C :: Find The Least Amount Of Coins Required To Make A Value

Mar 8, 2014

Write a program in C that will allow a user to enter an amount of money, then display the least number of coins and the value of each coin required to make up that amount. The twist to this program is the introduction of a new coin - the jonnie (value = $1.26). Therefore, the coins available for your calculations are: Twonies, Loonies, Jonnies, Quarters, Dimes, Nickels and Pennies. You can assume the amount of money user enters will be less than $100.00.

User enters $4.53. Your output should be:

The least number of coins required to make up $4.53 is 4. The coins needed are:

1 Toonie $2.00
2 Jonnies $2.52
1 Penny $0.01
$4.53

I'm wondering if i'm close. I'm stuck on what to do for the output. This is what i have so far.

Code:
//Start
#include <stdio.h>
int main() {
//Get user input for amount of money

//Input
int i;
//Store input from user

[Code] .....

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javascript:tx('
#include <iostream>
using namespace std;
//******************************************
//CLASS COMPARATOR
//******************************************

class comparator {
public:
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[Code] .....

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Code:
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Code:
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[Code] .....

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