#include <iostream>
using std::cout;
using std::cin;
using std::endl;
using std::ios;
#include "Course.h"
#include <list>
[Code] ....
The program works well, except for the fact when it prints out the list (starting at the for-loop on line 65) each line is the same as the last, like it overwrites itself every time it traverses the while(true) loop.
I am trying to get to print a powerset from my linked list however I am not sure how to go about it. I need to create a void function for it so I know that much.
Any ways this is my code.If you do not know what a powerset is here is an example.
say you have a set {1,2,3}the power set would be the following:{{}, {1}, {2}, {3}, {1,2}, {1,3}, {2,3}, {1,2,3}} another example say you have the power set {1,2,3,4,5} the result should be this:{{}, {1}, {2}, {3}, {4}, {5}, {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3,5}, {4,5}, {1,2,3}, {1,2,4}, {1,2,5}, {1,3,4}, {1,3,5}, {1,4,5}, {2,3,4}, {2,3,5}, {2,4,5}, {3,4,5}, {1,2,3,4}, {1,2,3,5}, {1,2,4,5}, {1,3,4,5}, {2,3,4,5}, {1,2,3,4,5}} #ifndef TEST1_H_INCLUDED #define TEST1_H_INCLUDED class List{
I've got this program that I'm working on. Most of the code is from a video tutorial, but I was editing it to be able to search for an element by name. That's working fine, but suddenly the part of the program that prints out all the elements starts in an infinite loop after I input two elements, and search for one.
I created a linked list, but I wanted to make sure it was storing each word appropriately and going over the text. It compiles and runs, so I know it works. I'm just not sure if it's doing what I want...
Code: #include <stdio.h> #include <stdlib.h> //creating the linked list struct node {
Write a program that creates a forward linked list of at least 20 elements, where each element holds a random integer between 0 and 99. Print the list.
Write the function "returnMiddleList" to find the middle element of the linked list in one pass. Print the integer value of this element and the position of this element (starting at zero) in relation to the head (where the head = 0, the element pointed to by the head = 1, the element pointed to by the previous one = 2, etc).
Split the list in half at the middle element to create two entirely separate* linked lists of near equal size (+/- 1) and print the two lists. Modify the "returnMiddleList" function to accomplish this, returning the head of the second linked list and setting the link of the element pointing to that head to null. Then print the two sums of the integers stored in the elements of both lists.
Sort the two lists from least to greatest and print them out (printing at this step is optional depending on the sort approach taken). Then combine the two lists while sorting them again from least to greatest and print out the new list. (HINT: you can subdivide the lists further and sort them on a scale of one to two element lists before sorting and combining the first two unsorted lists. What is this sort called?)
I have got #1 and #2 working, but #3 and #4 is where the issue is beginning. When I split my link list into two lists and print the individual lists out, my first link list prints out 9 numbers when it should be printing out 10 (the 10th number somehow disappears?), but when I do the sum of the first list right after that, the number that has disappeared gets added in the sum! I do not know why it is disappearing, and this is one issue. Another issue is in the second list, a random "0" gets added to the list and one of the numbers is lost. My last issue is about #4 as the merge algorithm I have used does not seem to work (I am merging the list together while sorting them, but I am not using a recursion sort because we have not learned that yet).
#include <iostream> #include <stdlib.h> #include <time.h> using namespace std; struct nodeType { int data; nodeType *link;
Code: struct _Node { // list node _Genptr _Next; // successor node, or first element if head _Genptr _Prev; // predecessor node, or last element if head _Ty _Myval; // the stored value, unused if head };
The stored value is wasted space for the list head. Is there any advantage to implementing list using the same structure for a list head and node?
// Write a function called insertEntry() to insert a new entry into a linked list.
Have the procedure take as arguments a pointer to the list entry to be inserted (of type struct entry as defined in this chapter), and a pointer to an element in the list after which the new entry is to be inserted.
// The function dveloped in exercise 2 only inserts an element after an existing element in the list, thereby prenting you from inserting a new entry at the front of the list.
(Hint: Think about setting up a special structure to point to the beginning of the list.)
This is a working version of the exercise, but I don't think I'm doing what's asked. I was able to add an element to the beginning of the list using an if statement, not creating a special structure that points to the beginning of the list. How would I go about creating a special structure that points to the beginning of the list to add a new element at the beginning of the list?
