In the code below:
void test(int * i) {
i = new int;
*i = 10;
cout << "i: " << *i << endl;
[Code] ....
The outuput is:
i: 10
t: (some memory position).
If I really want to allocate an integer variable to t, i need to modify the void test(int * i) procedure to void test(int *& i).
I am trying to make a function that allows me to allocate memory to a "mem" variable and setting each of its chunk's status to FREE. FREE is defined as 0. Below is my code of the function.
Code:
int allocate(mem *mm, int num_chunks, int chunk_size) {
int i;
mem *temp;
if((mm = (mem *) malloc((num_chunks + 1) * chunk_size)) == NULL){
perror("Failed to Malloc
[code]...
mem; If my function works the way it should, it should print out five 0 because that is how I set them in the function, but this is not the case. I've looked at my function for 2 hours, but I could not figure out any logical error. Now, I think my problem lies with my limited knowledge of pointer arithmetic. On the other hand, when I insert 1000 as the second argument into my function, it gives seg faults, which is not the case for smaller values like 5, 10, 15, etc.
There is a part in the lesson that explains how malloc is used to allocate free memory to a pointer and gives us 2 examples:
Code:
float *ptr = malloc( sizeof(*ptr) ); and Code: float *ptr;
ptr = malloc( sizeof(*ptr) );
From my logic in the first case we allocate the memory to *ptr and in the second to ptr.
It's a bit confusing, am I missing something?
I'm making a system like twitter for class called ShoutOut.com I want to be able to get the PublicShoutOut pointer pointed to by the start iterator and assign it to firstShoutOutToDisplay and secondShoutOutToDisplay because I need that in order to pass the pointers to one of my functions. When I step through the debugger the values in start are all default values like "" and so are the values in this->firstShoutOutToDisplay but the message that start points to is being output just fine.
EDIT: got rid of irrelevant code. Am I using the correct syntax to do this?
if (start != finish) {
//getting these because a shoutout needs to be passed to the function that displays
//options for a shoutout
this->firstShoutoutToDisplay = (*start);
[Code] ....
I want define Variable that has all amount of between two integer example: 2-4
View 1 Replies View RelatedIn my program I'm trying to add 200 to the variable named "gold". I thought this would work, but I guess it's not:
int gold2=gold+200;
int gold=gold2;
Consider the below initialization of x.
int x = 0x01234567;
If x is stored in RAM as given below, what would be the address x in both case?
(if image is invisible please follow this link)
Assume that size of integer is 4 byte.
this program is not giving to chance to enter the ooplevel value.
Code:
#include <iostream>
using namespace std;
const int SLEN = 30;
struct student {
char fullname[SLEN];
char hobby[SLEN];
int ooplevel;
};
// getinfo() has two arguments: a pointer to the first element of
// an array of student structures and an int representing the
[Code]...
I intend to reference this thread from another thread so I do not clutter that thread with code
/* This code is relied on by some of the functions I will post */
typedef unsigned long long zxumax;
typedef signed long long zxsmax;
[Code]....
I need to create a stack with the container being an unsigned int. I tried to put in numbers up to four bits each and have the program read the numbers individually. This is the code I am using:
void push(int n)//item n is pushed onto the stack, throw exception on full stack {
string str="Error";
if (isFull())
throw str;
[Code] ....
When I have tested it, the program is reading the numbers as one whole number. For example, I put in the number 2, and it displays the number 2. Then I put in 2 again, but this time it displays the number 10, instead of 2 2.
I already have the standard one that mimics the one taught in schools written but I've found that there is a faster formula that can be used however I not sure how to implement this. The formula is called the "Fast Fourier Transform", any simplistic example using this function base:
typedef unsigned int uint;
typedef unsigned char uchr;
uint umul( uint* src, uint val ) {
uint des = *src;
[Code] ....
If you're doing the buffer based functions then I have some pre-made functions you may need. [URL]
How can I use an integer variable in a http command example:
int num, canal;
for (num =0, num < 10, num++){
canal = num;
system( "wget http:'/'/192.168.3.4/channel.cgi?channel= canal");
}
On a controlled buffer of unsigned char it is possible to do subtraction faster than if you followed standard mathematical rules, here is an example:
typedef unsigned char uchr;
uchr num1 = 5; //00000101
uchr num2 = 3; //00000011
num2 = ~num2; // 11111100
++num2; // 11111101
uchr num3 = num1 + num2; // 00000010(2) - computer truncates result to fit char
Since you will be working with a buffer you don't even need to worry about truncating the final bit because the add function will not be able to reach it - unless it is given the ability to grow the buffer in which case you just set the bit to 0 yourself
I have this code:
Code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
[code]....
