int a[20],x;
for(x=0; x<20; x++)
{
[Code]....
This should be the output
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: -1
Input: -1
Input: -1
Input: 1
Input: -1
Input: 1
Input: -1
Stop!
I am trying to make sure no floating point numbers can be input at any time in my roulette program. My code is too long to put in one post so I shall piece it out
#include <iostream>
#include <iomanip>
#include <random>
#include <cstdlib>
#include <ctime>
using namespace std;
// structure of arrays to pass to functions
[Code] .....
I am trying to find the max number entered by the user, and it should terminate when a negative number is entered. For my code, it will just end when the user inputs a lower number than the previous. i.e.- 10 20 15 "The highest number is 20" when it should be "10 20 5 40 15 -1" "The highest number is 40". No arrays or do/while loops either.
#include <iostream>
using namespace std;
int Max(int x);
int main() {
int x;
[Code] ....
I am new to c++ programming, and I wrote this program. It runs perfectly but the problem is I want the program to stop If I entered letters other than A,B or C
The code as follows:
#include <cstdlib>
#include <iostream>
#include <cstring>
#include <iomanip>
using namespace std ;
int main() {
// Deceleration Statements
[Code] ....
here's one more thing id like to do to make the input even better able to handle user error, but im not sure if its possible or at least easy. I need the function to return a large positive number. As of right now, it can handle users entering characters, but what if the user enters a negative number? is there a way to check to see if what is coming in is negative before the sign gets lost in conversion to unsigned"ness"?
Code:
unsigned long getNum(char prompt[80])
{
unsigned long darts;
printf("%s", prompt);
while((scanf("%lu", &darts)) != 1)
{
[code]....
Write a program to enter the number till 100 till the user want and at the end it should display the count of positive and negative and zero entered.
View 8 Replies View RelatedA program that asks 10 positive integers and classify them as odd or even positive integer inputs. The algorithm has to trap negative integer inputs. The output will be displayed in two columns. ODD and EVEN.
here's my program code...
#include<iostream>
using namespace std;
main() {
int countA;
for(countA=0;countA<=10;countA++) {
[Code] ....
Program is to add two fractions together like so..
This program adds fractions. ‘Y’ continues, any other key exits program
===================================================
Enter numerator 1 ==> 1
Enter denominator 1 ==> 3
Enter numerator 2 ==> 1
Enter denominator 2 ==> 6
1 1 1
--- + --- = ---
3 6 2
-----------------------------------------------------
Continue? Y or N! ==> n
My question is that i need each input to be a number.
if a character is entered i want it to output something like..
This program adds fractions. ‘Y’ continues, any other key exits program
===================================================
Enter numerator 1 ==> 1
Enter denominator 1 ==> a
You need to enter a number here.
Press any key to continue.
and then clear the part where the letter was entered.
This program adds fractions. ‘Y’ continues, any other key exits program
===================================================
Enter numerator 1 ==> 1
Enter denominator 1 ==>
I am trying to find a way to put a getSmallest function in here so that it will output smallest integer entered. If it is just an arbitrary amount of #'s and I don't know what will be entered I am confused. Both on how to do it and how to link my function to my loop.
Code:
/* Prompts user and gets integer numbers from keyboard, one number at a time. Ends program when 99999 entered. and displays various results.
Written by:
Date: 10/20/14
*/
#include <stdio.h>
#include <stdlib.h>
[Code] .....
Could I take this and just replace all variables a, b, and c with getNumber, where would I link/declare smallest?
Code:
/* ==================== smallest ======================
This function returns the smallest of 3 integers.
Pre given 3 integers
Post the smallest integer returned
*/
int smallest (int a, int b, int c) {
[Code] ......
I need to have a program display an error message if the variable entered isn't an integer but then I want it to cin again. I have this but it doesn't work:
cout << "Enter an Integer: " ;
for (;;) {
cin >> var;
if (!cin) {
[Code] ....
I am not sure how to do what I want and this doesn't work, it just repeats That wasn't an int.. over and over again.
I'm trying to get the user to input their 5 digit zip code but my problem is how can I stop the program after the five characters have been inputted. Also how can I only get numbers to be inputted cause so far letters can be inputted as well.
View 2 Replies View RelatedIt's a tic-tac-toe program. I haven't finished doing everything I need to for the project, I'm just trying to get certain parts working as I go.
Anyway, my problem: The program will print the board and ask the first player which square they want to mark. Then it will print the updated board, print the question for the second player to input their square choice but not actually stop to let the user enter anything. Instead it prints the board again and then prints the question for player one again -- this time stopping to let them type in their choice.
Here's my code:
#include <stdio.h>
// Function prototypes
void printBoard(char board[3][3]);
int main() {
int quit = 0;
// Loop so game continues until player quits
[Code] .....
And it looks like this when I run it, as an example:
-------------
| 1 | 2 | 3 |
-------------
| 4 | 5 | 6 |
-------------
| 7 | 8 | 9 |
-------------
Player 'C' enter a square: 5
-------------
| 1 | 2 | 3 |
-------------
| 4 | C | 6 |
-------------
| 7 | 8 | 9 |
-------------
Player 'U' enter a square:
-------------
| 1 | 2 | 3 |
-------------
| 4 | C | 6 |
-------------
| 7 | 8 | 9 |
-------------
Player 'C' enter a square:
I am studying c and I thought what would be better than using my pi to play with relays and c. I am used to PHP as a scripting lang and don' t do much programming. So I wrote this to use wirepi and ask the user "on or off" they type on or off and it does it. it does work but I know something is wrong when I use strcmp in the if statment I can -10 for a value. Here is the code.....
