How to compare the time fetched from two week number of different year using C,C++.
I have used a naming convention for the files generated in a linux system. The naming convention will have the week number and date's day indication like Monday means M. I need to compare the two files of same week but on different years and calculate the time?
So for my C++ class I am required to create a program that will "Write a program to generate a calendar for a year. The program should accept the year and the day of the week for january 1 of that year (0=Sunday, 1=Monday, etc.)" (problem statement) and I am completely stuck. I've posted what I have so far below:
#include <iostream>
#include <iomanip>
using namespace std;
bool isLeapYear(int year);
int daysInMonth(int month, bool lpYear);
int printCalendar(int month);
int printDay(int dow);
[Code] .....
Whenever I run the program I get no errors yet it doesn't return a value for total it just exits the program. The program is supposed to output the number of the day based on the month day and year and check whether it is a leap year.
#include <iostream>
using namespace std;
int totaldays();
int days();
int month, day, year;
bool leap();
int main() {
char dash;
cout << "Enter the date in mm-dd-yyyy format to find out what day this is in the year." << endl;
[Code] ....
I want to compare dates of first week of every year input by user to determine that what was the day on 02/01/1998 compare to 02/01/2014, or 04/01/2001 compare to 04/01/2003.
I want to compare from 01/01/1997 , 07/01/2014.
For example user enter first date 04/01/2002 and other date 04/01/2003, then the program show that there was tuesday on 04/01/2002 and monday on 04/01/2003.
[Code] ......
I have a fun question that is an end of an inherited class. I am trying to return the day of the week using time structures. However, I cannot get the correct date from two different structures, even if they are declared as different structures. So, when I check the number of the week, the two provided to check with are the same.
point is: They keep coming up as the same.
bool Weekly::occurs_on(int year, int month, int day) {
struct tm * chec ;
time_t clock1 ;
time(&clock1);
[code]....
Write a program that determines the day number (1 to 366) in a year for a date that is provided as input data. As an example, January 1st, 1994, is day 1. December 31, 1993, is day 365. December 31, 1996 is day 366, since 1996 is a leap year. A year is a leap year if it is divisible by four, except that any year divisible by 100 is a leap year only if it is divisible by 40. Your program should accept the month, day, and year as integers. Include a function leap that returns 1 if called with a leap year, 0 otherwise. Extend the requested solution so that your program continues to prompt the user for new dates until a negative year is entered. This is what I have so far.
Code:
#include <stdio.h>
#include <stdbool.h>
int main(void) {
int d,m,y;
int days=0;
int k;
[Code] .....
I am unsure how to make this a loop so that it keeps asking for dates?
The first time my application opens up, it should get the local date out of the System and store this in a registry key. But the second time it should get the date stored in that registryKey and compare it to the date right now.And there is where I am stuck, I just don't know how to get the date out of that key and compare it to the date right now.
This is my code:
RegistryKey key1;
private void btnTrial_Click(object sender, EventArgs e) {
DateTime current = DateTime.Now;
key1 = Registry.CurrentUser.OpenSubKey("myKey");
if (key1 == null)
[code]....
at the last "if" statement it should compare the date stored in the key with the DateTime.Now.
I have a file called example.txt . In that file, the int 123456 is stored. How can I read one independent number from that int? Lets say, I have an int variable called "Weight." How do I set weight equal to the number 1 from the int 123456 in the file?
View 4 Replies View RelatedEverytime I type a character, the number 1 appears in the next line. And i just keep getting the message "Wrong! I have more than that." even when I type a number bigger than 1023
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main(void) {
srand(time(NULL));
[Code] ....
How can I read a file that contains numbers only, but read it by three digits at a time? I have a long string of numbers and every three digits corresponds to a particular number in itself. i.e. a string of 064045154 would need to be read as '064' '045' and '154'. I need to then subtract one from each of these numbers and the new values I need to convert into their ASCII characters and place these in a new file. This is what I have (focusing on the 'Decrypt' function) but all it does is in the new file place a string of the same character repeated over and over a total number of times equal to the number of integers in the numbers file.
Code:
#include "stdio.h"
#include "stdlib.h"
#include "string.h"
#include "limits.h"
int Encrypt(char * FILENAME)
[Code]..
so i have a loop that will run x number of times and each time it will produce a prize which is a certain sum of money. I need to a way to sum all the money earned. I am thinking there should be a way to extract the prize one for each time the loop runs but i am not sure how to do that.
#include <iostream>
#include <string>
#include <cstdlib>
#include <cmath>
using namespace std;
int main() {
cout <<"Option A: Drop one chip into one slot" << endl;
[Code] .....
I have this project, The problem is I have most of the code written, I am just having trouble setting it up correctly and placing it correctly. My code is rather long but as I said I know this is the longer and harder way to go about this.
//This program will be used to find out the day of the year
#include <iostream>
int month, day, year;
bool isALeapYear(int year) {
//Check if the year is divisible by 4 or is divisible by 400
[Code].....
I have an school assignment that asks me to measure the most famous sorting algorithms for performance in terms of number of steps and CPU running time. ( Here I'm testing for running time)
I decided to test for bubble sort first:
#include <iostream>
#include <ctime>
using namespace std;
void bubbleSort(int ar[], int size) {
int temp;
[Code] ....
