I actually am wanting to practice on a 2 dimension char array. so, I am using the below program and getting the error - Lvalue Required For Function Main
#include <stdio.h>
#include <conio.h>
#include <string.h>
char varStringArray[1][5];
int main(void) {
clrscr();
varStringArray[0] = 'a';
printf("%c", varStringArray[0]);
return 0;
}
The issue arises with case 3 where it tells produces an error when I attempt to compile and says "lvalue required for left operand of assignment error". How to fix this so that I can properly run the program.
View 5 Replies View RelatedI get the following error:
pointers_array.c: In function ‘readlines’:
pointers_array.c:42:37: error: lvalue required as left operand of assignment
I know what the error is saying but what it is giving it with this code:
/* readlines: read input lines */
int readlines(char *lineptr[], int maxlines) {
int len, nlines;
char *p, line[MAXLEN];
nlines = 0;
[Code] ....
I got above error in my program. My program is socket program. I am using ubuntu 11.10.
#include <netdb.h>
#include <netinet/in.h>
#include <string.h>
#include <cstdlib>
#include <iostream>
#include <stdio.h>
#define PORT 4547
/*int parseARGS(char **args, char *line) {
[Code] ....
i want to modify value of whole array by passing it to a function and make each value of array multiplied by 3 ,return the value to main and print it using pointer.
error : invalid Lvalue is the error
Code:
#include<stdio.h>
main()
{
int i,arr[10];
for (i=0;i<=9;i++)
{
printf("Enter value of arr[%d] : ",i);
scanf("%d",&arr[i]);
[Code] ....
Ok so I am working on a game and I'm in the process of developing my Player class. Anyways, what I have is a keyboard function that is called in my main function to make a shape move.
void myKeyboardFunction(unsigned char key, int x, int y) {
switch ( key ) {
[Code].....
But when I try to call it, trying to copy my previous method,
glutKeyboardFunc(Player1.playerControls);
I get an error
error C3867: 'Player::playerControls': function call missing argument list; use '&Player::playerControls' to create a pointer to member
I get an error saying it can't convert parameters. I would just like to understand why the arguments become a problem when I make the function a member of my class, when the first method I used is so easy.
The function is supposed to return value from the file in my main, but I am getting empty value. I am trying to get better with pointer. Right now just teaching myself.
right now the only way for this code to show value is when in put the putchar(*ps) inside my readfile function. I would like to readfile to return value and print in the main function.
Code:
#include <stdio.h>
char *readfile(char filename[]);
int main(int argc, char *argv[] ) {
[Code].....
I am writing a program in which a Fucntion has to be wriiten to parse the Command Line . When I include Code for parsing in main fuction iteslf ,its run ok . But I want to make a fucntion of that code and call it from main ,than it show Segmentation error .
By using Debugging I found Some thing is mess with " -m" Parameter of Command line , But Cant Rectify it ..
Code:
int main (int argc, char *argv[]){
//get_parameter_value(argc,argv);
// buffer[packet_size+1]= char ("'");
while (argc > 1) {
if (argv[h][0] == '-')
[Code] .....
int example (int [], int, *int,*int,*int,*int);
int main () {
My code will be here
example (int array[], int size, &a,&b,&c,&d); // Like this??? I try it didnt work
[Code] ....
Trying to understand the lvalue and rvalue references, and come up with some strange codes, which compile and run, but is confusing to understand.
Define this class Thing:
class Thing {
public:
Thing(int k = 0): i(k) {};
~Thing() { std::cout << "destroying Thing (i=" << i << ")" << std::endl; }
int getValue() const { return i; };
Thing &getMe() { return *this; };
private:
int i;
};
and a non-member function:
Thing construct_Thing10() {
Thing t(10);
return t;
}
Then these two lines in main():
Thing &thg=construct_Thing10().getMe();
std::cout << "member=" << thg.getValue() << std::endl;
The output is:
destroying Thing (i=10)
member=10
My understanding is that the rhs of line 1 construct only a temporary object. getMe() then return the reference of this temp object and bind it to thg (as a lvalue reference). After line one, the temp object is really destroyed (hence the first output line). At this point thg is really binding to a destroyed, invalid object. But somehow the 2nd line still prints the correct value of 10 is because the memory storage is not yet corrupted (still holding the previous value). Is this correct?
