C++ :: How To Use While Loop To Control Sudden Termination Program
Jan 4, 2013how to use while loop to control sudden termination program of win32 console application ?
View 1 Replieshow to use while loop to control sudden termination program of win32 console application ?
View 1 RepliesWhy I have a
HTML Code:
FLOATING POINT ERROR: OVERFLOW
ABNORMAL PROGRAM TERMINATION
in the code below?
Code:
#include<stdio.h>
#include <math.h>
#include<conio.h>
#define A 0
#define B 1
float F(float x0, float y0) {
return (0.2*x0)+(y0*y0);
[Code] .....
What is wrong with this code? I keep getting
HTML Code:
FLOATING POINT ERROR: OVERFLOW
ABNORMAL PROGRAM TERMINATION
Code:
#include<stdio.h>
#include<math.h>
#include<conio.h>
#include<iostream.h>
#define N 4
float x[5]={0, 1, 2, 3, 4};
float y[5]={0.5, 2, 7.5, 20, 42.5};
[Code] ....
This program I'm working on just exits unexpectedly right after outputting "Expression?"
int main(void) {
provideHelpIfNecessary();
while(true){
cout << "Expression? ";
[Code] ....
And I'm not allowed to change anything in main().
I'm using an animation program. In this program I've simulated a particle system. The particles are flying around at different and varying speeds. I've attached birds to the particles and I want to be able to control each bird's flapping animation based on its velocity; so birds moving faster will be flapping faster.
Initially, the bird's flapping animation is controlled by a parameter that goes from 0 to 100%. So not only do I need to drive the speed at which the animation goes from 0 to 100%, I need to set it on a loop so once it reaches 100%, it loops back to 0%. I'm extremely new to code so I don't think it would be wise for me to even provide a jumping off point, not that I could.
I came across a strange problem while writing a program using the getline function. I understand that when using the getline function an input string will terminate when the "enter" key is pressed and in the following program it works as one would suspect.
#include <iostream>
#include <string>
using namespace std;
int main() {
string str;
cout << "Enter: ";
getline(cin, str);
cout << str;
}
However when I use it in this next program (below) that I have been working on it will only terminate after pressing the "enter" key if the first character is a number, otherwise it will not terminate. So the question is: How do I get it to terminate the string regardless of the input order?
#include <iostream>
#include <string>
using namespace std;
int i = 0, j;
int numValue;
[code]....
Additional Info: the purpose of this program is to change a character, which is extracted from a string, into an equivalent numerical value, if the character is an integer, and assign it to an int variable. I plan on eventually adapting it to return the correct value of a multi-character integer such as 123.
... and not with a brace followed by a semicolon like in class-definitions - reason for that?
View 2 Replies View Relatedis there any way to have the program control go some two paths at once? For example: if my program has two functions, one that does some simple calculation that requires nothing from outside it to set the variables and another that displays text for the user to read then enter something. Is there any way to have both run at the same time?
simpleFnc()
{int a = 1;
int b = 2 ;
int c = a+b ;
[code]....
There is no connection of simplefnc to anywhere else in the program so is there any way to get it to run at the same time the other function is running?
I am having trouble understanding what I need to do to halt the flow of a program until a video file finishes playing. So far I have accomplished getting the video to play, but the program continues while the video is playing rendering the content of the program on top of the video making it not seen.
My goal is to make the video play, then once it has finished the rest of the program should run.
So far I have this in the start up area of my code:
//Initialize components for DirectShow to stream a video at start-up
CoInitialize(NULL);
//creates filter graph manager
[Code].....
After this code runs once, the program proceeds immediately into the loop where my update and render functions for the program runs. Preferably, I want to stop just the render function while allowing the update to continue to check if the user presses a key to skip the video. What do I need to add to the code to do this?
I have researched quite extensively, experimented, and still cannot seem to change the properties of a control on an active winform from a user control.
So I have a user control which populates each dynamically added tab page in a tab control.
I have a textbox in the user control which I would like to type in, capture the text_change event, and change the text of the label in the winform.
How do I bind a DATE column in a DataGridView Control to a DatePicker control (using C#)? I already have the DataGridView control bound to a database stored procedure which takes a DATE value as a parameter and selects joining table based on the results.
View 7 Replies View RelatedWe are making a program--but every time we input a value for scanf, the following for loop does not work and the program quits without displaying the for loop's function. We are not getting any errors.
View 11 Replies View RelatedI need to program and simulate a 2 floor lift control system. How to do that ? I need to design its program only.
