I can get the first letter to change if there is only one word. But if there are two words it wont change and display the second word's first letter and I'm not sure why.
#include <iostream>
#include <iomanip>
#include <cstring>
[Code].....
can i do in this way to check if letter is upper case or lower case is it better to using casting or i can do without casting.
Code:
if(selectOption == (char)81){
selectOption = (char)113;
}
I just dont know how to get my upper case and lower case equal...heres the program: Write a program to calculate utility cost for ACME UTILITY COMPANY. The company has 3 types of customers (R) residential, (C) Commercial and (G) government. Customers are billed based on the number of kilowatts used and they type of customer they are (R,C,or G).
Residential cusstomers are charged 0.25 cents per kilowatt hour for the first 500kw used, and 0.35 cent per kwh for all kw used over 500.Commercial customers are charged 0.22 cents per kilowatt hour for the first 999kw used, 0.29 cents per kwh for all kw used over 999 kw up to 1999 and 0.45 cents per kwh for all kilowatts used greater than 1999. Commercial customers that use over 2000 kw are charged a special surcharge of 100.0 in addition to the regular charges.
Government customers are charged 0.34 cents for the first 1500 kwh used(<=1500). 0.30 cent for the next 1000 kwh(1501-2500) and 0.25 cents for all kwh used over (>=2501)
in addition residential customer are charged .5% tax on the cost utilities while Commercial customers are 5% tax on the cost of utilities not including the special surcharge Government customers are not charged a tax
Code:
#include <stdio.h>
#include <math.h>
int main(void)
{
int R;
int ct;
int kwh;
int taxes;
int surcharge;
int charge
}
[code].....
the program should quit with Q and calculate the amount owed, utility charge, and surcharge
Write a program that reads characters from the keyboard using the getch() function. All lower case letters will be converted to upper case and printed out to the display using the putchar() function. All uppercase letters will be printed using putchar(). All individual digits will be accumulated and the sum will be printed at the end of the program using printf(). You will write a function to return the upper case of the letter and a second function which receives the current sum and the character digit.
The convert digit function will convert the character digit to a decimal value and accumulate the digit to the sum returning the new sum. Only the letters will be printed out nothing else. The program will continue until the return is received at which time the sum of the digits will be printed on the next line. What was entered: a9 wF23’;/4i What the line actually shows: aA9wWFiI The sum of the digits is: 18
I dont understand why it expects more () in the functions....
My code so far
Code:
#include <stdio.h>
#include <ctype.h>
#include <string.h>
[Code]....
I keep getting these 3 errors :
error expected '=', ',', ';', 'asm' or '__attribute__' before '{' token|.
error expected '=', ',', ';', 'asm' or '__attribute__' before '{' token|.
error expected '{' at end of input|.
"C++ is a general-purpose programming language." I have to find the word "C++" and replace it with "Java" and then capitalize all letters.
#include <iostream>
#include <string>
using namespace std;
int main( ) {
string origin; //contains input string
string replace; //the string obtained by replacing "C++" with "Java"
[Code] ....
I am trying to understand why i keep getting errors in my code. The errors are after the string is converted in my console window. I have to allocate and delete memory via dynamic array to do the problem.
#include<iostream>
#include<string>
#include<cctype>
using namespace std;
int main() {
string sentence;
int size;
[code]....
I just want to know why the extra characters are at the end of my conversion and how to make them stop.
I am unsure how to write a function which modifies the content of the 1D character array and puts all of the letter it contains into uppercase. the following are the letters which i am trying to convert.
char text[MAX+1] = {'T', 'e', 's', 't', 'e', 'r', EOT};
The output to this should look like T E S T E R EOT
Write a program that inputs a string and then converts each 1st letter of a word in the string into capital case. An example run of the program is shown below:
Enter string: introduction to programming
Output string: Introduction To Programming
I am building a tamagotchi like application/game. As for the leveling up and changing of character I am using a char value so that the icon can change as the character progresses.
Due to the fact that the value for level is changing I need it to also change for what is being used for the case statements
I know I cant use variables in case statements because I have tried every way I can think of.
The code is
switch(Area[y][x])
{
case '*':
Area[y][x] = Level;
break;
case 1:
{
CODE
}
}
Where I have the case 1 I need it to change as level increases (as level is starting at 1)
Code software that, from an original text file, generate another file with the text content in upper case.For exemple:
entrence:
luke
tom
alex
outings:
LUKE
TOM
ALEX
My code so far:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
}
[code]....
This code ran well until i added in the ToLower function which is supposed to convert the char array string to lower case (based off ascii strategy -32). correct this function so it converts string to lower case and doesn't get errors.
#include <iostream>
#include <string>
using namespace std;
const int MAX = 81; //max char is sting is 80
void ToLower(char s[]);
int main(){
string y_n;
[Code]...
I have this array (assume sorted) and i need to find out the closest upper value for any input int. Example:
Code:
/* bsearch example */
#include <stdio.h> /* printf */
#include <stdlib.h> /* qsort, bsearch, NULL */
int compareints (const void * a, const void * b) {
return ( *(int*)a - *(int*)b );
[Code] ....