While executing this code i was getting a error Invalid lvalue in assignment. Can any one tell how to correct this.
dataItem* d=(dataItam*)malloc(10*sizeof(dataItem));
dataItem* temp;
temp=(d+6);
(d+6)=(d+8);//error line
(d+8)=temp;//error line
Why the value does not return; Here is code
#include <iostream>
#include <string>
#include <ctime> // to use the time function
#include <cstdlib>
using namespace std;
int getUserChoose (int);
[Code] ....
here is the output
Welcome to the program of Rock, Paper, Scissors
The computer is ready to play the game
Are you ready to play the game
Y for yes and N for no
Y
R = Rock; P = Paper; S = Scissors
R
You have choose Rock
1TN
1RM
0U
0C
If so what is the reason, and the returning int value indicates wat?
View 4 Replies View RelatedI am getting call of nonfunction in function main <> error and 's' is assigned a value that is never used in the function warning...
#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;
int main() {
float a,b,c,s,area;
[Code] ....
I'm currently writing a poker game and am trying my best to avoid using global variables. I have a few variables in int main() which i was hoping to use to store the value of each players hand. I then created a function which calculates the value of the hand but cannot get this value back into the main function.
For example:
Code:
#include <iostream>
using namespace std;
void getValue(int value) {
value = 4;
[Code] ....
Is there any way i can get the value of value using this function? If not what can I do?
i would like to know if i need to dynamically allocate a string in main before passing it to a function that i have created.
in that function i just read the string and do not change any chat in it.
This code is for a program that allows you to play a guessing game or arithmetic game and shows your total score from both as you go along. The program works fine the only problem I'm having is with the score. Is there a way to call the score value from the outside function into main?
Code:
#include <stdio.h>
#include <time.h>
#include <stdlib.h>
//prototype functions
void menu();
[Code] .....
So trying to pass the value of score from the outer function int guessGame() into the score print statement in choice 3 of the main function? Oh and the "17 -turn_count" was just part of the requirements of the assignment.
I am just practicing some recursion and I am having trouble with printing out a recursive function in main. Here is what I have:
Code:
// This function adds the squares 4, 5 = 4*4 + 5*5 recursiveley
int recursive_sumSquares(int m, int n) {
if (m < n) {
return m*m + recursive_SumSquares(m+1, n);
}
else {
return m*m;
[Code]...
I am getting an error that says undefined reference to 'recursive_SumSquares'
I have i want to call a function with two results for example x = 1 and y = 2.How do i return this function in c and how do i call such a function in the main program.
View 9 Replies View RelatedI know how to define a shape and attach it to a window as follows:
#include <Simple_window.h>
void cir() { Circle c(Point(100,100),50); }
int main() {
Simple_window win(Point(100,100),600,400, "test");
Rectangle r(Point(100,100),Point(300,200));
win.attach(r);
win.wait_for_botton();
}
But how to define a shape (say a circle by that cir() function which is) outside of the main() function? And how to attach it to be visible on window win?
I don't exactly know how to test my ==friend function in my main.
Here is my .h file:
#include<iostream>
using namespace std;
class Car{
public:
Car();
Car(int yer, string mke);
[Code] ....
Get user input should be done in a function. The function should read the product number, price per unit, and quantity sold and return them to the main().
Display the value of product number, price per unit and quantyty sold in main().
I have simple LCd_call function . I am calling this function from main . I wanted to call this function once. problem i am facing here, When lcd_call function being called. It enter the cases but instead of staying paricular case it coming back and starting case 1 iteslf . for every 6s it change the case to 1:
View 2 Replies View RelatedI know how to define a shape (here, a rectangle) and attach it to a window in C++ as follows:
#include <Simple_window.h>
void cir() { Circle c(Point(100,100),50); }
int main() {
Simple_window win(Point(100,100),600,400, "test");
Rectangle r(Point(100,100),Point(300,200));
win.attach(r);
win.wait_for_botton();
}
But how to define a shape (say a circle by that cir() function which is) outside of the main() function? And how to attach it on the window win to be visible?
i wrote a program on implementation of stacks using functions (data structures )...but i got expression syntax error in function main.....
View 2 Replies View RelatedI'm trying to return a string to then call it on main function.
Code:
const char* coiso(int chave){
char str [50];
sprintf(str,"%d",chave);
char txt[50] = ".txt";
strcat(str,txt);
return str;
}
int main () {
const char* info = coiso(8);
printf("%s",info);
}
If I do a printf("%s",str) in coiso function it works but the following code doesn't work.