View 1 Replies View RelatedHow to write a program that will prompt and read 5 numbers. Then the program should print numbers that are larger than 80.
View 1 Replies View RelatedI was given an assignment to create a simple program for traffic control. How should i output data at a specific time, for e.g a driver approaches an intersection, the yellow light will flash indicating that he needs to slow down and then the red light to stop before taking a route. is there any function i can use to output red light a few seconds after yellow light.
View 10 Replies View RelatedI am having problems at the end of the program with the do-while loop to restart the program and the validation.
#include <iostream>
#include <string>
#include <iomanip>
#include <cstdlib>
#include <time.h>
using namespace std;
[code]....
I need starting a do-while loop in my program that runs up to 10 time that asks the user to enter up to 10 scores, which include the slope and rating for the course, and calculates the handicap for each score.
Here's what I have so far:
Code:
{
//This program calculates a golfers handicap.
#include <iostream>
#include <string>
using namespace std;
[Code] ....
I've just started to learn C programming. In following program I need to use a loop, so at the end, it asks the user that if wants to try other numbers or not. If yes program restarts from beginning.
Code:
/*
A program who checks three positive integers to be 3 sides of a triangle and calculates the area and shows the triangle type.
*/
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
int main(void)
[Code] .....
3. Write a program that reads a sequence of positive integers and prints out their sum, except that if the same number occurs several times consecutively, ignore all but the first. Assume an input of 0 marks the end of the input. For example, if the input is 3 8 5 5 4 9 1 1 1 1 8 0 then you should print 38 (i.e., ignore one of the 5's and three of the 1's).
View 5 Replies View RelatedI'm trying to write a program for a lab, I know how easy it is but cant see to crack it.
I need to make a program using while or for loop.
I must have the user type a number, for an input value an output value but then do it again several times but without it going on forever asking again and again.
How to make a loop so program never end, it end only by typing "EXIT"
View 1 Replies View RelatedI need a program in c++ that will enter a limit of the loop. using nested for loop with a limit of 3 loops only.
like this !
for (){
for (){
for (){
cout
}
}
}
Sample output:
Enter a number : 3 [enter]
1 2 3
4 5 6
7 8 9
2 3 4
5 6 7
8 9 10
3 4 5
6 7 8
9 10 11
So I learned how to make a basic for loop and I decided to try my best to make an infinite one. Every time I run it, it doesn't say anything and just closes. Visual Studio doesn't say there's anything wrong with my code.
Here's the code
#include <iostream>
#include <conio.h>
using namespace std;
int main () {
int d = 9;
for(int k = 10; k < d; k = k +1) {
cout << "For loop value = " << k << endl;
getch();
} }
I was asked by my teacher to create while loop for this, iv have completely for gotten how and all the tutorial that i have found show basic lopping.
#include <iostream>
#include <iomanip>
using namespace std;
void checkAnswers(char[], char[], int, int);
int main(int argc, const char * argv[]) {
int choice = 0;
const int num_question=20;
const int min_correct=15;
char answers[num_question] ={
[Code] ....
I'm trying to get this program to return total taxi cab fair an infinite number of times, however, when I use the while statement after for and try to run the program, it just keeps displaying the first total fair rapidly.
specifications:A cab company needs a program to calculate the cost of a cab ride.
The driver will enter the length of the trip in miles.
The miles entered must be greater than 0.
Create a function to calculate the charge. The function should receive one argument, the length of the trip, and should return the total fare for the ride.
The taxi charges a fixed charge of $2.50, plus an additional charge of $1.85 per mile.
Allow the user to calculate any number of trips.
At the end display the total of all the fares.
here is my code:
#include <iostream>
#include <iomanip>
using namespace std;
//function prototypes
double getLength ();
int main () {
[code]....
I'm writing a series of basic decipher programs and I have run into an issue where I get the correct answer when I start the loops at the iteration that contains the correct answer.
Code:
// generate key "words" with length of 3
for (int x = 0; x < 26; x++){
for (int y = 0; y < 26; y++){
for (int z = 0; z < 26; z++){
[Code] ....
This is the essence of the loop, I've attached the program in its entirety if necessary. Basically what happens is if I start the loops at x = 17, y = 7, z = 12, then I get the correct decipher shifts but if I start at 0,0,0 whenever it gets to that iteration (12,000 ish) the shifts are off by 2 or 3. "koq" should translate to "the" but im getting "dcz". Is this a simple bug in the or is something moving to fast for something else to keep up?
l3_ws.txt
main.cpp