C++ :: Intentional Template Redundancy Possible?

I'm writing a class Vector3<T> to represent a threedimensional vector with elements of type T. I am doing this as a practice for C++ operator overloading. Turns out to contain some template lecture as well. :-)

I have typedefed some variants for my class like so:

typedef Vector3<float> Vector3f;
typedef Vector3<double> Vector3d;
typedef Vector3<long double> Vector3ld;

etc.

Now, I can even implicitly go from a Vector3f to a Vector3d using a type cast function template. However, the other way around requires an explicit cast and I am still on non C++11 here, so I write a function for it:

template<typename V> Vector3<V> as() const {
return Vector3<V>(V(this->x), V(this->y), V(this->z));
}

Then I can write this:
Vector3i intVec = Vector3d(3.2, 5.4, 9.5).as<int>();

However, I'd much prefer if I could instead have the call look like this:
Vector3i intVec = Vector3d(3.2, 5.4, 9.5).as<Vector3i>();

Is it possible to do that?