C :: How To Initialize A Variable That Is Not A Letter Or Number
Feb 25, 2014
In C how can I initialize a variable that is not a letter or number? For example with a number I can :
Code:
int i = 5;
for ( i = 0; i <=5; i++ );
printf( "%d", i ) This would display a row of 5's
but what if I wanted to display a row of -----? What I am trying to do is read in a simple txt file, around the file I want ----1----2-----3 ect ect on the top ----a----b-----c down the side Then I want to be able to change the file at lets say position c2 and save it. This is the early stages of my attempt to set up a editable table.
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Apr 4, 2013
I've been messing around with loops/functions and basic logic and come up with a small maths program. Here it is:
Code: #include <iostream>
#include <string>
float divide (float x, float y) //function to divide numbers {
return x / y;
[Code] ....
Would initializing the string 'anotherGo' to a value that makes the loop run at least once be a suitable way of doing this rather than using a do/while loop? I read that a do/while loop is a black sheep but I have come across a number of uses for it. Maybe it is just preference which one you should/could use?
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Dec 28, 2013
I need to initialize a pointer variable with a knowing address. See code below, ptr is the final destination and value of ptr_address contains the address value, so I need to do something like ptr = *ptr_address.
Code:
int *ptr;
int *ptr_address;
int address;
address = 0x10000005;
ptr_address = &(address);
ptr = *ptr_address;
The problem is that compiler gives the following warning message:
warning: assignment makes pointer from integer without a cast [enabled by default]
Is my code wrong or there is any other way to do it without receiving this compiler warning?
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Mar 2, 2014
this question would their be a different process if they asked "declare and initialize a pointer to the variable int cost[N][N]" Here's what I have so far
[#include<stdio.h>
int main() {
int a; // Step 1
int *ptr; // Step 2
a = cost; // Step 3
ptr = &a; // Step 4
return(0);
[Code] .....
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Aug 7, 2013
I wrote the following program to initialize a string after the variables is declared, but it isn't working. A warning is given by the compiler, and the execution of the program shows a strange string. How do I initialize variable word in a separate statement from its declaration?
Code:
#include <stdio.h>
int main( void )
{
char word[20];
*word = "Hello";
printf( "The string is %s.
", word );
return 0;
}
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Apr 9, 2014
I'm trying to write a program which prints a table of ASCII chars, I'm not really done with my thoughts on it but I already
ran into the following error:
Error: cannot initialize a variable of type 'char' with an rvalue of type 'char (*)[16]'
Here's my code so far:
# include <iostream>
using namespace std;
int main() {
char asciiTable = new char[8][16];
int nextSign = 0;
[Code] .....
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Sep 26, 2014
For example if I have typed 0xFF (a literal hex number that represents the value 255 for Unsigned Char or -1 for Signed Char) in part of my program. That 0xFF is treated as a Char not an Int, because the value is within the range supported by Char, the C compiler always tries to use the smallest datatype possible for the number that is needed for a literal value like this.
Unfortunately because Signed Char is the default Char type, 0xFF is translated into -1. I am wanting to use it to represent 255. So I'm trying to tell the compiler that 0xFF should be interpreted as either an Int or an Unsigned Char. How do I do this?
I already tried typing it with the magic letter "I", like this: 0xFFI
But that didn't work. What is the correct way to do this?
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Apr 30, 2013
I am working on Euler Project exercise number 17. Here is the problem from the website.
"If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used?"
Code:
#include <stdio.h>
#include <string.h>
#define LENGTHOFHUNDRED 7
#define LENGTHOFONETHOUSAND 11
#define NUMSTART 1
#define NUMEND 1000
[Code] .....
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Aug 22, 2014
I have one string from user. Let say,
"The deviceId is 2"....but user also can give input like this..
"The deviceId is a".
I just need to know how to differentiate a word/letter and number in the string.
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Feb 7, 2013
So I have to write a program to calculate a grade letter into a number.
