C++ :: Output Address Of Variable In Binary?
Sep 24, 2014How can I output the address of a variable in binary?
#include <iostream>
#include <sstream>
#include <string>
using namespace std;
[Code] ....
How can I output the address of a variable in binary?
#include <iostream>
#include <sstream>
#include <string>
using namespace std;
[Code] ....
I've been experimenting with pointers and am getting the below error.
'error: cannot convert 'int**' to 'int*' in assignment'
I thought it was ok to assign a variable address to another variable. Line 18 is where I get the error.
I am trying to show the progression of memory as I increment it as I have done on line 17 and again, I don't know why I don't see a progression through memory locations when output to the console on line 20.
Here's the code:
#include <iostream>
#include <cstring>
#include <cstdlib>
using namespace std;
int main() {
int *tt = new int;
int *p = new int;
[Code] .....
Converting an IP address to a binary number? As in the entire thing 123.45.555.49 to it's binary equivalent.
View 14 Replies View RelatedI've run across this issue before, but for the like of me, I can't figure out what keeps causing it. The problem compiles and runs as expected; however in the salaried object (Employee #1 in main.cpp) the console displays the number of vacation days as -858993460 instead of the value entered.
The parent Employee class is abstract with calculatePay() and displayEmployee() being pure virtualls and with a Benefits, Salaried, and Hourly class derived from it.
The Salaried displayEmployee() and the portion of the Main.cpp that contains the salaried object follows. What causing this?
Salaried displayEmployee()
Code:
void Salaried::displayEmployee()
{
cout << endl;
cout << "Employee Information" << endl;
cout << "----------------------------------" << endl;
cout << "Employee Name: " << setw(7) << FirstName << " " << LastName << endl;
cout << "Gender: " << setw(12) << Gender << endl;
[Code] .....
Consider the below initialization of x.
int x = 0x01234567;
If x is stored in RAM as given below, what would be the address x in both case?
(if image is invisible please follow this link)
Assume that size of integer is 4 byte.
I know that this code is wrong because it returns the address of local variable which no longer exist after function:
int *f1()
{
int x = 2;
return &x;
}
However, why this one does not show problem and runs fine, here the pointer p is also a local variable:
int *f2()
{
int x = 2;
int *p;
p = &x;
return p;
}
How can I find/calculate the address of the entry point for an exe binary file using its PE32 optional header?
I have added a picture, where it says (file addr) thats the address I want to know how to calculate
I need to initialize a pointer variable with a knowing address. See code below, ptr is the final destination and value of ptr_address contains the address value, so I need to do something like ptr = *ptr_address.
Code:
int *ptr;
int *ptr_address;
int address;
address = 0x10000005;
ptr_address = &(address);
ptr = *ptr_address;
The problem is that compiler gives the following warning message:
warning: assignment makes pointer from integer without a cast [enabled by default]
Is my code wrong or there is any other way to do it without receiving this compiler warning?
I am doing a piece of gui code on some embedded system.
I'm trying to find a way of eliminating the local variable kEvent:
Code:
EVENT kEvent;
....
Code:
kEvent = EVENT_UPSTREAM;
xStatus = xQueueSendToBack(getEventProcessorQueue(),&kEvent, 0 );
....
I tried this, it doesn't work:
Code:
xStatus = xQueueSendToBack(getEventProcessorQueue(),(EVENT *)EVENT_UPSTREAM, 0 );
Shouldn't this work?
How can I add the variable adress to a void pointer inside of a class?
class variant2 {
private:
void *Vvariant=NULL;
public:
template<typename b>
variant & operator = (b *adress)
[Code] ....
if possible i want avoid the '&' when i assign the variable address.(variant2 f=varname;//like you see i don't use the '&')
for the moment i just need put the address to Variant pointer. but i receive several errors .
I want to store the address of a customer (with spaces) in a char variable (say cadd). First I tried to use "cin", as we know it reads until it sees any whitespace. So it reads only first word before a white space. So, I used "getline()" function, it will work. But when I used it, It did'nt wait for the I/P (it skipped it).
char cadd[20];
std::cout<<"Enter Customer Address:
";
std::cin>>cadd;
std::cout<<"Enter Customer Address:
";
std::cin.getline(cadd,20);
I need to create a function that outputs all possible binary combinations. I'm really stumped on this. I have to do it with nested loops, and am not sure how to go about it. Below is what I tried so far.
