C/C++ :: Passing Two Dimensional Array To Function And Print To Screen?
Apr 4, 2015
This seems simple enough but I'm missing something here to make this code work.What I'm trying to do is print the contents of the two dimensional array in 25 rows and 4 columns. I experimented with something similar to this code when I initialized the array with numbers.
I'm getting garbage. I tried including the name of the array in the cin object but I got an error message that says "no match for operator '>>'. When I take the name of the array out, the program compiles but I get garbage. Program is suppose to reads data from a file of 25 students and calculates test scores and class grade average output each student's name score, letter grade and grade average. I would be happy at this point if I could just print out something that wasn't garbage.
Here is the code.
#include <iostream> #include <iomanip> #include <cmath> #include <string> #include <fstream> using namespace std; //const const int Array_Row = 25; const int Array_Col = 4;
I want to use one median function "selectfunction" to choose one of the 2 other functions at random to pass my 2-dim array to the selected function. There is a problem in the median function
#include <iostream> #define random(x)(rand()%x) // for random number between numbers of 0 and 1 using namespace std; void proc1 (int iArray[][2]); void proc2 (int iArray[][2]); void selectfunction(int iArray[][2]); int A[4][2] = {{1, 2} , {3, 4} , { 5, 7} , {8, 1} };
I wanted to print the values of a array from a function by passing the array as well as the number of elements to be read. For a single dimensional array, this is how i have written it. It's pretty straight forward. I want to read 5 elements from the 5th element in the array.
Code: #include<stdio.h> void display(int array[],int size) { int i;
[Code]....
With this code I want to print the five elements from the element present in [0][4].
But shows an error that
Code: D:BennetCodeblocks CLearning CSingleDimentionalArray.c||In function 'main':| D:BennetCodeblocks CLearning CSingleDimentionalArray.c|18|warning: passing argument 1 of 'display' from incompatible pointer type [enabled by default]| D:BennetCodeblocks CLearning CSingleDimentionalArray.c|2|note: expected 'int (*)[10]' but argument is of type 'int *'| ||=== Build finished: 0 error(s), 1 warning(s) (0 minute(s), 0 second(s)) ===|
I know when you pass a array as an argument it gets decomposed into a pointer, but with a multi-dimensional array this is not the case. how this works for mult- dimensional array's?
i am programming Cli/Ser ,so part of the program is to open file to download it from client side,but i want to return the global value Errorno to print it to screen , and how to use strerror() func ??? i write this "This is part of server code" :
Code:
fd= open("abc.txt",O_RDONLY); //error handilng in open file if(fd<0) {
How can I concatenate two 2-dimensional int arrays into one larger 3-dimensional array. This question is also valid for the 3-dimensional vectors. I know the command for the one dimensional vector as:
I need to create subfunctions to do basic Matrix mathematics (addition, subtraction, etc.) I need to be able to pass bot of my Matrices to subfunctions. I started with the addition sub function and I cant get the code to run. I keep getting expected primary-expression before ']' token error for line 75.
#include <iostream> #include <stdio.h> using namespace std;
Numbers are 3d6 Rolling die no.1... RolledDie: 4 DieTotal: 4 Rolling die no.2... RolledDie: 5 DieTotal: 9 Rolling die no.3... RolledDie: 5 DieTotal: 14
How to print to the screen the value of n after it has been multiplied.
For example: if I use cout << "n: " << n << " power: " << power << " "; I
can see the variable "power" decrementing by 1, but I don't see the variable "n" incrementing with its new value after it has been multiplied by n * n.
#include <iostream> using namespace std; typedef unsigned short int USHORT; typedef unsigned long int ULONG;
fstream infile1(argv[1]); if(!infile1.is_open()) cout << "Could not open file"; else { char listNum; while(infile1.get(listNum)) cout << listNum; }
However, when I check for odd or even numbers it will check each and every number.
printed like this (partial list): 1 is odd 3 is odd 8 is even 9 is odd
But it should print: 138 is even 9 is odd
I tried using getline, but it keeps giving me the errors: invalid conversion from 'void*' to 'char**' invalid conversion from 'char' to 'size_t*' too few arguments to function 'ssize_t getline(char**, size_t*, FILE*)'
Here is the getline code, what am I doing wrong? I have tried switching things around, adding things. Just nothing works.
ifstream infile1(argv[1]); if(!infile1.is_open()) cout << "Could not open file"; else { char listNum; getline(infile1, listNum); cout << listNum; }
Given this sentence as an input: "Hello my name and "John" (with its spaces and capital letters), print it on the screen .. NB the phrase must be entered from the keyboard all at once ... you can do this in C / C + +?
I'm trying to write a program that prints all of the prime numbers to the screen. I'm getting angry because it only prints EVERY number. I think it has something to do with the bool change not being able to leave the for-loop but how to fix it.
Code: #import <stdio.h> #include <stdbool.h> int main(void){ printf(" The Primes Are: 1");
I want to pass array to function, to fill array with new values and then to print the array in the main. But I have problem because it prints me just array of zeros. Maybe the concept is wrong, I'm new with passing arrays to function.
function:
Code: void printSum(int *return_array) { int return_array[3]; int i; for(i = 0; i < 3 ; i++){ return_array[i] = 5;
Code:
void printSum(int *return_array); int main { int m_return_array[3]; int i,j; for(i= 0 ; i < 3 ; i++){ m_return_array[i] = 0; } printfSum(start,m_return_array);
I need to pass a 2D array to a function. I want to know, where I may have made a mistake. This is the piece of code that I found on the web, and I am using it to allocate my 2D array.
Code: signed char allocate2D( int** arr2D, int rows, int cols ) { int i; arr2D = malloc( rows*sizeof( int* ) ); if( !arr2D ) return -1;
[Code]....
My main function passes the 2D array to the function
Code: signed char read_root_message_file( int **Root_Messages, int *num ) This is how I pass the array in the main function to the above function:
Code: int main( int argc, char *argv[] ) { int **Root_Messages; ... ... Root_Messages = NULL; read_root_message_file( Root_Messages, &num_root_msg );
I am following a tutorial and the topic was passing array to function so i tried to do a BMI calculator by myself. I am using code blocks to compile the codes, it is actually working while using compiler's run button. But when I open the exe file, its closing the window after entering the persons' weights and heights. Here is the code
Code:
// Passing array to function example BMI calculator of n person #include<stdio.h> #include<math.h> void assess(float bmi[],int a); int main(void){ int n,i,j; }