Letter grades are A, B, C, D, and F, possibly followed by + or –. Their numeric values are 4, 3, 2, 1, and 0. There is no F+ or F–. A + increases the numeric value by 0.3, a – decreases it by 0.3. If the letter grade is illegal (such as "Z"), then your output should be "INVALID LETTER GRADE"; If the combination is illegal (such as "A+" or "F-") then your output should be "INVALID GRADE COMBINATION"
Also the code should look like this
Enter your letter grade: C+
Grade value is [2.3]
// Input
cout << "Enter your letter grade: ";
string s;
cin >> s;
[Code].....
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Oct 28, 2013
Dont know how to replace each letter as s number ... this is the question i was given ...
In cryptarithmetic puzzles, mathematical equations are written using letters. Each letter can be a digit from 0 to 9, but no two letters can be the same. Here is a sample problem:
SEND + MORE = MONEY
A solution to the puzzle is S = 9, R = 8, O = 0, M = 1, Y = 2, E = 5, N = 6, D = 7.
Write a program that finds a solution to the cryptarithmetic puzzle of the following:
TOO + TOO + TOO + TOO = GOOD
The simplest technique is to use a nested loop for each unique letter (in this case T, O, G, D). The loops would systematically assign the digits from 0 to 9 to each letter. For example, it might first try T=0,O=0,G=0,D=0, thenT=0,O=0, G = 0, D = 1, then T = 0, O = 0, G = 0, D = 2, etc., up to T = 9, O = 9, G = 9, D = 9. In the loop body, test that each variable is unique and that the equation is satisfied. Output the values for the letters that satisfy the equation.
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Feb 3, 2013
I need to create a program that asks the user for the filename, then counts the number of occurrence of each letter in that file.
Ex. if the file contains
Absacsac
asdasda
Output will be
a = 6
b = 1
c = 2
.
.
.
z = 0
This has been my program so far:
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
#include <cstdlib>
void countingFunction(string sentence) {
[Code] .....
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Sep 2, 2014
I am trying to fill an array with blank spaces and instead i get the number 32 over and over, i think this is the ANSI code for that character. how do i get the character itself?
char values[max];
for(o=0;o<=max;o++)
{
values[o]=' ';
printf("%2d ", values[o]);
}
printf("
");
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Feb 14, 2014
I have a string - a whole sentence that I want to assign a number to each letter, space, comma and period etc. So all "A's" will have the same number, all "B's" will have another number etc. I don't want to use the ASCII numbers because they all need to be sequential and some of the punctuation isn't. I have put the string into a char array to separate each character out and was thinking about running it through a loop with if statements for each letter and assigning numbers there and then saving the numbers in the order they appear into a list as a string but I keep coming up with errors so I don't know how to do it or if there is a better way to accomplish what I'm trying to do.
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Jan 8, 2013
Assignment:
1. Choose what to enter NUMBER or LETTER.
2. Choose type of sorting ASCENDING or DESCENDING.
#include<iostream.h>
#include<conio.h>
main() {
int x,y,z;
cout<<"choose Number or letter
1.number
2.Letter";
[Code] ....
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Aug 27, 2013
I am trying to run a programme implementing a function with structures in c... which is:
#include<stdio.h>
#include<conio.h>
struct store {
char name[20];
float price;
int quantity;
[Code] .....
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Feb 19, 2014
So I have a template, part of a larger code, that is designed to calculate the number of multiplications it took to reach a certain number. The problem is, whenever I execute the program, mults is always printing out a strange number, perhaps its actual address.
template <class T>
T power3(T x, unsigned int n, unsigned int& mults) {
if (n == 0) return 1;
if (n == 1) return x;
if (n == 2){
[Code] ....
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Feb 24, 2013
i'm having trouble with my c programming assignment. i'm trying to convert a number grade to a letter grade. I'm trying to Write a function (called: numToLetter) that takes as input a number from 0 to 100 and returns a character ( a single character ), based on the following: if the number is between 60 and 70 return Dif the number is greater than 90 return Aif the number is between 70 and 80 return Cif the number is between 0 and 60 return Fif the number is between 80 and 90, return B and i need to use the return statements to call the function like for example:
if (a > 90) return ('A');
elseif (a > 80)
return ('B');
elseif (a > 70)
return ('C'); else
return ('F');
how do if write my code with this function?
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Jun 9, 2013
How do i get the fraction for any decimal number in a variable?
