I want to find the type of an argument . suppose if user is giving input from commandline, i want to know the type of the value that he has given.
EX: suppose user has given 10,10.34 as two arguments, how could i find the type of the value i.e 10 -- integer, 10.34-- float.. like that ...
How to check the type of argument passed to each function, checktype, in below?.
void checktype(void *p)
{
}
or
template <typename Type>
Type checktype(Type t) {
}
Code:
#include <stdio.h>
#include <stdlib.h>
int size_b_row1;
int size_b_col1;
[Code].....
I'm currently trying to solve a programming assignment and i got the logic of it, however i find it hard to implement.
What i need to do basically is fill an array with objects. Each object is a class that contains only one type of data. This means i can place int, double and string for example in one simple array.
However i can't figure out how to read data and then decide what it is. Even if i use templates once i call the function i have to give it a type, so getType<int> for example will not work with double or string.
I know about typeID and how to use it, i just can't figure out where to use it.
for ex: say i'm declaring two variables under int type and some 3 under char,my output should be lyk this: 2 variables in int and 3 var of type char...(input to the main program is actually another program where these 2 int and 3 char are defined).
View 1 Replies View RelatedI'm having some problems with changing an array of numbers of type char to type int. Every time i try to sum 2 array indexed values it returns some letter or symbol. Also, if i change the type of the array in the functions the compiler gives me an error message. I would also like to add that the problem requires that the first two arrays be char so each individual number gets assigned to a different value.
My current code is:
Code:
#include <iostream>
void input(char a[], char b[], int& size_a, int& size_b);
void convert(char a[], int size);
void reverse(char a[], int size);
void add(char a[], char b[], int c[], int size);
int main()
[Code]....
how to convert an element of int type of an array to char type?
View 2 Replies View RelatedI have a function like this:
template<typename T>
void f() {
//...
[Code]....
list contains, in order: A, B and C in any order, D, E
I am thinking it is possible with some clever template and polymorphism combos, but maybe not. As a last resort I know how to make it work by storing static type information in each class, but I'd like to avoid that if possible.
I need to use the type RectangleF as a built in type in c++ ie I need to declare a variable rect as RectangleF rect;
what do I have to include to be able to do this.
Let me put it into the code snippet:
/**
This class build the singleton design pattern.
Here you have full control over construction and deconstruction of the object.
*/
template<class T>
class Singleton
[Code]....
I am getting error at the assertion points when i call to the class as follows:
osgOpenCL::Context *cxt = osgOpenCL::Singleton<osgOpenCL::Context>::getPtr();
I tried commenting assertion statements and then the debugger just exits at the point where getPtr() is called.
How to pass an int that I got from user input into a function to use it. I am trying to print out the words to a string of numbers.
I got the input from user.
I got an absolute value of the input.
I then separate the string into individual digits and name them.
I can print these out.
Then I started my if statement by checking if the original input was zero, and if it is, printing zero and exiting.
Then I an trying to pass the digits into a switch function and this is where I go off the rails.
Code:
#include <iostream>
#include <string>
#include <cstdio>
#include <iostream>
#include <iomanip>
#include <cstdlib>
using namespace std;
[Code] .....
I was reading about void as function argument, but I did not fully understand it's meaning in C.
In C++
void foo(void) {}
and
void foo() {}
are the same. It means no arguments for foo function. But in C it's different. First function means the same as in C++, but second means
In C, an empty parameter list means that the number and type of the function arguments are unknown. But if it is unknown you can't use this arguments if user specifies same. Because here are no variables to store them. So doesn't result are the some? You do not get any arguments. O do I can get this arguments from some hidden variable?
For example.
void foo() {
printf("%d", var);
}
foo(5);
It is very unclear for me. Do this apply to main function too?
int main(void)
int main()
or can I use arguments given to int main() like given to int main(int argc, char* argv[])
I'm writing a program in C that performs operations on an array of 4-byte unsigned integers. Here's some usage examples:
+ n m // print sum of elements at indexes n and m
& n m // bitwise and of elements...
< n m // shift element at index n by m bits
I will have to implement functions for sum, bitwise-and, bitwise-or, xor, left-shift, right-shift... All with the same function format:
void print_operation(unsigned n, unsigned m) {
printf("%u
", n some_operator m);
}
Is there any way that I can pass an operator as an argument so that I can have a single elegant function that looks like this? I'd really like this to work like callback functions.
void print_operation(unsigned n, unsigned m, some_type oper) {
printf("%u
", oper(n, m));
}
My assignment is to write a program using VOID FUNCTIONS WITH AN ARGUMENT.
*I need one non-void function with an argument to generate the first 15 numbers greater than 500, another non-void function with an argument to generate the first 15 perfect squares that are greater than 500. Last, they need to be in columns next to each other.* also i cant use x,y, coordinates to align them. i must create a for loop with the
These are some notes from examples in the class. i just don't know how to do it with non void functions with an argument.
