The code I have is below. Im able to print them all onto one line but I need to print 10 per line separated by commas and Im not sure how to do that ):
for (int i = 0; i < MAXVALUE; i++){
for (int j = 0; j < counts[i]; j++){
output << i << ",";
I'm a beginner at c++ and I need to write a program that reads a set of integers and then finds and prints the sum of the even and odd integers. The program cannot tell the user how many integers to enter. I need to have separate totals for the even and odd numbers. what would I need to use so that I can read whatever number of values the user inputs and get the sum of even and odd?
View 2 Replies View RelatedI need to write a ANSI program to print out each command line argument on a separate line using a for-loop. also it need to print the name of the executable .so far I have
Code:
#include <stdio.h>
int main(int argc, char **argv) {
int i;
printf("")
[code]....
Just working up for the google coding contest to start soon and have been practising some of the test questions however i make correct algorithms but my output is rejected because of the fact that my strings are printed on a new line so i wish to know a method to print strings using a printf statement or any other function on the same line ...
View 3 Replies View RelatedI know this works as expected if your command line arguments are strings.
#include <stdio.h>
int main( int argc, char *argv[] ) {
printf("Program name %s
", argv[0]);
if( argc == 2 ) {
printf("The argument supplied is %s
", argv[1]);
[code]...
Would you be able to do something similar to this if you have integers or would you need to use the first method then convert it with atoi?
#include <stdio.h>
int main( int argc, int *argv[] ) {
printf("Program name %s
", argv[0]);
if( argc == 2 ) {
[code]...
I have a file with such a format:
string string 8 7 2
string string 7 12 19 -4
string string 1
As you can see I don't know how many numbers there are at the end. I have this code now:
while(!in.eof()) {
kr = 0;
getline(in, pavard, ','); getline(in, vard, ','); getline(in, gr, ',');
while(in.peek()) {
in >> k;
kr += k;
}
in.ignore();
}
in.close();
I tried various combinations with peek() function, but nothing worked.
parsing integers and characters in same line.
I trying to parse g8,7.
{
token = strtok(NULL, ",");
token2 = strtok(NULL, "g");
}
I am trying to make 8 an integer so that i get two integers 8 and 7.
I already know how to get 7, but every time i do it i get (0,7) instead of (8,7).
I have a vector of integers, which can take values 0 or 1, say
0 0 0 1 1
I need to print indicators, telling in which position 1-values occur. So
0 0 0 1 0
and
0 0 0 0 1
Using a do-while loop, for loop, or while loop. This is what I have so far but i don't know what to do after that.
#include <iostream>
using namespace std;
int main() {
int num;
int min = 2;
int max = 256;
}
Also the results should be printed out with 10 integers per line, right justified in a 5 byte field.
I'm very very new to maps and am really just trying to hash them out by myself.
If you're mapping strings to integers:
map <string, int> myMap;
myMap[ "zero" ] = 0;
myMap[ "one" ] = 1;
How do I print the string "zero", for instance, from myMap?
cout << myMap.at(0) << endl;
doesn't work. Nor does:
cout << static_cast<string>( myMap.at(0) ) << endl;
I need access to the string using the int and the int using the string. Or just direct access to one or the other. . . It's just confusing that they're technically mapped to one another but I can't really access either of them.
I am trying to Write a program that inputs three integers from the keyboard and prints the sum, average, product, smallest and largest of these numbers. How do i go about it. What i dont know is how to come up with smallest and largest number .
View 1 Replies View RelatedI want to write a program to read in 15 integers from the user, and then store them in a 5x3 array, and print out the numbers as a 3x5 array.
View 7 Replies View RelatedMy C programming class wants us to write a program to read integers into an array, sort the numbers and print out the occurrence of each number. I've tried everything that I can think of but the core dump is still occurring.
void countValues ( FILE *inf, int list[], int size ); /* Function prototypes. */
void printFrequencies( const int list[], int size );
int main (void) {
int status = EXIT_SUCCESS; /* defaulting status to success. */
FILE *inf = fopen( "numbers.txt", "r" ); /* input data file */
[Code] .....
write a program in c to read a sequence of N integers and print the number that appears the maximum number of times in the sequence.
View 1 Replies View RelatedWe need a program that takes three names ( first middle last ) and print it each one at a different line...
View 5 Replies View RelatedI try to learn string class, resolving some problem, but i have some dificulties.The is ok, but when i print the longest string it does'n print on the same line.I enter the number of string, after that i enter the first string until i introduced from keyboard "#" character. I enter the second string and so on.Look at these example :
For i = 3;
Text[0] : I learn class String#
Text[1] : I dont learn class String#
Text[2] : String#
It print me like that : Text[1] :
I dont learn class String More than that look at the next example :
For i = 3;
Text[0] : I learn class String#abcdef
Text[1] : I dont learn class String#
Text[2] : String#
You see that in the first sentence i have continue to introduce some characters after # character and look what is happened :
Text[1] : abcdef
I dont learn class String
#include<iostream>
#include<string>
using namespace std;
int main() {
string text[100], cuvant;
int i, j, m, lung = 0;
cout << "
[code]....
