I'm having problems fully comprehending how to do this task (I'm only going to include my function code since that's the basis of my problem). How should I go about getting my vector to print off 12 items per line. Here's my current function.
void printVec(const vector<int>& v) {
for(unsigned i=0; i < 12;i++)
cout<<v[i]<<" "<<endl;
}
I rote this code in my program
JSONNode::const_iterator iter = root.begin();
for (; iter!=root.end(); ++iter) {
const JSONNode& arrayNode = *iter;
std::string type = arrayNode["type"].as_string();
if(type == "node")
[code]......
But when i try to ptint id of second item std::cout<<"Item Id ->>>>>>>>>>>>>" << collection[2].GetId() << std::endl; it gets a blank value. but size of the collection is 82, get the correct value for the collection size.
I wrote this code in my program
JSONNode::const_iterator iter = root.begin();
for (; iter!=root.end(); ++iter) {
const JSONNode& arrayNode = *iter;
std::string type = arrayNode["type"].as_string();
if(type == "node")
[Code] .....
But when I try to ptint id of second item std::cout<<"Item Id ->>>>>>>>>>>>>" << collection[2].GetId() << std::endl;
it gets a blank value. but size of the collection is 82, get the correct value for the collection size.
I need to write a ANSI program to print out each command line argument on a separate line using a for-loop. also it need to print the name of the executable .so far I have
Code:
#include <stdio.h>
int main(int argc, char **argv) {
int i;
printf("")
[code]....
I have the following code in which I wish to dynamically delete items out of a vector based on the condition of the item in the vector.
The below code works but throws the error: "vector iterator not incrementable" at certain times.
It seems like this happens when the last item in the vector get's deleted. How do I solve this problem?
for (std::vector<PhysicsObject*>::iterator it = CurrentBoxes.begin(); it != CurrentBoxes.end();/*it++*/) {
(*it)->CalculatePhysicsOrientation();
(*it)->DrawMe();
glm::vec3* CurrentBoxPosition = (*it)->GetCurrentPosition();
if (CurrentBoxPosition->y < -750.0f) {
it = CurrentBoxes.erase(it);
}
++it;
}
how to add a list of information from a file to a vector of a class. Here is my code:
Champion_Info.h
#ifndef CHAMPION_INFO_H_INCLUDED
#define CHAMPION_INFO_H_INCLUDED
#include <vector>
#include <string>
[Code].....
Just working up for the google coding contest to start soon and have been practising some of the test questions however i make correct algorithms but my output is rejected because of the fact that my strings are printed on a new line so i wish to know a method to print strings using a printf statement or any other function on the same line ...
View 3 Replies View RelatedI need to read a text file which has various lines containing integers. I need to write those integers separately in a vector. Example, the first line of the text file contains 3 9 8 7 6 so vector[4]=3, vector[3]=9, vector[2]=8 and so on. Next read the second line 4 1 2 3 4 5 and write to another vector vector[5]=4, vector[4]=1...
I tried the code below but it will write from the second line, the whole line in one vector index.
int str; // Temp string to
cout << "Read from a file!" << endl;
ifstream fin("functions.txt"); // Open it up!
string line;
// read line count from file; assuming it's the first line
getline( fin, line );
[Code]...
I am trying to print a matrix solution that I've stored in a vector of doubles. The original matrix was stored in a vector of vector of doubles. I want to print to the screen and an output file. Right now it just prints to screen column-style and the output file is horizontal-style. I tried to change the solution from vector of doubles to a vector of vector of doubles like the original matrix but when I run my code it crashes. Here is what I am referring to:
void readMatrix(vector<vector<double>> &matrix, vector<double> &b, int &N, string input) {
ifstream in(input);
in >> N;
matrix.resize(N);
b.resize(N);
[Code] ....
