I want to monitor a text file. So far what I have is the program reads and prints the names in the file to standard out. When the program reaches the end of the file, it closes.
I want the program to stay active and continue to print names as they are saved to the text file.
I was toying with FindFirstChangeNotification function, but it seems that returns a handle so I'm back to the drawing board.
So i have to use these prototype functions to run loops and to pause the program, the only problem is after i select a loop option and enter a number of dots to print in the loop it goes into an infinite loop and why, also when i try using the 4 option to exit it still asks me how many dots i want to print.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int pause(char *);
int getInt(char *);
void whileFunction(int);
void doWhileFunction(int);
void forFunction(int);
[Code] .....
I know there has to be a system call to pause (not system("pause") execution of a program for a few seconds. I would like to give the illusion that my program is 'thinking' rather than just spit out the result as soon as the user has hit the enter key.
View 5 Replies View RelatedIf I create a file that looks like this for example,
car 2 4 6 8
truck 1 2 3 4 5 6
plane 4 5 6 7 9
Whenever I go to open it back up like this,
ifstream inputFile;
string line;
inputFile.open("file.txt");
while (inputFile>>line) {
cout << line << endl;
} inputFile.close();
return 0;
}
It displays output like this,
car
2
4
6
8
How can I get it to display like above?
Write a C program that calculates the final value of an investment made in a TSX Market Linked GIC.
Specification
The return on this type of GIC (Guaranteed Investment Certificate) is based on the initial investment, the number of years (1, 2 or 3), a minimum return rate, a maximum return rate, a participation rate, the values of the TSX (Toronto Stock Exchange) index at specified intervals during the years, and the type of averaging of these values. The final investment value can only be calculated once all the TSX values are known.
If averaging is not used the TSX rate is determined from the opening and closing values only. If averaging is used the TSX rate is determined by calculating the TSX average at 6 monthly intervals, then is based on this average relative to the opening value. The TSX rate is then multiplied by the participation rate. If this new rate is below the minimum rate, then the minimum rate is used, and if it is above the maximum rate, then the maximum rate is used. Rates are printed to 2 decimal places, and the final investment is rounded down, and formatted using commas.
Only round down for the final investment. If the TSX rate is negative do not print the line for rate adjusted for participation. Assume that the final investment is less than one million dollars. (Hint: if you need to print leading zeros in a number, use the %0m.n format: example - the format specifier %06.2f prints 4.56 as 004.56)
Example 1: See below; averaging is not used, so TSX rate = (107-100)/100 = 7%. After using a participation rate of 80%, get 5.6% (which is between min & max rates).
Example 2: See below; averaging is used over 5 values to get a rate of 68% which equals 54.4% due to participation. This is more than the max rate, so the max rate is used.
The GIC calculator must use the following layout exactly.
+------------------------------------+
| TSX MARKET LINKED GIC CALCULATOR |
+------------------------------------+
Enter initial investment : 1000.00
Enter number of years [1,2,3] : 3
Enter minimum and maximum rates [%] : 1 20
Enter participation rate [%] : 80
Enter if averaging used [1=yes,0=no]: 0
Enter open and close values : 100 107
TSX rate . . . . . . . . . . . . . . 7.00%
Rate adjusted for participation . . 5.60%
Final investment . . . . . . . . . . $ 1,056.00
+------------------------------------+
| TSX MARKET LINKED GIC CALCULATOR |
+------------------------------------+
Enter initial investment : 2000.00
Enter number of years [1,2,3] : 2
Enter minimum and maximum rates [%] : 1 20
Enter participation rate [%] : 80
Enter if averaging used [1=yes,0=no]: 1
Enter 5 TSX values : 200 190 320 430 540
TSX rate . . . . . . . . . . . . . . 68.00%
Rate adjusted for participation . . 54.40%
Maximum rate is applicable . . . . . 20.00%
Final investment . . . . . . . . . . $ 2,040.00 i wrote something like
Code:
#include <stdio.h>
int main (void)
{
int years, minimum, maximum, partrate, x, open, close, tsxvalue;
float investment, tsxrate, y, finalinvestment, maxrate, minrate;
printf("+------------------------------------+
[Code] ....
I don't know what the exact calculation should be here now to get the rest....so I'm stuck here
I dont know anything about filestreams. I want to record the files that the customer bought, total, cash and change.
