C++ :: Infix To Postfix Using Stack Conversion
Mar 8, 2013
I am Getting following errors I don't know why.I have mentioned the lines (in comments) where these errors are occurring.
__________________________________________________
warning C4018: '<' : signed/unsigned mismatch
error C2064: term does not evaluate to a function taking 0 arguments
error C2064: term does not evaluate to a function taking 0 arguments
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Code:
/////////////////////////////////////////////////
//libraries
/////////////////////////////////////////////////
#include <iostream>
#include <string>
using namespace std;
[Code] .....
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Mar 27, 2014
I keep getting the same error messages every time on Visual Studio. I don't know where the error is originating. Basically I'm trying to convert an infix expression (A+B-C) to a postfix expression (AB+C-) using stacks.
#include <iostream>
#include <fstream>
#include <string>
#include <stack>
#include "Expression.h"
#include "stackType.h"
using namespace std;
int main() {
string fileName;
string infixExpression, postfixExpression;
[Code] .....
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Feb 4, 2014
Array based stack class. So i am having a problem, i do not understand how to convert an infix notation into a postfix notation from a txt file. The infix expressions are stored in a text file. for example inside the text file is
6+9
2+7*8
(1+5)*3
5+(6-2)*((2-8)
at the moment my header file is
#ifndef STACKS_H
#define STACKS_H
#include <iostream>
using namespace std;
const int STACKS_CAPACITY = 128;
typedef int StacksElement;
[Code] ....
but how to make it convert the into postfix...
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Apr 12, 2015
I am trying to convert from infix to postfix, and then evaluating the postfix expression to get the final answer. I am having a severe problem though, because for somereason the conversion is not working at all. For example, when I input the first infix expression:
24 + 33 * ( 7 - 5 ) + 8 / 3 it ouputs 24 33 7 5 - 5 ) + 8 / 3( 7 - 5 ) + 8 / 3* ( 7 - 5 ) + 8 / 3+ 33 * ( 7 - 5 ) + 8 / 3 8 3/ 3+ 8 / 3
Which is obviously very wrong. I am not really sure where the problem is though.
Below I have included all of the code needed. I also had to create my own stack class, so I will include it too .
#include "stacks.h"
#include <iostream>
using namespace std;
bool IsOperand(char C) {
if(C >= '0' && C <= '9') return true;
if(C >= 'a' && C <= 'z') return true;
[Code] .....
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Sep 25, 2013
I trying to write a code for a calculator using stack is how to convert an operation from infix to postfix . Here is my attempt I created a header file.
#ifndef STACK_H
#define STACK_H
#include <iostream>
using namespace std;
template<class T>
struct node {
T item;
[Code] .....
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Sep 16, 2013
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
#include<ctype.h>
#define MAX 50
[Code] ....
[URL] .....
My output should look like this ..
Enter an expression in infix form: (9+6)/(2*4)^15
Specify output expression type,1) Prefix 2)Postfix
The Prefix expression is: /+96^*2415
----------------------------------------------
Enter an expression in infix form: (9+6)/(2*4)^15
Specify output expression type,1) Prefix 2)Postfix
The Postfix expression is:96+24*15^/
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Sep 14, 2014
I'm trying to make an infix to postfix notation calculator. The difficult thing is th stack class is custom. It's not to hard to understand, I don't know if the fact that it is that way will not allow me to receive support. The difference is that the pop functions is as such:
stack<char> conversion;
char temp;
conversion.pop(temp);//It receives a parameter and puts the popped element in there.
conversion.peek(temp);//Places the top element in said parameter
not only that... but these are boolean functions. they return true if the operation was completed. So they can be used as conditions.
#include<iostream>
#include<string>
#include<stdio.h>
#include"stack.h"
using namespace std;
int main(void) {
Stack<char> conversion;
string infix,inter,temps;
[Code] .....
The error is that i am mismanaging parenthesis handling and i can't seem to grasp where and how.
An example input is:(35+7)-(9-2)
that input gives me:35 7 + 9 2 ) -
but another input such as :(35+7)/7
outputs as: 35 7 + 7 /. Totally fine.
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Oct 1, 2013
Program which convert expression from PostFiz to Infix and also wants to evaluate them....
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Nov 21, 2014
So I have been working my way through this assignment and I'm just stuck now. I cannot get this work properly It just tells me I'm trying to return a local variable when attempting to return postfix in the to_postfix function. It is line 97 that wont compile. Also I cannot change anything in runner.c.
Calculator.c
Code:
1 #include <stdio.h>
2 #include <stdlib.h>
3 #include <ctype.h>
4 #include <string.h>
5 #include "stack.h"
[Code] .....