So basically what I want to know is:
1. Is this clock function giving the correct CPU running time?
2. Is there any way to write code that would measure the number of steps for each algorithm?
3.I need to test it for number of integers=100 then 200, then 300... Well you get my point, and I don't want to have to actually input 200 numbers with my keyboard. Is there any way to generate as many entries as I want?
I have been given an assignment which I have big troubles with. The assignment is:
"If I ask you “When is the weekday of the 2nd of August in 1429?”, you can answer immediately with your program to my question.
The initial value for the 1st of January in (the year) 1 will be sought by inducing, for example the crucifixion of Jesus is said to be held on Friday, the 3rd of April, AD 33."
How can I solve this?
My program is supposed to get ask the user a date (MM DD YYYY) and its supposed to tell them what day of the week that specific date is. Well, I was told to check for leap years, and if the Feb 29 is a non-leap year, its supposed to cout an invalid statement and tells the user to try again. My problem is that its not looping through only when its Feb 29 2015 for example.I have been trying to find a solution and I cant find one so far? Like, I said, it works for other dates, just not checking and looping Feb 29 2014 or 2015, etc?
#include <iostream>
using namespace std;
const int JANUARY = 1;
const int FEBRUARY = 2;
const int MARCH = 3;
[code].....
I am writing a program that takes the Month, Day, and Year inputted from the user and outputs the day of the week (Ex. "February 2, 2014 falls on a Sunday"). I got it to print out the date but I can't figure out how to output the day. Would I be using the ctime function?
#include <iostream>
#include <string>
using namespace std;
[Code].....
I'm trying to determine the first Tuesday of any month in a given year.. I'd prefer to use my own functions to arrive at a solution, but logically I could sorting these things out.
View 6 Replies View RelatedProblem: Write a program to generate a calendar for a year. The program should accept the year and the day of the week for January 1 of that year (0 = Sunday, 1 = Monday, etc.). The calendar should be printed in the following form:
January
1
2 3 4 5 6 7 8
9 10 11 12 13 14 15
16 17 18 19 20 21 22
23 24 25 26 27 28 29
30 31
February
1 2 3 4 5
I have wrote code that has three functions, one to print the month, one to print the days in month, and one to find if it is a leap year or not. I have gotten up to the point where I can print the 12 months with a for loop, but how to print out the days in the format above.
This is my code.
#include <iostream>
using namespace std;
void printOneMonth(int month, int& dow, int year);
void daysInMonth(int month, int year, int& dim);
bool isLeapYear(int year);
int main(){
int year=0, dow, count;
[Code]...
Check the Leap Year Program In C++:
#include <iostream>
using namespace std;
int main() {
int yr;
cout << "Enter year : ";
[Code] ....
Check the LeaP Year... [URL] ....
I am trying write a void function which will tally up the totals for each day and then display the most profitable day of the week.
#include "stdafx.h"
#include <iostream>
using namespace std;
#include <iomanip>
#include <string>
#include <fstream>
struct Menu_Items {
string Item;
double Price;
[Code] .....
The void function must pass as a parameter a pointer to the first element of the Orders_Placed array. I have attempted to write this. But I do not think I am even close. I need to have 7 double variables that hold the totals for each day of the week. Those are the MonTotals , TueTotals , etc....
How do I get these totals for each day?
How do I fix this void function so that is displays the most profitable day. Also, would the function call be Biggest_Profit(Orders_Placed)??
The GetPrice function provides the price given a menu item.
I am in a computer science class at LSU and i can not figure out how to writhe this program. The program must let the user input (MM/DD/YYYY) and then output what day that date was on and also if it was a leap year or not.
View 1 Replies View RelatedHow can I check for an invalid date when I run the program? I am trying to enter a conditional statement that checks for a valid or invalid date.
Programing Question: Write a program that inputs a date (e.g., July 4, 2008) and outputs the day of the week that corresponds to that date. Here is what I Have. The program runs. I need it to loop around.
#include <iostream>
using namespace std;
const int JANUARY = 1;
const int FEBRUARY = 2;
const int MARCH = 3;
const int APRIL = 4;
[Code] ....
I need to make a program to calculate the business days (Monday-Friday) in a year in C. As example:
Input
2026
Output
261
I need to consider that the year could be a leap year and that every year can start with a different day. My Problem is that i dont know how to implement the right number of business days in C. I wrote down the business days in Excel for 2010-2040. I cant see any system behind it, some years have 261 business days, some have 260 or 262 but in no order.
I need to write a program that tells the day of the week, month, day, year, and whether it is a leap year or not from a input of MM DD YYYY form.
Example: Enter numeric values for month, day and year of a date> 10 31 1990 Wednesday, October 31, 1990 occurred in a non-leap year.
I'm just starting coding and I just want it to input a date, then output a day of the week.
Code:
#include <iostream>
#include <cmath>
using namespace std;
int main() {
int startday = 0, sm = 1, sd = 1, sy = 2000, cm = 0, cd = 0, cy = 0;
cout << "Please enter the current month, day, and year: ";
[Code] ....
How to print a year like DIGITAL CLOCK NUMBER for any input four digit number ...
For example if input 1000 the output should be 1000 but each number should look like this in the block form for example number 0 is, don't mind those stars, i did not know to print it here, that is number zero ...
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