C++ :: Using String And Atoi At Same Time
Aug 25, 2013How do I use string and atoi at the same time?
string scroes;
char input[SIZE];
cout<<" Enter your score" << endl;
cin.getline (input, SIZE);
scores = atoi (input);
How do I use string and atoi at the same time?
string scroes;
char input[SIZE];
cout<<" Enter your score" << endl;
cin.getline (input, SIZE);
scores = atoi (input);
char intToStr(int a) {
int n, i, j, sign, set;
char r[10], s[10];
if (a[0] == '-')
sign = -1;
if (sign == -1)
[Code] ....
I have doubt at the time of handling of negative numbers at the time of converting to string ....
Intead of using scanf("%d",&a) to take a input from the user,how to take a input using fgets(buffer, BUFFERSIZE , stdin) and atoi?
View 1 Replies View RelatedI have saved the contents of an int vector to a txt file and the numerical data was converted into a c-string. Nov I need to import and read the contents back into my program but I have not been able to convert c-string numerical data back into ints.
View 1 Replies View RelatedThis is what I have:
#include <ctime>
#include <string>
using namespace std;
void date_and_time(string &date, string &time){
time_t current_time;
[Code] ......
Is there a way to make sure that the strings would not contain trailing spaces?
Is there a variable that can hold string and int in the same time?
If not, what can I do if I want to input data with string and int like a password for an example.
I have a vector<string> of times that I want to convert to vector<double>. The time string is in the form 00:00.000. Is there a STL or something like it algorithm or function to do this, otherwise what would be the best way to do this with a function.
View 3 Replies View Relatedmay i know how do i read a string 2 characters at a time?
lets say i have a for loop like this
for(int i=0;i<stringLen;i++)
{
for(int j=0;j<???;j++)
{
//insert code
}
}
what i want to do is i want to read a string 2 characters at a time and store them into a vector.
I would like to have a program with a 5 mb string embedded in it kind of like this:
Code:
const char *c;
c = (const char*)"BEGIN_STRING_HERE, (5 MB of arbitrary values here)";
Is it possible to generate this string at compile time? Maybe with a macro? I'm trying to avoid a source file with a 5 mb string in it.
How can I read a file that contains numbers only, but read it by three digits at a time? I have a long string of numbers and every three digits corresponds to a particular number in itself. i.e. a string of 064045154 would need to be read as '064' '045' and '154'. I need to then subtract one from each of these numbers and the new values I need to convert into their ASCII characters and place these in a new file. This is what I have (focusing on the 'Decrypt' function) but all it does is in the new file place a string of the same character repeated over and over a total number of times equal to the number of integers in the numbers file.
Code:
#include "stdio.h"
#include "stdlib.h"
#include "string.h"
#include "limits.h"
int Encrypt(char * FILENAME)
[Code]..
This is a round robin execution. with gantt chart. arrival time and burst time. I think there is an error in my formula to get the right answer,i cant resolve it but my program is running. What is the code or the right formula??
#include<stdio.h>
int main(){
int i,j=0,n,time,remain,flag=0,ts;
int sum_wait=0,sum_turnaround=0,at[10],bt[10],rt[10];
int ganttP[50],ganttStartTime[50];
printf("Enter no of Processes : ");
scanf("%d",&n);
remain=n;
[Code] ....
So I'm trying to learn how to use time for time based movement and what not. I did this only knowing the command time(&variable)
time_t timer;
int I, X;
void main() {
time(&timer);
X=timer;
while(I==5) {
[Code] ......
There's probably some other better way to do it... Obviously but for now I see it as putting current time in X.
start while
take in time constantly until I is 5
constantly asking is time>X(preset time 5 seconds ahead)
if it is
display message and add one to I
Why doesn't this display my message after 5 seconds?
make a time-in time-out fuction which extracts the no. of hours and minutes from a string entered by the user.
#include <iostream>
#include <fstream>
#include <string>
[Code].....
when we would use add items at design time and when we would add them at run time
does it have anything to do with the page load method? if so, can i type this in source code instead?
why nGrade comes out as 0 every time?
Its as if im not inputting the values into the dynamic arrays in int main.
#include <iostream>
using namespace std;
void Calc(int a_anScores[], int a_anPerc[], int a_nTotal){
for( int iii = 0; iii < a_nTotal; ++iii){
a_anScores[iii] = (a_anScores[iii] * (a_anPerc[iii]/100));
}
int nGrade=0;
[Code]...
