C++ :: User Input Number And Then Computer Calculates It For Fibonacci Series
Mar 15, 2013
I was asked to write a code that has the user input a number and then the computer calculates it for the Fibonacci series. The output should be separated by commas and a period should follow the last number. Ex. 1,2,3,4,5. <---period
I can't seem to get the period at the end. I have the commas and everything else. Here is my code:
#include "stdafx.h"
#include <iostream>
using namespace std;
int main() {
double num;
cout << "How many Fibonacci numbers do you want to display?";
[Code] ....
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Sep 3, 2014
When ever I enter a value higher than 10, my out put looks like this
How many numbers are in the Fibonacci Series? 20
0 0 0 0 0 0
0 0 0 0 34 21
13 8 5 3 2 1
1 0
Press any key to continue . . .
This is what I got when I entered the value 20.
As you can see, it will only display up to the 10 term of the Fibonacci sequence
I'm trying to get the output to look like this:
4181 2584 1597 987 610 377
233 144 89 55 34 21
13 8 5 3 2 1
1 0
Here is my code:
#include <iostream>
#include <iomanip>
using namespace std;
#define SIZE 20
void Fibonacci( int );
int main( ) {
cout << "How many numbers are in the Fibonacci Series? ";
[code].....
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Apr 12, 2013
This is a function that calculates factorials of the user input.I'm not getting a favorable printf result.
Code:
void calcFactorial ()
{
int arr [100];
int num = 0;
int i;
int factorials = 0;
int product = 1;
}
[code].....
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Oct 11, 2014
I can't seem to get the math portion right. It is supposed to approximate pi using (sigma,i=-1 to infinity)(-1)^(i+1)(4/(2i-1))=4(terms of pi). And what I have does some math but it is incorrect because I get a negative value for pi and one that is entirely too large at that. The precision is also to be at 20 decimal places. I also need it to end immediately after if I get an invalid input, but I can't seem to get it to end after trying a few different things it will say that it is an invalid number, but will continue to run the math loop. I also need the final cout to print all the terms that is multiplied by 4.
[code]#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;
int main() {
int nterm, numerator;
double sum = 0.0;
const int upperBound = nterm * 2;
cout<<"This program approximates pi using an n-term series expansion. "<<endl;
[code]....
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May 27, 2014
I am making a program to run Fibonacci series. I have created 2 array.
1)- 1st array holds only 0, 1
2)- 2nd array holds other values eg: 1, 2, 3, 5..........etc
I am using while loop to get the febonacci series and storing it in a 2nd array called int[] numbers.
After getting value using while loop, I am joing both the arrays using int[] final = arr.Concat(number).ToArray();
At last, I have used foreach loop to add the febonacci series into the listbox.
The problem I have is that, I cannot able to concat both the arrays. I tried to assign number array at the top of the while loop. so that number variable will be accessible outside the while loop. But I am getting a error.
See the code below
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
[Code] .....
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Feb 11, 2013
I'm currently creating a guessing game program where the user will be asked to guess the computer generated number. Once the program is finished, at the end the user will be asked if they want to play again. If the user types "Y or Y" the program will loop and when the user types "n or N" it will not loop. Check out my code below.
#include<iostream.h>
#include<stdio.h>
#include<dos.h>
#include<stdlib.h>
#include<conio.h>
#define g gotoxy
void main(){
int a,l,b,guess,row,col,answer,num,clue=5;
[Code] ....
I can't loop this program.
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Aug 26, 2013
I'm trying to make a fibonacci sequence with some user inputs. I'm using arrays for this, the user inputs are for the Nth term and the starting number (as in the number in front of 0).
My problem is that when the program runs it's an infinite loop which constantly prints the starting number. Which, I think, means that my WHILE loop isn't coming to an end and my 'count' variable isn't increasing.
#include <iostream>
using namespace std;
int main() {
int start;
int term;
cout << "Input a starting number for the sequence: ";
cin >> start;
cout << "
Enter the Nth term for the sequence to reach: ";
[code].....
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Feb 16, 2014
The next code is right. I mean it works. It gives the sequence of fibonaci numbers ...
Code:
#include <iostream>
#include <iomanip>
using namespace std;
int fibo(int pos) {
if(!pos)return 0;
if(pos==1)return 1;
[Code] .....
But.... when I change the lines:
Code:
int r1=fibo(pos1);
int r2=fibo(pos2);
int r=r1+r2;
For the lines:
Code:
int r=fibo(pos1)+fibo(pos2);
It doesn't work right. Apparently it should work the same.
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Feb 28, 2013
I was trying to create a code to calculate the nth number in a Fibonacci sequence, when the nth number is entered interactively.
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Jun 19, 2013
I need to implement the fibonacci number sequence. Here is an example output of the program:
Server:Waiting for connection
Server:Receive connection from client
Client:10
Server:Print 10 Fibonacci
Server:1 1 2 3 5 8 13 21 34 54
Client:1 1 2 3 5 8 13 21 34 54
if Client send value of 5, the output would be 1 1 2 3 5
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Feb 24, 2013
Is it even possible to store the 100th Fibonacci number (beginning with the numbers 1 and 1) into a variable? I know the number is pretty huge, and wondered if there is a data type to hold a number that big.
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Jun 29, 2014
There's this program I'm trying to code where the user gives input of 2 values.
