how are we able to print out a random number (after using srand() and rand() ) - where you there is an unspecified amount of variables given. So, if the user selects yes to have another number given, how are we able to show the previous numbers and the current one?
View 1 RepliesI'm working on a program that prints every even number from 100 to 200. How i would be able to print 10 numbers per line?
Code:
#include <iostream>
using namespace std;
int main()
{
int x;
for (x=100; x<=200; x++)
cout <<x++<< endl;
system("pause");
return 0;
}
The program is supposed to be printing 21 different numbers that are randomly generated. Why am I getting the same number 21 times? Using dev C++ compiler.
Code:
/*prints random numbers between 1 - 99*/
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
[Code]......
We never really had a thorough discussion yet about if-else statements and while.. but our teacher already gave us a difficult assignment..
We should write a program the accepts a number , n, and displays the first n values of the number series:
the pattern to be print was like this 1 1 2 3 4 5 8 7 16 9 32 11 64 13...
alternating odd and even numbers using while and if-else statements
if you input n, the output will print only until 1 1 2 3 4 5 8 7
I'm currently trying to write a program that takes an integer input from the user and displays that number of square-free numbers. I've gotten most of the program to work, but I encounter an error during the noSquare function that causes it to print incorrectly.
A square-free number is a number that is not evenly divisible by the square of any prime number. It's hard to see the bold in the code area, but it begins after the "//I think below is where the problem is"
#include <iostream>
#include <vector>
using namespace std;
[Code]........
I'm currently trying to write a program that takes an integer input from the user and displays that number of square-free numbers. I've gotten most of the program to work, but I encounter an error during the noSquare function that causes it to print incorrectly. I have bolded the area where I believe the problem is what I am doing wrong.
The problem with the program is that it prints ALL numbers from 1 to the input number instead of just the square-free.
A square-free number is a number that is not evenly divisible by the square of any prime number ....
#include <iostream>
#include <vector>
using namespace std;
bool noSquare (int num); //Function to determine if the number is square-free
vector<int> getPrimes(int num); //Function to get a vector of all primes below num
bool isPrime (int number); //Function to determine if individual numbers are prime
int main()
[Code]...
By the way, the in the middle of the code was me trying to bold a section, not an actual part of the code. I can't seem to find where to edit my original post.
//Finding prime numbers
#include <iostream>
using namespace std;
[Code]....
/*The program currently prints all the prime numbers up to n (For example, if 7 is entered, it prints out: 1, 2, 3, 5, 7. What I want it to do, is print out the first 7 numbers; 1, 2, 3, 5, 7, 11, 13.
i got 2 arrays, how would i print 10 numbers per line, so that would be 5 numbers from each array.
array1[40];
array2[40];
array1 array2// array1 array2// array1 array2 // array1 array2 // array1 array2
array1 array2// array1 array2// array1 array2 // array1 array2 // array1 array2
array1 array2// array1 array2// array1 array2 // array1 array2 // array1 array2
...... and so on
how can i put this in a loop?
and so on but there are 80 elements so i cant go one by one.
How to do the problem below using loop?
Input numbers until the user types a 0, then output the product of the non 0 numbers: e
E.g., if the user types 2 4 6 0, the program should output 48
User enters sentence "The Smiths have two daughters, three sons, two cats and one dog." (The numbers may change depending on what the user chooses to enter. He told us the range would be from zero to nine.) and we have to convert the written numbers within the sentence into actual decimal numbers and print out the new sentence. Ex. The Smiths have 2 daughters, 3 sons...etc.
I have written the following bit of code which reads the string and finds all the "written numbers" but I am not sure how to proceed from there. I am stuck on how to print out the new sentence with the converted numbers as my professor mentioned something about creating the new string using dynamic memory allocation.
Code:
#include <stdio.h>#include <string.h>
int main () {
char A[100];
int length = 0;
int i;
[Code] .....
Find all the prime numbers between a given pair of numbers. Numbers should be read in from an input file called "numbers.txt" and find all the prime numbers between them. Store the prime numbers in an array, then sort the array from greatest to least. Display the array before and after the sort.
I'm stuck on how to put the prime numbers into an array.
The input file has the numbers 1 & 100.
Here's what I have so far.