I'm trying to display a list of MSMQ messages in a list box based on a drop-down list holding the environment.So i've setup the binding and i know that the list loads but nothing shows up in the list? I should be setting like a display member or something but i'm not entirely sure
What the heck is wrong with my logic? I just print a rectangle!!! I have played with thing for ever it seems. I thought the rotating part would be hard but now I find myself stuck.
I have an array, ary[size+1] and the original values entered and then another value, x, entered. I found the index of x that makes the array nondecreasing order
Code:
void InsertX (int ary[], int size, int x) { int i=0; int j; int index; while(ary[i]<x)
[Code]...
But i can't figure out how to print the new array with x in it, using its index
how to print a box using 2d arrrays. i have to create a tetris game which a im stuck at this stage... so far i have tired i can only come out with this..my coding done so far is as follows:
Code: Enter your desired monthly salary: $2000___ Gee! $2000.00 a month is $24000.00 a year. Instead, it printed out: Code: Enter your desired monthly salary: $2000___
Gee! $2000.00 a month is $24000.00 a year. I don't understand how it got the extra nextline in the middle.
Here is the code:
Code:
#include <stdio.h> int main(void) { float salary; printf("aEnter your desired monthly salary:");
I have previous threads asking how to make a list of words that were matched up be printed out into a .css or .txt
Is there anyway to make the words being printed out in CMD after debugging/compiling a script printed out in a .txt/.cpp file instead? CMD only has 300 lines. I need the outcome to be printed out elsewhere so more lines can be posted rather than 300.
I am writing a program that takes the Month, Day, and Year inputted from the user and outputs the day of the week (Ex. "February 2, 2014 falls on a Sunday"). I got it to print out the date but I can't figure out how to output the day. Would I be using the ctime function?
#include <iostream> #include <string> using namespace std;
So i wouldn't have to retype it again in the loop, i would just call the function. but it seems whatever i try it doesn't display the text. i've tried making a function with no return time like this " Void Pausemenu(); " but that just goes blank.
Code:
#include <iostream> using namespace std; //This function displays different results based on the users input int menu(int menuchoice); int main()
I want to make a program that asks the user for a message and then print out a large graphic of that message. For example, if the user types "he" I want to print out
H..................H EEEEEEEEE H..................H E H..................H E H..................H E HHHHHHHHHH EEEEEEEEE H..................H E H..................H E H..................H E H..................H EEEEEEEEE
(treat the periods as spaces. I only put them there because it wouldn't separate the H's correctly.)
I will loop this to continue until the user types quit.
1. How would I set this up to store the user input characters into an array?
2. How would I print out the stored data in the shape of the word?
Code: char Answer; printf(" To search for a specifc word, type (Y), to use a dictionary file, type (N):
[Code] .....
When I run the program, it gives:
To search for a specific word, type (Y), to use a dictionary file, type (N):
Sorry, the given input is invalid, please try again:
I can then input the number. Typing n,N,y or Y goes to the next part of the program without any problems, but if I type something else, I get:
Sorry, the given input is invalid, please try again:
Sorry, the given input is invalid, please try again:
I've fiddled about with the code for a while now, but nothing I do seems to work. What is causing it to be printed twice, or why the first getchar() is ignored.
I'm trying to make a program that prints a rectangle using "*" asterisks. I am only allowed to use "for loops" and I simply cannot get this to work properly. Here is my code so far...
Code: int main(void) { //RectangleSize represents the area of the rectangle(width*length) int length, width, RectangleSize;
These are the instructions: read a number between 1-26 and build a parallelogram in the size (height&width) of the number entered.
Each row of the parallelogram will be built from each capital letter from 1 to the number read (max 26).for example: by entering the number 3, will be printed:
AAA _BBB __CCC
for the number 4: AAAA _BBBB __CCCC ___DDDD
I am struggling with how to change each char in every different row, how do I print this parallelogram ?
This code i made divided a user input into characters and non character. The problem im having is that if a mixed sentence is created, such as 32B, it will only print the 'char string' and not the 'non char string'. But when the sentence is just non characters like 32 it will print the 'non-char string'. So essentially if a mixed sentences is created both of the strings won't be created or printed.(This is only a function by the way).