinking its the way I'm operating on long?
I am new to C. I've been trying to use C to code some statistical functions originally coded in R. I've encountered an interesting phenomenon. In the function foo1, I declared the array v1v2b using an actual value 1999000. The function runs fine when I call it in R.
Code:
void foo1(double *x, double *y, int *nsamp){
int i, j, k, oper=2, l;
double* v1v2=malloc(sizeof(double)*((*nsamp)*(*nsamp-1)/2 + 1));
outer_pos(x, y, nsamp, &v1v2[0]);
double v1v2b[1999000]; //<-------HERE
for(i=1; i<= 1999000]; i++){
v1v2b[i-1]=1;
} }
However, in foo2, I first create an integer variable called index, and store the value 1999000 in it. I then use it to initialize the same array. When I tried calling this function in R, it either led to a stack overflow error, or completely crashed R.
Code:
void foo2(double *x, double *y, int *nsamp){
int i, j, k, oper=2, l;
double* v1v2=malloc(sizeof(double)*((*nsamp)*(*nsamp-1)/2 + 1));
[Code] .....
What does the order of console output from your program tell you about when the static object is initialized?
#include <iostream>
using namespace std;
//class
class Firstclass {
private:
Firstclass(); //constructor
~Firstclass(); //destructor
[Code] ....
Doesn't it allocate the class static variable to the heap, thus executing its algorithm then destroying it when the program ends - or. What exactly does it tell me? When the static variable is initialized, it takes place first before any of my other functions?