C++ :: How To Create N Matrices Of Dimension Simultaneously
Feb 27, 2014I would like to create N matrices of dimension (n,k) simultaneously. Lets say for example that N=3.
I read the command a[n][k][N] but I don't understand how to use it.
I would like to create N matrices of dimension (n,k) simultaneously. Lets say for example that N=3.
I read the command a[n][k][N] but I don't understand how to use it.
I would like to create N matrices of dimension (n,k) simultaneously. Lets say for example that N=3. I read the command a[n][k][N] but I don't understand how to use it.
I know that for some of you this question is silly but I' m new to this language and I have noone else to ask.
I am trying to create a rectangle with 3*5 dimension which would look like:
#####
#####
#####
I wanted to use for, and do while loop for that programming. I couldn't been able to create my desired dimension of 3*5.
//complier directives
#include<iostream>
#include<cstdlib>
using namespace std;
//main body
int main () {
//local identifiers
//complier directives
[Code] .....
I need to create a main function with a one dimension dynamic array with float data type. The total number of array elements must be controlled by a user input from the keyboard. Test data is three different lengths 3,6,9 of the array. The lengths have to be set up at run time from users input. I understand how to create dynamic array but not where the user inputs the length of the array. How would I implement this?
View 6 Replies View RelatedIs there a way to simultaneously update two variables, like in Python?
For example
Code: x, y = 0, 1
x, y = y, x + y
If I have a struct of some vector members, like
struct {
vector<double> a;
vector<double> b;
vector<double> c;
// ...... continue
} struct_test
How can I assign a value (push_back()) to all the vector members simultaneously, instead of do it one by one?
I have two or more printers and one computer. I want to print to both printers the same document at the same time... Thus when I press print on my document both printers will print the file simultaneously.
View 6 Replies View RelatedI have an image of size 640x480 pixels. It's possible to obtain the dimension in mm of one pixel from that image given only that size?I do not have the size of the image in mm,however.
View 5 Replies View RelatedI try to write code for one problem which is worked with the matrix.I have written in specific size 5 by 5 and I know the general formula for these matrix based on dimension,I want to write a general form that take the matrix size and then create my favor matrix.However,when I write like below the following error is appeared
int m;
cin>>m;
int A[m][m];
Error: m must be constant
I would like to initialize a N-dimensional matrix by specifying the dimension N.
To be clearer :
if N=2 I use to do that :
std::vector<std::vector<double>> myMatrix;
if N=3 :
std::vector<std::vector<std::vector<double>>> myMatrix;
and so on...
What I would like is to give N as an argument of a function which construct a N-dimensional empty matrix. Is that possible ?
I am trying to figure out the syntax to dynamically allocate a single dimension of a triple dimensional array. Basically i have a 2D array of structs. but each struct is an array (basically rows of the information). The rows of this structure need to be allocated dynamically, but the height and width of the overarching structure are static.
Basically: Struct * ts_FieldInfo[100][100] = new Struct[Class.returndataitems()];
Want to initialize a local one dimensional array. How can I do the same without a loop?
Found from some links that
int iArrayValue[25]={0};
will initialize all the elements to ZERO. Is it?
If yes then can we write below code to initialize the elements to a non-ZERO value?
int iArrayValue[25]={4};
Do we have some other way to initialize an array to a non-ZERO value? Memset can initialize the element to ZERO.
I would like to print a multiplication table, with the dimension n given as input. I attached how the table looks like for n=7.
How do you output the character "-" in that sequence? The first and last numbers have 13 "-" characters before and after them, but the numbers in between have 8 "-" characters.
I am trying to read in data from a text file and store it inside a 3D array. The text file looks like this:
bar bell orange
bell bell 7
lemon cherry cherry
I can read in the data fine, but how to store it inside the array. My array looks like : [ Char slotMachine[10][3][8]; ] T
he dimensions are Row, Column, and symbol. There are 10 rows and 3 columns inside the file. The third dimension is supposed to hold the symbols as a C-style string.
This is what I have been trying:
char symbol[8];
int rowIndex = 0, colIndex = 0;
While(fin.good()){
fin >> symbol;
slotMachine[rowIndex][colIndex][] = symbol;
rowIndex++;
colIndex++;
}
I know that i'm not storing the symbol right. How to correctly store it inside the third dimension.
How do you add two matrices together ?
View 2 Replies View RelatedI have a set of n- dimension point store in `vector< vector<double> >`
ex A[0][1].............[N], and A[0][0] = X, A[0][1] = Y, A[0][2] = Z
and I want to sort the vector of all of the dimension
ex sort X, Y, Z ,.........N in ascending order
ex A[0] = (1,5,3), A[1] = (3,2,1) A[2] = (2,8,4) after sorting
index: 0 1 2
A[0] = (1,5,3), A[1] = (2,8,4) A[2] = (3,2,1)
original index : 0 2 1
I find that `sort(vector.begin(), vector.end())` can sort it but how can I record the original index with a additional vector?
Is there a algorithm or C++ feature can solve it?
I have tried to solve it with a class wrapper it but I don't know how to write the compare function.
class point{
public:
point(int totalLength = 0, int elementLength = 0);
vector<vector<double> > pointSet;//store the n-D points
vector<double> pointIndex;//store the index
};
point::point(int totalLength, int elementLength){
pointSet.resize(totalLength,vector<double>(elementLength, 0));
pointIndex.resize(elementLength);
}
I want to save the char[8][8] // fixed size 2 dimension array
to a vector
such as
vector<?????> temp;
is there anyway to approach this?
