I'm trying to pass my structure to a function using switch method, so that It will ask for user's name and age then then from the switch method it will call a print function, but my coding is not working.
Printing out a sequence data structure. I am using a PC running Windows 7 with Microsoft Visual Studio 2008. This sequence has a dynamic array which stores a value_type which can be any of the built in data types for C++. Initially the sequence is 30 slots long. When the program starts the user starts at the beginning of the sequence by choosing the "!" option from the menu. The user will then insert a number such as 11 by selecting the "I" option (upper or lower case). Then the user will go to the next position in the sequence by selecting the "+" option then insert 22, then go to the next position and insert 33.
To show that the numbers are actually in the sequence the user goes back to the beginning of the array by selecting "!" and then select "C" to display the current number of 11. Then the user goes to the next position by selecting "+" and then "C" to display 22 and so forth. At this point the member function called current() works just find , but when trying to print the contents of the entire sequence the program displays garbage. Why?
Code: // FILE: sequence_test.cpp // An interactive test program for the new sequence class #include <cctype> // Provides toupper #include <iostream> // Provides cout and cin #include <cstdlib> // Provides EXIT_SUCCESS #include "sequence2.h" // With value_type defined as double using namespace std; using namespace CISP430_A2;
I am making a program where the user enters numbers into an array and then a number,x. The array is sorted, then x is inserted into the appropriate place. I wrote my selection sort
Code:
void Sort(int ary[], int size) { int temp; int smallest; int current; int move; }
[code]....
put it wont print the numbers sorted when I use my print function, just the unsorted numbers.
Code: const MenuData breakfast[NUMOFBREAKFASTITEMS] = { {"Egg Breakfast", "Two eggs with a side of bacon and two slices of toast.", "", "2 Eggs, 2 Toats, 2 Bacons", "", 250.00}, {"Pancake Breakfast", "Three Buttermilk pancakes served with butter and syrup.", "", "Three Pancakes, Butter, Syrup", "", 200.00},
[Code]....
What I'm trying to do is call the printReceipt function in the main, but I'm doing it wrong. Here is my attempt.
I am trying to wright a program that takes student grade data from a command line file, calculates a final grade, and copies the final grades to an output file. So far I have two functions, one that creates a student structure by allocating memory for it and returning its address, and one that should take that address and fill it with data from a line from the input file. My ultimate goal is to use a linked list to connect all the structs, but for now I just want to get the functions working. When I run what I have so far, I get an error C2440 (using visual 2010) that says "cannot convert from 'cStudent *', to 'cStudent', and points to the line where I call my fill function. How should structure pointers be passed?
I am having problems with my function definition of a function that should return a structure value.
This is the error I get compute.cpp(9): error C2146: syntax error : missing ';' before identifier 's_advertisebus'
The error is on the line where I start my function definition typing my function type as a structure. A long time ago in c the keyword struct is used with the structure type like struct s_advertisebus s_readadbus(). I tried it both ways but I got errors.
// struct.h #ifndef STRUCT_H #define STRUCT_H
struct s_advertisebus { int nnumberofads; float fpercentused;
I've been able to write the program completing all requirements except for one... creating a function that accepts a nested structure array. Here's the program:
This works if the function pointer being passed to the event manager is not a member function.
I have two other classes Scene and Object that could potentially use this EventManager to create callback events. Scene and Object are both pure virtual objects. How can I pass a pointer to a member function of the child classes of both Scene and Object? I am fine with just having two separate watchEvent functions for Scene and Object but how do I pass the type of the Object or the type of the Scene? The child classes are unknown as they are being created by someone using this game engine.
For example, if I want to make a player object it would be something like
class PlayerObject : public Object{...};
Now that PlayerObject type has to find its way to PlayerObject::functionToCall(). I think I need templates to do this but, since I never used them before
This is how I intend to use this
class OtherScene : public Scene{ void p_pressed(void){ //pause }
We had to write a "selling program for computers, laptops and tablets", which I did but for the extra credit, we have to have those three points in the application and I have tried but how to do the "extra credit" part, which I really need.
1.) A loop to prompt the user if they would like to place another order
2.) At least one user-defined function
3.) An enumerated data type, array or struct (structure)
I did one of these three, it's a "DO WHILE" loop asking users if they want to make another order, it's right at the beginning of the code.
I'm trying to call a function via a function pointer, and this function pointer is inside a structure. The structure is being referenced via a structure pointer.
Code:
position = hash->(*funcHash)(idNmbr);
The function will return an int, which is what position is a type of. When I compile this code,
I get the error: error: expected identifier before ( token.
Is my syntax wrong? I'm not sure what would be throwing this error.
Finally got to functions. Made a simple one that adds two numbers:
Code: int add(int a, int b){ cout<<"a+b="; return a+b; }
It refuses to give an output unless I use cout.
If I just call the function like so: "add(12, 24);", shouldn't it print out a+b=36? It only prints out "a+b=", unless I use "cout<<" ahead of the call.
My simple question is why does it need cout ahead of the call? Shouldn't "return" do its job and print out the number?
I am just practicing some recursion and I am having trouble with printing out a recursive function in main. Here is what I have:
Code:
// This function adds the squares 4, 5 = 4*4 + 5*5 recursiveley int recursive_sumSquares(int m, int n) { if (m < n) { return m*m + recursive_SumSquares(m+1, n); } else { return m*m;
[Code]...
I am getting an error that says undefined reference to 'recursive_SumSquares'
I'm having trouble with my for loop near the end of the program was able to print everything else.
Sample Output:
*** end of 27610_Arrays04.cpp program ***
City City Points --------------- 1---5----10---15---20 Belvidere ********** Freeport ******** Byron ************ Stillman Valley *************** Rockford *********
*** end of 27610_Arrays04.cpp program ***
Input:
TODO #1: complete the coding of the points array An integer array of 5 numbers: 10, 8, 12, 15, 9
TODO #2: complete the coding of the cities string array An string of 5 city names intialized to: "Belvidere", "Freeport", "Byron", "Stillman Valley", "Rockford"
Compile-time arrays with initialization lists.
Processing & Output:
TODO #3: complete the coding of the call to the printStars() function
TODO #4: code the printStars() function
#include <iostream> #include <iomanip> #include <string> using namespace std; int main(void) { /* declarations ------------------------------------------------*/
C programming, make it use a function call to print the smallest number? this is a program which prints out the smallest of three numbers within the main function that I was asked to write.Now the other question i am asked,5. Re-write the program, uses a function call to print the smallest number?
Code:
# include <stdio.h>
main() { int a,b,c; int temp, min; a = 100; b = 23; c = 5; }