So whenever i hit something that is not in the array i would like to know the closes upper value. So for 4 closest upper value is 5, then for 8 it is 12 , for 35 it is 44. how would one do this?
This is a program to print upper half of the matrix.
#include <iostream>
using namespace std;
int upperhalf(int n, int apu[n][n]) {
cout<<"The upper half of the matrix is :
[Code] ....
the compiler is giving these errors:-
sh-4.2# g++ -o main *.cpp
main.cpp:4:31: error: use of parameter outside fun
ction body before ']' token
int upperhalf(int n, int apu[n][n])
[Code] ....
I dont know where i am wrong.
My coin/money change code works when there can be an exact change each time, i.e. when the 1 cent option is available. However, when the change options are only $10, $5, $1, 25 cents and 10 cents, it does not give me what I want for instance, I wanted to get change for $237.80, I was expecting to get:
23 10's, one 5, two 1's and 8 dimes. However, the code below is giving me 23 10's, one 5, two 1's and 3 quarters (there is no option left for the 5 remaining cents).how to fix it?
Code:
#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;
void change(double cents, int a[]);
int main() {
double Dollars;
double cents;
[code]...
I was investigating for the first time how to generate prime numbers with a considerably high upper limit, around 10^6 or so. I read about sieve's algorithm and tried to implement it using c#, as I had previously brute forced the generation. In Sieve's algorithm, instead of marking the values that were not prime I simply eliminated them, but I don't think that would make any difference. The issue is that my implementation of sieve's algorithm must be wrong, as when I establish the limit as 10^5 I get the following output:
Brute force:
Computation time: 00:00:00.0643539
Sieve's algorithm:
Computation time: 00:00:20:6934223
I have already checked that their generation of primes is correct, but I do not know why one is significantly slower than the other. Here is my code.
using System;
using System.Collections.Generic;
using System.Linq;
[Code].....
I need to print like below pattern.
1
121
12321
1234321
123454321
1234321
12321
121
1
I got the upper pattern but below pattern is not working it executes infinte loop, how to reslove this.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ro {
class ro {
static void Main(string[] args) {
int numberoflayer = 5, Space, Number;
[Code] ....
how can my program read if a letter is inputted again it prompts "letter inputted already"? heres my code:
Code:
#include <stdio.h>
#include <string.h>
#include <conio.h>
[Code].....
Can I capitalize first letter of each word without using arrays ? If yes, how can I ?
View 11 Replies View RelatedI am trying to print out the letter frequency of a vector that the user inputs and what number that letter is in the ASCII. I am supposed to say, for example: "w" which is ASCII 119 occurs 2 times. How to do this?
View 1 Replies View Relatedi`m currently racking my brains out over this issue. How do i go about the x as the first occurrence of the letter?
lets say helxo , x is the 2nd occurrence of l. I will want to change back x into l
i have replaced it with x in the earlier step with this code...
string everySecondChar(const string &s,char source,char distance)
{
string t(s);
for(std::string::size_type even =0,pos=t.find(source,0);pos!=std::string::npos;pos=t.find(source,++pos))
{
[Code]....
i would like to reverse the process now, letting x becoming l again!
I am new to c++. I am writing a program that reads in a text file and gives a count of how many times each letter appeared in the file. I got it to read the text file and do the letter count. B
X = 102
Y = 126
Z = 165
etc...
THAT IS WORNG
The sample output should be
E = 165
T = 126
A = 102
O = 93
etc...
I got it to sort from lowest to highest for the frequency, but cant seem to get the appropriate letter assigned to it.
#include <iostream>
#include <fstream>
#include <iomanip>
#include <string>
[code].....
Supposed i have a word hammer.
how am i suppose to search for the 2nd occurrence of the letter and then replace it with x?
example hammer will become hamxer
I thought about using replace for it, however i`m lost on how to find 2 occurrences of the same letter in the word.
string formatEncrypt(string message) {
int msgLength=message.length();
for(int i=0;i<msgLength;i++) {
if(message[i] == 'j' {
message[i]='i';
[Code] .....
at line 31 i tried to put a z into the alphabet that occurs twice.
this is what i have done so far
example: hello world
It will turn out as helzlo world
However i want to make the output appear as helzo world
How would I detect if any letter key is pressed. Would I have to use GetAsyncKeyState() for every letter key? Or could I have some kind of loop going through all the hexadecimal values for every letter? I don't know how I would go through hexadecimal values with a loop.
View 6 Replies View RelatedI need to count how many times letter appears in a text. I know that for default letters from 'a' to 'z' and from 'A' to 'Z' there is an interval. But I need also Lithuanian letters, such as ž,č,ę. I wrote this method: (it accepts char code and checks whether that char is a letter)
bool eilutė::YraRaidė(int kodas)
{
if(kodas >= 'a' && kodas <= 'z') {
return true;
[Code]....
As you can see, a lot of checking in switch statement. I use 256 for this reason to have the same effect as unsigned char. But maybe there is a way to shrink down this method, or use some library?
I just would like to turn this into cpp:
string eg("azertyFTW");
if(eg[one of the letters contained in this string] == 'c') {
cout << "eg has the letter c in it";
} else {
cout << "not this time :(";
}