Code: Code: #include<iostream>
using namespace std;
int main()
{
double x = 1/6;
cout << x;
cin.get();
}
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Apr 21, 2014
Write a function write with variable number of arguments that takes a string first argument followed by any number of arguments of type double and prints on the screen a string formatted by the rules described below. The first argument may contain formats in curly braces of the form {index[:specifier]}, where the square brackets show optional parts (this is :specifier may be missing), and index is the sequence number of an argument of type double (starting from sequence number 0).
Rules for formatting: In the printed string the curly brackets and their content will be replaced by the argument with the given index, formatted according to the given format specifier. If the format specifier is missing, the argument will be printed with its default format. For example:
write("The number {0} is greater than {1}.", 5, -3);
will print
The number 5 is greater than -3.
write("There are no format specifiers here.");
will print
There are no format specifiers here.
The format specifiers and their meanings are listed in the following table
Specifier MeaningFormat Output for 1.62 Output for 2.0
none default {0}1.62 2
ccurrency{0:c}$1.62 $2.00
escientific{0:e}1.620000e+000 2.000000e+000
ffixed point{0:f}1.620000 2.000000
iround to int{0:i}2 2
Limitations: You may limit the maximum number of arguments your function can process to a certain value, for example 10.
Suggested extensions:
-Add an optional alignment specification in the format , e.g., make the format of the form {index[,alignment][:specifier]}, where alignment is an integer specifying the width of the field in which the corresponding argument will be printed. If alignment is positive, align to the right, if it is negative, align to the left.
-Accept an optional integer after the specifier letter, specifying the required precision in the output. For example, {0:f2} will print the number 1.6234 as 1.62, but {0:f5} will print it as 1.62340.
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Oct 10, 2014
Im having trouble on getting the quantity up of the variable "item.iqty". For example the current quantity is 5 and in this function, the user inputs a number and it should add to the variable "item.iqty". So if if the user inputs 2 then the current quantity should be 7 now but in my program it hasnt changed. its still 5
void addQty(FILE *fp)
{
int num, qty, r, c, n;
bool found;
[Code]....
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Apr 23, 2013
I'm a basic C++ programmer, and I am stuck on this problem. You work for a company that collects a set of numbers. The numbers are located in a data file named "./Data_File". The data file contains two columns. how do you count a certain number on the left column.
#include <iostream>
#include <fstream>
#include <cstdlib>
#include <iomanip>
using namespace std;
#define DATA_FILE1 "./Data_File"
#define SUCEESS 0
#define FAIL 1
[code].....
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Jan 9, 2015
how to make a program in which a user is prompted to input four numbers like 1234 and then print those four numbers one by one on screen using only one variable..??
For example:
1
2
3
4
in ascending order...
I've done that with two methods but i am not sure whether the methods were correct..
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Jun 4, 2013
I am writing a math program, using variables of type double, and had initialized all variables to 0.0.
I now realize that not all results will be valid.
Is there a way to explicitly assign a variable of type double a non-numeric value, for example, "NaN", "Undefined", or "Unassigned" or something like that?
That way, when I read through the printout of results, I will realize the "NaN" results indicate a valid solution was not found. Whereas a 0.0 might not stand out.
I'd hate to have to go back and delete the initialization, and then re-assign 998 values just for the sake of 2 non-solutions.
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Jul 18, 2014
I have a simple problem about memory allocation.In the function Nr_elements() i assign a value which represent the elements of array. The pointer p is initialised with the address of variable n, but when i compile i dont know why but dont work. This function return a pointer.
Code:
#include<stdio.h>
#include<stdlib.h>
int *Nr_elements();
int *allocate(int);
void deallocate(int *);
[code]....
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Mar 6, 2015
Program that has the user enter 5 digits then asks the user what they want to know about the 5 digits. My issue is when the program goes to print the value, its a totally ill related number
10 34 8 17 50
program prints out:
2 for smallest
79 for largest
119 for sum
23.80 for average
Code:
#include <stdio.h>#include <stdlib.h>
int main(void)
{
int smallNum, largNum, count=0, sum=0, value, choice;
double avgNum;
printf("Enter 5 integers
");
printf("
");
[Code]...
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