Here's my code.
// Create a program that will initiate a purchasing system for registered agents in an agency.
#include<iostream>
#include<windows.h>
#include<conio.h>
#include<fstream>
#include<string>
using namespace std;
void password();
[code]....
I have a client/server program. My Client process spawns my server process using a `fork()` and `system()` call. The client and the server are meant to communicate to each other through named piped, that is a requirement of my homework. The client and the server are supposed to initially send a message to the other one, through a pipe, to confirm that a connection is made. My issue is that my client is trying to open one of the named pipes before the server has a chance to make it. This doesn't always happen though. Occasionally, it will run fine. Is there some way to synchronize this?
My overall goal is to get a filename and search target from the user, send those to the server through a named pipe. And the server searches for the target and sends info back.
OUTPUT:
Client: PID 2986 - Running on Tue Sep 30 20:59:28 2014
Client: PID 2986 - Enter File Name: largeSampleText.txt
Server PID 2988 - Running on Tue Sep 30 20:59:32 2014
Server: PID 2988 - Synchronized to Client.//This means the client-to-server fifo is working
There was an error opening serverToClientfifo//This means client couldn't open the server-to-client fifo
error is: 2//This means the fifo doesn't exist yet
[Code] ....
CORRECT OUTPUT:
Client: PID 2542 - Running on Tue Sep 30 20:58:44 2014
Client: PID 2542 - Enter File Name: largeSampleText.txt
Server PID 2557 - Running on Tue Sep 30 20:58:54 2014
Server: PID 2557 - Synchronized to Client.
[Code] ....
RELEVANT CLIENT CODE:
int main() {
char requestedFileName[1024];
//Get initial information on the client
pid_t clientPID = getpid();
time_t currentTime = time(0);
char* stringTime= ctime(¤tTime);
[Code] ....
I tried creating both of my fifos in my client and my output changed to this
Client: PID 3150 - Running on Tue Sep 30 21:23:17 2014
Client: PID 3150 - Enter File Name: largeSampleText.txt
Client: PID 3150 - Enter Target:
Server PID 3153 - Running on Tue Sep 30 21:23:21 2014
was
Client: PID 3150 - Input File >>>largeSampleText.txt<<<
Client: PID 3150 - Target >>>was<<<
Client: PID 3150 - Synchronized to Server
Server received unexpected connection message
Message: was
Terminating
So It appears like the client went ahead and put `requestedFileName` and`requestedTarget`into the pipe and the server read out `requestedTarget` instead of the connection message. Not sure why though
I mean on the executable file. It just displays the results and quickly flashes away, cin.get() has no effect and system("PAUSE") is undeclared.
I never found a single sure way to pause effectively. Is there a method that works all the time? Sometimes cin.get() gets skipped even in the code itself. The IDE I am using is Code Blocks if that matters any.
I know there has to be a system call for a pause function. I simply want the program to pause for a few seconds before executing the next line of code. I do NOT want the user to enter a keypress, just pause the output or code execution for a few seconds.
system (pause); waits for keypress right? I just want it to wait 3 seconds before proceeding. I know it should take an argument for milliseconds right? Also, this is for a homework assignment I have already completed, just doll'in it up a bit for extra credit...maybe...
I am trying to add a small function to allow me to pause the game I am making. I measure the time elapsed using the following algorithm:
1. USE ""clock_t begin=clock();"" FOR SYSTEM TIME OF GAME BEGINNING.
2. USE ""cout<<(clock()-begin)/CLOCKS_PER_SEC;"" TO DISPLAY TIME ELAPSED IN SECONDS.
Now, if I want to pause, I would want to subtract the 'paused' time from the total time elapsed.Say,
clock_t pause, resume;
{
pause=clock();
.
.
.
resume=clock();
}
Then I would do cout<<(clock()-begin-(resume-pause))/CLOCKS_PER_SEC;
This, though is what I want, works only once(I can pause only once). I can use arrays of resume and pause, but it would still limit the number of times I can pause.
What I am looking for is a way to pause any number of times.
I would like to have my program pause at a certain screen but not to have the "Press any key to continue..." message or the press of a button. In my program, the code looks similar to this:
for(;;)
{
cout
cin
cout
cin
...
//
here, I want to have a pause to view what the for loop has come up with but to not have a message display or a button press needed. At the end of the loop, I want it to pause before looping again. IS this possible?
