C :: Magic Letter For Making A Constant Number Be Int?
Sep 26, 2014
For example if I have typed 0xFF (a literal hex number that represents the value 255 for Unsigned Char or -1 for Signed Char) in part of my program. That 0xFF is treated as a Char not an Int, because the value is within the range supported by Char, the C compiler always tries to use the smallest datatype possible for the number that is needed for a literal value like this.
Unfortunately because Signed Char is the default Char type, 0xFF is translated into -1. I am wanting to use it to represent 255. So I'm trying to tell the compiler that 0xFF should be interpreted as either an Int or an Unsigned Char. How do I do this?
I already tried typing it with the magic letter "I", like this: 0xFFI
But that didn't work. What is the correct way to do this?
The code gives me seemingly logical integer values for size, width and height. But how would I find the max color value and so called "magic number" for this PPM image file?
In C how can I initialize a variable that is not a letter or number? For example with a number I can :
Code:
int i = 5; for ( i = 0; i <=5; i++ ); printf( "%d", i ) This would display a row of 5's
but what if I wanted to display a row of -----? What I am trying to do is read in a simple txt file, around the file I want ----1----2-----3 ect ect on the top ----a----b-----c down the side Then I want to be able to change the file at lets say position c2 and save it. This is the early stages of my attempt to set up a editable table.
I am working on Euler Project exercise number 17. Here is the problem from the website.
"If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used?"
So I have to write a program to calculate a grade letter into a number.
Letter grades are A, B, C, D, and F, possibly followed by + or –. Their numeric values are 4, 3, 2, 1, and 0. There is no F+ or F–. A + increases the numeric value by 0.3, a – decreases it by 0.3. If the letter grade is illegal (such as "Z"), then your output should be "INVALID LETTER GRADE"; If the combination is illegal (such as "A+" or "F-") then your output should be "INVALID GRADE COMBINATION"
Also the code should look like this Enter your letter grade: C+ Grade value is [2.3]
// Input cout << "Enter your letter grade: "; string s; cin >> s;
Dont know how to replace each letter as s number ... this is the question i was given ...
In cryptarithmetic puzzles, mathematical equations are written using letters. Each letter can be a digit from 0 to 9, but no two letters can be the same. Here is a sample problem:
SEND + MORE = MONEY
A solution to the puzzle is S = 9, R = 8, O = 0, M = 1, Y = 2, E = 5, N = 6, D = 7.
Write a program that finds a solution to the cryptarithmetic puzzle of the following:
TOO + TOO + TOO + TOO = GOOD
The simplest technique is to use a nested loop for each unique letter (in this case T, O, G, D). The loops would systematically assign the digits from 0 to 9 to each letter. For example, it might first try T=0,O=0,G=0,D=0, thenT=0,O=0, G = 0, D = 1, then T = 0, O = 0, G = 0, D = 2, etc., up to T = 9, O = 9, G = 9, D = 9. In the loop body, test that each variable is unique and that the equation is satisfied. Output the values for the letters that satisfy the equation.
I am trying to fill an array with blank spaces and instead i get the number 32 over and over, i think this is the ANSI code for that character. how do i get the character itself?
I have a string - a whole sentence that I want to assign a number to each letter, space, comma and period etc. So all "A's" will have the same number, all "B's" will have another number etc. I don't want to use the ASCII numbers because they all need to be sequential and some of the punctuation isn't. I have put the string into a char array to separate each character out and was thinking about running it through a loop with if statements for each letter and assigning numbers there and then saving the numbers in the order they appear into a list as a string but I keep coming up with errors so I don't know how to do it or if there is a better way to accomplish what I'm trying to do.
I'm trying to understand why this won't work, the output i get is a list of even numbers. I'm trying to get all prime numbers below the number thats scanned in.
#include <stdio.h> int isPrime(int number); int main(){
I am writing a game that is 2 to 4 players. i am wondering how to ask how many players, and make the score stay with each player. it is a rip off of zombie dice, this is what i have so far the playerScore array is to hold the score for each player and the turn array is hold hold the values that they rolled that turn, i also dont know how to clear out the turn array when it goes to the next player.