I have created this code with the classes for time and message. Basically the point of this code is to give the information of the sender, recipient, time, and message and im having issues with the time part.
#include <iostream>
#include <string>
#include <ctime>
[Code].....
so when you run this you can see i left a spot for the time but I just cant figure out how to figure out the Time part of this.
I am trying to make this while loop cut out / self break after 3 seconds. It is part of a simple game I am creating that gives the users 3 seconds to react otherwise it moves on to the next part.
while(1) {
key=getch();
if(key=='a'||key=='k'||key=='g') {
break;
}
}
All I need is it to end after 3 seconds, the rest of the code is working fine.
This sort of thing:
long startTime = System.currentTimeMillis(); //fetch starting time
while(false||(System.currentTimeMillis()-startTime)<10000)
If it IS for C, then I implemented it wrong or something.
I want to convert time from est to utc. Is there any function for this.
View 3 Replies View RelatedI just spent 3 hours writing and debugging 37 lines of code. Is this normal or am I "below average" in coding abilities. I come from a C background and decided to write C++ code that I finally got right as shown below for the specific example:
Code: #include <iostream>
#include <fstream>
#include <string>
#define SPACE_SEARCH 10
using namespace std;
[code].....
I think it was more the learning along the way that consumed atleast 75% of my time for this specific case. But then again, I read that programming always entails learning along the way and so its somehow no excuse for the long time taken in this specific case.
So as a matter of interest, what pace do all of you operate on, on average? i.e. LOC/day, Debugs per day or any other indicator of productivity?
I tried to write a simple program to calculate monthly yield, APR, and principle in various directions. Anyway, here's some code to get the APR from the principle and monthly yield. When I run it though, it spits 0 at me every time! What the problem is; the other functions work just fine and the code line for the APR calculation is just what it ought to be - I see neither a math nor tech problem here.
Here is the offending function:
Code:
void calculateAPR() {
int principle, monthlyYield, apr;
cout<<"
Please input the principle:";
cin>>principle;
cin.ignore();
[code]....
I am looking for simple code that subtract two time interval. I have time t1=5hour 30 minute and other time in 24 hour format. This code i written but it not working as expected. it not printing 5:30 minute subtract
Code:
main() {
intTime1;
intTime2;
int hour=10;
int minute=5;
int second=13;
int h;int m;
doubleNtime;
[Code] ....
The issue is that I am trying to run a code which can trigger different timers at the same time. That is, when 3 is typed by the user, the firstimer is triggered. If before expiration another 3 is introduced, the second timer will be launched, and the difference between both triggers will be shown. Under this circumstance, timer_gettime only works once. I tried all the things I could imagine but still, it_value_tv_sec and _nsec return zero after the first expiration.
-Theoretically, and following the manuals, once the timer is restarted the gettime function should work as it does the first time.
-I have also tried to removed the timer and start it again, but in this case the timers are still being triggered, but the gettime outputs(even the first time) are nonsense.
Here is the code I am testing: [CODE]#include<stdio.h>
Code:
#include<signal.h>
#include<time.h>
timer_t firstTimerID;
timer_t secondTimerID;
timer_t thirdTimerID;
[Code] ......
I created a program to display time continuously so it auto updates every sec but the issue is i cant integrate the code in the main program because to make time update continuously it needs a loop a infinite loop so none of the rest program gets to work. My q is : is it possible to display time continuously and make the rest of program continue normally? like a multi thread program because i want to display time every sec in the bottom of program. By the way this is console app not gui
View 8 Replies View RelatedWrite a program to convert the time from 24-hour notation and vice versa. Your program must be menu driven, giving the user the choice of converting the time between the two notations. Furthermore your program must contain at least the following function : a function to convert the time from 24-hour notation to 12-h notation, a function to convert the time from 12-hour notation to 24-hour notation, a function to display the choices, function(s) to get the input, and function(s) to display the results.
View 2 Replies View RelatedI have a code to check the last time modification of a file using "gmtime". Is it possible to remove the seconds in the result?
Here is my code:
struct tm* clock;// create a time structure
struct stat attrib;// create a file attribute structure
stat("test.txt", &attrib);// get the attributes of afile.txt
clock = gmtime(&(attrib.st_mtime));// Get the last modified time and put it into the time structure
Why in this code the destructor is called 2 time? How can i avoid it?
int _tmain(int argc, _TCHAR* argv[]) {
Elenco e1;
std::cout << "Test 2" <<std::endl;
std::cout<<e1.size()<<std::endl;
[Code] ....