I want to move a character in a 2D array This Character should move vertically in a 2D Array To exemplify it for Exam in Snake Game A character automatically moves Please Write a example code that works
View 4 RepliesHow can I move a character around a 2D map? After some research and a bunch of work I made a function for movement:
unsigned int gamespeed = 100;
unsigned int stage = 1;
void controls()
{
[Code]....
Maps are stored in a different .cpp file
So this code works, but is complicated, ugly and evil (I have to make a pointer to the first map and change the pointer to the next map every time the user reaches the exit, without the pointer this code is, of course, incompatible). How can I reduce this code to be less evil/ugly or at least smaller?
Also it would be nice if the user could move around with arrows as well as with WASD
Can we do this :
Code:
char strings[][100]={"ABC","EFG","IJK","LKM"};
char temp[100];
temp=strings[1];
Just making typical console game where hero moves with w a s d.
However, in my code, while a and w work (minusing), s and d dont work (adding). I have used a switch statement to change the char position of the hero based on kbhit.When you hit s or d, the buttons that add 1 to the 2nd dimension of the array, the screen goes crazy!
#include <iostream>
#include <string>
#include <conio.h>
#include <ctime>
#include <cstdlib>
using namespace std;
const char PLAYER = 'H';
[Code] .....
The program should store a character array in reverse order then display the reversed array. I have also included in the code that will display the actual characters into the array as it loops through. So I know the characters are being stored, but why doesn't it display the entire string when I call it?
Code:
#include<stdio.h>
int main(){
char str[50];
char rev[50];
printf("Enter Desired Text: ");
scanf ("%[^
[Code] ....
Is it just my compiler?
I am currently having an issue with validating user input for a state abbreviation. I have an array where a list of abbreviations is stored to use as a comparison for whatever the user inputs. I have been able to get the list loaded properly but whenever i go to compare, it always comes back as true even if it isn't. Here is some relevant code:
static char stateTable[STATE_TABLE_SIZE][STATE_SIZE];
int main() {
char buffer[40], *testCustName[40], testState[5], testCode;
buffer[0] = ' ';
int quit = 0;
int p = 0;
[code].....
this function subtracts a given value for each element in an array. I If the array is: hellohowareyou, and the value is 6 then result will be : 6 characters from each letter in the initial array
and the prototype of it is:
void minusFromArray(char arr[], int size, int value);
how do i convert each element in the array into ascii and subtract the values from those ascii characters?
I'm having a little trouble writing program that on remove all repeat characters and leave only the non repeated characters. This is want I have so far.
#include <iostream>
#include <cstring>
#include <string>
unsigned repeatingCharCount(char const* s) {
std::string unique ;
const unsigned length = std::strlen(s) ;
[Code]...
How to extract a floating value from a character array in separate variables .
Example : multiply 7.5 with 2
Out put : 7.5 , 2
How do i delete the first character in a character array?
I want output to be
void DeleteFirst (char S[ ])
{
for( int i = 1; i < MAX_LENGTH; i++)
cout << S[i];
}
i am just writing the wrest of the Array without deleting the first. how do i delete the first?
I have a character Array 'Hello'
I want to add a space in whatever space the users chooses.
"Where do you want to add space? --> " 3 String after space is added --> 'Hel lo
I am trying to clear the first character of my array. The first two methods don't seem to work. The third method seems to but doesn't look like a good idea.
char operand[] = "abc";
//both methods seem to null it out
operand[0] = 0;
memset(operand, 0, 1);
printf("%s", operand);
//seems to work
memset(operand, 5, 1);
Code:
class Robot{
char name[15]; //assign to char n
int x, y , direction;
void ToString(int d);
[Code]......
how do i assign char name[] in the class to char n in the constructor?
I am creating a program and am having trouble with one part. The input file looks like:
Code:
2
3
Bill Jeff Steve
Linda Brittany Jessica
3 1 4
2 1 9
8 3 7
6 4 9
4 8 9
6 9 4
Where I am stuck is putting the numbers into the string array. For example, Bill's scores should be set up as Bill's scores should be set as
Code: bill_score = {3, 1, 4}
and when this code is ran
Code:
for (i=0; i<3; i++) {
printf("%s - ", men[i]);
[Code].....
I am able to work with n instances of a structure in one mallocated area, but when I try to do the same thing with just character pointers, I get compiler errors about making integer from pointer without a cast. If I create a structure with just a character pointer in it, it works just fine... I am just not seeing something here!!!
This works:
Code:
#include <stdio.h>
#include <stdlib.h>
int main (void) {
struct items {
unsigned int item_1;
unsigned int item_2;
[Code]...
This DOES NOT work!
Code:
#include <stdio.h>
#include <stdlib.h>
int main (void) {
char * items_ptr = NULL;
unsignedint i = 0;
char * one = "one";
char * two = "two";
[Code]...
I am still working on my project which will be reading some old data from some old DOS files. The data stored there is naturally, char*. Once I read in my character array, how do I assign this to a wstring since my application is UNICODE?