#include <iostream> #include <cstdlib> #include <cmath> #include <ctime> using namespace std; int main() { int playerScore[4];
My university assignment requires us to create a magic square. The definition of which can be found on Wikipedia and such, but essentially it's a (n) times (n) grid where all the row, column and diagonal totals meet the formula [n(n2 + 1)]/2. So a 3x3 would provide totals of 15 for example.
It's been requested that we use brute force for this, nothing mathematically fancy. I've succeeded in the task and initially during testing was coming up with a result of a 3x3 magic square after between 10 million and 1 billion attempts over a few minutes to nearly an hour.
I proceeded to refine my code and have as little as possible in the while loop which I'd break out of once the function had found a magic square, nothing really made much difference until I moved the declaration of my random to just before my while loop instead of within.
Random RanGenerator = new Random();
Once I'd done this I was getting 3x3 magic squares after a few thousand iterations in less than a second, which has completely baffled me. I can understand if it would save time, but how could that reduce the amount of attempts required to solve the magic square?
Alexandra has some distinct integer numbers a1,a2...an.
Count number of pairs (i,j) such that: 1≤ i ≤ n 1≤ j ≤ n ai < aj
Input
The first line of the input contains an integer T denoting the number of test cases. The description of T test cases follows. The first line of each test case contains a single integer n denoting the number of numbers Alexandra has. The second line contains n space-separated distinct integers a1, a2, ..., an denoting these numbers.
Output
For each test case, output a single line containing number of pairs for corresponding test case.
Constraints
1 ≤ T ≤ 4 1 ≤ n ≤ 100000 0 ≤ ai ≤ 109 All the ai are distinct
Example
2 2 2 1 3 3 1 2
Output: 1 3
Explanation
Case 1: Only one such pair: (2,1) Case 2: 3 possible pairs: (2,1), (2,3), (3,1)
as I understand the problem is just counting how many Ai's are 1 <= Ai <= N and then apply ((R*(R-1))/2), R is the count of valid Ai's
I have an assignment that I have to make a 3x3 magic square that sums up to 15 on all sides. I can't use arrays, just Loops and If and Else statements.
My first attempt was like this
//Program for printing magic square that sums up to 15.
#include <iostream> using namespace std; int main() { int a, b, c, d, e, f, g, h, i; int r1, r2, r3; int c1, c2, c3;
[Code] .....
I can't think of a way to loop that when it prints out, it will have a sum of 15 on all sides and/or print one of the 8 solution for a 3x3 magic square.
I have been asked to develop a program with 6 methods which I have presented below. The aim of the program is to find and generate a magic square with a given dimension. This is a console program and so the 'Main' is also provided. However, I am having a problem with my code. When ever I try to generate a magic square it continuously cycles through 'forever' and I have never yet got a magic square; no matter what dimension I enter.
I must use methods 'CreateRandomlyAssignedArray' and 'CheckSquareMatrix'. There is another method 'SearchForValue', which we were told to creat. How this can be useful.
I have provided my code below:
class Program { static Random rand = new Random(); static void Main(string[] args) { int[,] array = new int[5,5]; array = GenerateMagicSquare(5);
i'm having trouble with my c programming assignment. i'm trying to convert a number grade to a letter grade. I'm trying to Write a function (called: numToLetter) that takes as input a number from 0 to 100 and returns a character ( a single character ), based on the following: if the number is between 60 and 70 return Dif the number is greater than 90 return Aif the number is between 70 and 80 return Cif the number is between 0 and 60 return Fif the number is between 80 and 90, return B and i need to use the return statements to call the function like for example:
if (a > 90) return ('A'); elseif (a > 80) return ('B'); elseif (a > 70) return ('C'); else return ('F');
#include <iostream> class Hello { public: void Test() {
[Code].....
As i know a non-constant member function cant be called inside a constant member function but how the above code has been compiled successfully and giving the expected result .
I am trying to print out the letter frequency of a vector that the user inputs and what number that letter is in the ASCII. I am supposed to say, for example: "w" which is ASCII 119 occurs 2 times. How to do this?