However when I change my printResult function to this (I removed the string argument because I just want to get it working to the screen first):
void printResult(vector<vector<double>> &sol, const int N) {
//ofstream out(output);
//int j;
for (int i = 0; i < N; i++) {
for (int j = 0; j < N; j++){
[Code] ....
The program crashes. Am I even printing the matrix correctly?
The code I have is below. Im able to print them all onto one line but I need to print 10 per line separated by commas and Im not sure how to do that ):
for (int i = 0; i < MAXVALUE; i++){
for (int j = 0; j < counts[i]; j++){
output << i << ",";
We need a program that takes three names ( first middle last ) and print it each one at a different line...
View 5 Replies View RelatedI try to learn string class, resolving some problem, but i have some dificulties.The is ok, but when i print the longest string it does'n print on the same line.I enter the number of string, after that i enter the first string until i introduced from keyboard "#" character. I enter the second string and so on.Look at these example :
For i = 3;
Text[0] : I learn class String#
Text[1] : I dont learn class String#
Text[2] : String#
It print me like that : Text[1] :
I dont learn class String More than that look at the next example :
For i = 3;
Text[0] : I learn class String#abcdef
Text[1] : I dont learn class String#
Text[2] : String#
You see that in the first sentence i have continue to introduce some characters after # character and look what is happened :
Text[1] : abcdef
I dont learn class String
#include<iostream>
#include<string>
using namespace std;
int main() {
string text[100], cuvant;
int i, j, m, lung = 0;
cout << "
[code]....
I am using C++ to write data into a (.ini)file. However, when I try to print the value '0A' I am getting '0D 0A'. (this is what I see when I copy the output to HexEdit). From what I can figure out, '0A' is the ascii for 'new line' so write function automatically adds the '0D' which is 'carriage return'. What I want is to print 0A alone. how can I do this?
Note: Windows it is working fine, but linux it is not working...
unsigned char arrRes[4];
int N = 10;
memcpy(arrRes,&N,4);
std::ofstream Output(LUT_OUTPUT_FILE_BINARY,std::ios_base::binary | std::ios_base::out);
Output.write((const char*)arrRes, 4);
here 10 means 0x0a but it is printing 0d,0a...
I'm trying to enter an 'x' and 'y' coordinate on only one line separated by a comma. But I keep getting a syntax error. Here are the lines of code I'm using. This has to be simple. What am I doing wrong with this code?
Code:
cout<< "Please enter the x and the y coordinates of the first point,"<<endl;
cout<< "use a comma to separate them. " <<endl<<endl;
cin>> "You entered: " >>x1>>",">> y1 >>"for the first point" >>endl;
The problem is with the first "Type and Run," where the code looks like this:
Code:
/* print_it.c--This program prints a listing with line numbers! */
#include <stdlib.h>
#include <stdio.h>
void do_heading(char *filename);
int line = 0, page = 0;
[Code] ....
I am using the gcc compiler in Ubuntu 12.04 LTS and I get the following error:
Code:
print_it.c: In function "main":
print_it.c:36:15: error: "stdprn" undeclared (first use in this function)
print_it.c:36:15: note: each undeclared identifier is reported only once for each function it appears in
print_it.c: In function "do_heading":
print_it.c:49:16: error: "stdprn" undeclared (first use in this function)
I was told that "stdprn" can be recognised by a DOS based compiler and the book says I can try using "stdout" instead. It looks like this now:
Code:
/* print_it.c--This program prints a listing with line numbers! */
#include <stdlib.h>
#include <stdio.h>
void do_heading(char *filename);
int line = 0, page = 0;
[Code] .....
It compiled OK with the gcc compiler but I only get this when I run the program:
Code:
Proper Usage is:
print_it filename.ext
I am not sure whether I should continue looking into this but even when I tried compiling and running it on Windows, the .exe file won't even launch. The other ones do but this first one doesn't.