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Feb 6, 2014
So i solved my earlier problem but now how do i make it read from the text file that i have and output the postfix notations? Because right now it is only outputting what is currently in the text file for example
6+9
2+7*8
(1+5)*3
5+(6-2)*((2-8)
Header file is
#ifndef STACKS_H
#define STACKS_H
#include <iostream>
using namespace std;
const int STACKS_CAPACITY = 128;
typedef int StacksElement;
[Code]...
test client cpp is
#include <iostream>
using namespace std;
#include "Stacks.h"
#include <fstream>
#include <string>
#include <cassert>
#include <cctype>
[Code]...
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May 24, 2014
I need to convert from an infix expression to postfix using stacks!
#ifndef EXPRESSIONMANAGER_H_
#define EXPRESSIONMANAGER_H_
#include <iostream>
#include <stack>
#include <string>
#include <sstream>
using namespace std;
class ExpressionManager : public ExpressionManagerInterface{
[code]....
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Apr 25, 2014
I have the following problem on my C++ Program and I am not sure why it is not working. I am creating a infix to postfix program through an inherited class which I am not sure it is working.
#include <iostream>
#include <stack>
using namespace std;
int in_stack_Priority(char a){
if(a == '*' || a == '/')
return 2;
[Code] .....
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Sep 28, 2014
I was given a task to convert infix to post fix using both linked lists and stacks in the code so this is what i have written but the problem is it is giving me same error at three different places "missing function header(old style format?)
#include <iostream>
#include <string>
using namespace std;
const int size = 100;
class stack{
private: // Declare a structure for the list
[Code] ....
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Dec 14, 2013
i try to write a postfix calculator program using stack in C++ the in put must be the infix expression but can dont know how to write a infix expression in put.
this is my code :
#include <iostream>
#include <stdio.h>
#include <math.h>
#include <conio.h>
using namespace std;
}
[code]....
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Mar 15, 2015
I'm having some significant trouble with an assignment to create a postfix calculator that simulates the dc calculator function in linux. I have attached the handout with project instructions, but my main problem at the moment lies with parsing through the string input and adding the numbers into a stack of ints.
Project #2.pdf (47.78K)
Here's a brief summary of the methods used in the switch statement:
OPERATORS AND COMMMAND INPUTS
+ : Pops two values off the stack, adds them, and pushes the result.
- : Pops two values, subtracts the first one popped from the second one popped, and pushes the result.
* : Pops two values, multiplies them, and pushes the result.
/ : Pops two values, divides the second one popped from the first one popped, and pushes the result.
% : Pops two values, computes the remainder of the division that the / command would do, and pushes that.
Commands
p - Prints the value on the top of the stack, without altering the stack. A newline is printed after the value.
f - Prints the entire contents of the stack without altering anything. A newline is printed after each value
n - Prints the value on the top of the stack, pops it off, and does not print a newline after.
c - Clears the stack, rendering it empty.
d - Duplicates the value on the top of the stack, pushing another copy of it. Thus "4d*p" computes 4 squared and prints it.
r - Reverses the order of (swaps) the top two values on the stack.
Exception handling also needs to be added to account for division by zero and and invalid operator.
Right now my biggest problem is that I keep getting the following strange output where a 0 is automatically added to the stack when I call a function or operator. I realize this is probably because of the lines I have placed outside of the for loop that read
//END FOR LOOP
int num = atoi(operands.c_str());
myStack.push(num);
operands = "";
cout << num << " added." << endl;
But when I tried putting these statements INSIDE the for loop, I just get more errors. I've been working on this for a number of hours but I can't figure out my issue. I've also attached an image of my current output.
#include <iostream>
#include <cctype>
#include <string>
#include <cstdlib>
using namespace std;
#include "stack.h"
bool isOperator(const char& input );
[code]....
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Apr 26, 2014
Write a program that evaluates postfix expression using array implementation of stack.
The expression [the input] is evaluated from left to right using a stack. When the element read from the expression is an operand, push it into the stack.When the element read from the expression is an operator: Pop two operands from the stack.Evaluate the two operandsPush the result of the evaluation into the stack.
The final result lies on the top of the stack at the end of the calculation. Make sure to display the result before terminating the program.Write a program that evaluates postfix expression using array implementation of stack.
Code:
#include <stdio.h>
#include <string.h>
#include <stdbool.h>
#define M 20
typedef struct{
[Code] ....
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Dec 3, 2014
Also, can't use namespace std for this.
