I was given a task to convert infix to post fix using both linked lists and stacks in the code so this is what i have written but the problem is it is giving me same error at three different places "missing function header(old style format?)
#include <iostream> #include <string> using namespace std; const int size = 100; class stack{ private: // Declare a structure for the list
i feel like im really close to completing this but i cant seem to get the result printed out i dont think im calling my evaluate function correctly and its not performing the operations..
#include <iostream> #include <stack> //stack header file using namespace std;
I am trying to convert from infix to postfix, and then evaluating the postfix expression to get the final answer. I am having a severe problem though, because for somereason the conversion is not working at all. For example, when I input the first infix expression:
I trying to write a code for a calculator using stack is how to convert an operation from infix to postfix . Here is my attempt I created a header file.
#ifndef STACK_H #define STACK_H #include <iostream> using namespace std; template<class T> struct node { T item;
I'm trying to make an infix to postfix notation calculator. The difficult thing is th stack class is custom. It's not to hard to understand, I don't know if the fact that it is that way will not allow me to receive support. The difference is that the pop functions is as such:
stack<char> conversion; char temp; conversion.pop(temp);//It receives a parameter and puts the popped element in there. conversion.peek(temp);//Places the top element in said parameter
not only that... but these are boolean functions. they return true if the operation was completed. So they can be used as conditions.
#include<iostream> #include<string> #include<stdio.h> #include"stack.h" using namespace std; int main(void) { Stack<char> conversion; string infix,inter,temps;
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The error is that i am mismanaging parenthesis handling and i can't seem to grasp where and how.
An example input is:(35+7)-(9-2) that input gives me:35 7 + 9 2 ) - but another input such as :(35+7)/7 outputs as: 35 7 + 7 /. Totally fine.
I am Getting following errors I don't know why.I have mentioned the lines (in comments) where these errors are occurring. __________________________________________________ warning C4018: '<' : signed/unsigned mismatch error C2064: term does not evaluate to a function taking 0 arguments error C2064: term does not evaluate to a function taking 0 arguments __________________________________________________ _
So I have been working my way through this assignment and I'm just stuck now. I cannot get this work properly It just tells me I'm trying to return a local variable when attempting to return postfix in the to_postfix function. It is line 97 that wont compile. Also I cannot change anything in runner.c.
So i solved my earlier problem but now how do i make it read from the text file that i have and output the postfix notations? Because right now it is only outputting what is currently in the text file for example
6+9 2+7*8 (1+5)*3 5+(6-2)*((2-8)
Header file is
#ifndef STACKS_H #define STACKS_H #include <iostream> using namespace std; const int STACKS_CAPACITY = 128; typedef int StacksElement;
I have the following problem on my C++ Program and I am not sure why it is not working. I am creating a infix to postfix program through an inherited class which I am not sure it is working.
#include <iostream> #include <stack> using namespace std;
int in_stack_Priority(char a){ if(a == '*' || a == '/') return 2;
I keep getting the same error messages every time on Visual Studio. I don't know where the error is originating. Basically I'm trying to convert an infix expression (A+B-C) to a postfix expression (AB+C-) using stacks.
Array based stack class. So i am having a problem, i do not understand how to convert an infix notation into a postfix notation from a txt file. The infix expressions are stored in a text file. for example inside the text file is
6+9 2+7*8 (1+5)*3 5+(6-2)*((2-8)
at the moment my header file is
#ifndef STACKS_H #define STACKS_H #include <iostream> using namespace std; const int STACKS_CAPACITY = 128; typedef int StacksElement;
The question was to evaluate postfix expression (floating point numbers). I had been able to implement stack data structure using one way singly linked list linked list but I am not been able to extract the original input by the user expressions like
How to take such inputs from the user for proper evaluation . Previously I tried to extract separate digits from integer and decimal fields and computed numbers. The method is very lengthy. Any optimised way for taking such input!
Write a program that evaluates postfix expression using array implementation of stack.
The expression [the input] is evaluated from left to right using a stack. When the element read from the expression is an operand, push it into the stack.When the element read from the expression is an operator: Pop two operands from the stack.Evaluate the two operandsPush the result of the evaluation into the stack.
The final result lies on the top of the stack at the end of the calculation. Make sure to display the result before terminating the program.Write a program that evaluates postfix expression using array implementation of stack.
Code: #include <stdio.h> #include <string.h> #include <stdbool.h> #define M 20
I just started by defining a stack class (stackDouble). I need to write a program that accepts an infix calculator expression, with the following operators (**, exponentiation, /, division, and, -, subtraction. The operator precedence is exponent, division, and subtraction.I need to use a stack of doubles and a stack of strings, of which I can write two classes, or write a single stack template. The user will input the expression just via cin, and there will be a # before every number, a ! before each operator, and a . at the end of the expression. '#', '!', or '.' can be input into a char variable, numbers into a double variable and operators into a string variable.
For example, the following would output 6:
# 3 ! / # 2 ! / # .5 ! ** # 2 .
As stated above, I already made up a stackDouble class. What would I need to do to create the other class (I don't think I want to do it with a template)?
Code: #include <iostream> #include <string> using namespace std; class stackDouble{
Given a set of different types of paired symbols; determine whether it is balanced or not (the opening and closing version of each type are paired correctly). Any other type of characters may appear in the input will be neglected.
For example: (**(*[*])****) is balanced, also [{}**[]**()]** is balanced. But ((*{*)*}) is unbalanced as well as [()***[]***{*(*)}.
Write a C++ program that requires a string containing and expression as an input from the user and check for balanced bracket pairs using stack data structure.
Here is my code which give me nothing when I run it.
#include <iostream> #include <string> using namespace std; class CustomStack {
How to implement the main queue functions Enque() and Deque() using two stacks S1 & S2. You allowed only to call push () and pop() functions of the two stacks to implement Enque()and Deque() functions.
#include<iostream> using namespace std; const int size=5; int arr[size]; int front=-1,rear=-1; bool isfull() { if(rear==size-1)
Any example of a graph search algorithm that uses a recursion and linked list based stacks to determine a route from a single point on a graph to another single point on a graph?
I am still new to stacks and recursion and am trying to implement two functions using recursion to get the maximum element in a stack and copying one stack into the other but it keeps repeating some elements and i dont understand why!!
Code: #include<stdio.h> #include<conio.h> #include<string.h> #include<ctype.h> #define MAX 50
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My output should look like this ..
Enter an expression in infix form: (9+6)/(2*4)^15
Specify output expression type,1) Prefix 2)Postfix The Prefix expression is: /+96^*2415 ---------------------------------------------- Enter an expression in infix form: (9+6)/(2*4)^15
Specify output expression type,1) Prefix 2)Postfix The Postfix expression is:96+24*15^/
/* It will read in a infix expression from a text file.check if the parentheses in the input expression are balanced.convert the infix expression into a postfix expression and evaluate the expression.*/
int main() { string expression; string postfixExpression; double result; testBalanced();