I'm working on a program that prints every even number from 100 to 200. How i would be able to print 10 numbers per line?
Code:
#include <iostream>
using namespace std;
int main()
{
int x;
for (x=100; x<=200; x++)
cout <<x++<< endl;
system("pause");
return 0;
}
i got 2 arrays, how would i print 10 numbers per line, so that would be 5 numbers from each array.
array1[40];
array2[40];
array1 array2// array1 array2// array1 array2 // array1 array2 // array1 array2
array1 array2// array1 array2// array1 array2 // array1 array2 // array1 array2
array1 array2// array1 array2// array1 array2 // array1 array2 // array1 array2
...... and so on
how can i put this in a loop?
and so on but there are 80 elements so i cant go one by one.
I have a vector of structs.
struct myStruct{
string text;
int num;
};
vector<myStruct> foo;
And I am attempting to print the text followed by a space, then the number. Like so:
foobar 5
But when trying to print my vector using
ofstream outputFile;
outputFile.open ("file.txt");
for(int i = 0; i < foo.size(); i++) {
outputFile << foo[x].text << " " << foo[x].num << endl;
}
It prints like
foobar
5
moretext
8
With an extra newline and space. How to get rid of it and print it on the same line.
I have checked that text does not include new line character at the end. Also, it seems to print correctly using cout, but not print correctly to output file...
I need to print all the values in a square 2d array that are above the diagonal line. So if I have this 6x6 array for instance:
{0,0,0,0,0,0},
{1,1,1,1,1,1},
{2,2,2,2,2,2},
{3,3,3,3,3,3},
{4,4,4,4,4,4},
{5,5,5,5,5,5}
I'd have to print the elements in italics. I've tried this:
for (i = 1; i < a.GetLength(0); i++) {
for (j = i-1; j >=0; j--)
Console.Write("{0,-2}", a[i, j]);
Console.WriteLine();
}
with the array mentioned above but for some reason it keeps printing the elements BELOW the line, when I need it to print those above it. I know that for arrays we usually start loops with a value of 0 but seeing as there should be nothing to print at [0,0] I started the loop at 1.
I'm trying to print Chinese/unicode characters to a line printer(EPSON LQ-2090) using the writePrinter method in c++.
ANSI characters print fine, but when I throw the buffer of widechar Chinese characters at it, they come out like garbage/ANSI chars.
while debuging string shows chinese characters but in memory it shows ANSI characters not chinese and these ANSI characters are get printed on printer.
Note that if I change the DocInfo datatype parameter to "TEXT" instead of "RAW" then also the Chinese characters donot print.
Is there a way to get Chinese or unicode characters to print correctly?
how are we able to print out a random number (after using srand() and rand() ) - where you there is an unspecified amount of variables given. So, if the user selects yes to have another number given, how are we able to show the previous numbers and the current one?
View 1 Replies View RelatedThe program is supposed to be printing 21 different numbers that are randomly generated. Why am I getting the same number 21 times? Using dev C++ compiler.
Code:
/*prints random numbers between 1 - 99*/
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
[Code]......
We never really had a thorough discussion yet about if-else statements and while.. but our teacher already gave us a difficult assignment..
We should write a program the accepts a number , n, and displays the first n values of the number series:
the pattern to be print was like this 1 1 2 3 4 5 8 7 16 9 32 11 64 13...
alternating odd and even numbers using while and if-else statements
if you input n, the output will print only until 1 1 2 3 4 5 8 7
I'm currently trying to write a program that takes an integer input from the user and displays that number of square-free numbers. I've gotten most of the program to work, but I encounter an error during the noSquare function that causes it to print incorrectly.
A square-free number is a number that is not evenly divisible by the square of any prime number. It's hard to see the bold in the code area, but it begins after the "//I think below is where the problem is"
#include <iostream>
#include <vector>
using namespace std;
[Code]........
I'm currently trying to write a program that takes an integer input from the user and displays that number of square-free numbers. I've gotten most of the program to work, but I encounter an error during the noSquare function that causes it to print incorrectly. I have bolded the area where I believe the problem is what I am doing wrong.
The problem with the program is that it prints ALL numbers from 1 to the input number instead of just the square-free.
A square-free number is a number that is not evenly divisible by the square of any prime number ....
#include <iostream>
#include <vector>
using namespace std;
bool noSquare (int num); //Function to determine if the number is square-free
vector<int> getPrimes(int num); //Function to get a vector of all primes below num
bool isPrime (int number); //Function to determine if individual numbers are prime
int main()
[Code]...
By the way, the in the middle of the code was me trying to bold a section, not an actual part of the code. I can't seem to find where to edit my original post.
//Finding prime numbers
#include <iostream>
using namespace std;
[Code]....
/*The program currently prints all the prime numbers up to n (For example, if 7 is entered, it prints out: 1, 2, 3, 5, 7. What I want it to do, is print out the first 7 numbers; 1, 2, 3, 5, 7, 11, 13.
I'm trying to add line numbers to a text editor I'm building but not having much luck. I'm trying to find a way around building something massive with a picture box next to my textbox etc. I'm tried adding VS Basic to my references and searching for the linenum_rtf.cs but I can't seem to find it under existing items.
View 4 Replies View RelatedThe problem is with the first "Type and Run," where the code looks like this:
Code:
/* print_it.c--This program prints a listing with line numbers! */
#include <stdlib.h>
#include <stdio.h>
void do_heading(char *filename);
int line = 0, page = 0;
[Code] ....
