C++ :: Using (this) In Template Header?

Sep 28, 2013

i have 1 class:

from here: [URL]

template <typename Container, typename ValueType, void (Container::*setptr)(ValueType t),ValueType (Container::*getptr)(), int nPropType=3>
class property {

[code]....

(but i did the version 2;))

my question is: can i put these:

void setContainer(Container* cObject) {
m_cObject = cObject;
}

in header template?

i did these:

template <typename Container,Container* cObject, typename ValueType, void (Container::*setptr)(ValueType t),ValueType (Container::*getptr)(), int nPropType=3>
class property {

[Code] .....

how use it:

property <person2,this,string,&person2::setname,&person2::getname> Name;

(person2 is the class name)

errors messages:

"C:UsersJoaquimDocumentsCodeBlocks esteventsmain.cpp|31|error: invalid use of 'this' at top level|"

"C:UsersJoaquimDocumentsCodeBlocks esteventsmain.cpp|31|error: template argument 2 is invalid|"

how can i use the 'this' in template header?

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C++ :: Splitting Template Class To Header H File And Implementation CPP File

Sep 12, 2014

What is the right syntax for implementing the .cpp of a template class?

Consider this LinkedList.h file:
Code: #include<iostream>
#include"Iterator.h"

template <class T>
class LinkedList {

[Code] ....

How should the implementation for the LinkedList constructor, for example, should look like in the LinkedList.cpp file?

I tried this:

Code: #include "LinkedList.h"
template <class T>
LinkedList<T>::LinkedList<T>() {
// constructor
}
LinkedList<T>::~LinkedList<T>() {
// destructor
}

But the compiler wouldn't accept it.

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May 16, 2014

I'm doing a compiler, and I'm using writing everything in headerfiles.

at the moment I have lexer.h, token.h and for this case I need reservedWords.h

reservedWords.h is made up of enums showing the needed words

in token.h I have a function called reservedWords reservedLookup(string str) which returns a reservedWord (enum)

now in lexer.h I have a function called Token* getNextToken() in which I need to make use of the function reservedLookup found in token.h

note that all of them are classes apart from reservedwords as in

class Lexer
{
public: .....
}
class token
{
public .....
}

how I can call that function?

I tried declaring reservedWords reservedLookup (string str) BUT obviously it's directing me as Lexer::reservedLookup and not as Token::reservedLookup

When I tried using Token::reservedLookup it gave me

E:Universitycompilerslexer.h|65|error: cannot declare member function 'Token::reservedLookup' within 'Lexer'|

N.B I use namespace std, that's why I didnot write std::string str

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Dec 5, 2013

I'm trying to implement a simple template array class, but when i came into the operator< i actually have to use a template :

my code is something like :

template<typename _Type, std::size_t _Size>
class array {
public :

[Code] ......

but i am having an error of shadows template param 'class _Type' is it w/ the name conflict between the array template parameter and the function template parameter ?

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Nov 6, 2013

Error1error C2955: 'DoubleLinkedListInterface' : use of class template requires template argument listdoublelinkedlist.h10
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Error3 .cpperror C2244: 'DoubleLinkedList<T>::~DoubleLinkedList' : unable to match function definition to an existing declaration 12

.h

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#include "Node.h"
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[Code]....

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May 27, 2013

I have a generic template class with another template in one of its types. Now I want to specialize one of its methods for a particular (template) class, which leads to a compile error, however.

Here is the example:

#include <stdio.h>
template<typename Type>
class Obj1 {
public:
void ID() { printf("Object 1, size = %zu

[Code] .....

GCC ends with:
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What is wrong with the specialization? Can it even be achieved and how (if so)?

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Nov 2, 2014

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Basically I want the "Channels<3>" to be a type that I can use to specify a Cable with similar to vector<float/int> it would be Cable<Channels<2 or 3>>.

What have I messed up with the syntax?

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#include <vector>
using namespace std;

[Code].....

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Mar 14, 2014

I have a function:

template<class Iterator, class T>
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instead of having to call:

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I also want to be able to generalize the function to handle any of the standard iteratable contains: array, vector, deque, whatever.

I was under the impression I could write:

template<template<class T> class U> a(U<T>& container) {
a(container.begin(), container.end(), g(T()));
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where 'g()' returns an object of the element type. However, the compiler is claiming, no matter how I write a call to the overload, the original template is selected and/or the overload is invalid, depending on the various ways I attempt to write said overload.

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Nov 17, 2013

[URL]

#include <iostream>
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template<typename T>
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[Code] .....

I have tried several variants on this code to no avail. Outer is in a header, along with the extern template statements, and the specializations after main are in their own cpp file. Main is in a different cpp file.

What do have to do to make this work? I cannot bring the definitions of f() into the header, and they will be different for different template parameters. Ideally, I want Test to remain a private member of Outer, though this can change if it's the only option.

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Dec 11, 2014

I have been trying to get a hang on templates. I have the two following functions that that could be consolidated in a single template function:

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center.x = ofGetWidth()/2;
center.y = ofGetHeight()/3;
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[Code] .....

NotesController and FamiliesController have the same parent. The thing that I'm trying to grasp with templates is that is could something like:

template<class TYPE>
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[Code] ....

And then have another template function declaration for all the attractor functions where I pass the same template value as in the first one.

As you can see, I'm calling another functions inside called attractors(_tmp). I know that one way around it could be to get rid of that function and just do all the logic inside of each if statement. Is there any way to pass the same template function parameter within a template function parameter?

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I have a class like this

PHP Code:
template<class X>
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  X m_x;
public:
    X* foo();
    X* bar();
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}; 

I would like to get rid of

PHP Code: template<class X> 

For class level but still use it for members. Like this

PHP Code:
class A {
  X m_x;
public:
    template<class X>
    X* foo();
    template<class X>
    X* bar();
    //others are not related to X
}; 

However, I am still stuck at

PHP Code: X m_x; 

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Let me put it into the code snippet:

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Here you have full control over construction and deconstruction of the object.
*/
template<class T>
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[Code]....

I am getting error at the assertion points when i call to the class as follows:

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Given:

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[Code] .....

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[Code] .....

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1. Write a program the calculates the volume of a sphere.

Use a define to set Pi to 3.14 and a macro for the formula for the sphere.
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In main ask for the radius (R).
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Code:

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[Code].....

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Code:

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[XCode] .....

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Can we put using namespace std; in a header file? Someone told me not to do it, but I don't know why...

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