The output should look like this:
00000000
00000001
00000010
00000011
00000100
...
11111110
11111111
Code:
void outputBinary(){
int a[2][2][2][2][2][2][2][2];
for (int i = 0; i < 2; i++){
for (int j = 0; j < 2; j++){
[Code] .....
I need to get up to speed in Embedded systems. I need to create a 3led binary counter, when an input is operated the it needs to count up using these leds from 0 to 7. I have written this so far and how to pulse a counter or interger to 7 and then reset back to 0.
int main (void) {
LED_Init_1();
LED_Init_2();
LED_Init_3();
[Code]......
I have written a function that takes in a positive decimal and returns its Binary equivalent; however, the output always adds an additional zero to the binary. What could I do to get rid of it?
If the number is 7, it outputs 0111 instead of 111.
Code:
#include <stdio.h>
void Dec(int n) {
if(n > 0)
Dec(n/2);
printf("%i", n%2);
[Code] ....
I am learning c because I want to get back into programming microcontrollers, which I previously did in assembly. I wanted to make something fairly tight in terms of program memory and RAM to show me an output in binary form. When you are troubleshooting a file register or serial interface when you can see the actual bit values (on a small LCD for a micro-controller) and compare it to a datasheet.
Code:
#include <stdio.h>
#include <math.h>
int main() {
int i;
int decimaltoconvert;
int convertingarray[7];
int convertingarray2[7];
[Code] .....
Also, how might I go about putting that into a function that I could call?
I'm attempting to split a large binary file into smaller manageable files for analysis. I've written most of the software but I'm stuck in a couple of places.
1. The binary file is split by looking at a couple of bytes to determine when to create a new file or continue appending to the current new file. The question is when I need to create a new file, how can I dynamically sign it a name? My intention is to rename each subfile by: "original_name" + new section id + ".log".
2. The start of each section is determined by a specific pattern (6 bytes of FF's). I'm running into an issue where the pattern check is checking for 5 bytes instead of 6 because the for..loop doesn't increment for one instance.
I've attached the code I have so far.
#include <iostream>
#include <stdlib.h>
#include <stdio.h>
#include <string>
#include <sstream>
using namespace std;
int append_to_file(FILE *f,long sec_start, long sec_end)
[Code] ...
I want to separate this binary string every 4 characters..I am trying to get a better understanding of how variables are stored in memory and I am looking at their binary address for a pattern..I see a pattern for the last 4 bits
#include <iostream>
#include <bitset>
int main() {
using namespace std;
int x[100];
[Code] ....
I need to create a binary calculator that outputs the operation of subtraction whenever you input 2 4 bit binary numbers. For example:
If I enter
1000
- 0111
This program has to convert an unsigned binary number into a decimal number. No matter what binary number I enter, however, it always outputs that the decimal number is 0.
My code is as follows:
#include <iostream>
#include <cmath>
#include <algorithm>
using namespace std;
int main() {
string binarynumber;
cout << "Enter an unsigned binary number up to 32 bits." << endl;
[Code] ....
And my output:
Enter an unsigned binary number up to 32 bits.
00001111
That number in decimal is 0
The output should have shown the binary number in decimal to be 15, and I cannot find my error.
Write a C++ application program to accept a signed decimal integer as input and output the equivalent 2s complement version in 16-bit binary. Include a space between every four bits in the output string. The input will only be processed by the application if it falls in the valid range that can be represented in 2s complement format with 16 bits. The range of a decimal number from - to + is -32768 to 32767.
View 3 Replies View RelatedHow to read and write an arbitrary number of bits from/to a file stream.
For instance, how to repeatedly read 9 bits from a file, then change to 10 bits, then 11 bits, and so on?
Obviously one way is by doing a lot of bit shifting, and masking. But honestly, I'm too dumb to get it right. Then I thought about using std::bitset and std::vector<bool>.
I'm trying to get the current position of the cursor in the terminal window. I know that the ansi escape sequence "