#include<iostream>
#include<stack>
#include<fstream>
#include<iomanip>
#include<queue>
#include<cassert>
[Code] ....
/* It will read in a infix expression from a text file.check if the parentheses in the input expression are balanced.convert the infix expression into a postfix expression and evaluate the expression.*/
int main() {
string expression;
string postfixExpression;
double result;
testBalanced();
[Code] ....
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Feb 15, 2015
My program suppose calculate postfix expression.
Ex. 5 4 + 3 10 * + the answer is 39 because if I change it to infix, it's (5 + 4) + (3 * 10)
I need to use vector to compute the value. Here is what I think. First, I save leftmost from the string. If it is a number, I push. If that is a operation, I pop twice and push the result. By doing it until the string is emptied, the vector will only contain the final answer. And here is my code
#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main(){
vector<int> stack;
string input;
[Code] .....
When I put 1 1 + or 2 2 +, it showing me a correct answer, but when I put the above example which is 5 4 + 3 10 * +, it shows 30 instead of 39.
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Apr 25, 2013
first code,
Code:
int aRRay[] = {2,4,8,-2,-1,100};
int *ptr;
int loop;
ptr = &aRRay[0];
}
[code].....
first code result, " aRRay[] " and " ptr + loop " are in the same result
second code result, " aRRay[] " and "ptr + loop " are in the same result too,
third code result, " aRRay[] " and "ptr + loop " are in the same result Except "aRRay[4] = -1 with ptr + 4 = 100 " and "aRRay[5] = 100 with ptr + 5 = 14"
Question:Why the third code had a different result ? Its only because of the increment ++ptr or the round brackets on the *(++ptr) ?
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Nov 3, 2013
i feel like im really close to completing this but i cant seem to get the result printed out i dont think im calling my evaluate function correctly and its not performing the operations..
#include <iostream>
#include <stack> //stack header file
using namespace std;
[Code].....
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Jul 27, 2012
Recently, i successfully overloaded postfix operator to class counter by using Object and Class. Now, i want to overload same postfix operator to Inheritance. I created my code and generated in compiler. But, my compiler signaled me uncommon error(saw first time) and i couldn't generate any idea where my actually mistake is.
Here is my Code which objective is to count the number increasingly or decreasingly as per object created of CountDn class.
Code:
#include <iostream>
using namespace std;
class Counter // base class
{
protected : // NOTE : Not Private
unsigned int count;
[Code] ....
Error :|41|error: no 'operator++(int)' declared for postfix '++', trying prefix operator instead|
|42|error: no 'operator++(int)' declared for postfix '++', trying prefix operator instead|
|42|error: no match for 'operator=' in 'c2 = c1.CountDn::<anonymous>.Counter:perator++()'|
|44|error: no 'operator--(int)' declared for postfix '--', trying prefix operator instead|
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May 2, 2013
The objective is to build a month class that hold data on the number of the month and the name of the month. Using constructors and overloads, set it up to where you can input either the month or the name and it will output the results for both the month number and name.
Here is the code I have so far:
#include<iostream>
#include<string>
using namespace std;
class Month{
private: string name;
int monthNumber;
[Code] ....
It is almost fully compiled if I go by the error list. The only problems I see to be having are with the prefix and postfix overloads.
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Oct 26, 2012
I have an assignment which includes overriding the prefix and postfix operators, and my teacher has provided what the output from the program should be. I've written the code and it's nearly perfect, except for one tiny error I can't seem to get right.
This is (most of) the code from the header--I left out a few of the parts that aren't relevant to my question:
Code:
using namespace std;
#include<string>
#include<iostream>
class NumDays {
private:
int hours;
[Code] ....
The two problem lines are supposed to be outputting 12 and 1.5, respectively, but are instead showing 13 and 1.625. I know that hours is being changed to 12 at the end of the overriden prefix operation in the line above them, so I don't understand why it returns to 13 again. What I need to change?
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Apr 4, 2013
The question was to evaluate postfix expression (floating point numbers). I had been able to implement stack data structure using one way singly linked list linked list but I am not been able to extract the original input by the user expressions like
ex:
1. 252.124 3453.7 * 46.3 346.2 23.6 ^/$
2.45.23 87.045 * 6.5 ^$
etc,($ELIMETER)
How to take such inputs from the user for proper evaluation . Previously I tried to extract separate digits from integer and decimal fields and computed numbers. The method is very lengthy. Any optimised way for taking such input!
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Apr 9, 2014
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int displayMenu ();
void addRecords ();
void zip ();
void city ();
[Code] ...
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Apr 1, 2013
I want to convert time from est to utc. Is there any function for this.
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