I have a difficulty with string methods for some reason. I tried solving a question from my book, which requires me to capitalize the first letter of every word in a string. I kept trying for maybe two hours yesterday, re-reading the string chapter to see if I'm forgetting a certain method or if something similar was discussed in the examples but I didn't find anything. I also googled it, and found a few answers, none of which I understood. They mostly had keywords or methods I wasn't familiar with. Anyway, here's where I am so far.
class Program { static string UpperCase(string s) { int place; string b, st1, st2,st3; char letter; for (int i = 0; i <= s.Length - 1; i++) { if (i == 0) {
[Code]....
The code compiles without any errors, but when I enter a string it capitalizes correctly for the first two words and then it starts capitalizing letters in the middle of the words.
Write a program that inputs a string and then converts each 1st letter of a word in the string into capital case. An example run of the program is shown below:
Enter string: introduction to programming Output string: Introduction To Programming
I need to reverse a word . For instance "Hello" after reversing will be "olleh" . It reverse first and last letter but its not reversing the rest of them
char arr[]="Hello"; int first=0; int last=sizeof(arr-1); int mid=sizeof(arr)/2;
I need to write a C program to make the user input some text,and the first letter of each word has to be uppercase.(have to use while loops)So for example lets say the user inputs:
i lOvE pRoGrAmMiNg The output needs to be: I Love Programming
Code:
#include <stdio.h> int main() { int i = 0; char c, lower_c;
printf("Enter text ");
[code]....
I have started this code by making the letters lowercase.I am not sure how proceed after this step, the step of making the first letter uppercase.
In C how can I initialize a variable that is not a letter or number? For example with a number I can :
Code:
int i = 5; for ( i = 0; i <=5; i++ ); printf( "%d", i ) This would display a row of 5's
but what if I wanted to display a row of -----? What I am trying to do is read in a simple txt file, around the file I want ----1----2-----3 ect ect on the top ----a----b-----c down the side Then I want to be able to change the file at lets say position c2 and save it. This is the early stages of my attempt to set up a editable table.
For example if I have typed 0xFF (a literal hex number that represents the value 255 for Unsigned Char or -1 for Signed Char) in part of my program. That 0xFF is treated as a Char not an Int, because the value is within the range supported by Char, the C compiler always tries to use the smallest datatype possible for the number that is needed for a literal value like this.
Unfortunately because Signed Char is the default Char type, 0xFF is translated into -1. I am wanting to use it to represent 255. So I'm trying to tell the compiler that 0xFF should be interpreted as either an Int or an Unsigned Char. How do I do this?
I already tried typing it with the magic letter "I", like this: 0xFFI
But that didn't work. What is the correct way to do this?
I am working on Euler Project exercise number 17. Here is the problem from the website.
"If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used?"
So I have to write a program to calculate a grade letter into a number.
Letter grades are A, B, C, D, and F, possibly followed by + or –. Their numeric values are 4, 3, 2, 1, and 0. There is no F+ or F–. A + increases the numeric value by 0.3, a – decreases it by 0.3. If the letter grade is illegal (such as "Z"), then your output should be "INVALID LETTER GRADE"; If the combination is illegal (such as "A+" or "F-") then your output should be "INVALID GRADE COMBINATION"
Also the code should look like this Enter your letter grade: C+ Grade value is [2.3]
// Input cout << "Enter your letter grade: "; string s; cin >> s;
string eg("azertyFTW"); if(eg[one of the letters contained in this string] == 'c') { cout << "eg has the letter c in it"; } else { cout << "not this time :("; }
Dont know how to replace each letter as s number ... this is the question i was given ...
In cryptarithmetic puzzles, mathematical equations are written using letters. Each letter can be a digit from 0 to 9, but no two letters can be the same. Here is a sample problem:
SEND + MORE = MONEY
A solution to the puzzle is S = 9, R = 8, O = 0, M = 1, Y = 2, E = 5, N = 6, D = 7.
Write a program that finds a solution to the cryptarithmetic puzzle of the following:
TOO + TOO + TOO + TOO = GOOD
The simplest technique is to use a nested loop for each unique letter (in this case T, O, G, D). The loops would systematically assign the digits from 0 to 9 to each letter. For example, it might first try T=0,O=0,G=0,D=0, thenT=0,O=0, G = 0, D = 1, then T = 0, O = 0, G = 0, D = 2, etc., up to T = 9, O = 9, G = 9, D = 9. In the loop body, test that each variable is unique and that the equation is satisfied. Output the values for the letters that satisfy the equation.
I am trying to fill an array with blank spaces and instead i get the number 32 over and over, i think this is the ANSI code for that character. how do i get the character itself?
I have a string - a whole sentence that I want to assign a number to each letter, space, comma and period etc. So all "A's" will have the same number, all "B's" will have another number etc. I don't want to use the ASCII numbers because they all need to be sequential and some of the punctuation isn't. I have put the string into a char array to separate each character out and was thinking about running it through a loop with if statements for each letter and assigning numbers there and then saving the numbers in the order they appear into a list as a string but I keep coming up with errors so I don't know how to do it or if there is a better way to accomplish what I'm trying to do.
I've created this code that differentiates between various uses of banks like for example if the user enters he went to bank to deposit money and then went to the river bank.The output will be finance river.
I'm havin trouble outputing different false statements in a boolean function... I'm currently working on a "secret number game" program which must generate a secret number and inform the user if his/her guess number is to high, to low or correct. I know boolean return true and false.. If the number is correct, the true statement will appear, if false... THAT'S where my problem starts cause now I have TWO statements to output..In a Function.. How do I make my program able to tell if the number guessed is "too high" or "too low" ?
I need a code that will search through string 1 and find the first place with a letter that also appears in string 2 and return the pointer of that place. This is what I wrote:
char strPbrk(const char *s1, const char *s2) { char p = *s1; for (int i = 0; i < strlen(s1); i++) for (int j = 0; j < strlen(s2); j++) if ((p+i) == *(s2+j)) return p; return NULL; }
but it continues to return wrong values idk what I'm doing wrong.
Any way to do it...its only works with the first letter. So i have a txt file with information such as de3 dn5 dn7 dw9 ds1 and how to get the letters and then the number.
example:
if de print this is de; and print the number that follow de
Code:
#include <stdlib.h> int main () { FILE * pFile; int c; pFile=fopen ("de3.txt","r"); if (pFile==NULL) perror ("Error opening file"); else
I'm working my way through some C exercises to get some practice and have hit a wall. I need to use a function to take a number, such as 1, and print out One.Here's what I've got so far:
Code: #include <stdio.h> int name(int n); char numberOne[] = "One"; int main(void) { int n; }
[code]...
However, when I run the code and enter "1" the only thing that gets printed to the screen is "(lldb)". I've tried changing it to doing it without variables and just printing "One" but that gave the exact same result.
1. Create a variable named index and nitialize it to zero(0) 2. Prompt for and input a string value from thekeyboard. Store the string inthe string variable newstring[80]. 3. While (newstring[index] does not equal ‘ ’).
i. Display the character at newstring[index] followed by a NL ii. Increment index ====================================== ...
And this is what i have done so far and i dont know where I am wrong ...
Code: #include<stdio.h> int main() { int index = 0; //initialize index to zero since first elementin an array is numbered zero char newstring[80];