What I want is basically to assign to the *p the pointer of the string so that i could do the following printf(" print string %s",*p); so i dont know how to do that.
The warning: :63:7: warning: passing argument 1 of fputc makes integer from pointer without a cast [enabled by default]
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <pthread.h>
#include <sys/types.h>
#include <sys/stat.h>
[Code]....
I am getting error"incompatible integer to pointer conversation..." and don't know how to fix this. In my code, user inters line like this (3+3*(55-52)) I need to separate number from the line so I can do other operation.here is my code
Code:
#include <stdio.h>
#include <stdlib.h>
#include<string.h>
int main(){
[Code]....
Code:
#include <stdio.h>
#include <stdlib.h>
#define CLASS 4
#define STUDENT 11
#define GRADE 5
[Code] ....
Giving me that error on 75:10
avesub+=grade[k];
and 90:17
donkeypunch+=grade[j][k];
not sure exactly why
I have written this program
Code:
#include <stdio.h>
#include <string.h>
int main(void) {
struct point {
[Code] ....
error: request for member is not a structure or union
printf("%d
,%d
",p1->i,p1->j);
I was just trying to typecast a integer pointer to structure pointer, but throws error as shown.
I am trying to make a program that prints out an 8 by 8 board with 1 queen on each row.
For example, if the user enters: 0,3,4,0,0,7,6,7
the program should create following board and print:
Q.......
...Q....
....Q...
Q.......
Q.......
.......Q
......Q.
.......Q
I think I am doing it right but im getting a couple of errors that i cant fix ...
#include <iostream>
using namespace std;
int main(){
int x [8] [8], r, c;
for(c = 0; c <= 8; c++){
cout << " Enter a number from 1 to 7 " << endl;
[Code] .....
these are the errors :
assignment15_meem.cpp: In function âint main()â:
assignment15_meem.cpp:7: error: no match for âoperator>>â in âstd::cin >> x[c]â
assignment15_meem.cpp:10: error: ISO C++ forbids comparison between pointer and integer
template <class ST>
bool OrderedSet<ST>::IsIn (const ST & value) const {
for (LNode * np = first; np != NULL; np = np -> next)
if (np -> next == value)
return true;
return false;
}
when i compile the following program i get a compiler warning, but i don't understand why. for me the code seems to be all right and does legitimate this warning. so here is the code
// multiplication.c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
#include "crypto.h"
#define PROGNAME "multiplication"
void usage();
int isnumaber(char* str);
[code]....
What I'm trying to do is to assign the length of a string to an integer variable. This is what i tried, it did not work.
Code:
printf("Enter a string
");
fgets(test_pass, 30, stdin);
strcpy(x,(strlen(test_pass)));
printf("%d", x);
This was just a test, and it did not compile. How to do this?
I have an integer pointer and i want its address without allocating memory,
main() {
int *a;
cout<<a;
}
This is giving 00000000 and its but obvious. Now if i use address of a (&a) along with *a,
main() {
int *a;
cout<<a;
cout<<&a;
}
'cout<<a' gives me a constant address but 'cout<<&a' gives me different address.
what is the reason behind & and why behaviour of 'cout<<a' changes when using with &.
int hash = 0;
char *strings[100];
if((int)strings[i] != 0)
if((int) strings[hash] != 0)
while((int) strings[hash] != 0)
if((int)strings[hash] != 0)
if((int)strings[hash] != 0)
Create in the private section of the ServerGroup class a pointer to a dynamic integer array called servers.
#ifndef ServerGroup_h
#define ServerGroup_h
class ServerGroup {
public:
private:
int *ptr = new int; // needs pointer to a dynamic integer array called servers
};
#endif
what I need is to get the first integer from a file and assign it to a variable and the others integers to an array. Example: Thats my file content 5 4 6 7 8 0 and that would be the code:
Code:
struct Array{
int n;
int *v;
}
[code]....