I am using C++ to write data into a (.ini)file. However, when I try to print the value '0A' I am getting '0D 0A'. (this is what I see when I copy the output to HexEdit). From what I can figure out, '0A' is the ascii for 'new line' so write function automatically adds the '0D' which is 'carriage return'. What I want is to print 0A alone. how can I do this?
Note: Windows it is working fine, but linux it is not working...
unsigned char arrRes[4];
int N = 10;
memcpy(arrRes,&N,4);
std::ofstream Output(LUT_OUTPUT_FILE_BINARY,std::ios_base::binary | std::ios_base::out);
Output.write((const char*)arrRes, 4);
here 10 means 0x0a but it is printing 0d,0a...
I'm having problems fully comprehending how to do this task (I'm only going to include my function code since that's the basis of my problem). How should I go about getting my vector to print off 12 items per line. Here's my current function.
void printVec(const vector<int>& v) {
for(unsigned i=0; i < 12;i++)
cout<<v[i]<<" "<<endl;
}
I'm trying to enter an 'x' and 'y' coordinate on only one line separated by a comma. But I keep getting a syntax error. Here are the lines of code I'm using. This has to be simple. What am I doing wrong with this code?
Code:
cout<< "Please enter the x and the y coordinates of the first point,"<<endl;
cout<< "use a comma to separate them. " <<endl<<endl;
cin>> "You entered: " >>x1>>",">> y1 >>"for the first point" >>endl;
The problem is with the first "Type and Run," where the code looks like this:
Code:
/* print_it.c--This program prints a listing with line numbers! */
#include <stdlib.h>
#include <stdio.h>
void do_heading(char *filename);
int line = 0, page = 0;
[Code] ....
I am using the gcc compiler in Ubuntu 12.04 LTS and I get the following error:
Code:
print_it.c: In function "main":
print_it.c:36:15: error: "stdprn" undeclared (first use in this function)
print_it.c:36:15: note: each undeclared identifier is reported only once for each function it appears in
print_it.c: In function "do_heading":
print_it.c:49:16: error: "stdprn" undeclared (first use in this function)
I was told that "stdprn" can be recognised by a DOS based compiler and the book says I can try using "stdout" instead. It looks like this now:
Code:
/* print_it.c--This program prints a listing with line numbers! */
#include <stdlib.h>
#include <stdio.h>
void do_heading(char *filename);
int line = 0, page = 0;
[Code] .....
It compiled OK with the gcc compiler but I only get this when I run the program:
Code:
Proper Usage is:
print_it filename.ext
I am not sure whether I should continue looking into this but even when I tried compiling and running it on Windows, the .exe file won't even launch. The other ones do but this first one doesn't.
Questions:
1. What should be done to make this program run?
2. Even though the book says "don't care" if the reader does not understand the items (It's Day 1/Lesson 1), I would still like it to run as I don't want to experience compiling and running problems in the future. Should I even bother doing this section of the book or is it obsolete and should be skipped?
I have written the following code but i am stuck. Write a program that will prompt the user for a file name and open that file for reading. Print out all the information in the file, numbering each new line of text.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <ctype.h>
int main()
{
char line[81], filename[21], c;
int i = 1;
FILE *inFile;
[code]....
I have a text file where in each line is 3 words and 2 int type numbers. I'm doing search by word and I want to print out to the screen the whole line where that word was found (the words is repeated in some lines). My search looks like this:
Code:
#include<iostream>
#include<string>
#include<fstream>
#include<stdlib.h>
#include <vector>
using namespace std;
int main(){
vector <string> words;
string str, paieska;
[Code] .....
How to print line(s) where I found that word?
How can a mulitline string be read line by line
ex: str = "PERIOD="week"
DAY="day"
TIME="time"";
l need to write a program which writes out its command line arguments in reverse order one per line. The output from the program should look like this:
% a.out Two roads diverged in a yellow wood
wood
yellow
a
in
diverged
roads
Two
I am trying to read a file line by line and then do something with the informations, so my method looks like this:
Code:
void open_file(char *link) {
FILE *file = fopen(link, "r");
if (file == NULL) {
fprintf(stderr, "Could not open file.
");
exit(EXIT_FAILURE);
[Code] ....
1) The first complain of valgrind is at the line where I use fgets and its telling me (invalid write of size x), but I have allocated my line to 56000 and the read line is shorter, why is there a write size error then :S?
2) at the line where I realloc where I try to shrink the space he's telling me: Address .... is 0 bytes inside a block of size 56000, But I know i need only this space so why is there a write over space error :S??
So I'm reading a file line by line and storing it backwards into a list. So if the file has has this format...
1
2
3
4
The code should store each line in a list as such...
4, 3, 2 ,1
Instead the code will store the last variable in all nodes. So the final list will look like this...
4, 4, 4, 4
Here is my code...
struct node *head = NULL;
int i;
while(read(in, &i, sizeof(int)) != 0) {
struct node *temp = malloc(sizeof(*temp));
temp->line = &i;
temp->next = head;
head = temp;
}