Error 1 error C3867: 'std::basic_string<char,std::char_traits<char>,std ::allocator<char>>::size': function call missing argument list; use '&std::basic_string<char,std::char_traits<char>,st d::allocator<char>>::size' to create a pointer to member.
error C3867: 'WordParsor::Form1::PutUpfrmIO': function call missing argument list; use '&WordParsor::Form1::PutUpfrmIO' to create a pointer to memberc:userskingc++wordparsorwordparsorForm1.h... and the suggestion fix generate another error.
One person suggested the gcroot<> object wrapper... but I do not know how to modify/declair the function or its argument type.
I am new to C programming and I am trying to compile and run an exponent program my instructor posted for us but it is giving me an error saying:
Warning c4550: expression evaluates to a function which is missing an argument list.
Why this is happening (she doesn't seem to find anything wrong with the code). From what I could gather there is some issue with the math but idk. It is supposed to prompt for the number and the exponent to raise it to, then calculate and output the result.
Code: #include <stdio.h> int main() { int base, exp; long long int value=1;
I was trying to look up solution for this for quite a while already but found nothing. I am writing a simple console based turn based RPG game for my class project. I was trying to have a member function attack() in class of the player character, which affects the component called health of the class Enemy. both this classes are inherited from the base class Unit. I tried to pass the object of type enemy as an argument to the function attack, but the function call gives me Error: too many arguments in function call. Here's the code for classes:
We are programming a function calculator and my instructor hinted that the add() function is almost exactly like the subtract() function and we would only have to write one function if we "called it in a special way." This got me thinking, can I turn a function's argument to negative during the call to make it subtract?
Example:
void addSub(int &num1, int &num2) into this void addSub(int &num1, int -(&num2))
I try to use passing function as argument but I'm stuck. I have two questions: First, I try to call uppercase and open .txt in tfm Second, How can I read characters from in.txt as string and assign to char content[] ?
#include <stdio.h> void tfm( char str_filename[], void(*pf_convertion)( char content[])); void uppercase(char content[]); //converts all letters to uppercase int main(){ puts("-------------------------------"); printf("tfm: "); tfm("in.txt", uppercase);
Im using a recursive function to sort array. The decrement operator is used to eventually get to base condition in function. Used debugger the size-- expression is not decrementing. I figured out how to fix it but dont quite understand it.
[coed]
#include "stdafx.h" #include <iostream> void selectionsort(int [], int); int main() { using namespace std; const int arrysize = 10;
I'm trying to get a Browse Directory dialog to update a text box with the path selected. I had it working fine in Unicode build but now using TCHAR - I see the variable contains the correct path, but the textbox only gets updated with a single weird character.
write a code using vs studio 8 to read a diretory name as argument and then open the directory and read each file one at a time and find the match for a string passed as an nother argument in the lines of each file. When it matches create a file and write in that output file the file name whetre the match found, the line number and line which matched.
My vis does not have dirent.h. so please use another ways to read directory call witha system acll and then then extract the fienames in a file(use some primitive way to open the the directory)
I cant do this parts
(1) read a directory
(2) create a file with only file names
(3) read file names ans open the files one at a time till the end of the file reached
I'm having some issues with my code. For the produce function i am getting an error saying 'no instance of overload function produce() matches the argument list' and also for the lines buffer[head].data = message; buffer[head].time = current_time i get an error saying 'expression must have pointer to object type.
In the code i'm not sure if i passed the variables to the function correctly. I have attached the code .....
Hey I am trying to use the getline() function to read a line from a file. For some reason Visual Studio 2010 gives me the following error. "No instance of overloaded function "getline" matches the argument list". The piece of code that produces the error is in a class in a separate .h file and is executed as a method of the object. I'm almost certain it has something to do with either the compiler thinking I am calling another getline in a different namespace or my parameters for the function are incorrect. Here is the code:
Code: #include <iostream> #include <string> #include <vector> #include <fstream> using namespace std; class InsultGenerator
I'm trying to develop a program that stores a list of hw assignments in the form of "Date,Assignment name,grade". I have functions that add,remove, and delete from a list, but I would also like to search and delete a particular date found in the list. From here, split - Splitting a string in C++ - Stack Overflow I've tested Evan Teran's method to split a string, but I'm unsure of how to implement it in my code.