I haven't found anything that small for Matrix multiplication i was just going to ask about how i would multiply to matrices together in c++ as easy as possible, so for example say a i have the following
[2 0 1 0 * [3 0
6 -1 0 2] 0 3
1 2
3 1]
How would i multiply these together. Here is the example
Attached image(s)
I am writing a class which loads a bitmap image into a one dimension char* array.
This class has methods to allow for resampling and cropping the image before saving the bitmap image. It works perfectly for all images in which the width is divisible by 4. However when the width is not divisible by 4 the resulting bitmap is all mixed up.
I have spent much of the day googling this problem but to no avail. I know it is a problem with making sure the scanlines are DWORD aligned, and I believe I have done that correctly. I suspect that the problem is that I need to take the padding into account during the crop for loops but am lost to how to do this.
BTW: Coding on Linux using GCC
The following code is a cut down version from my bitmap class. I have removed methods which are not needed to make reading a little easier.
#include "BMP.h"
// FIXME (nikki#1#): Portrait bug on images of specific sizes
// TODO (nikki#1#): Memory leak checks
// THIS METHOD WRITES A BITMAP FILE FROM THE CHAR ARRAY .
bool BMP::saveBMP(string fileName, string *err) {
FILE *filePtr;
[Code]...
I tried writing a cofactoring routine for n x n matrices and my code works but it shouldn't. Like, at all. But it does. Idk how and it's consistent.
Basically, my error is when assigning the sub-matrix for the cofactorization method I'm using from here :
Mathwords: Cofactor Matrix
My assignment routine should not work for the sub-matrix because of how I address the rows. under is always 0 and yet it'll assign values to the proper row. Idk how, it's magic.
Code:
#include <stdio.h>
#include <stdlib.h>
long double det(long double **x, int rank) {
/* Determinant calculator routine */
/* We initialize the resulting determinant to zero */
[Code] .....
Any example code for printing a square matrix without arrays?
View 7 Replies View RelatedThe program below should add two matrices using function. I have problem in the third function (the summing function). It's saying that something wrong with the array! I'm new to arrays and functions.
#include<iostream>
#include<fstream>
#include<conio.h>
using namespace std;
int matrix1 ();
int matrix1 ();
int add ();
[Code] ....
I want to implement operator overloading for +=, so that the following arethmetic is possible for matrices: matrix += matrix
Here is how I have defined it in matrix.h
#ifndef MATRIX_H
#define MATRIX_H
#include <cassert>
#include <iostream>
#include <iomanip>
using namespace std;
template <class T> class Matrix;
template <class T> Matrix<T> operator+= (const Matrix<T>& m1, const Matrix<T>& m2);
[code].....
How do I implement this correctly?
I am currently trying to pass a matrix (multidimensional array) from my main into a function in a class. As usual, you have to include all array sizes, except the first. Unfortunately, the size saved under a variable. When I write it in the square brackets, it doesn't work.
Example:
//main
int main () {
int n = 5;
random object;
object.declare_variable(n);
int array [3][n];
object.pass_matrix(array);
[code].....
I also tried, putting the variable 'var' in the public section above the void and declaring it as static, but still there are error messages; fewer, in my case:
...not an integer constant
So what should I do? Id like to repeat that the int n will vary, which is why I can't just directly write down the size.
Two different matrices will be read from text files (input1.txt, input2.txt) and they will be stored in two dimensional arrays (matrix1, matrix2) and one dimensional arrays (array1, array2). Our aim is to obtain the matrix multiplication using two dimensional and one dimensional arrays.
You are asked to write the main and the following functions. The definitions of the functions are given in the skeleton code.
int read_file(ifstream& in_file, int &row, int &col, double *array, double **matrix)
int write_file(ofstream& out_file, int row, int col, double **matrix)
void print_matrix(double **matrix, int row, int col)
void print_array(double *array, int row, int col)
void multip(double **matrix1, double **matrix2, double **result, int k, int m, int n)
void multip_array(double *array1, double *array2, double *array_result, int k, int m, int n)
You are going to obtain the input and output files as command line arguments
input1.txt :
3 4
2 3 4 5
1 3 5 4
0 4 4 7
The first element in the first line represents the number of rows (3) and the second element represents the number of columns (4) of the matrix (the result file will have the same format).
likewise;
input2.txt :
4 5
1 2 3 4 5
2 9 43 44 21
32 32 32 43 54
1 3 3 4 5
thats my homework and here is the code i wrote from the sceleton code they gave me :
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int read_file(ifstream& in_file, int &row, int &col,/* double *array,*/ double **matrix)
[Code] ....
I didn't understand the array part but even when i exclude the array part i get the program has stopped working message. My os is windows7 ultimate with mingw installed and i compile the program using g++ command in cmd with the arguments input.txt input2.txt resultt.txt
when i am running this program no errors are being shown but as soon as i press ctr+f9 to run the program my tc++ window closes.....
Code:
#include<stdio.h>
#include<conio.h>
void multiply(int m1[50][50],int ,int,int m2[50][50],int ,int );
void main() {
int i,j,m,n,p,q,m1[50][50],m2[50][50];
[Code] ....