#include <iostream>
#include <fstream>
using namespace std;
int main() {
ifstream fin;
fin.open("numbers.txt");
[Code] .....
What the heck is wrong with my logic? I just print a rectangle!!! I have played with thing for ever it seems. I thought the rotating part would be hard but now I find myself stuck.
Code:
#include <istream>
#include "triangle.h"
using namespace std;
void triangle::create_triangle() {
[Code] ....
I need c source that give the url txt file and print the txt file
(get the http://site.com/text.txt) and print the (text.txt) file Content.
I have an array, ary[size+1] and the original values entered and then another value, x, entered. I found the index of x that makes the array nondecreasing order
Code:
void InsertX (int ary[], int size, int x)
{
int i=0;
int j;
int index;
while(ary[i]<x)
[Code]...
But i can't figure out how to print the new array with x in it, using its index
how to print a box using 2d arrrays. i have to create a tetris game which a im stuck at this stage... so far i have tired i can only come out with this..my coding done so far is as follows:
Code:
#include <stdio.h>
#define ROW 15
#define COLUMN 15
void disp_box (char b[ROW][COLUMN])
}
[code]....
I expected this program to print out:
Code: Enter your desired monthly salary: $2000___
Gee! $2000.00 a month is $24000.00 a year. Instead, it printed out:
Code: Enter your desired monthly salary: $2000___
Gee! $2000.00 a month is $24000.00 a year. I don't understand how it got the extra nextline in the middle.
Here is the code:
Code:
#include <stdio.h>
int main(void) {
float salary;
printf("aEnter your desired monthly salary:");
[Code].....
#include <iostream>
#include <string>
using namespace std;
struct studentType {
string name;
double gpa;
[Code] .....
#include <iostream>
using std::cout;
using std::cin;
using std::endl;
using std::ios;
#include "Course.h"
#include <list>
[Code] ....
The program works well, except for the fact when it prints out the list (starting at the for-loop on line 65) each line is the same as the last, like it overwrites itself every time it traverses the while(true) loop.
I have previous threads asking how to make a list of words that were matched up be printed out into a .css or .txt
Is there anyway to make the words being printed out in CMD after debugging/compiling a script printed out in a .txt/.cpp file instead? CMD only has 300 lines. I need the outcome to be printed out elsewhere so more lines can be posted rather than 300.
A simple UNIX shell that supports some built-in commands, external commands, and file redirection.
#include <stdio.h>
#include <stdlib.h>
#include <errno.h>
#include <unistd.h>
[Code]....
I've got this assignment where I have to print every other number from 1 to 10.
so far I've got this.
#include <iostream>
using namespace std;
int main() {
[Code].....
wondering if its really counting from 1 to 10 and only printing every other number.
I am writing a program that takes the Month, Day, and Year inputted from the user and outputs the day of the week (Ex. "February 2, 2014 falls on a Sunday"). I got it to print out the date but I can't figure out how to output the day. Would I be using the ctime function?
#include <iostream>
#include <string>
using namespace std;
[Code].....
Question: How to find a duplicate numbers and numbers found once in array.
View 7 Replies View RelatedI'm working on this program that I have to design a class Numbers that can be used to translate whole numbers to the English description of the number.
Now this is what I got so far:
#include <iostream>
#include <string>
using namespace std;
class Numbers {
private:
int number;
static string ones[];
static string tens[];
[Code] ....
The program seems to work. However its not giving me the right number description,
Example:
Please enter the amount you would like translated into words: 5
six dollars
please enter another number: 10
eleven dollars
please enter another number: 20
thirty dollars
please enter another number: 30
forty dollars
please enter another number: 100
two hundred dollars
please enter another number: 150
two hundred sixty dollars
please enter another number: 500
six hundred dollars
please enter another number: 1000
two thousand dollars
please enter another number:
ignoring negative numbers when I am trying to add up only positive numbers.
SAMPLE:
if (num>=0) {
sum= sum + num;
}
else
how would the else in this case being a negative number not be included in the sum
It only prints out the root in an infinite loop.
Code: void Btree::printTree(Node* tree)
{
tree=root;
if (tree != NULL)
{
std::cout<<" "<< tree->key;
printTree(tree->left);
printTree(tree->right);
}
}