List.h Code: #ifndef LIST_H #define LIST_H #include <string> using namespace std; class List{
I am trying to generate a couple of vectors, but the exact number of vectors that will be needed can only be determined at runtime. Therefore I had the idea to use a macro call and text substitution in order to declare the necessary number of vectors. Unfortunately, the arguments of a macro call are always (as far as I know) considered text only. So, the loop in my example below in which I am trying to generate the following code:
Write a program that creates a forward linked list of at least 20 elements, where each element holds a random integer between 0 and 99. Print the list.
Write the function "returnMiddleList" to find the middle element of the linked list in one pass. Print the integer value of this element and the position of this element (starting at zero) in relation to the head (where the head = 0, the element pointed to by the head = 1, the element pointed to by the previous one = 2, etc).
Split the list in half at the middle element to create two entirely separate* linked lists of near equal size (+/- 1) and print the two lists. Modify the "returnMiddleList" function to accomplish this, returning the head of the second linked list and setting the link of the element pointing to that head to null. Then print the two sums of the integers stored in the elements of both lists.
Sort the two lists from least to greatest and print them out (printing at this step is optional depending on the sort approach taken). Then combine the two lists while sorting them again from least to greatest and print out the new list. (HINT: you can subdivide the lists further and sort them on a scale of one to two element lists before sorting and combining the first two unsorted lists. What is this sort called?)
I have got #1 and #2 working, but #3 and #4 is where the issue is beginning. When I split my link list into two lists and print the individual lists out, my first link list prints out 9 numbers when it should be printing out 10 (the 10th number somehow disappears?), but when I do the sum of the first list right after that, the number that has disappeared gets added in the sum! I do not know why it is disappearing, and this is one issue. Another issue is in the second list, a random "0" gets added to the list and one of the numbers is lost. My last issue is about #4 as the merge algorithm I have used does not seem to work (I am merging the list together while sorting them, but I am not using a recursion sort because we have not learned that yet).
#include <iostream> #include <stdlib.h> #include <time.h> using namespace std; struct nodeType { int data; nodeType *link;
I've been given a ton of code (5 files worth) that does various things with a linked list. I'm supposed to add a function to split this list into two separate lists by testing whether or not each number is <,=, or > a certain element. I am completely lost and don't understand linked lists at all. I'm also a bit lost on pointers since it's been almost a year since I've looked at programming, but I could probably figure that out if I could just get this linked list thing down.
Here's my SplitLists function so far:
void UnsortedType::SplitLists () { // Pointers for each new list NodeType* list1Ptr; NodeType* list2Ptr;
[Code] ....
In other places in the code, I have GetNextItem, ComparedTo, PutItem, and ResetList that were already given to me.
I am suppose to make a program that when the user is asked "Enter a Letter for the day:" if the user enters M or m then the screen will output "The day of the week is Monday" and so on until Sunday. I looked over my code and everything looks right but I still get errors saying Missing terminating character " and int function main error.
#include <iostream> using namespace std; int main() { char day; cout << "Enter a letter for a day of the week: ";
I am needing to code a shorted path algorithm through a sort of sudo-linked list. I say sudo because its not a true linked list as in *next *prev. The Data in memory that i need to do this through is in memory via a class.
The important parts of the class is one element is just an int that tells me the current node number, the second is an int that tells me how many neighbors this node has, and the third is a vector of ints containing the number of the neighboring nodes.
The vector was needed because each node type can have a different amount of neighbors.
For example if the class data looks like this:
0 1 1
that means that it is node 0, it has 1 neighbor, and the neighboring node is 1
another example:
8 3 1 2 3
means node 8, 3 neighbors, and the neighbors are nodes 1 2 3
I need to find a way to get from 1 node to another using this linked list, and the shortest path if we plan the data points well enough can be determined by how many nodes there are from start to finish.
