User enters sentence "The Smiths have two daughters, three sons, two cats and one dog." (The numbers may change depending on what the user chooses to enter. He told us the range would be from zero to nine.) and we have to convert the written numbers within the sentence into actual decimal numbers and print out the new sentence. Ex. The Smiths have 2 daughters, 3 sons...etc.
I have written the following bit of code which reads the string and finds all the "written numbers" but I am not sure how to proceed from there. I am stuck on how to print out the new sentence with the converted numbers as my professor mentioned something about creating the new string using dynamic memory allocation.
Code: #include <stdio.h>#include <string.h> int main () { char A[100]; int length = 0; int i;
I'm having trouble converting a 4 digit number into a BCD number, in the program I did below I was able to convert a 2 digit number into BCD, but I do not know how to convert a 4 digit number or how to start it.
#include <cstdlib> #include <iostream> #include <string> using namespace std; int main(int argc, char *argv[])
I am trying to read into a file that has something like
I have 5 apples and 9 bananas. Sam has 8 apples and 6 bananas.
and I need to replace the numbers with words. For example I need to change the "5" to five and so on. The problem is that im not sure how to access and then replace just the numbers.
Take a number that is entered by a user and turn that into printed text. Ex. 85 would be eight five. The problem I am having is I'm not quite sure how to go about this. I don't know if I should use an array, string, or something else.
Now I have the binary numbers printed out in my code, but I don't know how I can covert them into to decimal.
#include <iostream> #include <iomanip> #include <string> #include <cmath> using namespace std; int main() { int numberOfDigits; int numberOfRows; char flag;
I have my program working, as far as converting the letters to numbers, but i want be able to enter as many numbers as i want. so i figured i could put into a loop asking a question at the end. question being whether the user wants to enter another number or not. also i'm assuming the user enters exactly 7 letters each time. this is my code so far.
const int arSize = 9; char letters[arSize]; int numbers[arSize]; int count = 0; cout << "Enter a telephone number expressed in letters. (e.g. CALL loan ( it is not case sensetive))"; for (int i = 0; i < 7; i++,count++)
I need to convert characters in a input file to numbers in output file and display both the characters and numbers in a console window.Only 7 numbers can be displayed, the rest needs to be dropped.The input file contains the following data, with one number per line:
CALL HOME GET LOAN Hi THERE BYE FOR NOW
For example, once the first number in the input file has been processed, the console window should display the following: CALL HOME 225 5466.
The output file should now also contain the number: 225 5466
Currently my console is displaying the following:
Enter the input file name. infile.txt
Enter the output file name.
outfile.txt 2554663Invalid Input 4385626Invalid Input 4Invalid Input 84373Invalid Input 293367669Invalid Input 4357637277CALL HOME GET LOAN Hi THERE BYE FOR NOW
#include <iostream> // for screen/keyboard i/o #include <fstream> // for file #include <cstdlib> // for exit using namespace std; void openFile(ifstream& infile)
I'm a games/apps developer and right now I'm developing games/apps for iOS, Android and also PC / Facebook. I've also been working on C++ for some time but since I'm learning it all by myself, I still have some beginner doubts.
Is there any easy way to code a value conversion (for example an octal value to an actual number)?
I am working on an assignment about converting an integer number to its 2's complement presentation. The binary representation is consisting of a single linked list.
As we all know, the steps of this converting is to taking the reminder of the absolute value, then flipping the 1 to be 0, and the 0 to be 1 in the binary number. And the last step will be to add 1 to the binary number invers.
I wrote a code that implements every thin correctly. However, when I reached the part of adding 1, the program was hanged.
int Absolute; //the first step is to convert the number to the binry reprezentation Absolute = abs (value);// by take the Absolute value of the negative number, then find the while (Absolute !=0) //the binary reprezentation { int res; res= (Absolute % 2); pushFront (res); Absolute /=2 ;
The program is supposed to convert a two digit hexadecimal number to its binary representation. My code runs without any problems but I do not know how to limit the user's input to two digits only. For example the person can input "1ABC" and the program will give the binary representation and I need it to only accept two digit only like for example "1A".
#include<stdio.h> #define MAX 1000 int main(){ char binaryNumber[MAX],hexaDecimal[MAX]; long int i=0; printf("Enter a two digit hexadecimal number: ");
Write a program in c++ to accept a number and convert this number into binary or hexa decimal or octal number according to the user choice using the concept of array.
Store the result into an array D of 8 elements. Your program should show the decimal numbers for every binary number. Print screen of 6 answers. This means you should try your program six times with different numbers in every run and show the printed screen result.
program that prompts the user to enter a person’s date of birth in numeric form such as 8-27-1980.The program then outputs the date of birth in the form: august 27, 1980.Your program must contain at least two exception classes; invalidDay and invalidMonth.
Not a major issue since I got this to work but for some reason both my random numbers are the same and not sure why ...
using System; using System.Collections.Generic; using System.Linq; using System.Text; public class ComputerAssistedInstructions { private static Random rand1 = new Random(); private static Random rand2 = new Random();
I am a beginner at C++, the output is pretty self explanatory. I'm trying to make a number sorting program with other features, but the numbers are all wrong.
Code: #include <iostream> #include <iomanip> #include <fstream> using namespace std;
I've written a program which takes a character string and then prints each character vertically so that for instance the string 123 can be written as 1 2 3
no what i need is for all the numbers from zero to the inputted number to print the numbers digits vertically but each number to be printed horizontally so that for instance an input of 11 prints
1 2 3 4 5 6 7 8 9 1 1 0 1
i've made it so that i can print all numbers up to the inputted number vertically; however, i am stuck with a method for making each number print horizontally as described above.
I have a error with one of my programs. I'm supposed to get rid of negative numbers when there are numbers that are randomly generated. Here is the middle part of the code.
{ int vectorLength = 10; vector<int> bothSigns(vectorLength); cout << " Input vector: "; for (int i = 0; i < vectorLength; i = i + 1) { bothSigns[i] = rand()%201 - 100;
[code] .....
The part where i'm supposed to start is after the /////'s. However, whenever I input a number for the random numbers(not put in part of code), i keep getting a segmentation error.
Write a program that prompts the user to enter a number larger than 2. The program should use the Number class to determine the prime numbers between 2 and the number entered, and display them in the console window.I've been stuck for a while now and just lost in implementing classes and contstructors.
#include <iostream> using namespace std; int main(int argc, char * argv[]) { cout << "Enter a number larger than 2: " << endl; int n; cin >> n;