#include "stdafx.h"
#include <iostream>
#include <iomanip>
using namespace std;
void ClearTheScreen();
void NormalTermination();
[Code] ....
I have two questions :
1)
#include <iostream>
using namespace std;
void func1() {
cout << "Func1" << endl;
[Code] ....
Why ptr_func1() does not work here?
IntelliSense: expression preceding parentheses of apparent call must have (pointer-to-) function type
2) How can i pass func1 to func2 as parameter?
I tried void func1(void* function), but I think I'm wrong here.
I am writing a text-based rpg and I'm having some issues trying to pass the player struct to a function. First, here are the relevant code snippets. Also, Player.c and Player.h aren't completed but the relevant function is. I just run tests every now and then to see if everything is working right.
Monster.h
#ifndef MONSTER_H
#define MONSTER_H
#include "Weapon.h"
typedef struct Player;
typedef struct {
char* mName;
[Code] ....
The errors are:
1. line 33 in Monster.h, the void Attack_Monster_Types(Monster* m, Player* p) the ide says missing ')' before '*', missing '{' before '*' and 'Player' name in formal parameter list illegal
2. line 18 in main.c when the attack function is called. it says 'Attack_Monster_Types' Undefined; assuming extern returning int.
I believe I have all the right headers included so I'm not sure what to do ....
difference between an argument and parameter...understanding the difference between these two.
View 2 Replies View Relatedi have used single argument conversion function which gets called in below scenario.
Code:
#include<iostream>
using namespace std;
class Demo
{
[Code]....
It is giving error "test3.cpp: In function `int main()':test3.cpp:18: syntax error before numeric constant"
But it should work as Demo d=100; works
Write a c++ function that takes int as an argument and doubles it.the function does not return a value.
View 5 Replies View RelatedI faced a compilation error in the following code :
Code:
#include <iostream>
using namespace std;
void addition(int a, int b = 2, int c);
int main()
[Code]......
My question is that when i have called addition() with the 3rd argument, then what is the necessity of having the default argument for the 3rd parameter ?
I get an error when i try to compile this code. I tried to allocate memory in main function and that works. But why it doesn't work in function? I think that there is something wrong with function argument, but not sure.
Code:
#include <iostream>
#include <fstream>
using namespace std;
struct Word
[Code].....
I have a function
Code:
int exec_program(char * arguments[])
{
...
}
I can call it like this without a problem:
Code: char * uselessvariable[] = {"/bin/echo", "Testing", NULL};exec_program(uselessvariable);
However I get an error if I try to compile it like this:
Code: exec_program({"/bin/echo", "Testing", NULL});
How, in c, I can put this array inside of the argument in one line without having to name a new variable name?
What does collection of parameters as argument of a function in C mean? Also any place I can refer to find those parameters?
Googling gives me Parameters and Arguments But not really sure whether that is what is needed.
I was wondering if one could write a function that could accept one or the other variable type.
Ex: I have 2 arrays, int** and double**, and a function
Code: void PGMWrite(double** Matrix, int Matrix_dimension){.....}
Is there any way to change the function to
Code: void PGMWrite(int** Matrix || double** Matrix, int Matrix_dimension){.....}
And then have some sort of type identifier in the function that picks the correct section via an if loop? If so how, and how would I identify in the function if the input it type double or int?
I am using a small robotic-car that is controlled by writing C/C++ codes under Linux. I need to use a particular function from the library provided by the manufacturer. The relevant API documentation for the function is:
BASEBOARD_ERROR_KIND ZMP zrc :: :: :: Baseboard GetRS232Data (char * msg )
RS232 data acquisition.
Argument:
[Out] msg Address of the acquired data.
Returns:
BASE_OK RS232 data acquisition success
BASE_BASE_232_GETDATA_ERR RS232 data acquisition failure
I have trouble writing the relevant code in the main program that invokes this function. Here is a snippet of what I have tried:
# include "Baseboard.h"
int main () {
Baseboard _Baseboard; // Class name is Baseboard
char *msg ;
[Code] ......
The part where I am uncertain is how to handle the char pointer "msg" in the declaration, function call and referencing. According to the documentation, the char pointer "msg" is the output of the function so I presume that is is somehow dynamically allocated. Am I handling the char pointer properly in the declaration, function call and referencing parts?
Another related question I have is: I am printing out the value of the variable "dummy". I always get 0 for it. Since the variable "dummy" is an enum of type BASEBOARD_ERROR_KIND which can take on two values (first value represents success and the second failure), it is alright to get a integer value of 0 for it if the function call was successful ? (I do not have much experience with using enums so this is a enum-related question on whether we can get an integer value representing the first enum value) .
I have same type of errors in my program
#include "iostream"
#include <stdio.h>
#include <conio.h>
[Code].....