Sample :-
Value of X: 1234
Value of Y: 234567
Reversed value X: 4321
Reversed value of Y: 765432
New value as Z: 1223344567 (each number was taken in both X and Y)
Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream>
using namespace std;
int main(){
int x=0, y=0;
int reverse_x=0;
int reverse_y=0;
int z = 0;
int l;
[Code]....
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is then how I could use that concept here.
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Jun 29, 2014
There's this program I'm trying to code where the user gives input of 2 values.
Sample :-
Value of X: 1234
Value of Y: 234567
Reversed value X: 4321
Reversed value of Y: 765432
New value as Z: 1223344567 (each number was taken in both X and Y)
Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream>
using namespace std;
int main(){
int x=0, y=0;
int reverse_x=0;
int reverse_y=0;
int z = 0;
int l;
[Code]...
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is I can't seem to really get that idea how I could use that concept here. I'm not really good with programming, fairly new at this.
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Feb 10, 2013
I was wondering what function was the C++ equivalent for testing to see if a user input is numeric.
I have equivalents in Ruby, Java, Python, VB, VBA, php, but being a novice in C++, I have yet to find one - even with Google.
And I know C++ is such a wonderful language, that its extensive library must have one somewhere - considering it's already 2013!
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Apr 5, 2013
If the user puts in a 6. I need the array to display the even number from 0 - 6. Right now what it does is it displays the first six even numbers. Okay as I'm writing this I'm starting to see where my problem might be..
Code:
void sumIntegers () {
int arr[50];
int i = 0;
int num = 0;
int sum = 0;
[Code] .....
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Oct 2, 2014
I'm working my way through some C exercises to get some practice and have hit a wall. I need to use a function to take a number, such as 1, and print out One.Here's what I've got so far:
Code:
#include <stdio.h>
int name(int n);
char numberOne[] = "One";
int main(void)
{
int n;
}
[code]...
However, when I run the code and enter "1" the only thing that gets printed to the screen is "(lldb)". I've tried changing it to doing it without variables and just printing "One" but that gave the exact same result.
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Jun 18, 2013
I'm having a bit issue with ispunct in my function. The user can input a phone number in any of the formats below:
4147778888
(414)7778888
(414)777-8888
The program will only print out:
41447778888
What I am trying to do is accept any integer and parentheses. If the user inputs anything else, the program will display an error message. Right now, parentheses displays an error which is obvious but I'm wondering if there is a way I can allow a parentheses to be entered but not any other symbol. ex: . , : ; " '
Code:
void getPhoneNum(){
// Local Declarations
char string[14];
char* tokPtr;
[Code] ....
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Mar 8, 2014
User will input a number in the range of 2 and 2^63-1 and the program will decide whether it's prime or not by a simple 'YES' or 'NO'.
I figured out a code:
#include <stdio.h>
#include <string.h>
main() {
unsigned long long n,i=3; int temp=0;
int t;
scanf("%d",&t); //Number of test cases
[Code] ....
Now this code works for normal inputs but whenever I try it with large primes in tat range, like 987654321987654329 or 9223372036854775783 it does not work />.
I tried to print the values of i to check the limit to which it runs.. and I found it 23697, whose square is 561547809 - nowhere near about the input primes.
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Dec 11, 2012
input X and Y then write the program to compute
Sin(X++) Cos(Y--);Sin(X+X),Cos(Y--)
and write your conclusion for
X=46 & Y=90
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Aug 13, 2013
The basic idea of this exercise is to generate words from a user-input, seven-digit number(a phone number). The code runs, but for some reason, I can't get it to print the numbers into the file.
Code:
/*Write a program that will generate a word based on a randomly generated, seven-digit number. there should be 2187 possible words. Avoid "phone numbers" that begin with 0 or 1*/
#include<stdio.h>
#define PHONE 7
void wordGenerator(int number[]);
void wordGenerator(int number[]) {
//loop counters for each digit in the number
[Code] ....
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Sep 11, 2013
im writing a program that asks the user to input a number 1-10 and will transform it into the roman numeral of that number but it seems that its not after the user inouts the number nothing will output
#include <iostream>
#include<iomanip>
using namespace std;
[Code]....
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Jul 26, 2014
I am trying to generate a random number between two numbers that the user gives me.
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
void rand_int(const int &min, const int &max, int &val);
[Code] .....
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Oct 8, 2014
Write a C++ program that will input from the user a positive number n and find its factorial. Don’t forget to validate the input. The factorial of a positive integer n (denoted by n!) is defines as the product of the integers from 1 to n.
n! = 1* 2 * 3 * ... * (n - 1) * n
You should allow the user to continue working with your program for additional data sets.
Sample output:
Please enter a number: 5
5! = 120
Would you like to continue (Y/N)?Y
Please enter a number: 3
3! = 6
Would you like to continue (Y/N)?N
Good Bye!!
My code for what i think I'm doing is as follows:
#include <iostream>
using namespace std;
int main(){
int i=1;
int n;
[Code] ....
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Mar 11, 2014
The problem that I am having is that , the program outputs numbers that are perfect numbers and im not sure where i can add a statement to make it so that if it isn't a perfect number it doesn't output...
#include<iostream>// allows user input/output
#include<conio.h>
#include<fstream>//data file / result file
#include<iomanip>
#include<cmath> // math function
#define in_file "data.txt"
#define out_file "result.txt"
[Code] ....
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Apr 21, 2014
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#include <iostream>
#include <cmath>
using namespace std;
[Code]......
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