If so, how can I implement it into my program?
I am writing an application that needs to temporarily disable the Play/Pause button that appears on multimedia keyboards.
Normally, a key can be blocked quite easily by installing a low level keyboard hook (WH_KEYBOARD_LL) where the KeyboardProc intercepts the key (in this case VK_MEDIA_PLAY_PAUSE) and returns a "1" instead of calling CallNextHookEx. I have tried this with other keys (including the Windows key VK_LWIN) and this works perfectly. I also have no problems with this method under Windows 7 where all keys, including VK_MEDIA_PLAY_PAUSE get blocked.
Windows 8 is a different story. When my application has input focus, everything works as expected, meaning the VK_MEDIA_PLAY_PAUSE key gets blocked and no other application responds to it. However, when my application loses focus, my hook procedure gets called (this was verified by sending out a OutputDebugString) but other applications respond to key even though I return a "1". As soon as my app gets focus again, everything is block as it should.
After some investigation, I found that the multimedia keys not only generate keystrokes but also generate WM_APPCOMMAND messages so I added ShellProc (WH_SHELL) hook with the following hook procedure:
LRESULT __declspec(dllexport)__stdcall CALLBACK ShellProc(int nCode,WPARAM wParam,LPARAM lParam) {
// Do we have to handle this message?
if (nCode == HSHELL_APPCOMMAND) {
OutputDebugStringX(">>>>> HSHELL_APPCOMMAND");
[code]....
This procedure is only getting called when my app has input focus. Whenever I have input focus and return "1" the Play/Pause command gets blocked. As soon as I lose focus the procedure does not get called/hooked.
As I have mentioned, the code works for other keys, just not the multimedia keys.
Alternatively, another way of blocking the multimedia keyboards Play/Pause button?
You are given an integer, perhaps a very long long integer, composed of only the digits 1 and/or 2. You have the ability to change a 1 digit into a 2 and a 2 digit into a 1 and must determine the min. number of changes that you can make resulting in no 2 digits remaining in the number that are in a position(in terms of powers of ten) higher than any 1 digit.
example:
2222212 number of changes:1
1111121 1
2211221 3
1122112 2
no negative numbers.
how to get started. Also I'm not allowed to use anything related to arrays or sorting.
I want to make an encapsulated surface class that keeps track of important aspects about a surface. I have it started, except when I test the .onDraw() function, nothing appears on the screen. My Code is below:
#include "NSurface.h"
NSurface::NSurface() {
surface = NULL;
}
NSurface::~NSurface() {
SDL_FreeSurface(surface);
[code]....
why nothing is blitting to the screen when I test that class.onDraw() and SDL_Flip(screen)?
I want to know how to respond to a request made by a mobile application (preferably Android) through a desktop software. So for example if there is a button on the mobile app named 'do something and a user clicks it, I want the desktop software to respond to that request and 'do something
So what I was thinking was to upload a file to a server when the button on the app is clicked and add a timer to the desktop software to connect to the server and read the file and respond accordingly.
Is this how it is usually done or am I going about this the wrong way? Im developing the app in C# (Xamarin) and the desktop software in C# as well.
Running c in jgrasp.. i am getting error has gcc not found.
View 4 Replies View Relatedimplementing a game of chess, i was able to easily implement the grid with an 8x8 multidimensional array.but here is the case I need to implement a grid made of hexagons(six sided but in future may be seven sideded or eight may be needed): like a beehive something.
How can such a grid be implemented in c++ taking notes of coordinates and borders and stuff? From where i can start working from? this grid has to be just like the chess grid only we got six sided boxexs instead of four,
I am supposed to convert a string made of many numbers between every number spaces are between, to an integer variable for every number..
How am I supposed to get over this problem?
Example: String: " 322 52 231"
Is it possible in C to instantly react to keystrokes made in console?For example, consider the following code:
Code:
#include<stdio.h>
int main(int argc, char *argv[]) {
char ch;
printf("Enter a sentence...
");
[code]....
The evaluation of the if statement inside the loop will not occur until the Enter key is pressed on keyboard.To my best understanding, It just pushes the keystrokes to some buffer, and when the '' is introduced, it evalutes the characters one by one.Is there an elegant way to instantly react to keystrokes in C?
I am doing a c project .it is a system that stores the name of txt format reports made by students and opens them.