I am using the gcc compiler in Ubuntu 12.04 LTS and I get the following error:
Code:
print_it.c: In function "main":
print_it.c:36:15: error: "stdprn" undeclared (first use in this function)
print_it.c:36:15: note: each undeclared identifier is reported only once for each function it appears in
print_it.c: In function "do_heading":
print_it.c:49:16: error: "stdprn" undeclared (first use in this function)
I was told that "stdprn" can be recognised by a DOS based compiler and the book says I can try using "stdout" instead. It looks like this now:
Code:
/* print_it.c--This program prints a listing with line numbers! */
#include <stdlib.h>
#include <stdio.h>
void do_heading(char *filename);
int line = 0, page = 0;
[Code] .....
It compiled OK with the gcc compiler but I only get this when I run the program:
Code:
Proper Usage is:
print_it filename.ext
I am not sure whether I should continue looking into this but even when I tried compiling and running it on Windows, the .exe file won't even launch. The other ones do but this first one doesn't.
Questions:
1. What should be done to make this program run?
2. Even though the book says "don't care" if the reader does not understand the items (It's Day 1/Lesson 1), I would still like it to run as I don't want to experience compiling and running problems in the future. Should I even bother doing this section of the book or is it obsolete and should be skipped?
Program to read in 15 numbers and display them as follows //each number on a separate line
Code:
# include <stdio.h>
# define MY_ARRAY 15
int main(){
int i ;
printf("please enter 15 numbers
[Code] ....
Error that i get from compiler:
Error E2062 array1.c 14: Invalid indirection in function main()
Error E2062 array1.c 19: Invalid indirection in function main()
both pointing to the separate "scanf"
I am working on a project for school that has us read in a text file that contains 8 lines of SSN and grades. I am not sure how to go about reading in the lines and differentiate between the SSN and grades in the calculations.
View 1 Replies View RelatedThe program I have is from a tutorial where the user enters two points on a line, and then the program calculates the mid-point and slope.
I want to modify it from it's initial form so that co-ordinates can be input in (x,y) fashion. Right now the user has to enter the x-coordinate, enter a space, and then enter the y-coordinate (lame...)
I saw people using SStream and using that to either write functions to ignore the comma or similar things for converting one file into an array, but not quite what I am trying here.
// program to determine slope of a line
#include <ios>
#include <iostream>
#include <istream>
#include <limits>
using namespace std;
void myflush ( istream& in ) {
[Code] .....
How can a mulitline string be read line by line
ex: str = "PERIOD="week"
DAY="day"
TIME="time"";
I need to write a ANSI program to print out each command line argument on a separate line using a for-loop. also it need to print the name of the executable .so far I have
Code:
#include <stdio.h>
int main(int argc, char **argv) {
int i;
printf("")
[code]....
l need to write a program which writes out its command line arguments in reverse order one per line. The output from the program should look like this:
% a.out Two roads diverged in a yellow wood
wood
yellow
a
in
diverged
roads
Two
I am trying to read a file line by line and then do something with the informations, so my method looks like this:
Code:
void open_file(char *link) {
FILE *file = fopen(link, "r");
if (file == NULL) {
fprintf(stderr, "Could not open file.
");
exit(EXIT_FAILURE);
[Code] ....
1) The first complain of valgrind is at the line where I use fgets and its telling me (invalid write of size x), but I have allocated my line to 56000 and the read line is shorter, why is there a write size error then :S?
2) at the line where I realloc where I try to shrink the space he's telling me: Address .... is 0 bytes inside a block of size 56000, But I know i need only this space so why is there a write over space error :S??
So I'm reading a file line by line and storing it backwards into a list. So if the file has has this format...
1
2
3
4
The code should store each line in a list as such...
4, 3, 2 ,1
Instead the code will store the last variable in all nodes. So the final list will look like this...
4, 4, 4, 4
Here is my code...
struct node *head = NULL;
int i;
while(read(in, &i, sizeof(int)) != 0) {
struct node *temp = malloc(sizeof(*temp));
temp->line = &i;
temp->next = head;
head = temp;
}
I need to read lines from one file and copy them line by line into another file using dynamic memory allocation. It compiles but gives me a seg fault. Why/How?
Code:
int main(){
FILE *fp1;
FILE *fp2;
FILE *i;
fp1=fopen("file1","r");
fp2=fopen("file3","w+");
[Code] ....
There are numbers of lines connected to each other. I've extracted the line start point and end points but i am confused how to compare the end point of one line with the start point of adjoining line.
View 2 Replies View RelatedI was loaded a bmp file in my mfc window and stored rgb data in a file.My image size is 320x240.
Is possible to pick a single point (location) from that bmp image (Not the whole window)?
i like to plot a line graph using the pointed single line data using the stored file data?
here R is X Axis and G & B is Y Axis.
If i have 2D array of data means how can i plot the line graph?
I'm using fgets which will read a single line at a time, but unlike fgets I don't want it to return the new line char ( ) ?I want to be able to use printf to display the lines next to each other.
View 7 Replies View RelatedI have a text file (test.txt) with the following data:
01,05,25,20130728
01,06,25,20130728
01,07,25,20130728
01,08,25,20130728
01,05,25,20130728
01,05,25,20130728
01,05,45,20130728
01,05,65,20130728
01,05,85,20130728
01,05,35,20130728
01,05,25,20130728
01,05,35,20130728
I want to read this to one string called line. So far I have this code:
string line;
ifstream myfile ("/home/Test.txt");
if (myfile.is_open()) {
while (myfile.good()) {
getline (myfile, line);
for (int a = 0; a <= 335; a++) {
cout <<line.at(a);
} }
myfile.close();
}
so far its only printing the first line and then throwing an instance of 'std::out_of_range'