Here is my current solution:
wchar_t* Class::Function(char *pName) {
//I verify the pointer and such first, then do the below
this->_Name.assign(pName, (pName + strlen(pName));
return this->_Name.c_str();
}
Am I on the right track here?
I have to write a function Subtracts val from each character in the array
// If the array is: abcdefghi and value = 5, then result is: 5 ascii characters subtracted from the given array
// note: Make sure the character remains in the ' '
// to '~' (inclusive)
// If character < ' ', then add 95
// If character > 126, then subtract 95
// to put back within the range, and repeat as needed
// all printable characters are between this range
// ' ' is the 1st printable character (32)
// '~' is the last printable character (126)
note: subtracting values from the char will cause an overflow.
the prototype is: void subtracting(char array[], int size, int value)
i have a problem i cant find a way to count how many times a character occur in a character array the out put should be
a=2
b=1
but my output is
a=2
b=1
a=0
i cant find away to get rid of the other a letter i dont know what to do
#include <iostream>
using namespace std;
int main() {
char array[3] = {'a','b','a'};
char frequency[26] ={'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
[Code]...
m_sName-- character array shall be 128 bytes
How do i create a character array that has 128 bytes?
I'm taking an intro to programming course and my assignment is to Write a very simple program that uses two for loops and ONLY pointers and pointer arithmetic (NO other variables are allowed) to display a palindrome forward then backward. Declare the palindrome as follows: char str[] = “Straw Warts”; Well my prof never did anything with char arrays and I can't quite fit make the pointers work in the loop. This is my code. It runs how it should, i just can't seem to make a working for loop. It always says that you can compare int and char
#include <iostream>
using namespace std;
int main()
{
[Code]......
Its been too long since I have had to fiddle bits and I am coming up short.
Bottom line is the new IPv6 ip address representation is of the format:
xxxx:xxxx:xxxx:xxxx:xxxx:xxxx:xxxx:xxxx
These come to me as hex values for example:
2001:7D7E:0000:0000:111A:222B:333C:4444
I want to store this in a char array, of integers of size char_addr[16] where each byte represents the integer representation of each xx pair thus
char_addr[0]=32 (20) *note address above
char_addr[1]=1 (01)
char_addr[2]=125 (7D)
char_addr[3]=126 (7E)
char_addr[4]=0 (00)
...
char_addr[15]=68 (44)
So I am having trouble filling that char_addr array.
I keep getting this warning message and I do not know how to fix it. Is it because I'm using char to instead of strings to replace all 't' with 'lp'?
#include<iostream>
#include<string>
#include <stdio.h>
using namespace std;
char * scanf(char * a) {
[code]....
Double values are stored in text file. 23.5 36.8 34.2 ... My teacher told me to read them character by character and then make words, like i have to read "2" "3" "." "5" and now have to make it or treat it as word and then using atoi(). I have to convert it into double. but i dont know how to do this....
View 5 Replies View RelatedI am attempting to change a character in a character array.In the code below, there are three attempts to do this. Only the first one will succeed. The last two both segfaults. If I understand correctly, str_one is declared in the heap, and could therefore be manipulated; and in contrast, str_two is declared in the stack and is therefore immutable, thus the segfault, when update it is attempted. However, I understand that using malloc, one is able to assign a pointer and allocate space in heap memory. Thus, I should be able to manipulate the assigned variable str_three. Doing so, however, results in a segfault.
Code:
#include <stdio.h>
#include <stdlib.h>
int main (int argc, char const* argv[])
{
char str_one[4092] = "This is string number one";
char * str_two = "This is string number two";
[Code]...
I'm trying to make a character array, and be able to custom fill it by using the scanf() function to ask the user for each character spot in the array.
Code:
#include <stdio.h>
int main() {
int i;
char character_array[11];
char *charpointer;
charpointer = character_array;
[Code] .....
And this is the output i get when i run it:
Code:
root@kali-Tulips:~# ./myown
what letter would you like in the [0] spot of the array? :
a
what letter would you like in the [1] spot of the array? :
what letter would you like in the [2] spot of the array? :
b
what letter would you like in the [3] spot of the array? :
what letter would you like in the [4] spot of the array? :
[Code] .....
Obviously I'm trying to grasp C programming and am very new. I don't understand why this isn't working, and i think its more than my lack of knowledge of C syntax. I believe the correct memory is allocated but when examined with gdb i don't find what i expect....
I've initialized a character array in my main, and passed it onto one of my functions convertToPostfix(char infix[], char postfix[]). It isn't a constant read only array (constant char*) ive explicitly initialized it to char postfix[] = "";
Code:
if ((nextChar > 47) && (nextChar < 58)){ //if its a digit
postfix[++postfixIndex] = nextChar;
while (infix[i + 1] > 47 && infix[i + 1] < 58){
nextChar = infix[++i];
postfix[++postfixIndex]=nextChar;//segmentation fault when assigning from infix to postfix**
}