Code:
#include <stdio.h>
#include <string.h>
main(int argc, const char * argv[]) {
char oo[100];
system("gpio mode 0 out");
printf("Do you want it on or off?
[Code] ....
This is what it outputs at the prompt
Do you want it on or off?
on
on
It is now on!
How can I just get Code: if (oo = on) {} and like so with off.
how to stop outputting data based on a user input. The text file is as follows:
1. a
2. b
3. c
and the code I'm using is as follows:
int main (){
string line;
int search;
cout << "Enter a number from 1-3" << endl;
cin >> search;
search++;
ifstream myfile ("example.txt");
[Code]...
What I want to do is to just output number 1 (the whole line) if the user enters number 1. However, I get an error on the second condition w/c is the "&& line!= search"
I want the numbers to be put into the array until it hits a new line. Maximum number of numbers is 1000. What can I replace that while loop with to stop it from reading further into the input file?
Code:
while (input != '
'){
for(i=0; i<1000; i++)
fscanf(ifp, "%lf", &auctions_prices[i]);
#include <iostream>
#include <iomanip>
using namespace std;
// Function Prototype
void sortArray(int array[], int size);
[Code] ....
This program was made to allow students to enter as many test scores as they want and the program will show them in ascending order and then will calculate the average of all test scores. It works wonderful until you enter a negative test score and then it throws the averaging process off. I can't seem to be able to make the program not accept the negative numbers.
I am making a program that will suggest meal options when choosing specifics contained within, e.g. style, base, main, sauce.
What I would like to know is how to collect the input that has been entered by the user, say you are given 4 lists and each has an option, how could I chain these together in order to cout a suggestion that is in my database?
-------------------------------------------------------------------------------
Example (not my real Q's and A's):
OUTPUT: What meat would you like?
INPUT: "Beef" //<collect this!
OUTPUT: What sauce would you like?
INPUT: "Tomato" //<and this!
OUTPUT: What would you like to have as the main/base?
INPUT: "Pasta" //<and this!
OUTPUT: I can suggest... "Spaghetti Bolognese" //< and return this from the database using the 3 filters
--------------------------------------------------------------------------------
So I have to make a program that allows the user to enter both positive and negative numbers and the program is suppose to calculate the sum of only the positive values while ignoring the negative values. Also it is to be a sentinel-controlled loop with a number ending the set of values.
View 4 Replies View RelatedI have a problem with creating a process and waiting until the main window of the new process was shown. I thought I can wait for it with
WaitForInputIdle(pi.hp,INFINITE);
But when the function returns, the handle of the main window of the new process is not available. If I include also a ::Sleep(), the new window is available. Sleep is a bad solution. How can I do it?
I'm working on a code that needs to loop a switch case back to the beginning after a certain input is entered.
ex) Code:
printf("Select an option);
printf("1. Play game");
printf("2. Status");
printf("3. Exit");
scanf("%i", &userinput);
switch(userinput);
[Code]...
For my program, I want option 2 to display something, then loop back to "select and option" after the user presses enter. How would I write that? Would i use a while? do while?
I am stuck on an exercise where i am supposed to use a loop to take user input and keep a running sum until the user enters a 0. the code i have so far is:
#include <iostream>
int main() {
using namespace std;
int num;
int total = 0;
int x;
[Code] ....
The full text of the error message is: error c2678:binary'>>':no operator found which takes a left-hand operand of type 'std::istream' . and one more thing i was wondering, is there a difference between c++ and visual c++?
Having error . I multiplied 0 by -4 and my result is -0 instead of 0. I tried to change the data type put It won't work. This is my code:
#include <iostream>
int main () {
double b, c;
std::cout<<"b: ";
std::cin>>b;
std::cout<<"c: ";
std::cin>>c;
std::cout<<b*c<<std::endl;
return 0;
}
i wanna put an integer into a string for example:
Code:
string name;
int num=8;
name= "George"
//
I want in the end of George to pas the num variable i ve seen some examples but ive not yet come up with a solution like str.insert();
I have an assignment to do..i have done it..but i need to do one more thing. Things sound like this: user inputs 6 integers program needs to check them if there are integer if not it has to output a message for the user if the input is integer it has to go further and work with the input. I have used this structure :
if ( ! ( cin >> temp ) ) {
cout<<"Input is not integer.This program will end ! "<<endl<<endl<<endl;
system("pause");
return 0;
}
Where I declared temp as being int since i started, the problem is after it gets the last input still waits for an input i will attach the source code if needed.
Code:
Prompt the user to input a string,
and then output the sum of all the digits in the string.
Sample Run 1:
Input -> A111B222C
output -> 9
Sample Run 2:
Input -> ABC123XYZ32100000005555555555zzzzzz
output -> 62
I have a homework that needs to verify if the input of the user is an integer using only loops no if statements Here's the problem:
A program is required that prompts the user for a number. The program will then print a series of asterisks to represent the number. If the user enters a number less than 1, the program stops. For example:
Enter a number: 5
*****
Enter a number: 3
***
Enter a number: 9
*********
Enter a number: 0
All user input must be validated:
- Check for non-numeric input when reading numeric input
- Check that values entered are within the expected range for their purpose, or in range based on the requirements statement