View 1 Replies View RelatedI was going through Singleton design pattern and get to know that objects can be created only by static function of that class and constructors are make private.
My question is, why assignment operators are not made private through which we can create a copy of already existing object.
I tried below code and assignment works, so I have new object sc3. I know that its referring to memory of sc1 but finally I was able to create object without using static function.
Also, why copy constructor not made as private.
Below is code:
#include <iostream>
using namespace std;
class Singleton {
private:
static bool instanceFlag;
[Code] .....
Code:
class A
{
std::map<std::string, Unit*> aMap;
class B
[Code] .....
This code snippet results in "A non-static member reference must be made relative to a specific object". When I make callA() static, this error goes away, but there is problem with aMap.
so my homework assignment is to make a program of which removes any notes in a program file.
for example, you run my program it will ask for a filename, when entered it opens the file, copies everything in it and removes any double forward slashes (//) and anything after that up to the new line character ( ) and anything between /* and */ including the /* and */.
i created the entire program and it removed the // and anything after that up to the new line character but will not remove anything after the first / when it finds a /*. This includes the */ at the end of the comment.
the section of code that removes the comments is
//this loop removes all notes
for(i=0;i<buf.st_size;i++) {
if((filecontent[i]=='/')&&(filecontent[i+1]=='/'))//removes notes using //
{
for(i=i;filecontent[i]!='
';i++)
filecontent[i]=' ';}
[Code]....
i know that the section that removes the multi line comments would not remove the final */ at the end if it did work, i was planning to fix that later once it removed the comment.
One of my class assignments is to create a program that receive a .txt file containing a students name and their grades as follows:
John K. 99, 87, 57, 89, 90, 95
Amanda B. Jones 100, 88, 76, 99, 86, 92
etc..
The number of students is unknown until run time. You have to take those grades and average them weighing the first (4) at 10% a piece and the last (2) at 30% each.
Then return an output file with the students name and their letter grade A,B,C,D,F based on their computed score. In addition, on screen it needs to display the average scores for each Q1, Q2, etc. as well as the minimum and maximum for each test on the screen. I am having a hard time in assigning the scores to a variable so that they can then be computed as an average and then used to determine a letter grade. I have begun to write the code and am a bit stuck..here's what I have so far:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
[Code]....
We have to write a program that reads an input file containing data in the form:
Martha J, 80, 90, 90, 100, 89, 99, 85
Anna Smith, 65, 72, 77, 68, 62, 70, 65
Bill Gates, 60, 54, 89, 62, 65, 60, 50
...etc...
and then use that information to determine their letter grade and write that information to a .txt file. I have been able to successfully pass that information to a function to determine their letter grade and have been able to successfully compute their letter grade. However, I can get this information to successfully post within the *computeGrade () function. Yet, I don't know how to pass this information back to the main() on a student by student basis so that I can open a new .txt file and write just their name and letter grade to it.
Another issue I'm having is when it comes to computing the averages of the class. Each score is either a quiz (there are 4), a midterm (there are 2) or a final (there is 1). I'm a little stuck on how to pass say all of the quiz 1 grades as one entity to the function averagesminmax(). Is there a way to compile each of the grades for a specific quiz or midterm as one array and pass that to the function to then do the computation. Also we need the min and max so again from compiling the grades of a particular quiz or exam together as one.
Here's the code that I have so far.
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
const char *computeGrade();
int averagesminmax();
int main() {
char fName[20];
char lName[20];
[code]....
Do I need to re-read the input file and assign them to different variables?
Here's a sample of the output so far:
Enter input .txt file name
Graded
Thui Bhu, 91, A
Ariana B. Smith, 96, A
Emily Gonzales, 83, B
Jennifer L, 89, B
Maria Jones, 67, D
Bill Gates, 55, F
Escobar Morris, 78, C
Anne Latner, 88, B
Program ended with exit code: 0
Also in my output file, the only thing that it prints will be the first name of whatever the last student in the input file list is.
I've written a program to read inputs in a text file. The file named Input.txt contain integers 2 3 and 4. My program is as follows:
#include<iostream>
#include<cstdlib>
#include<fstream>
using namespace std;
int main (){
int x,y,z;
[Code] ....
the program is outputing x=2293616 , y=0 and z=0 instead of x=2, y=3 and z=4.