Questions:
1. What should be done to make this program run?
2. Even though the book says "don't care" if the reader does not understand the items (It's Day 1/Lesson 1), I would still like it to run as I don't want to experience compiling and running problems in the future. Should I even bother doing this section of the book or is it obsolete and should be skipped?
I have a vector of structs.
struct myStruct{
string text;
int num;
};
vector<myStruct> foo;
And I am attempting to print the text followed by a space, then the number. Like so:
foobar 5
But when trying to print my vector using
ofstream outputFile;
outputFile.open ("file.txt");
for(int i = 0; i < foo.size(); i++) {
outputFile << foo[x].text << " " << foo[x].num << endl;
}
It prints like
foobar
5
moretext
8
With an extra newline and space. How to get rid of it and print it on the same line.
I have checked that text does not include new line character at the end. Also, it seems to print correctly using cout, but not print correctly to output file...
I have written the following code but i am stuck. Write a program that will prompt the user for a file name and open that file for reading. Print out all the information in the file, numbering each new line of text.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <ctype.h>
int main()
{
char line[81], filename[21], c;
int i = 1;
FILE *inFile;
[code]....
I have a text file where in each line is 3 words and 2 int type numbers. I'm doing search by word and I want to print out to the screen the whole line where that word was found (the words is repeated in some lines). My search looks like this:
Code:
#include<iostream>
#include<string>
#include<fstream>
#include<stdlib.h>
#include <vector>
using namespace std;
int main(){
vector <string> words;
string str, paieska;
[Code] .....
How to print line(s) where I found that word?
I have a vector of integers, which can take values 0 or 1, say
0 0 0 1 1
I need to print indicators, telling in which position 1-values occur. So
0 0 0 1 0
and
0 0 0 0 1
I'm trying to print values from a vector of a struct and I don't really know how to do that. Here is a simple code that I have for now to test how to add data to the vector then attempt to print it out.
#include <iostream>
#include <vector>
#include <string>
#include <deque>
#include <fstream>
using namespace std;
struct Employee//employee data
[Code]...
I was assigned to print a linked list but as a vector of char (I cannot use the normal string type) , this is what I have:
char* List::asString(){
Node* ite = new Node();
ite= first;//ite is like an iterator of the list
for(int i=0; i<sizeOfList; ++i){//sizeOfList is the total of node of the list
[Code] ....
But when I print that, I get a bunch of weird symbols...
here is a piece of my code:
while(T--)
{
std::vector<std::pair<int, int> > *dragon;
std::vector<std::pair<int, int> > *villager;
[Code]....
I now wish to print the elements of the vector. How do I do it?
How can a mulitline string be read line by line
ex: str = "PERIOD="week"
DAY="day"
TIME="time"";
l need to write a program which writes out its command line arguments in reverse order one per line. The output from the program should look like this:
% a.out Two roads diverged in a yellow wood
wood
yellow
a
in
diverged
roads
Two
I am trying to read a file line by line and then do something with the informations, so my method looks like this:
Code:
void open_file(char *link) {
FILE *file = fopen(link, "r");
if (file == NULL) {
fprintf(stderr, "Could not open file.
");
exit(EXIT_FAILURE);
[Code] ....
1) The first complain of valgrind is at the line where I use fgets and its telling me (invalid write of size x), but I have allocated my line to 56000 and the read line is shorter, why is there a write size error then :S?
2) at the line where I realloc where I try to shrink the space he's telling me: Address .... is 0 bytes inside a block of size 56000, But I know i need only this space so why is there a write over space error :S??
So I'm reading a file line by line and storing it backwards into a list. So if the file has has this format...
1
2
3
4
The code should store each line in a list as such...
4, 3, 2 ,1
Instead the code will store the last variable in all nodes. So the final list will look like this...
4, 4, 4, 4
Here is my code...
struct node *head = NULL;
int i;
while(read(in, &i, sizeof(int)) != 0) {
struct node *temp = malloc(sizeof(*temp));
temp->line = &i;
temp->next = head;
head = temp;
}
